EET 2261 Unit 2 HCS12 Architecture Read Almy, Chapters 3, 4, and 5. Homework #2 and Lab #2 due...
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Transcript of EET 2261 Unit 2 HCS12 Architecture Read Almy, Chapters 3, 4, and 5. Homework #2 and Lab #2 due...
EET 2261 Unit 2HCS12 Architecture
Read Almy, Chapters 3, 4, and 5.
Homework #2 and Lab #2 due next week.
Quiz next week.
CPU Programming Model• Inside any processor’s CPU are certain registers
that the programmer has access to.
• The list of these registers is often called the CPU programming model.
• For the HCS12:Register Number of bits
Accumulator A 8
Accumulator B 8
Accumulator D 16
Index Register X 16
Index Register Y 16
Stack Pointer 16
Program Counter 16
Condition Code Register 8
HCS12 CPU Programming Model• See page 30
of textbook or page 375 of CPU Reference Manual.
Purposes of the Registers• Accumulators A, B, and D are general-purpose
registers that the programmer can use however she wants.
• PC and CCR are special-purpose registers that always perform specific functions:
• PC always holds the address of the next instruction to be executed.
• CCR always holds three mask bits and five status flags.
• The other registers (X, Y, and SP) sometimes serve as general-purpose registers and sometimes perform specific functions.
Accumulators A, B, and D• The HCS12 has two 8-bit accumulators,
named A and B. These two can also be regarded as forming a single 16-bit accumulator named D.
• Some instructions operate on Accumulator A or Accumulator B. Other instructions operate on Accumulator D.
• Examples: • LDAA loads an 8-bit number into A.• LDAB loads an 8-bit number into B.• LDD loads a 16-bit number into D.
HCS12 Instruction Set• A processor’s instruction set is the list of
instructions (or commands) that the CPU recognizes.
• Most of these instructions manipulate the CPU’s registers or locations in memory (or both).
Instruction Set Summary• For a summary of the HCS12’s instruction
set, see the table on pages 381-394 of the CPU Reference Manual.
Example: ABA• This table uses many abbreviations and
special symbols. They’re all explained in the pages before the table (pages 377-380 of the CPU Reference Manual.)
• Let’s look at one instruction, ABA, which adds Accumulator B to Accumulator A and puts the results in Accumulator A.
First Column: Source Form• This column shows how
you’ll type the instruction when you start writing assembly language programs next week.
• ABA is very simple. Other instructions are more complicated and have additional things you need to type, explained here:
Second Column: Operation
• This column explainsthe operation that the instruction performs.
• Some symbols used in this column:
Third Column: Addressing Mode• This column shows the addressing
mode(s) used by the instruction. As we’ll see below, there aresix different addressing modes.
• Some abbreviations used in this column:
Fourth Column: Machine Coding• Computers use numbers to
represent all kinds of information, including the instructions in a program. This column shows the numbers (in hex) that represent each instruction.
• Some abbreviations used in this column:
Fifth Column: Access Detail
• This column shows howmany cycles each instruction takes to execute, and what happens during each of those cycles.
• Some abbreviations used in this column:
Last Two Columns: Condition Codes
• These columns show howeach instruction affects the bits in the Condition Code Register.
• Symbols used in these columns:
Summary• This table summarizes a lot of useful
information for every one of the 207 instructions that you can use when writing programs for the HCS12.
• You’ll refer to this table often.
Instruction Set Details• For details on
all 207 of the HCS12’s instructions, see pages 100-309 of the CPU Reference Manual.
RISC Architecture versus CISC Architecture
• Some commercially available microprocessors use a RISC (Reduced Instruction Set Computer) architecture.• Small instruction set (maybe 25 or 30 instructions).• Each instruction performs a simple operation and
executes quickly.
• The HCS12 is an example of a CISC (Complex Instruction Set Computer) processor.• Large instruction set (207 in the HCS12’s case).• Some instructions perform complex operations that
might require a dozen or more instructions in a RISC processor.
Categories of Instructions• The Instruction Set Summary table lists
instructions alphabetically. Sometimes it’s more useful to have instructions grouped into categories of similar instructions.
• Examples of categories:• Load and Store Instructions• Addition and Subtraction Instructions• Boolean Logic Instructions• …
• See Section 5 (starting on p. 55) of the CPU Reference Manual.
Mnemonics• In this course we’ll write programs in a
language called assembly language.
• Assembly language contains many mnemonics, which are abbreviations for actions that we want to perform. (Mnemonics appear in the Source Form column of the Instruction Set Summary.)
• Some examples:Mnemonic Action
ABA Add Accumulator B to Accumulator A
LDAA Load Accumulator A with a number
STAA Store Accumulator A into memory
Operands• Some HCS12 instructions require the
programmer to specify one or two operands, in addition to the mnemonic.
• These operands are the data (usually numbers) to be operated on.
• Example: • The LDAA instruction loads some
number into accumulator A. The number that’s to be loaded is the operand.
• In the instruction LDAA #5, the operand is 5.
Opcodes• When an instruction is translated into
machine code, the mnemonic is replaced by an opcode.
• Example: The assembly-language instruction LDAA #5 becomes $8605
in machine code, because $86 is the opcode for LDAA.
Mnemonic
Operand
Opcode
Review: Memory Addresses• Every computer system has memory, where
programs and data are stored.
• Each location within this memory has an address by which we identify it. And each location holds some contents, which is one byte.
• The HCS12 uses a 16-bit address bus.
• So the addresses of its memory locations range from $0000 to $FFFF. (In decimal, that’s 0 to 65,535.)
• So we have 65,536 memory locations, each of which holds one byte.
Review: Memory Map• Programmers must pay attention to where in
memory their programs and data are stored.
• Some of a system’s memory is reserved for special purposes. Therefore, within the range of possible addresses, only some can be used by your programs.
• A memory map shows which memory addresses are reserved, and which are available for your use.
• Next slide shows memory map for our HCS12 chip.
• See page 26 of Device User Guide.
• Reserved addresses:
• $0000 to $03FF are reserved for special-function registers.
• $FF00 to $FFFF are reserved for interrupt vectors.
HCS12 Memory Map
Addressing Modes• Every instance of an instruction uses an
addressing mode.
• The HCS12’s six addressing modes are:• Inherent• Immediate• Direct• Extended• Indexed (which has several variations)• Relative
Which Addressing Mode(s) Does an Instruction Use?
• Some instructions come in only one “flavor”: they can only use one addressing mode.• Example: The ABA instruction always
uses the inherent addressing mode.
• Other instructions come in two or more “flavors.”• Example: The LDAA instruction can use
immediate, direct, extended, or indexed addressing.
Inherent Addressing Mode• In inherent addressing mode, the
programmer doesn’t specify any operands, because the mnemonic itself contains all of the information needed.
• Example: The ABA instruction adds the numbers in Accumulators A and B. So we already know where the two operands are located, and we don’t need to say any more.
• We just write ABA, instead of writing something like ABA #5.
Immediate Addressing Mode• In immediate addressing mode, the
programmer gives the operand(s) as part of the instruction.
• The pound sign (#) indicates immediate addressing.
• Example: LDAA #15 causes the number 15 to be loaded into Accumulator A.
• The following are all equivalent:• LDAA #15• LDAA #$F• LDAA #%1111
Direct Addressing Mode• In direct addressing mode, the programmer
gives the operand’s address as part of the instruction.
• Example: LDAA 51 causes the number located at memory address 51 to be loaded into Accumulator A.
• The following are all equivalent:• LDAA 51• LDAA $33• LDAA %00110011
Limitation of Direct Addressing Mode
• In direct addressing mode, the operand’s address can only be one byte long.
• So the highest address we can use with direct addressing is $FF, or 255.
• Since there are 65,536 locations in memory, this means that 65,281 of those locations can’t be reached by direct addressing!
• Solution: use extended addressing mode instead of direct addressing mode. (See next slide.)
Extended Addressing Mode• In extended addressing, the programmer gives the
operand’s address as part of the instruction (just as in direct addressing). But this address is two bytes long, so we can reach any memory location.
• Example: LDAA $701F causes the number located at memory address $701F to be loaded into Accumulator A.
• The following are all equivalent:• LDAA 28703• LDAA $701F• LDAA %0111000000011111
Summary: Addressing Modes• We’ve discussed the first four of the
HCS12’s six addressing modes:• Inherent• Immediate• Direct• Extended• Indexed (which has several variations)• Relative
• We’ll discuss the other two modes in the weeks ahead.
Condition Code Register• The Condition Code Register (CCR) is an 8-
bit register that contains:• 5 flag bits (H, N, Z, V, C)• 2 interrupt mask bits (X and I)• STOP instruction control bit (S)
Meanings of the H, Z, and C Flag Bits
• The flag bits are set or reset based on the results of previously executed instructions.
• H=1 if a half-carry (carry from bit 3 to bit 4) occurred.
• Z=1 if the result was zero.• C=1 if a carry out of the leftmost bit
occurred (or, in the case of subtract instructions, if a borrow into the leftmost bit occurred).
• But only some instructions affect these flag bits: check the instruction summary table.
Review: Two’s-Complement Notation• Recall that two’s-complement notation is
the standard way of representing signed numbers in binary.
• In this notation, the leftmost bit is the sign bit.• Sign bit = 0 for positive numbers or 0.• Sign bit = 1 for negative numbers.
• Examples, using 8 bits:• %0000 0011 = 3• %1000 0011 = 125
Meanings of the N and V Flag Bits• N=1 if the result’s leftmost bit (MSB) was
1. If you’re using signed numbers, this means that the result was negative.
• V=1 if a two’s-complement overflow occurred. This happens when either:• We added two positive numbers (MSB=0) and
got a negative result (MSB=1).• Or we added two negative numbers (MSB=1)
and got a positive result (MSB=0).
• Again, only some instructions affect these flag bits: check the instruction summary table.