Electric Field - Potential Difference

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    is defined as the electric force per

    unit charge.

    an influence produced by an

    electric charge on other charges in

    its vicinity.

    is a vector field that permeates the

    space around electrical charge.

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    FORMULAINGETTINGTHEELECTRICFIELD

    The electric field (E) is derived in the same way

    from the equation:

    where:

    Q = electric force of one object (C),q = electric force of the other object (C)

    d = distance between the two objects (m)

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    However, electric field E is a little bit different from

    gravitational field g. Gravitational force depends on

    mass, whereas electric force does not depend on

    mass. Instead, electric force depends oncharges on both objects.

    By rearranging the formula, we get:

    Electric field (E) for Q:

    Electric field for q:

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    Let's divide the electric force (F) by charge q:

    Therefore, the electric field tells us the force per unit

    charge.

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    SAMPLEPROBLEMS1. A uniform electric field of magnitude 30 N /

    C is directed downward. What are the

    magnitude and the direction of the force on

    a + 4.0 C charge placed in this electric

    field?

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    SOLUTION:The electric field is defined as the electric forcedivided by the magnitude of the test charge, so if

    we multiply both sides of the equation by the

    magnitude of the test charge we can determine the

    force.

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    ELECTRICFIELDLINES

    An electric field can be visualized on paper

    by drawing lines of force, which give an

    indication of both the size and the strength

    of the field. Lines of force are also called

    field lines.

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    The direction of the field is taken to be the

    direction of the force it would exert on apositive test charge. The electric field is

    radially outward from a positive charge and

    radially in toward a negative point charge.

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    ELECTRICALPOTENTIAL

    ENERGY

    a charge due to its location in an

    electric field

    a charged object can have potential

    energy by virtue of its location in anelectric field

    if the charge is released, it will

    accelerate in a direction away from

    the sphere and its electrical potential

    energy will transform into kinetic

    energy

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    FORMULAINGETTINGTHEELECTRICAL

    POTENTIALENERGY

    where Kis Coulombs constant.

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    POTENTIAL

    DIFFERENCEis measured in volts (V).

    A potential difference of 1 Vmeans that 1 joule of work is

    done per coulomb of charge.

    ( 1 V = 1 J C-1)

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    FORMULAINGETTINGTHEPOTENTIAL

    DIFFERENCE

    where:

    V = potential difference in volts (V)

    W = work done or energy transferred injoules (J)

    Q = charge in coulombs (C)

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    SAMPLEPROBLEMS

    1. A charge of magnitude -3.0 x 10-6C is

    moved through a potential difference

    of 80 volts. Calculate the work done

    on the charge.

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    SOLUTION

    The potential difference can be calculated by

    dividing the work done by the size of the charge.

    Multiplying both sides of the equation by the size of

    the charge allows us to calculate the work done.