ENGR221 Lecture 10

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    Equilibrium and TrussesEquilibrium and Trusses

    ENGR 221

    February 17, 2003

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    Lecture Goals

    Lecture Goals

    6-4

    Equilibrium in Three Dimensions 7-1 Introduction to Trusses

    7-2 Plane Trusses

    7

    -3 Space Trusses

    7-4 Frames and Machines

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    EquilibriumEquilibrium ProblemProblemDetermine the reactions

    at A and the force in bar

    CD due to the loading.

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    EquilibriumEquilibrium ProblemProblemDraw the free-body

    diagram of the main

    body.

    1 o6 in.tan 26.56512 in.

    U ! !

    RAx

    RAy

    TCD

    U

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    EquilibriumEquilibrium ProblemProblemLook at equilibrium

    o

    x x

    o

    x

    o

    y y

    o

    y

    cos 26.565 125 lb 0

    cos 26.565 125 lb

    sin 26.565 40 lb 60 lb 80 lb 0

    sin 26.565 20 lb

    F R T

    R T

    F R T

    R T

    ! !!

    ! !

    !

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    EquilibriumEquilibrium

    ProblemProblemTake the moment about A

    RAx

    RAy

    TCD

    U

    o

    A CD

    o

    CD

    CD

    0 cos 26.565 6 in. 40 lb 4 in.

    60 lb 8 in. 80 lb 12 in.

    cos 26.565 6 in. 320 lb-in

    59.628 lb

    M T

    T

    T

    ! !

    !

    !

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    EquilibriumEquilibrium

    ProblemProblemTake the moment about A

    RAx

    RAy

    TCD

    U

    o

    x

    o

    y

    59.628 lb cos 26.565 125 lb

    71.667 lb

    59.628 lb sin 26.565 20 lb

    6.667 lb

    R

    R

    !

    ! !

    !

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    Equilibrium in 3Equilibrium in 3--DimensionsDimensionsIn two dimensions, the equations are solved

    using the summation of forces in the x, y and z

    directions and the moment equilibrium includes

    moment components in the x, y and z directions.

    x y z0 0 0 F F F ! ! !

    x y z0 0 0M M M! ! !

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    TrussesTrusses --DefinitionDefinitionTrusses are structures

    composed entirely of two

    force members . They

    consists generally of

    triangular sub-element and

    are constructed and

    supported so as to prevent

    any motion.

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    FramesFrames --DefinitionDefinition

    Frames are structures that

    always contain at least one

    member acted on by forces

    at three or more points.

    Frames are constructed and

    supported so as to prevent

    any motion. Frame like

    structures that are not fully

    constrained are called

    machines or mechanisms.

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    TrussTrussPlanar Trusses - lie in a

    single plane and all

    applied loads must lie in

    the same plane.

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    TrussTrussSpace Trusses - are structures that are not

    contained in a single plane and/or are loaded out

    of the plane of the structure.

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    TrussTrussThere are four main assumptions made in the

    analysis of truss

    Truss members are connected together at theirends only.

    Truss are connected together by frictionless

    pins.

    The truss structure is loaded only at the joints.

    The weights of the members may be neglected.

    1

    2

    3

    4

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    Simple Truss

    Simple Truss

    The basic building block of a

    truss is a triangle. Large truss

    are constructed by attachingseveral triangles together A

    new triangle can be added

    truss by adding two members

    and a joint. A trussconstructed in this fashion is

    known as a simple truss.

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    Simple Truss

    Simple Truss

    It has been observed that the analysis of truss

    can be done by counting the number member

    and joints on the truss to determine the truss isdeterminate, unstable or indeterminate.

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    Simple Truss

    Simple Truss

    A truss is analysis by using m=2*j-3, where m is

    number of members, j represents the number of

    joints and 3 represents the external supportreactions.

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    Simple Truss

    Simple Truss

    If m< 2j-3, then the truss is unstable and will

    collapse under load.

    If m> 2j-3, then the truss has more unknowns

    than know equations and is an indeterminate

    structure.

    If m= 2j-3, ensures that a simple plane truss is

    rigid and solvable, it is neither sufficient nor

    necessary to ensure that a non-simple plane truss

    is rigid and solvable.

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    Simple Truss

    Simple Truss-- IdentifyIdentify

    Determine type of simple truss is it

    determinate, indeterminate or unstable.

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    Method of Joints

    Method of Joints --TrussTruss

    The truss is made up of single bars, which are

    either in compression, tension or no-load. The

    means of solving force inside

    of the truss use equilibriumequations at a joint. This

    method is known as the

    method of joints.

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    Method of Joints

    Method of Joints --TrussTrussThe method of joints uses the summation of

    forces at a joint to solve the force in the

    members. It does not use the

    moment equilibrium equationto solve the problem. In a two

    dimensional set of equations,

    In three dimensions,

    x y0 0F F! !

    z 0F !

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    Method of Joints

    Method of Joints ExampleExample

    Using the method of

    joints, determine the

    force in each member ofthe truss.

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    Method of Joints

    Method of Joints ExampleExample

    Draw the free body

    diagram of the truss and

    solve for the equations

    x x

    x

    y y

    y

    0

    0 lb

    0 2000 lb 1000 lb

    3000 lb

    F C

    C

    F E C

    E C

    ! !

    !

    ! !

    !

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    Method ofMethod of

    JointsJoints ExampleExample

    Solve the moment about C

    C

    y

    0 2000 lb 24 ft 1000 lb 12 ft 6 ft

    10000 lb

    C 3000 lb 10000 lb 7000 lb

    M E

    E

    ! !

    !

    ! !

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    Method ofMethod of

    JointsJoints ExampleExample

    Look at joint A

    y AD

    AD AD

    x AD AB AB

    AB AB

    40 2000 lb

    5

    2500 lb 2500 lb C

    3 30 2500 lb

    5 5

    1500 lb 1500 lb T

    F F

    F F

    F F F F

    F F

    ! !

    ! !

    ! ! !

    ! !

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    Method ofMethod of

    JointsJoints ExampleExample

    Look at joint D

    y

    x

    4 4 4 40 2500 lb

    5 5 5 5

    2500 lb 2500 lb T

    3 30

    5 5

    3 32500 lb 2500 lb

    5 5

    3000 lb 3000 lb

    F F F F

    F F

    F F F F

    F

    F F

    ! ! !

    ! !

    ! !

    !

    ! !

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    Method ofMethod of

    JointsJoints ExampleExample

    Look at joint B

    y

    x

    4 4

    0 1000 lb5 5

    4 42500 lb 1000 lb

    5 5

    3750 lb 3750 lb

    3 305 5

    3 32500 lb 1500 lb 3750 lb

    5 5

    5250 lb 5250 lb T

    F F F

    F

    F F

    F F F F F

    F

    F F

    ! !

    !

    ! !

    ! !

    !

    ! !

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    Method ofMethod of

    JointsJoints ExampleExample

    Look at joint E

    y

    x

    4 4

    0 10000 lb5 5

    4 43750 lb 10000 lb

    5 5

    8750 lb 8750 lb

    3 305 5

    3 33750 lb 3000 lb

    5 5

    8750 lb 8750 lb

    F F F

    F

    F F

    F F F F

    F

    F F

    ! !

    !

    ! !

    ! !

    !

    ! !

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    Method ofMethod of

    JointsJoints ExampleExample

    Look at joint C to check

    the solution

    y CE

    x CE CB x

    40 7000 lb

    5

    48750 lb 7000 lb 0 OK!

    5

    305

    38750 lb 5250 lb 0 0

    5

    F F

    F F F C

    ! !

    ! !

    ! !

    ! !

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    Method of Joints

    Method of Joints Class ProblemClass Problem

    Determine the forces BC,

    DF and GE. Using themethod of Joints.

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    Method of

    Sections

    Method of

    Sections --TrussTruss

    The method of joints is most effective when

    the forces in all the members of a truss are to

    be determined. If however, the force is only

    one or a few members are needed, then the

    method of sections is more efficient.

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    Method of

    Sections

    Method of

    Sections --TrussTruss

    If we were interested in the

    force of member CE. We

    can use a cutting line or

    section to breakup the truss

    and solve by taking the

    moment about B.

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    Method of

    Sections

    Method of

    Sections ExampleExample

    Determine the forces in members FH, GH and GI

    of the roof truss.

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    Method of

    Sections

    Method of

    Sections ExampleExample

    Draw a free body diagram and solve for the

    reactions.

    RAx

    RAy

    L

    x x

    x

    y

    y

    0

    0 k

    0

    20 k

    F R

    R

    F

    L R

    ! !

    !

    !

    !

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    Method ofMethod of

    Sections

    Sections ExampleExample

    Solve for the

    moment at A.

    RAx

    RAy

    L

    A

    Ay

    6 kN 5 m 6 kN 10 m 6 kN 15 m

    1 kN 20 m 1 kN 25 m 30 m

    7.5 kN

    12.5 kN

    M

    L

    L

    R

    !

    !

    !

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    Method of

    Sections

    Method of

    Sections ExampleExample

    Solve for the member GI. Take a cut between the

    third and fourth section and draw the free-bodydiagram.

    HI HI

    HI

    1 o

    8 m 10 m8 m

    15 m 10 m 15 m

    5.333 m

    8 mtan 28.1

    15 m

    ll

    l

    E

    ! !

    !

    ! !

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    Method ofMethod of

    Sections

    Sections ExampleExample

    The free-body diagram of

    the cut on the right side.

    H GI

    GI GI

    1 k 5 m 7.5 k 10 m 5.333 m

    13.13 k 13.13 k T

    M F

    F F

    !

    ! !

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    Method of

    Sections

    Method of

    Sections ExampleExample

    Use the line of action of the forces and take the moment

    about G it will remove the FGI and FGH and shift FFH to the

    perpendicular of G.

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    Method ofMethod of

    Sections

    Sections ExampleExample

    Take the moment at G

    G

    o

    FH

    FH FH

    1 kN 5 m 1 kN 10 m 7.5 kN 15 m

    cos 28.1 8 m

    13.82 kN 13.82 kN C

    M

    F

    F F

    !

    ! !

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    Method of

    Sections

    Method of

    Sections ExampleExample

    Use the line of action of the forces and take the moment

    about L it will remove the FGI and FFH and shift FGH to

    point G.

    1 o5 mtan 133.25.333 m

    F ! !

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    Method ofMethod of

    Sections

    Sections ExampleExample

    Take the moment at L

    o

    L GH

    GH GH

    1 k 5 m 1 k 10 m cos 43.2 15 m

    1.372 k 1.372 k

    M F

    F F

    !

    ! !

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    Method ofSectionsMethod ofSections ClassClass

    ProblemProblem

    Determine the forces in members CD and CE using method

    of sections.

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    H

    omework (Due 2/24/03)H

    omework (Due 2/24/03)Problems:

    6-34, 6-37, 6-38, 6-40, 6-45, 6-63

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    TrussTruss Bonus ProblemBonus ProblemDetermine whether the

    members are unstable,

    determinate orindeterminate.

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    TrussTruss Bonus ProblemBonus ProblemDetermine the loads in

    each of the members.

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    TrussTruss Bonus ProblemBonus ProblemDetermine the loads in

    each of the members.

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    TrussTruss Bonus ProblemBonus ProblemDetermine the loads in

    each of the members.