Electrochemistry Solving a problem you’ve never seen before and for which you have no formula....

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Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School

Transcript of Electrochemistry Solving a problem you’ve never seen before and for which you have no formula....

Page 1: Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School.

Electrochemistry

Solving a problem you’ve never seen before and for

which you have no formula.

Produced by Mr. DoddridgeMurrieta Valley High School

Page 2: Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School.

What’s the most important thing in chemistry?

Units

Keeping Mr. D happy!

Units

Page 3: Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School.

Keeping Mr. D. happy!

This is a good thought. Although it is very important, it’s probably only #2.

Try again

Page 4: Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School.

Right!

So let’s proceed to a problem keeping this in mind and not panicking

Proceed (next)

Page 5: Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School.

Question:

How much copper can be plated in 30 minutes at 10 amps? (Cu+2 + 2e- → Cu)

What are we being asked? What unit? Were you thinking:

grams?

Next

Page 6: Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School.

What are some facts you know?

Next

1 amp = 1Coulomb/second 1Faraday = 96485 Coulombs/mole e-

Mass of copper = x g/mole (What’s x ?) (Where would you find it?) Were you thinking:

the periodic table?

Page 7: Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School.

Do you remember the question?

How much copper can be plated in 30 minutes at 10 amps? (Cu+2 + 2e- → Cu)

The facts:

10 amps in 30 minutes

1 amp = 1 C/s

1 F = 96,485 C/mole e-

1mole e- = how many moles Cu? (Cu+2 + 2e- → Cu)

1 mole Cu = X grams Cu?

Next

Page 8: Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School.

What’s the given?

=

30 minutes 10 ampsor

given

Page 9: Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School.

What’s the given?

10amps = 10 coulombs/ secondThis might work, but let’s try dealing with the time first.

=

30 minutes 10 amps

Page 10: Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School.

Good! Now what goes here?

30 min=

sec10 Coulomb/

1 min60 sec/ 96,485 C/1 mole e-1F=

/2 mole e-1 mole Cu(s)

1 mole Cu(s)63.5 g Cu/

Page 11: Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School.

Try Again.Remember: units must cancel

30 min=

sec10 Coulomb/

1 min60 sec/ 96,485 C/1 mole e-1F=

/2 mole e-1 mole Cu(s)

1 mole Cu(s)63.5 g Cu/

Page 12: Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School.

Good! Now what goes here?

sec10 Coulomb/

1 min60 sec/ 96,485 C/1 mole e-1F=

/2 mole e-1 mole Cu(s)

1 mole Cu(s)63.5 g Cu/

30 min

1 min

60 sec=

Page 13: Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School.

What will cancel “seconds”?

sec10 Coulomb/

1 min60 sec/ 96,485 C/1 mole e-1F=

/2 mole e-1 mole Cu(s)

1 mole Cu(s)63.5 g Cu/

30 min

1 min

60 sec=

Page 14: Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School.

Good! Now what goes here?

1 sec10 Coulomb/

1 min60 sec/ 96,485 C/1 mole e-1F=

/2 mole e-1 mole Cu(s)

1 mole Cu(s)63.5 g Cu/

30 min

1 min

60 sec

1 sec

10Coulomb=

Page 15: Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School.

Hint: I shortened Coulomb to C

sec10 Coulomb/

1 min60 sec/ 96,485 C/1 mole e-1F=

/2 mole e-1 mole Cu(s)

1 mole Cu(s)63.5 g Cu/

30 min

1 min

60 sec

1 sec

10Coulomb=

Page 16: Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School.

Good! Now what goes here?

sec10 Coulomb/

1 min60 sec/ 96,485 C/1 mole e-1F=

/2 mole e-1 mole Cu(s)

1 mole Cu(s)63.5 g Cu/

30 min

1 min

60 sec

1 sec

10Coulomb=

1 Coulomb

1 mole e-

Page 17: Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School.

Come on now! We’re almost finished.

sec10 Coulomb/

1 min60 sec/ 96,485 C/1 mole e-1F=

/2 mole e-1 mole Cu(s)

1 mole Cu(s)63.5 g Cu/

30 min

1 min

60 sec

1 sec

10Coulomb=

1 Coulomb

1 mole e-

Page 18: Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School.

Stop kidding around!

sec10 Coulomb/

1 min60 sec/ 96,485 C/1 mole e-1F=

/2 mole e-1 mole Cu(s)

1 mole Cu(s)63.5 g Cu/

30 min

1 min

60 sec

1 sec

10Coulomb=

1 Coulomb

1 mole e-

Page 19: Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School.

Finally! Now what could possibly

go here?

sec10 Coulomb/

1 min60 sec/ 96,485 C/1 mole e-1F=

/2 mole e-1 mole Cu(s)

1 mole Cu(s)63.5 g Cu/

30 min

1 min

60 sec

1 sec

10 Coulomb

96,485 C

1 mole e-

2 mole e-

1 mole Cu(s)

=

Page 20: Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School.

Care to try again?

1 mole Cu(s)63.5 g Cu/

30 min

1 min

60 sec

1 sec

10 Coulomb

96,485 C

1 mole e-

2 mole e-

1 mole Cu(s)

=

Page 21: Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School.

Alright! So, what’s the answer?

23.7 g Cu

30 min

1 min

60 sec

1 sec

10 Coulomb

96,485 C

1 mole e-

2 mole e-

1 mole Cu(s)

1 mole Cu(s)

63.5 g Cu=

5.92 g Cu or

Page 22: Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School.

Calculator error.Try again.

23.7 g Cu

30 min

1 min

60 sec

1 sec

10 Coulomb

96,485 C

1 mole e-

2 mole e-

1 mole Cu(s)

1 mole Cu(s)

63.5 g Cu=

5.92 g Cu

Page 23: Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School.

Right! Remember the question?

How much copper can be plated in 30 minutes at 10 amps?

We were expecting an answer in grams.

30 min

1 min

60 sec

1 sec

10 Coulomb

96,485 C

1 mole e-

2 mole e-

1 mole Cu(s)

1 mole Cu(s)

63.5 g Cu= 5.92 g Cu

Page 24: Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School.

Right! Remember the question?

How much copper can be plated in 30 minutes at 10 amps?

We were expecting an answer in grams. Click here to see how things cancel.

30 min

1 min

60 sec

1 sec

10 Coulomb

96,485 C

1 mole e-

2 mole e-

1 mole Cu(s)

1 mole Cu(s)

63.5 g Cu= 5.92 g Cu

Page 25: Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School.

Right! Remember the question?

How much copper can be plated in 30 minutes at 10 amps?

We were expecting an answer in grams. And that’s the only unit that didn’t cancel.

30 min

1 min

60 sec

1 sec

10 Coulomb

96,485 C

1 mole e-

2 mole e-

1 mole Cu(s)

1 mole Cu(s)

63.5 g Cu= 5.92 g Cu

Page 26: Electrochemistry Solving a problem you’ve never seen before and for which you have no formula. Produced by Mr. Doddridge Murrieta Valley High School.

Want to try some more?

Click below to go to a site where you can get more practice

More Practice