Electromagnetics Review

download Electromagnetics Review

of 8

description

EE 140

Transcript of Electromagnetics Review

  • EE140 Review Electrostatics Dr. Ray Kwok

    x(0,0)

    +Q Q

    (a,0) P(x,0)

    4. Consider two point charges (+Q, -Q) located along the x-axis as shown.

    a. What is the electric potential at point P(2a,0)? (Note: there is no charge at point P.)

    b. From this potential, derive an equation for the electric field at that point P.

    c. How much work is required to bring another point charge (+q) from infinity to this

    point P? What does the sign mean?

    d. How much energy is stored in this system of 3-charges? (+Q, -Q, +q).

    (a)

    (b)

    (c)

    sign means it doesnt require work to bring the charge to point P. Work is being done by the charge instead.

    (d)

  • EE140 Review Electrostatics Dr. Ray Kwok

    5. A conducting cylinder of infinite length and radius a has a total

    charge Q uniformly distributed on its surface. A dielectric shell

    (with relative dielectric constant K = 2) of inner radius b and

    outer radius c is shielding the conducting rod as shown in the

    Figure. Calculate the electric field in all regions. Sketch E(r) as a

    function of r.

    E(r

  • EE140 Review Electrostatics Dr. Ray Kwok

    L x

    E=?

    x

    E=? L

    (a)

    (b)

    r dy

    R

    6. (a) What is the electric field at a distance x away from the center of a thin line charge with a

    uniform linear charge density and length L? (see diagram below). (b) Using this result, write the electric field at a distance x above the center of a square loop of length L.

    =

    ==322x r

    dyxk

    r

    x

    r

    dykcos

    r

    dqkE

    4/Lxx

    Lk

    yx

    y

    x

    kE

    rx

    y

    x

    sindcos

    x

    1

    x

    cosdsecx

    r

    dy

    dydsecx

    x

    ytan

    r

    xcos

    22

    2/L

    2/L

    22x

    2223

    32

    3

    2

    +

    =

    +

    =

    =

    ==

    =

    =

    =

    =

    Apply the equation above to this with 2 changes:

    1. the distance x in the equation is from the wire

    to the point. So here, it has to be replaced by

    2. the E field is at an angle, and only the x-

    component add up. So:

    22 )2/L(xx +

    ( ) 2/Lx4/LxLxk4

    E

    4/Lx

    x

    2/Lx4/Lx

    Lk4E

    cos4/L4/Lx4/Lx

    Lk4E

    2222total,x

    222222total,x

    22222total,x

    ++

    =

    +++

    =

    +++

    =

  • EE140 Review Electrostatics Dr. Ray Kwok

    +Q

    Q a

    Q +Q

    a

    x

    y

    O

    7. Consider 4 point-charges (+Q, -Q, +Q, -Q,) located at the corners of a square as shown.

    a. List all the locations where electric field is zero.

    b. List all the locations where electric potential is zero.

    a. Only at center of the square (a/2,a/2) and at infinity (r).

    b. On the lines: y = a/2 and x = a/2 and at infinity (r).

  • EE140 Review Electrostatics Dr. Ray Kwok

    a b c

    r

    E

    3

    5a

    o

    2

    5

    5 b

    a

    o

    5. A non-uniform charge density of = r2 is distributed in an inner sphere of radius a, enclosed by an outer spherical conductor with radius b and c as shown in diagram. The

    outer conductor is electrically grounded. Calculate the electric field in ALL regions. Sketch

    E(r) as a function of r. What is the voltage between the inner sphere and the outer

    conductor? What is the equivalent capacitance of the structure?

    For r< a

    For a < r < b

    E(b < r < c) = 0

    (conductor)

    E(r > c) = 0

    (shielded, net charge =0)

    a

    b

    c

    rrE

    rrE

    drrrdVQEA

    o

    o

    o

    r

    o

    r

    o

    total

    5

    5

    ][4)4(

    )4)((

    3

    52

    0

    22

    0

    =

    =

    ===

    r

    =

    ==

    ===

    baba

    a

    a

    V

    QC

    ba

    adr

    r

    ardEV

    o

    o

    o

    a

    b o

    a

    b

    11

    4

    11

    5

    5

    4

    11

    55

    5

    5

    5

    2

    5

    rr

    rr

    aE

    arE

    drrrdVQEA

    o

    o

    o

    a

    o

    a

    o

    total

    5

    5

    ][4)4(

    )4)((

    2

    5

    52

    0

    22

    0

    =

    =

    ===

    r

  • EE140 Review Electrostatics Dr. Ray Kwok

    x

    E=? r

    y

    6. The electric field of an infinite line charge at a distance r away is

    where is the linear charge density defined by the Q/L (total charge on the line divided by the line length.) Use this result to derive the electric field at a distance x from an infinite

    charge plane of surface charge density of .

    .2

    rr

    Eo

    =

    r

    ( )

    ooo

    net

    oo

    x

    ooo

    x

    x

    r

    xdyE

    r

    xdy

    r

    dydE

    r

    dy

    r

    LdA

    r

    LdQdE

    222

    2cos

    2

    22

    /

    2

    /

    2

    2

    ===

    ==

    ===

  • EE140 Review Electrostatics Dr. Ray Kwok

    +Q Q a

    P

    7. Consider two point charges (+Q, -Q) located at the base of an equilateral triangle as shown.

    a. What is the electric potential at point P (vertex)? (See diagram.)

    b. What is the electric field at point P?

    c. How much work is required to bring another point charge (+q) from infinity to this

    point P?

    d. How much energy is stored in this system of 3-charges? (+Q, -Q, +q).

    (a)

    (b) xa

    kQx

    a

    kQE o )60cos(2

    22=

    =r

    (c) W = U = qV = 0 (from infinity)

    (d) U3q = kQ2/a + 0 = kQ

    2/a (or Ui )

    0==a

    kQ

    a

    kQV

  • EE140 Review Electrostatics Dr. Ray Kwok

    a b c

    r

    E

    or

    b

    a

    or

    8. A coaxial cable is made of an inner cylindrical conductor with radius

    a, an outer cylindrical conductor with radius b and c as shown in

    diagram. The outer conductor is electrically grounded. A dielectric

    material (r) is filled between the 2 conductors (a < r < b). Suppose we have an infinite length of such cable, and a surface charge density is introduced onto the inner conductor, calculate the electric field in ALL

    regions. Sketch E(r) as a function of r. What would the voltage

    between the 2 conductors be? What is the equivalent capacitance per

    length (i.e. the total capacitance divided by the total length)?

    E(r < a) = 0 (conductor)

    For b > r > a

    E(c > r > b) = 0 (conductor)

    E(r > c) = 0 (grounded conductor) [Think how the charges are distributed.]

    a

    b

    c

    rr

    aE

    aLrLE

    aLQEA

    or

    or

    freeor

    )2()2(

    )2(

    =

    =

    ==

    r

    ( )

    =

    ==

    ===

    a

    bL

    C

    a

    ba

    aL

    V

    QC

    a

    badrr

    ardEV

    or

    or

    or

    a

    b or

    a

    b

    ln

    2

    ln

    2

    ln

    rr