EEE121 Lecture 10 (1)
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Transcript of EEE121 Lecture 10 (1)
7/21/2019 EEE121 Lecture 10 (1)
http://slidepdf.com/reader/full/eee121-lecture-10-1 1/20
Previous Lecture Parallel Circuits
• Resistors in Parallel
• Voltage in a Parallel Circuit
• Kirchhof's Current Law
• Total Parallel Resistance
• Application o Ohm's Law
• Current Sources in Parallel
• Current Dii!ers• Power in Parallel Circuits
• Parallel Circuit Applications
7/21/2019 EEE121 Lecture 10 (1)
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Problems Solving_ParallelCircuits
Problem related to Resistors inParallel
"#$ Show how to connect the resistors in the
ollowing %igure in parallel across the &atter#
Lecture
10
7/21/2019 EEE121 Lecture 10 (1)
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Problem related to Voltage ina Parallel Circuit
"#$ (hat is the oltage across an! the currentthrough each parallel resistor i the total oltageis $) V an! the total resistance is **+,- Thereare our resistors. all o e/ual alue#
)$#0 mA. *#1* mA. )#)+K
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Problems related to Kirchhof'sCurrent Law
"#$ There is a total o *++ mA o current into 2eparallel resistors# The currents through our o theresistors are *+ mA. $*+ mA. )* mA. an! $++ mA#(hat is the current through the 2th resistor-
$3* mA
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"#) 4n the circuit o ollowing %igure. !etermine theresistance R) .R5 . an! R1 #
13 mV. )) 6. $++ 6. $#1) mA. 5
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"#5 The electrical circuit in a room has a ceilinglamp that !raws $#)* A an! our wall outlets# Twota&le lamps that each !raw +#055 A are plugge!into two outlets. an! an electric heater that !raws
$OA is connecte! to the thir! outlet# (hen all othese items are in use. how much current is in themain line sering the room- 4 the main line isprotecte! & a $* A circuit &rea7er. how much
current can &e !rawn rom the ourth outlet-Draw a schematic o this wiring#
$)#8) A. )#+0
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"#1 The total resistance o a parallel circuit is)*,# (hat is the current through a ))+, resistorthat ma7es up part o the parallel circuit i the totalcurrent is $++ mA-
)#* V. $$#1 m
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Problems related to TotalParallel Resistance
"#$ (hat is the total resistance o twele 9#07,resistors in parallel-
*93 6
! ! i th ll i %i th ll i
7/21/2019 EEE121 Lecture 10 (1)
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an! groun! in the ollowing %igure or the ollowingcon!itions-:a; S(4 an! S() open :&; S(4 close!# S()open
:c; S(4 open. S() close! :!; S(4 an! S()close!
*$+ 76. )1* 76. *$+ 76. $85
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Problems related toAlication o! "hm's Law
"#$ %our e/ual<alue resistors are connecte! inparallel# %ie olts are applie! across the parallelcircuit. an! $#$$ mA are measure! rom thesource# (hat is the alue o each resistor-
1#* 76. $0 7
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"#) %in! the alues o the unspeci2e! la&ele!/uantities in the ollowing circuit#
*+ mA. $++ 6. )++
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"#5 %in! the alues o the unspeci2e! la&ele!/uantities in the ollowing circuit#
45=$++ mA. 4)=$13 mA.4$=)*5 mA. R$=58*
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"#1 To what minimum alue can the $++,rheostat in the ollowing %igure &e a!>uste! &eorethe +#* A use &lows-
4$=#))A. 4)=#)0A. R)= *5#
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"#* %in! the alues o the unspeci2e! /uantitiesin the ollowing %igure#
45=05#5 mA. 4)=$99#3 mA. 4 T=5++ mA. R$=) 76. R)=
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Problem related to CurrentSources in Parallel
"#$ Determine the current through RL in each
circuit in the ollowing %igure#
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Problems related to Current#ividers
"#$ Determine the current in each &ranch o thecurrent !ii!ers o ollowing %igure#
9#00 ?A. 5#$) ?A *)* 6. *#)* mA. )#58 mA. $#*8 mA. +#3
" ) (hat is the current through each resistor in
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"#) (hat is the current through each resistor inthe ollowing %igure- R is the lowest<alue resistoran! all others are multiples o that alue asin!icate!#
+#10R, 1#0 mA. )#1 mA. $#*8 mA. $#)
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"#5 Determine all o the resistor alues in theollowing %igure# RT = 335,#
335 6. )#$1 mA. 5#5 76. $#0 76. *#9 76. 5#
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Problems related to Power inParallel Circuits
"#$ %in! the alues o the unspeci2e! /uantities inthe ollowing %igure#
P$=$#)* (. Vs=$+ V. 4)= 3* mA. R)= $55 6. 4$=$)* mA.R$=
i t Th t t l i t i $ + 7, ! th t t l
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resistors# The total resistance is $#+ 7,. an! the totalcurrent is *+ mA# 4 each resistor is operating at one<halits maimum power leel. !etermine the ollowingB:a; The num&er o resistors :&; The alue o
each resistor:c; The current in each &ranch :!; The applie!oltage
•
:a;) * ( $+ :&; $+ 76 :c;* mA :!;*