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ELECTROMAGNETIC FIELDS & WAVES EEEB 253 CHAPTER 1 BEEE/BEPE College of Engineering

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Electromagnetive Waves notes by Dr. Ker Pin Jern

Transcript of EEEB253_chap1 to chap9_20140911

  • ELECTROMAGNETIC

    FIELDS & WAVES

    EEEB 253

    CHAPTER 1

    BEEE/BEPE

    College of Engineering

  • 2Electromagnetic spectrum

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 3Chapter 1: Vector algebra

    1. Scalar and vector

    2. Unit vector

    3. Position vector

    4. Vector multiplication

    Electromagnetics (EM) A branch of physics or electrical engineering where

    electric and magnetic phenomena are studied

    Applications:- microwave, antenna, electric machine, radar, remote sensing etc.

    Eg. EM energy change vegetable taste by reducing its acidicity

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 41.1: Scalar and vector

    EM concepts can be understood through vector analysis

    Need to have strong vector analysis

    Scalar quantity that only has magnitude

    Vector quantity that has both magnitude and direction, identified

    by an arrow above the symbols (or bold in typing)

    EM theory study of a particular field

    Field is a function that specifies a particular quantity everywhere in

    a region. Eg. Gravitational field

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 51.2: Unit vector

    Magnitude of a vector A is A or |A|

    A unit vector aA, is a vector with magnitude of unity and direction A

    Vector A can be written as or

    Magnitude of a vector

    Unit vector is given by

    Vector addition / subtraction (revision)

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 6Examples / practice exercises

    PE 1.3 (position vector)

    Answers / solution will be done during lecture

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 7Examples / practice exercises

    Example (unit vector)

    What is the magnitude of unit vector ac???

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 81.3: Position vector

    Position vector (rp) also called the radius vector of a point P is the distance directed from the origin to point P

    Point (3, 4, 5) has a position vector

    Distance vector displacement from one point to

    another point

    Prac. Exercise 1.1

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 91.4: Vector multiplication

    2 types of vector multiplication

    Dot product

    2 vectors are orthogonal or perpendicular if

    Dot product commutative law

    Dot product Distributive law

    Dot product perpendicular vector

    Dot product parallel vector

    Cross product , an is the unit vector normal to the plane containing vectors A and B

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 101.4: Vector multiplication

    Cross product anticommutative

    Not associative

    Distributive

    Special cases

    Example 1.4 find the angle using dot product / cross product

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • ELECTROMAGNETIC

    FIELDS & WAVES

    EEEB 253

    CHAPTER 2

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    College of Engineering

  • 12Chapter 2: Coordinate system

    1. Cartesian coordinate

    2. Cylindrical coordinate / transformation

    3. Spherical coordinate / transformation

    Physical quantities in EM are functions of time and space

    To define all points accurately, use coordinate system

    Orthogonal coordinate system the ones in which the coordinates are mutually

    perpendicular. Eg. Cartesian, spherical, cylindrical, conical etc.

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 13

    2.1: Cartesian coordinate / 2.2 Circular cylindrical coordinate

    A point P can be represented by (x, y, z)

    Cartesian coordinate = rectangular coordinate

    Vector A

    Cylindrical coordinate convenient for problems

    with cylindrical symmetry

    is the radial distance from the z-axis; is called the azimuthalangle measured from the x-axis on the xy-plane

    z is the same as in Cartesian coordinate

    Vector A can be written as

    Magnitude of vector; Unit vectors are all perpendicular

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 142.2 Circular cylindrical coordinate

    Relationship between cylindrical and Cartesian coordinates

    Relationship between and

    In matrix form

    The unit vectors are related as below

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 152.3 Spherical coordinate

    Most appropriate when dealing with problems

    having spherical symmetry

    A point can be represented by

    r is the distance from the origin to the point

    is the angle between z-axis and position

    vector P (Colatitude angle)

    is measured from the x-axis (same as Azimuthal angle)

    Vector A can be expressed as and

    The magnitude is

    The unit vectors are all mutually orthogonal

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 162.3 Spherical coordinate

    Relationship between spherical and Cartesian coordinates

    The unit vectors are related as follows:-

    Components of vector

    The magnitude MUST stay the same

    after transformation to check answer

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 17Examples / practice exercises

    Example 2.1

    At point P,

    Exclude Spherical!

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 18Examples / practice exercises

    PE 2.1

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 19Examples / practice exercises

    PE 2.1

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 20Examples / practice exercises

    PE 2.2

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • ELECTROMAGNETIC

    FIELDS & WAVES

    EEEB 253

    CHAPTER 3

    BEEE/BEPE

    College of Engineering

  • 22Chapter 3: Vector calculus

    1. Line integral

    2. Surface and volume integral

    3. Del, Divergence, Curl and Laplacian

    Deals with integration and differentiation of vectors (Calculus)

    Learning the mathematical techniques in this chapter, which will be useful for the

    EM applications in subsequent chapters

    Differential normal area

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 233.1: Line integral

    Integration concept extension to an integrand which is a vector

    Vector field A; Line integral is the integral of the tangential component of A along curve L

    We can define the integral as

    For a closed path abca, closed contour integral

    Example 3.2

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 24PE 3.2

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 253.2: Surface and volume integral

    Vector A continuous in a region containing a smooth surface S

    Surface integral or flux of A through Sor

    At any point on S, an is the unit vector normal to the surface S

    For a closed surface that defining a volume,

    The volume integral , scalar over volume v

    Problem 3.2 (d)

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 26

    3.3: Del, Divergence, Curl, and Lapacian

    The Del operator , also known as gradient operator

    This operator is useful in defining:

    in Cartesian coordinate

    In cylindrical coordinate, using transformation

    In spherical coordinate,

    Divergence of A at any given point P, is the outward flux per unit volume as the volume shrinks about P

    Net outflow of flux of a vector field A from a closed surface is obtained

    from the surface integral

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 27

    3.3: Del, Divergence, Curl, and Lapacian

    Divergence of A can be written as , is the volume

    enclosed by the closed surface where the P is located

    Imagine divergence as a measure of how much the fields diverge or emanate from a point P

    +ve at a source point diverge

    -ve at a sink point converge

    Neither sink nor source Zero

    Divergence of A at point P in a Cartesian system

    In cylindrical coordinate

    In spherical coordinate

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 28

    3.3: Del, Divergence, Curl, and Lapacian

    Properties of the divergence of a vector field:-

    It is a scalar product; Divergence of a scalar makes no sense;

    ;

    Divergence theorem:- the total outward flux of a vector field A through a closed surface S is the same as the volume integral of the divergence

    of A

    Example 3.6

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 29PE 3.7

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 30

    3.3: Del, Divergence, Curl, and Lapacian Curl of vector A is an axial or rotational vector whose magnitude is

    the maximum circulation of A per unit area as the area tends to zero and

    whose direction is the normal direction of the area when the area is

    oriented so as to make the circulation maximum

    is the area bounded by curve L, is the unit vector normal to the

    surface , determined by the right hand rule

    is independent on the coordinate system

    Cartesian

    Cylindrical

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 31

    3.3: Del, Divergence, Curl, and Lapacian Properties of the curl:-

    Stokes theorem

    Example 3.8 Determine the curl vectors

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 32

    3.3: Del, Divergence, Curl, and Lapacian Example 3.8

    Example 3.9

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 33

    3.3: Del, Divergence, Curl, and Lapacian Example 3.9

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 34

    3.3: Del, Divergence, Curl, and Lapacian Laplacian operator is the composite of the gradient and divergence

    Definition:-

    Laplacian of a scalar field is another scalar field

    In Cartesian:-

    In cylindrical:-

    In spherical:-

    A scalar field vector V is said to be harmonic in a given region if its

    Laplacian vanishes in that region. i.e.

    Laplacian of a vector NOT the divergence of the gradient of A but the gradient of the divergence of A

    In Cartesian only, it becomes

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 35

    3.3: Del, Divergence, Curl, and Lapacian Example 3.11

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 36

    3.3: Del, Divergence, Curl, and Lapacian

    P.E. 3.11

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 37Chapter 3 Conclusion

    Line integral, surface and volume integrals

    Del operator used in divergence, curl and Laplacian

    Divergence of a vector results in a scalar quantity; total outward

    flux through a closed surface (Dot)

    Curl of a vector results in a rotational vector (Cross)

    Laplacian of a scalar field results in another scalar; divergence of

    a gradient of a vector

    Tutorial questions: 3.1(a), 3.2(a, b), 3.3(a, b), 3.4, 3.10(a, b), 3.15, 3.16(a,

    b), 3.17(a, b), 3.19, 3.24(a, b), 3.29(a, b), 3.31

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • ELECTROMAGNETIC

    FIELDS & WAVES

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    CHAPTER 4

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    College of Engineering

  • 39Chapter 4: Electrostatic fields

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

    1. Coulombs law

    2. Electric fields

    3. Electric flux density

    4. Gausss law

    5. Electric potential

    6. Electric energy

    Static electric field time invariant; E field produced by static charge distribution

    E field application Touch pad, capacitive keyboard, LCD

    Industry E field used for paint spraying, electrodeposition, measure moisture

    content of crops, speed baking of bread and smoking of meat

    Coulombs law & Gausss law both for calculating electric field

  • 404.1: Coulombs law

    Coulombs law:- deals with the force exerted by a point charge on

    another point charge

    The force F between two point charges Q1 and Q2 is:-

    Along the line joining them

    Directly proportional to the product Q1Q2 of the charges

    Inversely proportional to the square of the distance R between them

    With a proportionality constant, it can be expressed as

    Coulombs constant, k, expressed in terms of the permittivity of free space (in Farad per meter)

    F12 force exerted on Q2 due to Q1, if Q1 and Q2 are located at position vectors r1 and r2 respectively.

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 414.1: Coulombs law

    Using the formula for unit vector, or

    A few points to note:-

    Opposing force with same magnitude

    Like charges repel, opposite charges attract

    Distance R is much larger than the size of the charges i.e. point charges

    All the charges must be in static i.e. not moving

    Signs of the charges must be taken into account

    For cases with more than two charges,

    Electric field intensity (electric field strength), E force per unit charge when placed in the electric field

    E is in the direction of F in N/C or V/m

    For E due to many chargesKer Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 424.1: Coulombs law

    Example 4.1

    P.E. 4.1

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 43

    4.2: Electric fields due to continuous charge distribution

    More realistic cases charges distributed along a line, surface or

    volume with line , surface and volume charge densities

    The charge element dQ and the total charge Q

    The electric field intensity = sum of the field contributed by the point

    charges making up the charge distribution

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 444.3: Electric flux density

    Electric field intensity is dependent on the medium (free space)

    Introduce a new vector field D that is independent on medium

    Electric flux , measured in SI unit Coulomb

    Vector field D called the electric flux density; SI unit coulomb/m2

    Can obtain D from E. Eg. For infinite sheet of charge

    For a volume charge distribution,

    Example 4.7

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 454.3: Electric flux density

    P.E. 4.7

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 464.4: Gausss law

    Gausss law states that the total electric flux through any closed

    surface is equal to the total charge enclosed by the surface. i.e.

    Using the divergence theorem, , therefore

    1st of the 4 Maxwells equations the volume charge density is equal to

    the divergence of the electric flux density

    Gausss Law (GL) is an alternative statement of Coulombs Law

    (CL);proper application of divergence theorem to CL results in GL

    GL provides an easy way to determine E and D for symmetrical charge

    distribution

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 474.4: Gausss law

    Total net flux leaving surface v1 = 5 nC

    Charges 20 nC and 15 nC do not affect

    because net = 0; in = out

    For surface v2, net flux = 0

    Procedures to apply Gausss law to for calculation

    Determine whether symmetric charge distribution exists

    A closed surface (called the Gaussian surface) is chosen such that D is normal or tangential to the surface

    For a point charge Q, choose a spherical surface

    D is everywhere normal to the surface

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 484.4: Gausss law

    For an infinite line charge, choose a cylindrical surf.

    to satisfy the symmetry condition

    GL:-

    For top and bottom surface ZERO;

    For an infinite sheet of charge, choose a rectangular

    box that is cut symmetrically by the sheet

    GL:-

    If the top and bottom have an area A,

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 494.4: Gausss law

    For a uniformly charged sphere, spherical surf.

    For r a,

    GL:- For r => a,

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 504.4: Gausss law

    Try eg.4.8; P.E. 4.8

    P.E. 4.9 (XX Need)

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 514.5: Electric potential

    Recap:- To calculate E, can use CL for all cases; GL only suits highly

    symmetric charge distribution

    Another way use electric scalar potential V; easier to handle scalar than vector quantity

    Case Moving a point charge Q from point A to B in an electric field E . From CL, , work done

    -ve sign: indicates work done by external agent

    Potential energy per unit charge potential difference between point A and B ; A is the initial point, B is the final point

    VAB ve:- loss in PE when moving Q from A to B, work done by field

    VAB +ve:- gain in PE when moving Q from A to B, external agent performs the work

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 524.5: Electric potential

    VAB is independent of the path taken

    VAB is measured in Joules/C, commonly called as volt (V)

    Equations:-

    Always determine electric potential relative to another potential

    Calculation for point charge relative to infinity

    Using superposition principle

    Note:- if electric field is known, use

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 534.5: Electric potential

    Example 4.10

    P.E. 4.10

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 544.5: Electric potential

    Try xample 4.11

    P.E. 4.11

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 554.6: Electric energy

    To calculate the energy present in an assembly of charges, need to first

    determine the amount of work necessary to assemble them

    Wish to move Q1,2,3 to the shaded region

    Q1 no work required, E field = 0,no charge

    Putting the charges in reverse order

    Hence

    ; Generally,

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 564.6: Electric energy

    P.E. 4.14

    Try to calculate the total work done using the formula

    Compare the answers!

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • ELECTROMAGNETIC

    FIELDS & WAVES

    EEEB 253

    CHAPTER 5

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    College of Engineering

  • 58

    Chapter 5: Electric fields in materials

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

    1. Properties of materials

    2. Conductors

    3. Dielectrics

    4. Continuity equation

    5. Boundary conditions

    Previous chapter consider electric field in free space

    Electric field in other mediums / materials most of the equations are similar as in

    last chapter with little modification

    Materials classified based on electrical properties conductor and non-conductor

    (insulator or dielectric)

  • 595.1: Properties of material

    Materials are categorized based on conductivity in the unit of mhos/m

    or Siemens/m (S/m)

    Conductivity is usually dependent on the temperature and frequency

    High conductivity conductor / metal; low conductivity

    insulator; in between semiconductor

    Conductivity increases with decreasing temperature

    Superconductor extremely high / infinite conductivity at very low

    temperature (0-4 Kelvin) what degree celcius??

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 605.2: Conductors

    Conductors many freely moving charges

    An isolated conductor (top figure); external Efield is

    applied+ve charges are pushed along Efield and -vecharges move in opposite direction (charge migration

    happens very quickly)

    2 things are done by the free charges:-

    They accumulate on the surface of the conductor (induced

    surface charges)

    Induced charges set up an internal induced field

    A conductor is an equipotential body potential is the

    same everywhere

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 615.2: Conductors

    According to GL, if E=0, then charge density=0

    Under static condition,

    What happens when the ends / terminals of a conductor are

    maintained at a certain potential difference?

    E=0??the conductor is no longer isolated but wired to a source of electromotive force (battery)

    Disrupt the electrostatic equilibrium by forcing free charges to move

    There is an Efield to have current flows ; Efield, +ve charge,

    current have the same direction; electrons flow in opposite direction

    Electrons movement is opposed by a damping force Resistance

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 625.2: Conductors

    To obtain the resistance, assume the conductor has

    a cross section area, S; current density,

    Ohms law, ;

    Resistivity of material,

    For conductor with non-uniform cross section,

    Using power and energy equation,

    P.E. 5.3

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 635.3: Dielectrics

    Charges in dielectric are bounded but can displace if a sufficiently

    large external force is applied

    When an Efield is applied, +ve charge is displaced in the direction of

    Efield and ve charge is displaced in the opposite direction of Efield

    Dipole separation of +ve and ve charges; Dipole is created the dielectric is said to be polarized

    In a polarized state, the electrons are distorted; Distorted charge

    distribution = original distribution + dipole moment ( ), d is the

    distance vector from Q to +Q

    Total dipole moment

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 645.3: Dielectrics

    Calculate the field due to a polarized dielectric

    Net effect of the dielectric on the electric field is to increase D by an

    amount P. Polarization P will vary with E, usually as

    is the electric susceptibility of material a measure of how

    susceptible a dielectric is to electric fields

    Dielectric constant

    Permittivity of dielectric vs. permittivity of free space

    Dielectric constant / relative permittivity - ratio of to ; may

    change at high frequencies > 1 GHz

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 655.3: Dielectrics

    Try eg. 5.7; In class: P.E. 5.7

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 665.4: Continuity equation

    Principle of charge conservation time rate of decrease of charge =

    net outward current flow through the closed surface of a volume

    is the total charge enclosed by the surface

    Using Divergence theorem, ; Also,

    Hence, Current continuity equation

    For steady current, or i.e. total charge entering a

    volume = total charge leaving the volume

    Consider the effect of introducing charge at some interior point using

    Ohms law and Gausss law

    Relaxation time or rearrangement time = - the time it takes a

    charge placed in the interior of a material to drop to e-1 = 36.8% of its initial value

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 675.4: Continuity equation

    Good conductor short Tr; Good dielectric long Tr

    For copper, , what is Tr?

    For fused quartz,

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 685.5: Boundary conditions

    We considered Efield only in one medium

    When it involves more than one medium, the conditions that the field

    must satisfy at the interface separating the medium is called the

    Boundary Conditions

    Consider 3 cases 1) dielectric 1 and dielectric 2; 2) Conductor and

    dielectric; 3) Conductor and free space

    Use Maxwells equations:-

    Decompose electric field intensity into 2 orthogonal components

    tangential and normal components of E

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • ELECTROMAGNETIC

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    CHAPTER 6

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  • 70

    Chapter 6: Electrostatic boundary value problems

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

    1. Poissons equation

    2. Laplaces equation

    3. Procedures for solving Poissons

    and Laplaces equations

    4. Capacitance

    Previous chapters charge distribution is known, use GL or CL to determine Efield

    If the potential difference is known, use

    Practical electrostatic problems:- only electrostatic conditions (Charge or potential

    difference) at some boundaries are known need to find E and V throughout the

    region Boundary value problems

    Need to use Poissons or Laplaces equations derived from GL

  • 71

    6.1: Poissons equation // 6.2 Laplaces equation

    Poissons equation

    Special case for a charge-free region (Laplaces eqn)

    Hence, the Laplaces equations in different coordinate systems are:-

    Poissons equations in different coordinate systems are obtained by

    replacing 0 with

    Laplaces equations:- useful to solve electrostatic problems involving

    a set of conductors maintained at different potentials. Eg. Capacitors,

    vacuum tube diodes

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 72

    6.3: Procedures for solving Poissons and Laplaces equations

    Followings are the general procedures:-

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 736.4: Capacitance

    Capacitor must have 2 or more conductors carrying equal but

    opposite charge; separated by free space or dielectric

    Capacitance ratio of the magnitude of the charge on one of the plate

    to the potential difference between the plates

    Unit Farad (F); indicate how much charge can be stored

    2 methods to calculate capacitance of 2 conductors

    1) choose a suitable coordinate; 2) Plates carrying charge +Q and Q;

    3) Calculate E using CL or GL, calculate ; 4)

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 746.4: Capacitance

    Parallel plate capacitor

    Assume carrying charge +Q and Q; hence

    Using Laplaces eqn. (Example 6.11)

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 756.4: Capacitance

    Using Laplaces eqn. (Example 6.11)

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 766.4: Capacitance

    Coaxial capacitor coaxial cable Length, L; inner radius, a; outer radius, b Using GL for a < < b, ,

    Capacitance of a coaxial cable Using Laplaces eqn. (Example 6.8 with full cylinder) Coaxial = full cylinder (inner and outer surfaces)

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 776.4: Capacitance

    Using Laplaces eqn. (Example 6.8 with full cylinder)

    Q = s x surface area = s x 2piL C = Q/Vo = 2piL / ln (b/a)

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 786.5: Resistance

    Resistance

    1) Choose a suitable coordinate system; 2)Assume Vo as the potential difference between the conductor terminals; 3) Solve Laplaces

    equation to obtain V, then determine E and I from ; 4)

    Obtain R from V0/I

    Example 6.8

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 796.5: Resistance

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 806.5: Resistance

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 816.5: Resistance

    Example 6.9

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • ELECTROMAGNETIC

    FIELDS & WAVES

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    CHAPTER 7

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    College of Engineering

  • 83Chapter 7: Magnetostatic fields

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

    1. Biot-Savarts law

    2. Amperes circuit law

    3. Magnetic scalar and vector potentials

    Previous chapters concentrate on the electric field (E and D); this chapter study the static magnetic field (B and H) vs.

    A few similarities between magnetic and electric fields Most of the equations derived for Efield can be readily used for Mfield

    This chapter considers Mfield in free space due to the direct current

    Development of motors, transformers, microphones, compasses, etc.

    Biot-Savarts law CL and Amperes law GL

  • 847.1: Biot-Savarts law

    Biot-Savarts law states that the magnetic field intensity dH produced at a point P, by the differential current, I dl, is proportional to the product I dl and the sine of the angle betweenthe element and the line joining P to the element and is inversely proportional to the square of the distance R between P and the element

    Use right-hand rule to determine the direction of dH Represent the directions of I and H with cross and dot Efield different charge distribution; Mfield different

    current distribution

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 857.1: Biot-Savarts law

    Example of line current straight current carrying conductor with length AB.

    ,

    Hence,

    This expression is applicable to any straight line. For an infinitely long current carrying wire, point A (0, 0, -infinity), B(0, 0, infinity)

    P.E. 7.1

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 867.1: Biot-Savarts law

    How to determine each parameter?? Angles (1, 2) follow the flow of current starting of current is 1

    and end of current is 2 a UNIT VECTOR of the flow of current a UNIT VECTOR pointing from the filament to the point a = a x a

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 877.1: Biot-Savarts law

    Example 7.2

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 887.1: Biot-Savarts law

    Example 7.2

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 897.2: Amperes circuit law

    Amperes circuit law states that the line integral of the tangential component of H around a closed path is the same as the net current Ienc enclosed by the path comparison

    A special case of the Biot-Savarts law AL can be used to obtain Honly when symmetrical current distribution exists

    Stokes theorem , also, Therefore, 3rd Maxwells equation Infinite line current to determine H at point P Assume an Amperian path through P

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 90

    7.3: Magnetic scalar and vector potential

    Relate electric field intensity to potential Magnetic flux density B is related to magnetic field intensity H Permeability of freespace Magnetic scalar potential Vm (in amperes), Vector magnetic potential, A (in Wb/m) Example 7.7

    Try to solve using Stokes theoremKer Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 91

    7.3: Magnetic scalar and vector potential

    Example 7.7 Try to solve using Stokes theorem

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • ELECTROMAGNETIC

    FIELDS & WAVES

    EEEB 253

    CHAPTER 8

    BEEE/BEPE

    College of Engineering

  • 93

    Chapter 8: Magnetic forces and magnetic materials

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

    1. Force due to magnetic fields

    2. Magnetic torque and moment

    3. Magnetization

    4. Inductances and inductors

    5. Magnetic energy

    Study the force exerted by the magnetic field on a charged particle, current element

    and loop

    Consider the magnetic field in different material media

  • 948.1: Force due to magnetic field

    3 ways a force can be experienced in a magnetic field:- 1) moving charged particle in a B field; 2) current element in an external Bfield; 3) between two current element

    Magnetic force experienced by a charge Q moving with a velocity uin a magnetic field B ; Fm perpendicular to u and B

    Fm cannot perform work as it is normal to the velocity For a moving charge in E and B fields Lorentz force

    equation; With a mass m, Force on a current element current = flow of many charges for a closed path L, Note:- the B field produced by the current element does not exert

    magnetic force on itselfKer Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 958.1: Force due to magnetic field

    Example 8.3

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 968.2: Magnetic torque and moment

    Very important to understand the concept of a current loop experiencing a torque in a magnetic field in order to understand d.c. motors and generators

    The torque on a loop is the vector product of the force and the moment arm ,r , unit N.m

    A rectangular loop with length l and width w Under a uniform B field Along sides 12 and 34: dl parallel to B; Fm = 0 Therefore, , but both forces acting at different point If the normal to the plane makes an angle with B,

    or Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 978.2: Magnetic torque and moment

    The magnetic dipole moment:- is the product of the current and area of the loop in the direction normal to the loop

    Hence, from When do we get maximum torque? When will it be minimum? Example 8.5

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 988.3: Magnetization

    Magnetization, M in amperes/meter (A/m) is the magnetic dipole moment per unit volume

    Without an external B field, the sum of magnetic moments is zero due to random orientation; when Bfield is applied, the magnetic moments of the electrons align themselves with B

    A material is said to be magnetized if M is not zero Bound volume current density or magnetization volume

    current density Bound surface current density , is the unit

    vector normal to the surface , M depends linearly on H such that

    where is the magnetic susceptibility - dimensionless Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 998.3: Magnetization

    Hence,

    is the permeability of the material in Henrys/m (H/m) is the relative permeability

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 1008.4: Inductances and inductors

    Circuit carrying current I magnetic field B causes flux With N identical turns, flux linkages Flux linkages is proportional to the current L is the proportionality constant, called Inductance Circuit that has inductance is called inductor Inductance=ratio of magnetic flux linkage to current Unit Henry (H): 1H = 1Wb/A Usually called self-inductance since the flux linkages are produced

    by the circuit itself Capacitance measure of how much electric energy stored;

    Inductance measure of how much magnetic energy storedKer Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 1018.4: Inductances and inductors

    Magnetic energy stored in an inductor or Typical examples of inductor toroids, solenoids, coaxial

    transmission line; parallel-wire transmission line To find the self-inductance:-

    In an inductor such as coaxial or parallel wire transmission lines, inductance produced by the flux internal to the conductor is called the internal inductance; inductance produced by flux external to it is called the external inductance

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 1028.5: Magnetic energy

    To express the magnetic energy in terms of B and H

    Example 8.11

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 1038.5: Magnetic energy

    Example 8.11 What about L/length??

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • ELECTROMAGNETIC

    FIELDS & WAVES

    EEEB 253

    CHAPTER 9

    BEEE/BEPE

    College of Engineering

  • 105Chapter 9: Maxwells equation

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

    1. Faradays law

    2. Transformer emf

    3. Motional emf

    Stationary charge electrostatic fields; Steady currents magnetostatic fields

    Time-varying current Electromagnetic fields (and waves)

    2 major concepts electromotive force based on Faradays experiment;

    displacement current resulted from Maxwells hypothesis

    Maxwells equations:- summarize the laws of electromagnetism

  • 1069.1: Faradays law

    1831, Faraday and Henry discovered that a time-varying magnetic field would produce an electric current

    Static field no current; time-varying field produce an induced voltage (called the electromotive force, emf)

    Faradays law:-

    Lenzs law: the ve signthe induced emf acts in such a way that opposes the flux producing it; or the induced magnetic field by the induced current will oppose the original field

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 1079.2: Transformer emf

    Consider a single turn (N=1) circuit, In terms of E and B, , flux is replaced by

    where S is the surface area enclosed by the closed path L 3 ways to cause the variation of flux with time:-

    Stationary loop in a time-varying B field Time-varying loop area in a static B field Time-varying loop area in a time-varying B field

    1st case: , emf is induced by a time-varying current (producing a time-varying B field) Transformer emf

    Applying Stokes theorem, Maxwells eqn. for time-varying field;

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 1089.3: Motional emf

    2nd case: moving loop in static B field; Recall:-force exerted on a charge moving at a velocity in a B field

    Define the motional electric field Emf induced called the motional emf Type of emf found in motors and generators Example: voltage is generated when the coil

    rotates within the magnetic field Rod moving between a pair of rails Perpendicular,

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 1099.3: Motional emf

    Be careful when using

    Example 9.1

    Transformer emf

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 1109.3: Motional emf

    Continue Eg. 9.1 Motional emf

    It is easier to use

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 1119.3: Motional emf

    Problem 9.6

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power

  • 1129.3: Motional emf

    Problem 9.11

    Ker Pin Jern Universiti Tenaga Nasional, College of Engineering, Dept. of Electrical Power