Effect of surface area to volume ratio on the diffusion on sodium chloride from dialysis tubing
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Transcript of Effect of surface area to volume ratio on the diffusion on sodium chloride from dialysis tubing
Candidate Name: Tony Hong (Seung Mo Hong) IB Biology HL
Candidate Number: __002213-02______
Date: August 15, 2010
How will changing the surface area by changing the volume, affect the rate
of diffusion of sodium chloride across a visking tube, measured using a
conductivity probe?
Aim
To investigate the relationship between surface area and the rate of diffusion of sodium
chloride across a visking tube, measured using a conductivity probe.
Introduction
Diffusion is the process of which particles spread through random regions of higher concentration to
regions of lower concentration. The rate of diffusion is the measure of how fast the particles from a
region of higher concentration diffuse into the region of lower concentration or the change of
concentration over a period of time.
The rate of diffusion is affected by the following:
a) Surface Area – as the surface area increases, more particles can spread as there is more area
to travel.
b) Temperature – as temperature rises, molecules will have a greater kinetic energy and hence,
more molecules will have a greater energy than the activation energy, leading to more
formations of products.
c) Concentration Gradient – as the concentration gradient increases, more amounts of
particles (in the same amount of volume) would be able to travel through from the higher
concentrated region to the lower concentrated region.
Hence, if any of these three variables are changed, the rate of diffusion would change as well.
Candidate Name: Tony Hong (Seung Mo Hong) IB Biology HL
Candidate Number: __002213-02______
Date: August 15, 2010
Variables
Variable Measured Method of measuring /controlling the variable/reason
of why the variables was categorized in each section
Controlled
Variables
Rate of magnetic stirrer The rate of magnetic stirrer shouldn’t be too slow as it
would take a longer time to gather information as well as
due to the fact that the particles won’t spread throughout
the regions fast enough.
The rate of magnetic stirrer shouldn’t be too fast either as
the magnetic can lose its balance and spin out causing the
experiment to not work properly.
Once the appropriate rate is measured, do not change it
for other trials.
Volume of distilled water The volume of distilled water needed to be appropriate. If
the sodium chloride solution was put inside too much
water. The rate of diffusion would have been difficult to
measure as the concentration of the water wouldn’t
changed much and wouldn’t occur fast enough. Also, the
height of the volume needs to large enough for the whole
visking tube to fit.
Hence, 350cm3 of distilled water was used for all the
trials by using conical flasks. This is a controlled variable
as the rate of diffusion would vary if it changed
throughout the experiment.
Distance of conductivity
probe from the visking
tube
The distance of conductivity probe from the visking tube
is a controlled variable because the amount of
concentration would be higher as it is closer to the
visking tube and lower as it is further away from the
visking tube.
Size of visking tube The size of visking tube is controlled by using the same
sized visking tube. It is a controlled variable because if
the size differed the surface area would have also
changed.
Temperature All trials are experimented in room temperature which is
approximately 28℃
Concentration of sodium
chloride solution
All trials are experimented with the same concentration
as it can change the rate of diffusion if it isn’t controlled.
The experiment is conducted by 1.0M of sodium chloride
solution.
Independent
Variables
Surface area of the
sodium chloride solution
in the visking tube
The surface area of the sodium chloride solution was
changed by increasing the volume of sodium chloride
solution by 5cm3, resulting in 5cm
3, 10cm
3, 15cm
3, 20cm
3
and 25cm3,
Dependent
Variables
Rate of diffusion of NaCl
solution, ΔC/t
As the volume and surface area changes the rate of
diffusion would change as well as more particles can
diffuse across the visking tube. Change of conductivity
(over time) was measured through Logger Pro by using a
conductivity probe to calculate the rate of diffusion.
Table 1: List of Variables
Candidate Name: Tony Hong (Seung Mo Hong) IB Biology HL
Candidate Number: __002213-02______
Date: August 15, 2010
Hypothesis
The rate of diffusion is the measure of how fast the particles from a region of higher concentration
diffuse into the region of lower concentration or the change of concentration over a period of time.
Three variables that could change the rate of diffusion is shown in the introduction. However, as the
concentration and temperature is a controlled variable in the experiment, the surface area variable is
the variable that will be changed to determine the change of rate of diffusion. Hence, by changing the
surface area (by changing the volume) of the 1.0M of sodium chloride solution, the change of rate of
diffusion would be measurable.
The following equation is the formula for calculating the surface area of the visking tube:
2 2 + 2 x h
Where:
r = the radius of the visking tube
h = the height of the visking tube
The radius of the visking tube would be constant as the size of the visking tube is a controlled variable.
Hence, the height of the sodium chloride solution inside the visking tube would be the determining
factor that would change the surface area for diffusion. Therefore, by changing the volume, the height
of the sodium chloride solution would change, leading to the difference of the surface areas.
When looking at the equation, as the volume increases, the height also increases, leading to a greater
surface area. And when the surface area increases, the area for the number of particles to spread
through the regions increases as well. Hence, more numbers of particles are able to diffuse from the
higher concentrated region to the lower concentrated region during the same amount of time.1
As such, the hypothesis for this experiment is that as the surface area of 1.0M sodium chloride
solution increases, the rate of diffusion would linearly increase.
Therefore, as the surface area of the 1.0M sodium chloride solution increases, the rate of
diffusion would increase as well.
Figure 1: graph showing the predicted trend mentioned in the hypothesis
1 "Surface-area-to-volume ratio." Wikipedia. 13 Feb 2011. Wikipedia Foundation. 15 Feb 2011
<http://en.wikipedia.org/wiki/Surface-area-to-volume_ratio>.
Rate
of diffu
sion, μS c
m-1
s-1
Surface area, cm2
Rate of diffusion, r/(μS cm-1 s-1) against Surface
area, SA/cm2 of NaCl solution
Candidate Name: Tony Hong (Seung Mo Hong) IB Biology HL
Candidate Number: __002213-02______
Date: August 15, 2010
Apparatus
- Logger Pro
- Conductivity probe
- Sodium chloride solution (NaCl)
- 25.0cm3 pipette (±0.1)cm
3
- Visking tube
- 250.00 cm3 conical flask (±0.15)cm
3
- 100.00 cm3 conical flask (±0.10)cm
3
- Distilled Water
- Magnetic stirrer
- 30cm Ruler (±0.1)cm
- Beaker
Procedure
Preparation of making 1M of NaCl solution
1. Measure 14.61g of sodium chloride (NaCl) using an electric weighing machine.
2. Measure 250cm3 of distilled water using a conical flask and put the 14.61g of NaCl inside it
3. Stir well until all the NaCl is completely dissolved.
Preparation of preparing visking tube
1. Cut approximately 10cm of visking tube.
2. Wet one side of the visking tube and tie a firm knot
3. Wet the other side of the visking tube and open the visking tube.
4. Put water inside the visking tube and check for leakage.
Measurement of the radius and the height of different volumes of 1.0M NaCl solution
1. Transfer 5cm3 of NaCl solution into a visking tube with a 25cm
3 pipette.
2. Put pressure on the visking tube so that it would be shaped as a cylinder and measure its
radius using a 30cm ruler.
3. After finding its radius, measure the height of the NaCl solution in the visking tube using a
30cm ruler.
4. Repeat steps 1-3 with 10 cm3, 15 cm
3, 20 cm
3, and 25 cm
3 of NaCl solutions.
Figure 2: Diagram for the process of measuring the radius and height of different volumes of NaCl
Candidate Name: Tony Hong (Seung Mo Hong) IB Biology HL
Candidate Number: __002213-02______
Date: August 15, 2010
Process of measuring the conductivity of the different volume of 1.0M of NaCl solution
1. Measure 350cm3 of distilled water in a beaker by using a 250cm
3 conical flask and a 100cm
3
conical flask.
2. Place the beaker on top of a magnetic stirrer, and put the magnetic stirrer at a constant rate of
power.
3. Place the visking tube with 5cm3 of NaCl solution
inside the beaker filled with 350cm
3 of
distilled water and measure the change of conductivity through logger pro using a
conductivity probe.
4. Repeat steps 1-3 three times in order to collect triplicate data.
5. Repeat steps 1-4 with 10 cm3, 15 cm
3, 20 cm
3, and 25 cm
3 of NaCl solutions.
Figure 3: Diagram for the process of measuring the change of conductivity
Candidate Name: Tony Hong (Seung Mo Hong) IB Biology HL
Candidate Number: __002213-02______
Date: August 15, 2010
Data collection
Table 2: Conductivity measured for every 5 seconds of the triplicate trial of each different NaCl solution volume
Time,
t/s
Conductivity of 5cm3
NaCl solution inside the
distilled water, C/μS
(±0.1 μS)
Conductivity of 10cm3
NaCl solution inside the
distilled water, C/μS
(±0.1 μS)
Conductivity of 15cm3
NaCl solution inside the
distilled water, C/μS
(±0.1 μS)
Conductivity of 20cm3
NaCl solution inside the
distilled water, C/μS
(±0.1 μS)
Conductivity of 25cm3
NaCl solution inside the
distilled water, C/μS
(±0.1 μS)
Trial 1 Trial 2 Trial 3 Trial 1 Trial 2 Trial 3 Trial 1 Trial 2 Trial 3 Trial 1 Trial 2 Trial 3 Trial 1 Trial 2 Trial 3
0 14.4 9.8 17.0 21.2 17.8 8.7 17.1 26.8 7.6 24.9 19.9 16.3 16.2 23.4 20.7
5 14.5 8.8 11.2 14.4 11.4 13.8 17.1 37.1 12.8 21.8 34.0 29.7 39.4 19.4 44.4
10 29.3 17.4 17.8 24.6 20.7 31.1 38.9 65.9 38.7 55.3 59.8 66.1 75.9 60.6 90.2
15 42.0 26.0 32.3 33.4 34.3 49.6 59.1 85.5 64.7 79.7 99.6 111.1 101.0 97.6 133.8
20 53.0 34.5 41.2 44.6 48.1 68.5 72.5 108.2 87.3 96.1 124.5 141.4 150.3 139.0 160.4
25 63.0 41.4 50.9 57.0 57.4 78.9 90.6 122.0 114.7 116.5 143.8 161.9 180.7 164.9 187.2
30 71.2 48.4 60.5 69.4 69.5 95.5 118.1 138.6 133.7 133.8 166.1 183.1 201.3 182.0 218.1
35 79.3 57.4 71.6 84.2 82.6 114.8 131.1 158.6 149.7 154.4 181.5 204.3 218.5 205.9 248.9
40 91.5 63.6 77.2 95.7 92.4 127.2 147.1 168.6 167.1 173.4 191.9 223.2 236.3 219.5 269.5
45 97.7 70.6 88.6 105.5 101.0 138.0 162.6 185.3 183.1 187.3 205.3 243.0 253.6 237.1 300.0
50 103.5 79.3 96.2 118.5 112.7 151.8 175.4 194.2 197.3 204.6 217.7 264.8 271.6 258.7 324.9
55 113.0 84.5 103.7 129.9 121.0 164.8 188.9 201.8 208.4 218.4 227.8 283.3 294.4 273.2 351.1
60 119.8 92.7 113.2 141.2 135.6 173.9 201.7 214.0 218.2 233.7 246.3 310.3 315.9 289.1 370.5
65 128.4 99.7 118.5 148.1 144.5 182.5 215.9 225.5 230.2 247.4 258.7 328.6 335.5 308.6 389.6
70 138.6 110.1 128.7 157.6 158.6 192.0 223.8 234.0 241.0 264.6 266.9 357.1 356.1 330.3 411.1
75 143.6 114.4 141.1 170.3 168.1 198.8 233.9 242.6 252.6 282.5 283.2 375.3 372.2 351.1 434.7
80 154.7 122.2 143.9 183.7 175.5 205.2 245.3 251.3 265.7 299.0 299.6 388.3 391.4 367.8 456.4
85 161.5 127.7 148.5 196.4 187.3 219.2 258.4 260.7 280.2 313.7 317.4 407.6 412.0 386.0 476.6
90 170.3 135.1 155.8 211.0 194.6 223.0 270.6 273.5 293.4 326.2 330.6 425.4 428.5 401.2 497.6
Time,
t/s
Conductivity of 5cm3
NaCl solution inside the
distilled water, C/μS
(±0.1 μS)
Conductivity of 10cm3
NaCl solution inside the
distilled water, C/μS
(±0.1 μS)
Conductivity of 15cm3
NaCl solution inside the
distilled water, C/μS
(±0.1 μS)
Conductivity of 20cm3
NaCl solution inside the
distilled water, C/μS
(±0.1 μS)
Conductivity of 25cm3
NaCl solution inside the
distilled water, C/μS
(±0.1 μS)
Candidate Name: Tony Hong (Seung Mo Hong) IB Biology HL
Candidate Number: __002213-02______
Date: August 15, 2010
Figure 4: Graph showing the change of conductivity against time for every trial of five different volume of sodium chloride solution
(a)
Rate of diffusion for each trial was measured by calculating the gradient of the change of diffusion from the time interval, 0 – 90s
(a)
Candidate Name: Tony Hong (Seung Mo Hong) IB Biology HL
Candidate Number: __002213-02______
Date: August 15, 2010
Quantitative Data
Table 3: Rate of diffusion of triplicate trial of each different NaCl solution volume
(a)
Data that is an outlier and hence is not used to calculate the average rate of diffusion
Qualitative Data
- NaCl solution was colourless
- Visking tube containing the NaCl solution became slightly bigger after diffusion
Volume of NaCl, v/cm3
(±0.03cm3)
Rate of diffusion of NaCl solution, r/(μS cm-1
s-1
)
Trial 1 Trial 2 Trial 3
5.00 1.459 ± 0.0065 1.707 ± 0.01364 1.730 ± 0.01088
10.00 2.163 ± 0.01298 2.467 ± 0.03717 2.245 ± 0.01594
15.00 2.653 ± 0.04803 3.156 ± 0.05409 2.921 ± 0.03254
20.00 3.268 ± 0.05539 4.488 ± 0.04651 (-) (a)
3.436 ± 0.02606
25.00 4.204 ± 0.5900 5.195 ± 0.06209 (-) 4.439 ± 0.05810
Candidate Name: Tony Hong (Seung Mo Hong) IB Biology HL
Candidate Number: __002213-02______
Date: August 15, 2010
Data processing
The following equation is the formula for calculating the surface area of the visking tube:
2 2 + 2 x h
Where:
r = the radius of the visking tube
h = the height of the visking tube
To calculate the surface area, the following measurements were required:
Volume of NaCl solution, v/cm3
(±0.03cm3)
Radius of visking tube, r/cm
(±0.1cm)
Height of NaCl solution, h/cm
(±0.1cm)
5.00 1.0 1.1
10.00 1.0 2.7
15.00 1.0 4.3
20.00 1.0 5.9
25.00 1.0 7.4
Table 4: Measurement of the radius and height of different volume of sodium chloride solution
Volume of NaCl solution,
v/cm3
(±0.03cm3)
Calculation of surface area Surface Area of NaCl solution,
SA/cm2
(±0.2cm2)
5.00 2 2 + 2 x 1.1 ≈ 13.1 13.1
10.00 2 2 + 2 x 2.7 ≈ 23.2 23.2
15.00 2 2 + 2 x 4.3 ≈ 33.3 33.3
20.00 2 2 + 2 x 5.9 ≈ 43.2 43.2
25.00 2 2 + 2 x 7.4 ≈ 52.7 52.7
Table 5: Calculation of surface area
Candidate Name: Tony Hong (Seung Mo Hong) IB Biology HL
Candidate Number: __002213-02______
Date: August 15, 2010
The average rates of diffusion of the three trials were calculated by the following equation:
Surface Area of
NaCl solution,
SA/cm2
(±0.2cm3)
Calculation
Average rate of
diffusion of
NaCl solution,
r/(μS cm-1
s-1
)
(μS cm-1
s-1
± s.d(b)
)
12.6
≈ 1.632
1.63 ± 0.1503
22.6
≈ 2.295
2.30 ± 0.1623
32.7
≈ 2.910
2.91 ± 0.2517
42.7 c
≈ 3.352
3.35 ± 0.1188
52.8
≈ 4.322
4.32 ± 0.1662
Table 6: Calculation of average rate of diffusion (b)
s.d - Abbreviated form of Standard Deviation (c)
Data contained an outlier and hence was not put into the calculation of average rate of diffusion
Candidate Name: Tony Hong (Seung Mo Hong) IB Biology HL
Candidate Number: __002213-02______
Date: August 15, 2010
Data Presentation
Figure 5:Graph showing the average rate of diffusion against the surface area of NaCl solution
(a)
Error bar representing the standard deviation of the average rate of diffusion
y = 0.0649x + 0.7541
R² = 0.9843
0
0.5
1
1.5
2
2.5
3
3.5
4
4.5
5
0 10 20 30 40 50 60
Rate
of
Diffu
sion, (μ
S c
m-1
s-1)
Surface Area, (cm2)
Rate of diffusion, r/(μS cm-1 s-1) against Surface Area,
SA/cm2 of NaCl solution
(a)
Candidate Name: Tony Hong (Seung Mo Hong) IB Biology HL
Candidate Number: __002213-02______
Date: August 15, 2010
Uncertainty/ Error Analysis
Table 7: Uncertainty of the measurements of lengths due to the ruler
Surface Area of
NaCl solution,
SA/cm2
% uncertainty in surface area, SA/cm2
ΔSA (%)
Absolute % uncertainty in surface area,
SA/cm2
ΔSA (cm2)
Surface Area, SA/cm2 and uncertainty
ΔSA (cm2)
13.1 19.1 (19.1/100) x 13.1 = 2.5 13.1 ± 2.5
23.2 13.7 (13.7/100) x 23.2 = 3.2 23.2 ± 3.2
33.3 12.3 (12.3/100) x 33.3 = 4.1 33.3 ± 4.1
43.2 11.7 (11.7/100) x 43.2 = 5.1 43.2 ± 5.1
52.7 11.4 (11.4/100) x 52.7 = 6.0 52.7 ± 6.0
Table 8: The absolute uncertainty for each surface area
Surface Area of
NaCl solution,
SA/cm2
% uncertainty for length use
Total % of
Uncertainty
Surface Area with
uncertainty Length of radius
of visking tube,
using a 30cm ruler
(Δr = ± 0.1) cm
% uncertainty of
Length ( % )
Length of height
of NaCl solution,
using a 30cm ruler
(Δ = ± 0.1) cm
% uncertainty of
Length ( % )
13.1 1.0 ± 0.1 (0.1/1.0) x 100
= 10.0%
1.1 ± 0.1 (0.1/1.1) x 100
= 9.1%
10.0% + 9.1%
= 19.1%
13.1 ± 19.1%
23.2 1.0 ± 0.1 (0.1/1.0) x 100
= 10.0%
2.7 ± 0.1 (0.1/2.7) x 100
= 3.7%
10.0% + 3.7%
= 13.7%
23.2 ± 13.7%
33.3 1.0 ± 0.1 (0.1/1.0) x 100
= 10.0%
4.3 ± 0.1 (0.1/4.3) x 100
= 2.3%
10.0% + 2.3%
= 12.3%
33.3 ± 12.3%
43.2 1.0 ± 0.1 (0.1/1.0) x 100
= 10.0%
5.9 ± 0.1 (0.1/5.9) x 100
= 1.7%
10.0% + 1.7%
= 11.7%
43.2 ± 11.7%
52.7 1.0 ± 0.1 (0.1/1.0) x 100
= 10.0%
7.4 ± 0.1 (0.1/7.4) x 100
= 1.4%
10.0% + 1.4%
= 11.4%
52.7 ± 11.4%
Candidate Name: Tony Hong (Seung Mo Hong) IB Biology HL
Candidate Number: __002213-02______
Date: August 15, 2010
Solution
Surface Area, SA/cm2
ΔSA (cm2)
Average rate of diffusion of NaCl solution,r/(μS cm-1
s-1
)
(μS cm-1
s-1
± s.d)
NaCl
13.1 ± 2.5 1.63 ± 0.15
23.2 ± 3.2 2.30 ± 0.16
33.3 ± 4.1 2.91 ± 0.25
43.2 ± 5.1 3.35 ± 0.12
52.7 ± 6.0 4.32 ± 0.17
Table 9: Relationship between the surfaces areas with absolute uncertainty and the average rate of diffusion
Candidate Name: Tony Hong (Seung Mo Hong) IB Biology HL
Candidate Number: __002213-02______
Date: August 15, 2010
Conclusion
The exact relationship between the average rate of diffusion and the surface areas can be seen on table
6. As it can been seen on table 6, the surface areas increase approximately by 10.0 cm2 per variable
and the difference between the average rate of diffusion of the variables (of the one after it) is 0.67,
0.61, 0.44, 0.97 respectively. The difference between the average rates of diffusion of 3rd
– 4th is
relatively small and 4th – 5
th is relatively big when comparing it to the previous difference values.
Hence, when taking a linear perspective towards the data it can be said that the value of the average
rate of diffusion of the fourth SA variable (42.7cm2) is smaller than the theoretical value. This can also
be seen through figure 5 which show the overall relationship between the average rate of diffusion and
the surface areas. Therefore as it can been seen on both table 6 and figure 5, as the surface area
increases, the average rate of diffusion also increases; hence having a positive correlation. Although
the average rate of diffusion value (3.352 μS cm-1
s-1
) of the fourth SA variable (42.7cm2) is small,
making the differences between the average rate of diffusion not constant, I believe that the trend
increases in a linear manner as we have to take the relatively big error bars in consideration. The
linear relationship states that the average rate of diffusion is directly proportional to the constant
change of the surface areas of the reactant.
As it can be seen on table 6, 7 and 8, the experiment contained high uncertainties due to the fact that
the apparatus (especially the ruler) was not as accurate. However, to improve on the accuracy of the
experiment each variable was run 3 times, hence giving a triplicate data. Despite the high
uncertainties, the data was fairly constant and was reliable enough to confirm the trend. As such, the
hypothesis is valid and accepted.
Evaluation
Weaknesses Improvements
Uncertainty of the surface area was too high due
to the relative high uncertainty of the 30cm ruler
Can use an apparatus which has a lower
uncertainty than the 30cm ruler (±0.1cm) to
reduce the uncertainty, which allows the
experiment to become more accurate and reliable
The fluctuation of the initial collection of data
made the gradient (the rate of diffusion) less
accurate. Look at Figure 4.
Let the logger pro run before putting in the NaCl
solution. After seeing constant/ straight data
collection, put in the NaCl solution so that the
fluctuation of the initial data collection would be
smaller.
A visking tube is not a perfect cylinder. Hence,
the calculation of the surface area of the visking
tube is not exactly accurate.
Can use a more skinny visking tube (which has a
smaller radius) as it would be easier to put
pressure on it, in order to make a more accurate
cylindrical shape