Equation of a Plane
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Transcript of Equation of a Plane
![Page 2: Equation of a Plane](https://reader036.fdocuments.in/reader036/viewer/2022082316/55cf915f550346f57b8cf759/html5/thumbnails/2.jpg)
The Vector equation of a planeTo find the vector equation of a plane a point on the plane and two different direction vectors are required. The equation is defined as:
where a is the point on the plane and b and c are the vectors.
This equation can then be written as:
![Page 3: Equation of a Plane](https://reader036.fdocuments.in/reader036/viewer/2022082316/55cf915f550346f57b8cf759/html5/thumbnails/3.jpg)
The Cartesian equation of a planeThe cartesian equation of the plane is easier to use. The equation is defined as:
One of the advantages to writing the equation in cartesian form is that we can easily find the normal (perpendicular) vector to the plane. It will be:
A proof of this is shown next.
![Page 4: Equation of a Plane](https://reader036.fdocuments.in/reader036/viewer/2022082316/55cf915f550346f57b8cf759/html5/thumbnails/4.jpg)
The Cartesian equation of a plane and its normalLook at the diagram. It shows a plane
with the vector AB and a normal to the plane, n.AB is perpendicular to n, so:
So the vector n passes through these two points on the plane. This can be applied to any other point on the plane.
![Page 5: Equation of a Plane](https://reader036.fdocuments.in/reader036/viewer/2022082316/55cf915f550346f57b8cf759/html5/thumbnails/5.jpg)
Finding the cartesian equation of the plane - 1Method 1: Given a point on the plane and the
plane’s normal.Find the cartesian equation of the plane containing the point (2,3,-1) and with
normal vector . Cartesian equation is ax+by+cz=d
The normal to the plane is .
Equation is 5x-y+2z=d
Substitute the point in to find d: 5(2)-(3)+2(-1)=5
5x-y+2z=5
![Page 6: Equation of a Plane](https://reader036.fdocuments.in/reader036/viewer/2022082316/55cf915f550346f57b8cf759/html5/thumbnails/6.jpg)
Finding the cartesian equation of the plane - 2Method 2: Given 3 points on a
plane.Find the cartesian equation of the plane containing the points A(2,3,-1), B(4,0,5), and C(5,2,3).
Remember the work on the cross product:
Find two vectors, in this case AB and AC, then calculate the cross product. This will give us the normal vector to the plane.
The cross product:
Normal vector to plane will be .Plane has the equation -6x+10y+7z=d.Substitute the point in to find d: -6(2)+10(3)+7(-1)=11-6x+10y+7z=11