Empirical and Molecular Formulas Worksheets

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 1 Empirical and Molecular Formulas The empirical formula of a compound gives the  simplest whole number ratio of different types of atoms in the compound.  All salt formulas are empirical formulas. On the other hand, the molecular formula of a compound may or may not be the same as its empirical formula. For example, the molecular formula of butane is C 4 H 10 while its empirical formula is C 2 H 5 . The molecular formula gives the true number of each kind of atom in a molecule. Empirical formulas may be easily determined from experimental data. Usually you must first determine how many grams of each t ype of atom are in the compound. If percent composition data is given, assume that you hav e 100.0 g of the compound; then the number of grams of each element is equal to the percentage for that element. The next task is convert the grams of each element to moles of the element. Be sure to keep at least three significant figures in your answers. The final step is to write the molar amounts of each element a s subscripts in the formula. Then divide all molar subscripts by the smallest value in the se t. At this p oint, the subscripts may all be very close to who le numbers; if so, you are finished. If one (or more) of the subscripts is not close to a whole number, multiply all molar subscripts by the simple factor which makes all subscripts whole nu mbers. Once the empirical formula is determined, the molecular formula is easil y found if the molar mass (molecular weight) of the molecule is also known. You first calculate the molar mass of the empirical formula. Then you divide the molar mass of t he molecule by the molar ma ss of the empirical for mula. The division should give a simple whole number. That number is the factor  by which all subscripts i n the empirical formula must be multipl ied to obtain the molecular formula.  ________ ________ _ Exercises 1. The molecular for mula of the antifreeze ethylene glycol is C 2 H 6 O 2 . What is the empiri cal formula?  ________ _ 2. A well-known reagent in analy tical chemistry, dimethylglyoxime, has the empirical formula C 2 H 4  NO. If its molar mass is 116 .1 g/mol, what is the molecular formula of the compound?  ________ ________ _______ 3. Nitrogen and oxygen form an extensive series of oxides with t he general formula N x O y . One of them is a blue solid that comes apart, reversi bly, in the gas phase. It contains 36.84% N. What is the empirical formula of this oxide?  ________ _ 4. A sample of indium chloride weighing 0.5000 g is found to contain 0.2404 g of chlorine What is the empirical formula of the indium compound?  ________ ________ _ Answers: 1. CH 3 O 2. Molar mass of empirical formula is 58.06 g/mol. Thus molecular f ormula is C 4 H 8  N 2 O 2 . 3. The ratios are  N 1.00 O 1.50 . Since 1.50 is not close to a whole number, we multiply both subscripts by 2. The empirical formula i s thus N 2 O 3 . (The name is dinitr ogen trioxide.) 4. InCl 3 . 

Transcript of Empirical and Molecular Formulas Worksheets

 

 

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Empirical and Molecular Formulas

The empirical formula of a compound gives the simplest whole number ratio of different

types of atoms in the compound.  All salt formulas are empirical formulas. On the other hand,

the molecular formula of a compound may or may not be the same as its empirical formula. For 

example, the molecular formula of butane is C4H10 while its empirical formula is C2H5. The

molecular formula gives the true number of each kind of atom in a molecule.

Empirical formulas may be easily determined from experimental data.

Usually you must first determine how many grams of each type of atom are in the compound.

If percent composition data is given, assume that you have 100.0 g of the compound; then thenumber of grams of each element is equal to the percentage for that element.

The next task is convert the grams of each element to moles of the element. Be sure to keepat least three significant figures in your answers.

The final step is to write the molar amounts of each element as subscripts in the formula.

Then divide all molar subscripts by the smallest value in the set. At this point, the subscriptsmay all be very close to whole numbers; if so, you are finished. If one (or more) of the

subscripts is not close to a whole number, multiply all molar subscripts by the simple factor 

which makes all subscripts whole numbers.

Once the empirical formula is determined, the molecular formula is easily found if the molar 

mass (molecular weight) of the molecule is also known. You first calculate the molar mass of the

empirical formula. Then you divide the molar mass of the molecule by the molar mass of theempirical formula. The division should give a simple whole number. That number is the factor 

 by which all subscripts in the empirical formula must be multiplied to obtain the molecular 

formula.

 ______________________________________________________________________________ Exercises

1. The molecular formula of the antifreeze ethylene glycol is C2H6O2. What is the empirical

formula?

 ______________________________________________________________________________ 

2. A well-known reagent in analytical chemistry, dimethylglyoxime, has the empirical formula

C2H4 NO. If its molar mass is 116.1 g/mol, what is the molecular formula of the compound?

 ____________________________________________________________________________ 

3. Nitrogen and oxygen form an extensive series of oxides with the general formula NxOy. One

of them is a blue solid that comes apart, reversibly, in the gas phase. It contains 36.84% N.

What is the empirical formula of this oxide?

 ______________________________________________________________________________ 

4. A sample of indium chloride weighing 0.5000 g is found to contain 0.2404 g of chlorineWhat is the empirical formula of the indium compound?

 ______________________________________________________________________________ 

Answers:

1. CH3O

2. Molar mass of empirical formula is 58.06 g/mol. Thus molecular formula is C4H8 N2O2.

3. The ratios are  N1.00O1.50

. Since 1.50 is not close to a whole number, we multiply both 

subscripts by 2. The empirical formula is thus N2O3. (The name is dinitrogen trioxide.)

4. InCl3.