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ELECTROMAGNETIC
FIELDS & WAVES
EEEB 253
CHAPTER 1
BEEE/BEPE
College of Engineering
-
2Electromagnetic spectrum
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
-
3Chapter 1: Vector algebra
1. Scalar and vector
2. Unit vector
3. Position vector
4. Vector multiplication
Electromagnetics (EM) A branch of physics or electrical engineering where
electric and magnetic phenomena are studied
Applications:- microwave, antenna, electric machine, radar, remote sensing etc.
Eg. EM energy change vegetable taste by reducing its acidicity
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
-
41.1: Scalar and vector
EM concepts can be understood through vector analysis
Need to have strong vector analysis
Scalar quantity that only has magnitude
Vector quantity that has both magnitude and direction, identified
by an arrow above the symbols (or bold in typing)
EM theory study of a particular field
Field is a function that specifies a particular quantity everywhere in
a region. Eg. Gravitational field
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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51.2: Unit vector
Magnitude of a vector A is A or |A|
A unit vector aA, is a vector with magnitude of unity and direction A
Vector A can be written as or
Magnitude of a vector
Unit vector is given by
Vector addition / subtraction (revision)
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
-
6Examples / practice exercises
PE 1.3 (position vector)
Answers / solution will be done during lecture
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
-
7Examples / practice exercises
Example (unit vector)
What is the magnitude of unit vector ac???
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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81.3: Position vector
Position vector (rp) also called the radius vector of a point P is the distance directed from the origin to point P
Point (3, 4, 5) has a position vector
Distance vector displacement from one point to
another point
Prac. Exercise 1.1
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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91.4: Vector multiplication
2 types of vector multiplication
Dot product
2 vectors are orthogonal or perpendicular if
Dot product commutative law
Dot product Distributive law
Dot product perpendicular vector
Dot product parallel vector
Cross product , an is the unit vector normal to the plane containing vectors A and B
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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101.4: Vector multiplication
Cross product anticommutative
Not associative
Distributive
Special cases
Example 1.4 find the angle using dot product / cross product
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
-
ELECTROMAGNETIC
FIELDS & WAVES
EEEB 253
CHAPTER 2
BEEE/BEPE
College of Engineering
-
12Chapter 2: Coordinate system
1. Cartesian coordinate
2. Cylindrical coordinate / transformation
3. Spherical coordinate / transformation
Physical quantities in EM are functions of time and space
To define all points accurately, use coordinate system
Orthogonal coordinate system the ones in which the coordinates are mutually
perpendicular. Eg. Cartesian, spherical, cylindrical, conical etc.
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
-
13
2.1: Cartesian coordinate / 2.2 Circular cylindrical coordinate
A point P can be represented by (x, y, z)
Cartesian coordinate = rectangular coordinate
Vector A
Cylindrical coordinate convenient for problems
with cylindrical symmetry
is the radial distance from the z-axis; is called the azimuthalangle measured from the x-axis on the xy-plane
z is the same as in Cartesian coordinate
Vector A can be written as
Magnitude of vector; Unit vectors are all perpendicular
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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142.2 Circular cylindrical coordinate
Relationship between cylindrical and Cartesian coordinates
Relationship between and
In matrix form
The unit vectors are related as below
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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152.3 Spherical coordinate
Most appropriate when dealing with problems
having spherical symmetry
A point can be represented by
r is the distance from the origin to the point
is the angle between z-axis and position
vector P (Colatitude angle)
is measured from the x-axis (same as Azimuthal angle)
Vector A can be expressed as and
The magnitude is
The unit vectors are all mutually orthogonal
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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162.3 Spherical coordinate
Relationship between spherical and Cartesian coordinates
The unit vectors are related as follows:-
Components of vector
The magnitude MUST stay the same
after transformation to check answer
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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17Examples / practice exercises
Example 2.1
At point P,
Exclude Spherical!
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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18Examples / practice exercises
PE 2.1
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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19Examples / practice exercises
PE 2.1
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
-
20Examples / practice exercises
PE 2.2
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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ELECTROMAGNETIC
FIELDS & WAVES
EEEB 253
CHAPTER 3
BEEE/BEPE
College of Engineering
-
22Chapter 3: Vector calculus
1. Line integral
2. Surface and volume integral
3. Del, Divergence, Curl and Laplacian
Deals with integration and differentiation of vectors (Calculus)
Learning the mathematical techniques in this chapter, which will be useful for the
EM applications in subsequent chapters
Differential normal area
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
-
233.1: Line integral
Integration concept extension to an integrand which is a vector
Vector field A; Line integral is the integral of the tangential component of A along curve L
We can define the integral as
For a closed path abca, closed contour integral
Example 3.2
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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24PE 3.2
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
-
253.2: Surface and volume integral
Vector A continuous in a region containing a smooth surface S
Surface integral or flux of A through Sor
At any point on S, an is the unit vector normal to the surface S
For a closed surface that defining a volume,
The volume integral , scalar over volume v
Problem 3.2 (d)
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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26
3.3: Del, Divergence, Curl, and Lapacian
The Del operator , also known as gradient operator
This operator is useful in defining:
in Cartesian coordinate
In cylindrical coordinate, using transformation
In spherical coordinate,
Divergence of A at any given point P, is the outward flux per unit volume as the volume shrinks about P
Net outflow of flux of a vector field A from a closed surface is obtained
from the surface integral
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
-
27
3.3: Del, Divergence, Curl, and Lapacian
Divergence of A can be written as , is the volume
enclosed by the closed surface where the P is located
Imagine divergence as a measure of how much the fields diverge or emanate from a point P
+ve at a source point diverge
-ve at a sink point converge
Neither sink nor source Zero
Divergence of A at point P in a Cartesian system
In cylindrical coordinate
In spherical coordinate
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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28
3.3: Del, Divergence, Curl, and Lapacian
Properties of the divergence of a vector field:-
It is a scalar product; Divergence of a scalar makes no sense;
;
Divergence theorem:- the total outward flux of a vector field A through a closed surface S is the same as the volume integral of the divergence
of A
Example 3.6
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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29PE 3.7
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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30
3.3: Del, Divergence, Curl, and Lapacian Curl of vector A is an axial or rotational vector whose magnitude is
the maximum circulation of A per unit area as the area tends to zero and
whose direction is the normal direction of the area when the area is
oriented so as to make the circulation maximum
is the area bounded by curve L, is the unit vector normal to the
surface , determined by the right hand rule
is independent on the coordinate system
Cartesian
Cylindrical
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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31
3.3: Del, Divergence, Curl, and Lapacian Properties of the curl:-
Stokes theorem
Example 3.8 Determine the curl vectors
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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32
3.3: Del, Divergence, Curl, and Lapacian Example 3.8
Example 3.9
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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33
3.3: Del, Divergence, Curl, and Lapacian Example 3.9
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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34
3.3: Del, Divergence, Curl, and Lapacian Laplacian operator is the composite of the gradient and divergence
Definition:-
Laplacian of a scalar field is another scalar field
In Cartesian:-
In cylindrical:-
In spherical:-
A scalar field vector V is said to be harmonic in a given region if its
Laplacian vanishes in that region. i.e.
Laplacian of a vector NOT the divergence of the gradient of A but the gradient of the divergence of A
In Cartesian only, it becomes
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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35
3.3: Del, Divergence, Curl, and Lapacian Example 3.11
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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36
3.3: Del, Divergence, Curl, and Lapacian
P.E. 3.11
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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37Chapter 3 Conclusion
Line integral, surface and volume integrals
Del operator used in divergence, curl and Laplacian
Divergence of a vector results in a scalar quantity; total outward
flux through a closed surface (Dot)
Curl of a vector results in a rotational vector (Cross)
Laplacian of a scalar field results in another scalar; divergence of
a gradient of a vector
Tutorial questions: 3.1(a), 3.2(a, b), 3.3(a, b), 3.4, 3.10(a, b), 3.15, 3.16(a,
b), 3.17(a, b), 3.19, 3.24(a, b), 3.29(a, b), 3.31
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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ELECTROMAGNETIC
FIELDS & WAVES
EEEB 253
CHAPTER 4
BEEE/BEPE
College of Engineering
-
39Chapter 4: Electrostatic fields
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
1. Coulombs law
2. Electric fields
3. Electric flux density
4. Gausss law
5. Electric potential
6. Electric energy
Static electric field time invariant; E field produced by static charge distribution
E field application Touch pad, capacitive keyboard, LCD
Industry E field used for paint spraying, electrodeposition, measure moisture
content of crops, speed baking of bread and smoking of meat
Coulombs law & Gausss law both for calculating electric field
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404.1: Coulombs law
Coulombs law:- deals with the force exerted by a point charge on
another point charge
The force F between two point charges Q1 and Q2 is:-
Along the line joining them
Directly proportional to the product Q1Q2 of the charges
Inversely proportional to the square of the distance R between them
With a proportionality constant, it can be expressed as
Coulombs constant, k, expressed in terms of the permittivity of free space (in Farad per meter)
F12 force exerted on Q2 due to Q1, if Q1 and Q2 are located at position vectors r1 and r2 respectively.
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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414.1: Coulombs law
Using the formula for unit vector, or
A few points to note:-
Opposing force with same magnitude
Like charges repel, opposite charges attract
Distance R is much larger than the size of the charges i.e. point charges
All the charges must be in static i.e. not moving
Signs of the charges must be taken into account
For cases with more than two charges,
Electric field intensity (electric field strength), E force per unit charge when placed in the electric field
E is in the direction of F in N/C or V/m
For E due to many chargesKer Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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424.1: Coulombs law
Example 4.1
P.E. 4.1
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
-
43
4.2: Electric fields due to continuous charge distribution
More realistic cases charges distributed along a line, surface or
volume with line , surface and volume charge densities
The charge element dQ and the total charge Q
The electric field intensity = sum of the field contributed by the point
charges making up the charge distribution
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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444.3: Electric flux density
Electric field intensity is dependent on the medium (free space)
Introduce a new vector field D that is independent on medium
Electric flux , measured in SI unit Coulomb
Vector field D called the electric flux density; SI unit coulomb/m2
Can obtain D from E. Eg. For infinite sheet of charge
For a volume charge distribution,
Example 4.7
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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454.3: Electric flux density
P.E. 4.7
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
-
464.4: Gausss law
Gausss law states that the total electric flux through any closed
surface is equal to the total charge enclosed by the surface. i.e.
Using the divergence theorem, , therefore
1st of the 4 Maxwells equations the volume charge density is equal to
the divergence of the electric flux density
Gausss Law (GL) is an alternative statement of Coulombs Law
(CL);proper application of divergence theorem to CL results in GL
GL provides an easy way to determine E and D for symmetrical charge
distribution
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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474.4: Gausss law
Total net flux leaving surface v1 = 5 nC
Charges 20 nC and 15 nC do not affect
because net = 0; in = out
For surface v2, net flux = 0
Procedures to apply Gausss law to for calculation
Determine whether symmetric charge distribution exists
A closed surface (called the Gaussian surface) is chosen such that D is normal or tangential to the surface
For a point charge Q, choose a spherical surface
D is everywhere normal to the surface
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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484.4: Gausss law
For an infinite line charge, choose a cylindrical surf.
to satisfy the symmetry condition
GL:-
For top and bottom surface ZERO;
For an infinite sheet of charge, choose a rectangular
box that is cut symmetrically by the sheet
GL:-
If the top and bottom have an area A,
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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494.4: Gausss law
For a uniformly charged sphere, spherical surf.
For r a,
GL:- For r => a,
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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504.4: Gausss law
Try eg.4.8; P.E. 4.8
P.E. 4.9 (XX Need)
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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514.5: Electric potential
Recap:- To calculate E, can use CL for all cases; GL only suits highly
symmetric charge distribution
Another way use electric scalar potential V; easier to handle scalar than vector quantity
Case Moving a point charge Q from point A to B in an electric field E . From CL, , work done
-ve sign: indicates work done by external agent
Potential energy per unit charge potential difference between point A and B ; A is the initial point, B is the final point
VAB ve:- loss in PE when moving Q from A to B, work done by field
VAB +ve:- gain in PE when moving Q from A to B, external agent performs the work
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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524.5: Electric potential
VAB is independent of the path taken
VAB is measured in Joules/C, commonly called as volt (V)
Equations:-
Always determine electric potential relative to another potential
Calculation for point charge relative to infinity
Using superposition principle
Note:- if electric field is known, use
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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534.5: Electric potential
Example 4.10
P.E. 4.10
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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544.5: Electric potential
Try xample 4.11
P.E. 4.11
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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554.6: Electric energy
To calculate the energy present in an assembly of charges, need to first
determine the amount of work necessary to assemble them
Wish to move Q1,2,3 to the shaded region
Q1 no work required, E field = 0,no charge
Putting the charges in reverse order
Hence
; Generally,
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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564.6: Electric energy
P.E. 4.14
Try to calculate the total work done using the formula
Compare the answers!
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
-
ELECTROMAGNETIC
FIELDS & WAVES
EEEB 253
CHAPTER 5
BEEE/BEPE
College of Engineering
-
58
Chapter 5: Electric fields in materials
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
1. Properties of materials
2. Conductors
3. Dielectrics
4. Continuity equation
5. Boundary conditions
Previous chapter consider electric field in free space
Electric field in other mediums / materials most of the equations are similar as in
last chapter with little modification
Materials classified based on electrical properties conductor and non-conductor
(insulator or dielectric)
-
595.1: Properties of material
Materials are categorized based on conductivity in the unit of mhos/m
or Siemens/m (S/m)
Conductivity is usually dependent on the temperature and frequency
High conductivity conductor / metal; low conductivity
insulator; in between semiconductor
Conductivity increases with decreasing temperature
Superconductor extremely high / infinite conductivity at very low
temperature (0-4 Kelvin) what degree celcius??
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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605.2: Conductors
Conductors many freely moving charges
An isolated conductor (top figure); external Efield is
applied+ve charges are pushed along Efield and -vecharges move in opposite direction (charge migration
happens very quickly)
2 things are done by the free charges:-
They accumulate on the surface of the conductor (induced
surface charges)
Induced charges set up an internal induced field
A conductor is an equipotential body potential is the
same everywhere
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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615.2: Conductors
According to GL, if E=0, then charge density=0
Under static condition,
What happens when the ends / terminals of a conductor are
maintained at a certain potential difference?
E=0??the conductor is no longer isolated but wired to a source of electromotive force (battery)
Disrupt the electrostatic equilibrium by forcing free charges to move
There is an Efield to have current flows ; Efield, +ve charge,
current have the same direction; electrons flow in opposite direction
Electrons movement is opposed by a damping force Resistance
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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625.2: Conductors
To obtain the resistance, assume the conductor has
a cross section area, S; current density,
Ohms law, ;
Resistivity of material,
For conductor with non-uniform cross section,
Using power and energy equation,
P.E. 5.3
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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635.3: Dielectrics
Charges in dielectric are bounded but can displace if a sufficiently
large external force is applied
When an Efield is applied, +ve charge is displaced in the direction of
Efield and ve charge is displaced in the opposite direction of Efield
Dipole separation of +ve and ve charges; Dipole is created the dielectric is said to be polarized
In a polarized state, the electrons are distorted; Distorted charge
distribution = original distribution + dipole moment ( ), d is the
distance vector from Q to +Q
Total dipole moment
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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645.3: Dielectrics
Calculate the field due to a polarized dielectric
Net effect of the dielectric on the electric field is to increase D by an
amount P. Polarization P will vary with E, usually as
is the electric susceptibility of material a measure of how
susceptible a dielectric is to electric fields
Dielectric constant
Permittivity of dielectric vs. permittivity of free space
Dielectric constant / relative permittivity - ratio of to ; may
change at high frequencies > 1 GHz
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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655.3: Dielectrics
Try eg. 5.7; In class: P.E. 5.7
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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665.4: Continuity equation
Principle of charge conservation time rate of decrease of charge =
net outward current flow through the closed surface of a volume
is the total charge enclosed by the surface
Using Divergence theorem, ; Also,
Hence, Current continuity equation
For steady current, or i.e. total charge entering a
volume = total charge leaving the volume
Consider the effect of introducing charge at some interior point using
Ohms law and Gausss law
Relaxation time or rearrangement time = - the time it takes a
charge placed in the interior of a material to drop to e-1 = 36.8% of its initial value
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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675.4: Continuity equation
Good conductor short Tr; Good dielectric long Tr
For copper, , what is Tr?
For fused quartz,
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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685.5: Boundary conditions
We considered Efield only in one medium
When it involves more than one medium, the conditions that the field
must satisfy at the interface separating the medium is called the
Boundary Conditions
Consider 3 cases 1) dielectric 1 and dielectric 2; 2) Conductor and
dielectric; 3) Conductor and free space
Use Maxwells equations:-
Decompose electric field intensity into 2 orthogonal components
tangential and normal components of E
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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ELECTROMAGNETIC
FIELDS & WAVES
EEEB 253
CHAPTER 6
BEEE/BEPE
College of Engineering
-
70
Chapter 6: Electrostatic boundary value problems
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
1. Poissons equation
2. Laplaces equation
3. Procedures for solving Poissons
and Laplaces equations
4. Capacitance
Previous chapters charge distribution is known, use GL or CL to determine Efield
If the potential difference is known, use
Practical electrostatic problems:- only electrostatic conditions (Charge or potential
difference) at some boundaries are known need to find E and V throughout the
region Boundary value problems
Need to use Poissons or Laplaces equations derived from GL
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71
6.1: Poissons equation // 6.2 Laplaces equation
Poissons equation
Special case for a charge-free region (Laplaces eqn)
Hence, the Laplaces equations in different coordinate systems are:-
Poissons equations in different coordinate systems are obtained by
replacing 0 with
Laplaces equations:- useful to solve electrostatic problems involving
a set of conductors maintained at different potentials. Eg. Capacitors,
vacuum tube diodes
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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72
6.3: Procedures for solving Poissons and Laplaces equations
Followings are the general procedures:-
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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736.4: Capacitance
Capacitor must have 2 or more conductors carrying equal but
opposite charge; separated by free space or dielectric
Capacitance ratio of the magnitude of the charge on one of the plate
to the potential difference between the plates
Unit Farad (F); indicate how much charge can be stored
2 methods to calculate capacitance of 2 conductors
1) choose a suitable coordinate; 2) Plates carrying charge +Q and Q;
3) Calculate E using CL or GL, calculate ; 4)
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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746.4: Capacitance
Parallel plate capacitor
Assume carrying charge +Q and Q; hence
Using Laplaces eqn. (Example 6.11)
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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756.4: Capacitance
Using Laplaces eqn. (Example 6.11)
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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766.4: Capacitance
Coaxial capacitor coaxial cable Length, L; inner radius, a; outer radius, b Using GL for a < < b, ,
Capacitance of a coaxial cable Using Laplaces eqn. (Example 6.8 with full cylinder) Coaxial = full cylinder (inner and outer surfaces)
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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776.4: Capacitance
Using Laplaces eqn. (Example 6.8 with full cylinder)
Q = s x surface area = s x 2piL C = Q/Vo = 2piL / ln (b/a)
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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786.5: Resistance
Resistance
1) Choose a suitable coordinate system; 2)Assume Vo as the potential difference between the conductor terminals; 3) Solve Laplaces
equation to obtain V, then determine E and I from ; 4)
Obtain R from V0/I
Example 6.8
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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796.5: Resistance
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
-
806.5: Resistance
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
-
816.5: Resistance
Example 6.9
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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ELECTROMAGNETIC
FIELDS & WAVES
EEEB 253
CHAPTER 7
BEEE/BEPE
College of Engineering
-
83Chapter 7: Magnetostatic fields
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
1. Biot-Savarts law
2. Amperes circuit law
3. Magnetic scalar and vector potentials
Previous chapters concentrate on the electric field (E and D); this chapter study the static magnetic field (B and H) vs.
A few similarities between magnetic and electric fields Most of the equations derived for Efield can be readily used for Mfield
This chapter considers Mfield in free space due to the direct current
Development of motors, transformers, microphones, compasses, etc.
Biot-Savarts law CL and Amperes law GL
-
847.1: Biot-Savarts law
Biot-Savarts law states that the magnetic field intensity dH produced at a point P, by the differential current, I dl, is proportional to the product I dl and the sine of the angle betweenthe element and the line joining P to the element and is inversely proportional to the square of the distance R between P and the element
Use right-hand rule to determine the direction of dH Represent the directions of I and H with cross and dot Efield different charge distribution; Mfield different
current distribution
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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857.1: Biot-Savarts law
Example of line current straight current carrying conductor with length AB.
,
Hence,
This expression is applicable to any straight line. For an infinitely long current carrying wire, point A (0, 0, -infinity), B(0, 0, infinity)
P.E. 7.1
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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867.1: Biot-Savarts law
How to determine each parameter?? Angles (1, 2) follow the flow of current starting of current is 1
and end of current is 2 a UNIT VECTOR of the flow of current a UNIT VECTOR pointing from the filament to the point a = a x a
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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877.1: Biot-Savarts law
Example 7.2
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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887.1: Biot-Savarts law
Example 7.2
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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897.2: Amperes circuit law
Amperes circuit law states that the line integral of the tangential component of H around a closed path is the same as the net current Ienc enclosed by the path comparison
A special case of the Biot-Savarts law AL can be used to obtain Honly when symmetrical current distribution exists
Stokes theorem , also, Therefore, 3rd Maxwells equation Infinite line current to determine H at point P Assume an Amperian path through P
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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90
7.3: Magnetic scalar and vector potential
Relate electric field intensity to potential Magnetic flux density B is related to magnetic field intensity H Permeability of freespace Magnetic scalar potential Vm (in amperes), Vector magnetic potential, A (in Wb/m) Example 7.7
Try to solve using Stokes theoremKer Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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91
7.3: Magnetic scalar and vector potential
Example 7.7 Try to solve using Stokes theorem
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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ELECTROMAGNETIC
FIELDS & WAVES
EEEB 253
CHAPTER 8
BEEE/BEPE
College of Engineering
-
93
Chapter 8: Magnetic forces and magnetic materials
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
1. Force due to magnetic fields
2. Magnetic torque and moment
3. Magnetization
4. Inductances and inductors
5. Magnetic energy
Study the force exerted by the magnetic field on a charged particle, current element
and loop
Consider the magnetic field in different material media
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948.1: Force due to magnetic field
3 ways a force can be experienced in a magnetic field:- 1) moving charged particle in a B field; 2) current element in an external Bfield; 3) between two current element
Magnetic force experienced by a charge Q moving with a velocity uin a magnetic field B ; Fm perpendicular to u and B
Fm cannot perform work as it is normal to the velocity For a moving charge in E and B fields Lorentz force
equation; With a mass m, Force on a current element current = flow of many charges for a closed path L, Note:- the B field produced by the current element does not exert
magnetic force on itselfKer Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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958.1: Force due to magnetic field
Example 8.3
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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968.2: Magnetic torque and moment
Very important to understand the concept of a current loop experiencing a torque in a magnetic field in order to understand d.c. motors and generators
The torque on a loop is the vector product of the force and the moment arm ,r , unit N.m
A rectangular loop with length l and width w Under a uniform B field Along sides 12 and 34: dl parallel to B; Fm = 0 Therefore, , but both forces acting at different point If the normal to the plane makes an angle with B,
or Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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978.2: Magnetic torque and moment
The magnetic dipole moment:- is the product of the current and area of the loop in the direction normal to the loop
Hence, from When do we get maximum torque? When will it be minimum? Example 8.5
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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988.3: Magnetization
Magnetization, M in amperes/meter (A/m) is the magnetic dipole moment per unit volume
Without an external B field, the sum of magnetic moments is zero due to random orientation; when Bfield is applied, the magnetic moments of the electrons align themselves with B
A material is said to be magnetized if M is not zero Bound volume current density or magnetization volume
current density Bound surface current density , is the unit
vector normal to the surface , M depends linearly on H such that
where is the magnetic susceptibility - dimensionless Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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998.3: Magnetization
Hence,
is the permeability of the material in Henrys/m (H/m) is the relative permeability
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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1008.4: Inductances and inductors
Circuit carrying current I magnetic field B causes flux With N identical turns, flux linkages Flux linkages is proportional to the current L is the proportionality constant, called Inductance Circuit that has inductance is called inductor Inductance=ratio of magnetic flux linkage to current Unit Henry (H): 1H = 1Wb/A Usually called self-inductance since the flux linkages are produced
by the circuit itself Capacitance measure of how much electric energy stored;
Inductance measure of how much magnetic energy storedKer Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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1018.4: Inductances and inductors
Magnetic energy stored in an inductor or Typical examples of inductor toroids, solenoids, coaxial
transmission line; parallel-wire transmission line To find the self-inductance:-
In an inductor such as coaxial or parallel wire transmission lines, inductance produced by the flux internal to the conductor is called the internal inductance; inductance produced by flux external to it is called the external inductance
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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1028.5: Magnetic energy
To express the magnetic energy in terms of B and H
Example 8.11
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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1038.5: Magnetic energy
Example 8.11 What about L/length??
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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ELECTROMAGNETIC
FIELDS & WAVES
EEEB 253
CHAPTER 9
BEEE/BEPE
College of Engineering
-
105Chapter 9: Maxwells equation
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
1. Faradays law
2. Transformer emf
3. Motional emf
Stationary charge electrostatic fields; Steady currents magnetostatic fields
Time-varying current Electromagnetic fields (and waves)
2 major concepts electromotive force based on Faradays experiment;
displacement current resulted from Maxwells hypothesis
Maxwells equations:- summarize the laws of electromagnetism
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1069.1: Faradays law
1831, Faraday and Henry discovered that a time-varying magnetic field would produce an electric current
Static field no current; time-varying field produce an induced voltage (called the electromotive force, emf)
Faradays law:-
Lenzs law: the ve signthe induced emf acts in such a way that opposes the flux producing it; or the induced magnetic field by the induced current will oppose the original field
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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1079.2: Transformer emf
Consider a single turn (N=1) circuit, In terms of E and B, , flux is replaced by
where S is the surface area enclosed by the closed path L 3 ways to cause the variation of flux with time:-
Stationary loop in a time-varying B field Time-varying loop area in a static B field Time-varying loop area in a time-varying B field
1st case: , emf is induced by a time-varying current (producing a time-varying B field) Transformer emf
Applying Stokes theorem, Maxwells eqn. for time-varying field;
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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1089.3: Motional emf
2nd case: moving loop in static B field; Recall:-force exerted on a charge moving at a velocity in a B field
Define the motional electric field Emf induced called the motional emf Type of emf found in motors and generators Example: voltage is generated when the coil
rotates within the magnetic field Rod moving between a pair of rails Perpendicular,
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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1099.3: Motional emf
Be careful when using
Example 9.1
Transformer emf
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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1109.3: Motional emf
Continue Eg. 9.1 Motional emf
It is easier to use
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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1119.3: Motional emf
Problem 9.6
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power
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1129.3: Motional emf
Problem 9.11
Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power