Electrostatics..Sol
-
Upload
subhojyotidas -
Category
Documents
-
view
212 -
download
0
Transcript of Electrostatics..Sol
-
8/18/2019 Electrostatics..Sol
1/2
Visitors Online: 4195 | Sunday 21st February 2016 LOGINREGISTRATION
HOME PAPERS TUTORS CBSE BOOKS eBOOKS SCHOOLS ALUMNI ARTICLES CLASSIFIEDS EDUCATION FUN ZONE
CBSE Physics (Chapter Wise With Hint / Solution) Class XII
CBSE Guess > eBooks > Class XII > CBSE Physics (Chapter Wise With Hint / Solution) Class XII
+5
PHYSICS - CBSE CLASS XIIPHYSICS - CBSE CLASS XII
Electrostatics Key
View Questions
1. In the dielectric medium between the plates.
2. High potential, as electrons are negatively charged.
3. Zero
4. Zero
5. ML-1T-2
6. Zero
7. No.
8. Because they are indicators of electric field, extending to infinite distance.
9. C is proportional to A (area) Therefore C2 = 2C1 Since C = Q/V ,So the slope represents more capacitance. Hence P represents C2,Q
represents C1
10. Each charge experiences two forces each of magnitude F inclined at an angle of 600.Their
resultant is given by [F2 + F2 +2F2cos 60]1/2 = Ö3.F
11. (i)According to defn of P.D., VP>VQ .So VP-VQ is +ve for q>0.(ii)For qVP .So VP-VQ is -ve
12. Flux = 0, since Qen = 0
13. Due to polaraisation,opposing electric field is created.
14. Electric field at the midpoint of a dipole of length 2a is 2kq/a pointing towards the –ve charge or in the direction opposite to the dipole
moment.
15. Inside the cavity field at any point is uniform and non zero.
16. No. If the initial velocity of the charged particle makes a certain angle with a line of force, then the charged particle shall not move along theline of force.
17. E= -dv/dr= -d(q/4πεor)/dr = q/4πεor2
18. Yes, at the mid point of electric dipole.
19. U = kq2/a- kq2/2a- kq2/2a = 0.
20. C’ = C+C+C = 3C = 75µF Therefore, charge = 75µF x 4200 V = 315 mC*
21. Total ф = q0/ εo = 2/ εo ,→ flux through one face = ф/6 = 1/3 εo.
22. q →------------ Q
1/2mv2 = kQq/r
Or, v2 α 1/r
Or, r α 1/v2
Or, r’ = r/4
23. V = V1+V2
Q =C1V = 6 X 10-6 X 2 = 12mC
As C2 is in series same amount of charge will also flow through it. Now V2= Q/ C2 = (12 X 10-6)/ (12 X 10-6) = 1 Volt Total battery Voltage,V =
2 + 1 = 3 Volt
24.Capacitance of parallel plate capacitor with air between the plates is C0 = e0A/d When the separation between the plates reduced to half,
http://localhost/var/www/apps/http://www.cbseguess.com/http://www.cbseguess.com/papers/http://www.cbseguess.com/tutors/http://www.cbseguess.com/books/http://www.cbseguess.com/ebooks/http://www.cbseguess.com/schools/http://www.cbseguess.com/alumni/http://articles.cbseguess.com/http://www.cbseguess.com/classifieds/http://localhost/var/www/apps/conversion/tmp/scratch_4/electrostatics.phphttp://localhost/var/www/apps/conversion/xiihttp://localhost/var/www/apps/ebookshttp://localhost/var/www/apps/http://www.cbseguess.com/fun/http://www.cbseguess.com/education/http://www.cbseguess.com/classifieds/http://articles.cbseguess.com/http://www.cbseguess.com/alumni/http://www.cbseguess.com/schools/http://www.cbseguess.com/ebooks/http://www.cbseguess.com/books/http://www.cbseguess.com/tutors/http://www.cbseguess.com/papers/http://www.cbseguess.com/https://goo.gl/yZCvZmhttp://www.cbseguess.com/http://www.cbseguess.com/registration/registration.phphttp://www.cbseguess.com/members/login.php
-
8/18/2019 Electrostatics..Sol
2/2
Atomic Nucleus Solution
Current Electricity Solution
Communications Systems Solution
Electronic Devices Solution
Electrostatics Solution
Optics Solution
Electromagnetic Wave Solution
Dual Nature Of Matter And Rediations Solution
Magnetic Effects Of Current & Magnetism Solution
Electromagnetic Induction & Alternating Current Solution
COPYRIGHT © 2003 - 2016 CBSEGuess.comTerms of Usage / Privacy Policy POWERED BY DREAMZSOP
ABOUT CBSEGuessABOUT CBSEGuess
About UsAbout Us
Success StoriesSuccess Stories
Guest BookGuest Book
Important LinksImportant Links
Help / SupportHelp / Support
Advertise With UsAdvertise With Us
Contact UsContact Us
STAY CONNECTEDSTAY CONNECTED
Share 714
CBSE Book StoreCBSE Book Store
Customer CareCustomer Care
Shipping PoliciesShipping Policies
Payment OptionsPayment Options
Refund PolicyRefund Policy
Return PolicyReturn Policy
CBSEGuess CouponsCBSEGuess Coupons
Cbse Latest Sample Papers
Sample Question Papers
CBSE Guess Paper
Earn Money Online
Previous Years Question Papers
CBSE Board Papers
ads by media.net
=e = e us na capac ance s = p = p
25.The arrangement is of 5 capacitors in series.Therefore 1/C’= (1/C) +(1/C) +(1/C) +(1/C) +(1/C) =(5/C) Therefore C’=C/5 Or 5=C/5 or
C=25mF.
26. The charge given to a capacitor is given by q=CV So the remaining energy,qV- 1/2 qV =1/2 qV is lost as heat
27. On equatorial line ,the direction of electric field is reversed to that of axial line. Hence the angle between electric dipole moment& electric
field strength is 1800
CBSE Physics (Chapter Wise With Hint / Solution) Class XII (By Mr. Sreekumaran Nair)
Physics - Mr. Sreekumaran Nair
87KLikeLike
http://www.dreamzsop.com/http://www.cbseguess.com/pages/privacy_policy.phphttp://www.cbseguess.com/pages/termsof_service.phphttp://www.bumpercoupon.com/http://www.cbseguess.com/pages/return-policy.phphttp://www.cbseguess.com/pages/return-policy.phphttp://www.cbseguess.com/pages/payment-options.phphttp://www.cbseguess.com/pages/shipping-pilicies.phphttp://www.cbseguess.com/pages/customer-care.phphttp://findfriendz.com/clubs/profiles/cbseguess-295http://www.linkedin.com/company/1663551http://www.facebook.com/cbseghttps://plus.google.com/b/108367298477201209325/108367298477201209325/postshttp://www.cbseguess.com/pages/contactus.phphttp://www.cbseguess.com/pages/advertise_withus.phphttp://www.cbseguess.com/pages/help.phphttp://www.cbseguess.com/fun/links/http://www.cbseguess.com/fun/guestbook/http://www.cbseguess.com/pages/success_stories.phphttp://www.cbseguess.com/pages/aboutus.phphttp://localhost/var/www/apps/conversion/tmp/scratch_4/electromagnetic_induction_alternating_current_key.phphttp://localhost/var/www/apps/conversion/tmp/scratch_4/electromagnetic_induction_alternating_current.phphttp://localhost/var/www/apps/conversion/tmp/scratch_4/magneticeffects_ofcurrent_magnetism_key.phphttp://localhost/var/www/apps/conversion/tmp/scratch_4/magneticeffects_ofcurrent_magnetism.phphttp://localhost/var/www/apps/conversion/tmp/scratch_4/dualnatureof_matterand_rediations_key.phphttp://localhost/var/www/apps/conversion/tmp/scratch_4/dualnatureof_matterand_rediations.phphttp://localhost/var/www/apps/conversion/tmp/scratch_4/electromagnetic_wave_key.phphttp://localhost/var/www/apps/conversion/tmp/scratch_4/electromagnetic_wave.phphttp://localhost/var/www/apps/conversion/tmp/scratch_4/optics_key.phphttp://localhost/var/www/apps/conversion/tmp/scratch_4/optics.phphttp://localhost/var/www/apps/conversion/tmp/scratch_4/electrostatics.phphttp://localhost/var/www/apps/conversion/tmp/scratch_4/electronic_devices_key.phphttp://localhost/var/www/apps/conversion/tmp/scratch_4/electronic_devices.phphttp://localhost/var/www/apps/conversion/tmp/scratch_4/communications_systems_key.phphttp://localhost/var/www/apps/conversion/tmp/scratch_4/communications_systems.phphttp://localhost/var/www/apps/conversion/tmp/scratch_4/currentelectricity_key.phphttp://localhost/var/www/apps/conversion/tmp/scratch_4/currenteletricity.phphttp://localhost/var/www/apps/conversion/tmp/scratch_4/atomic_nucleus_key.phphttp://localhost/var/www/apps/conversion/tmp/scratch_4/atomic_nucleus.php