E{ectricat jvt&cfrines - ECED Mansoura · PDF file01-05-2014 · e.m.f. between slip...
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Transcript of E{ectricat jvt&cfrines - ECED Mansoura · PDF file01-05-2014 · e.m.f. between slip...
![Page 1: E{ectricat jvt&cfrines - ECED Mansoura · PDF file01-05-2014 · e.m.f. between slip rings is 100 V. find the rotor current per phase and power factor assuming the slip rings are short-circuited.](https://reader031.fdocuments.in/reader031/viewer/2022030405/5a7df6a27f8b9a2e358df33b/html5/thumbnails/1.jpg)
---l
E{ectricat jvt&cfrines
I
fftr e e -? fias e Induciion
SYlotors
?art (t)
mffiHs-ffi0f 0{2045000 . 0101I04$$$$
![Page 2: E{ectricat jvt&cfrines - ECED Mansoura · PDF file01-05-2014 · e.m.f. between slip rings is 100 V. find the rotor current per phase and power factor assuming the slip rings are short-circuited.](https://reader031.fdocuments.in/reader031/viewer/2022030405/5a7df6a27f8b9a2e358df33b/html5/thumbnails/2.jpg)
Examole (l)
A 6-pole, 3-phase indu"tion ryg!* i-u_-.,g -. 4 lq Hz supply. If it is running at 970 t'P'ffi',
findthesrip iu H ffi s- ffiExamole (2) 0t01 2015000 . $t $t 104[000
A 3-phase induction motor is wound for 4-poles and is supplied from 50 Hz system. Calculate (i)
the synchronous speed, (ii) the speed of the motor when the slip is 4Yo, and (iii) the rotor current
frequency when the motor runs at 600 r'p'm'I
Examole (3)
A 6-pole alternator is running at 1000 r.p.m. and supplies an 8-pole induction motor. Find the
actual speed of the motor if the slip is 25%'
Examole (4)
A 50 !Iz, 4-pote, 3-phase induction motor has a rotor current of frequency 2l1z' Determine (i)
the slip, and (ii) the speed of the motor'
Examole (5)
A 3-phase, 6-pole induction motor is connected to a60Hzsupply. The voltage induced in the
rotor bars is 4 v when ttre rotor i1y rt*rastill. calculate the.voltage and frequency induced in
the rotor bars at 300 r.P.m.J
Examnle (6)
A 3-phase supply, 400 V wound rotor motor has detta-connected stator-winding and star-
connected rotor-winding.'The stator has 48 tums per phase while the rotor has24 turns per
phase. Find the standstill or open-circuited voltage across the slip rings.
Example (7)
A 6-pole, 3-phase, 50 Hz induction motor is running at full-load with a slip of 4%' The rotor is
star-connected and its resistance and standstill reactanie are 0.25 Q and 1.5 Q per phase' The
![Page 3: E{ectricat jvt&cfrines - ECED Mansoura · PDF file01-05-2014 · e.m.f. between slip rings is 100 V. find the rotor current per phase and power factor assuming the slip rings are short-circuited.](https://reader031.fdocuments.in/reader031/viewer/2022030405/5a7df6a27f8b9a2e358df33b/html5/thumbnails/3.jpg)
_\
e.m.f. between slip rings is 100 V. find the rotor current per phase and power factor assuming
the slip rings are short-circuited.
Examole (8)
A 4-pole, 3-phase, 50 Hz induction motor has a star-connected rotor. The rotor has a resistance
of 0.1 C) per phase and standstill reactance of 2 Q per phase. The induced e.m.f. between the slip
rings is 100 V. if the full-load speed is 1460 r.p.ffi., calculate (i) the slip, (ii) the e.m.f. induced inthe rotor in each phase, (iii) the rotor reactance per phase, (iv) the rotor current, and (v) the,rotor
power factor. Assume slip rings are short-circuited.I
Example (9)
A 150 kW, 3000 V, 50 Hz, 6-pole star-connected induction motor has a star-connected slip ring
rotoi with a transformation ratio of 3.6 (stator / rotor). The rotor resistance is 0.1 Cl per phase
and its per phase leakage inductance is 3.61 mH. The stator impedance may be neglected. Find
the starting current on rated voltage with short-circuited slip rings.
Example (10)
A 3-phase siip ring motor gives a reading of 55 V across slip rings on open circuit when at
standstill with normal stator voltage applied. The rotor is star-connected and has impedance of(0.7 +3 5) Q per phase. Find the rotor current and power factor when the machine is (i) at
standstill with slip rings joined t6"a star-conn'ected starter with a phase impedance of (4 + j 3) O,
and (ii) when running normally with a 5% slip. :i
L L \-,'^c
B. " ol
Yo.' 5
f tllTrn {5
a
smffieffi[t ottoltooo' otot2o4$ooo
tr
![Page 4: E{ectricat jvt&cfrines - ECED Mansoura · PDF file01-05-2014 · e.m.f. between slip rings is 100 V. find the rotor current per phase and power factor assuming the slip rings are short-circuited.](https://reader031.fdocuments.in/reader031/viewer/2022030405/5a7df6a27f8b9a2e358df33b/html5/thumbnails/4.jpg)
Three Phase lnduction Motors
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Dis oJ.!*f"3*"f7
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' ( .,t.c. :1"^^t /{otor) Jl ^r'&1 rJ\ (s :,
+ - l.Lon5 Lr(lCLt o1r1
^r p-)l dlU
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tt-,tu, .{-rt ti\L\, -n't\ ^r it--r---,,-F* rg-
t$/"bt) 67l.--gt o/l n,;ff-
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![Page 5: E{ectricat jvt&cfrines - ECED Mansoura · PDF file01-05-2014 · e.m.f. between slip rings is 100 V. find the rotor current per phase and power factor assuming the slip rings are short-circuited.](https://reader031.fdocuments.in/reader031/viewer/2022030405/5a7df6a27f8b9a2e358df33b/html5/thumbnails/5.jpg)
Ttrree Fhase [nciuction lviotors
St",iorSTATOBwiNolNG
Wound r,vpe
-/"-r---/
d Wirxlho
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->r--W.rV
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-/-,& ,- '94\ \ -,FL OUll o -^-sD \a.^i
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RL.r
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MYo tof
Squiuel cage x
l"ll.-i
![Page 6: E{ectricat jvt&cfrines - ECED Mansoura · PDF file01-05-2014 · e.m.f. between slip rings is 100 V. find the rotor current per phase and power factor assuming the slip rings are short-circuited.](https://reader031.fdocuments.in/reader031/viewer/2022030405/5a7df6a27f8b9a2e358df33b/html5/thumbnails/6.jpg)
Three Phase induotion fulotors
: fotor JJ :4 2- 3.u,D
i') Silurr<-[ Qe t:p<Srllttr'rre ( {at14 "/*/*
W; ,Ett * ut -*;1,- -f -,\r)\ rd\ =-)\ - -
iL )
JrA-
Waund lyp"( 5t*tor) J\ g dU\rotf cs_tljl (; n-) yr; eGt_ GL-
' (Y - jt",r-) Lg* drrJ GJ(\ o--6>
(fb r-*,-gs) ,,sDtl O(Jf uGJ(l U\) i 4a;LtL d/\ ,u)-_r, Ns---d dd i;At? J{-,G- <l*:, -A
,l
( rh,eo:tot-) I-otor J\ aj\,
f?otC,15 Xgnel.ic [eU. d.ue to3- (PLose
fLt-u/ffeltU-S
;bL : 5t.J"r. J\ c-,Gf- ,f ,-4 1., ,U
mffiffi&trfr01012045000 . 01012040000
,r r l"t*__t ,Ln-
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.-l I s\,'-rl-r J-L
![Page 7: E{ectricat jvt&cfrines - ECED Mansoura · PDF file01-05-2014 · e.m.f. between slip rings is 100 V. find the rotor current per phase and power factor assuming the slip rings are short-circuited.](https://reader031.fdocuments.in/reader031/viewer/2022030405/5a7df6a27f8b9a2e358df33b/html5/thumbnails/7.jpg)
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Three Phase lnduction Motors
'uLf f*q,4 ov,6,1^n
.o-
, in u.)t,
Sin (tot -lzo") fiffiH&IUT0l 0t 20450u0 ' 0l 0{ 2040000
CSJltJ
qtrr/Yn
)
Fs)x
€ )7
,(+4")
? - of u'.lt = 3o
r\.-F\-J
€.., x
.G-l-lJ
cOr7 = € Sin (urt + l?o")I rrr
44 -t)-- ,L. iry ,{C\9) o r>\ d*}t db\ ipfJ
( + €") cP 4'3)*\tl arPt *:ti-r;v -+)oW -u@l it-dt \;-o (r-,/p"g,r)j c_,U])
)-\ - crj.. LL)t = o :c*
=O € ,Yn I
( art = o) " G \ 0 qF"rcr (*l ",f -e
)XCSI Yrr\
i 4l
tq- )
![Page 8: E{ectricat jvt&cfrines - ECED Mansoura · PDF file01-05-2014 · e.m.f. between slip rings is 100 V. find the rotor current per phase and power factor assuming the slip rings are short-circuited.](https://reader031.fdocuments.in/reader031/viewer/2022030405/5a7df6a27f8b9a2e358df33b/html5/thumbnails/8.jpg)
T'i"rree Phasc lnduction Motors
z[qiooo ' otrt2046000
ol'{\+)
s$ffi
tlt = 3e)'
tJJt = 9o*
+*7 L
60'
s,-
tut
rl.lt
:o-J-z
.Ca3s -S\\-. \/I -rY\
![Page 9: E{ectricat jvt&cfrines - ECED Mansoura · PDF file01-05-2014 · e.m.f. between slip rings is 100 V. find the rotor current per phase and power factor assuming the slip rings are short-circuited.](https://reader031.fdocuments.in/reader031/viewer/2022030405/5a7df6a27f8b9a2e358df33b/html5/thumbnails/9.jpg)
- _\
Three Phase Induction Motors
rut 3o
(^)tT
t,- lr.f0'
*-*r',-
r..tt- '.;h'{t*
Y F "'t' €!ts'
. ^.1^Y..,.ftous Spee.l
ol20 )
Dt- S- tr[*o s*PPb P-yn"^g , f Az7
,G ] (? -/);\> P,;*,_
Njt [r P,ml
Qt"s .
'*\;tt
"AJr" 1^-)il+J I J
l
na "-f flof-or
t 6 t
![Page 10: E{ectricat jvt&cfrines - ECED Mansoura · PDF file01-05-2014 · e.m.f. between slip rings is 100 V. find the rotor current per phase and power factor assuming the slip rings are short-circuited.](https://reader031.fdocuments.in/reader031/viewer/2022030405/5a7df6a27f8b9a2e358df33b/html5/thumbnails/10.jpg)
Tirree Phasc lnduction Motors
C-0,, ,? -,:)1 f C 6/ d# I *\.r-, " G I C).-(4 Vru+; qf ,
C tternnte tlolhe m^l"c-,( {t"'bsis Po"
f,?,t"l,y tuy"i,c freld
€
d)z€,Z
9,
{z
9'.,= Gs
Gs
6trn
3o
5o
rl-sL
in niL(lJL
L
Gs
/in ,nYGs \zci +
+ ;in *t /' tz'i
5(n tZ.; ]
€r1wts+ C-rt
(9,v
--1--n Sin ult t. €_-...L
G!t)L
€,- 6in of -ts +*
-3
r{ Sin ( t-.rt + t Zd) +t-
"r -J o
Sin (,rrt - n;) J Sin 3o
.--G--1.", --sI yr\
5in
l7l
(- sin -t )
![Page 11: E{ectricat jvt&cfrines - ECED Mansoura · PDF file01-05-2014 · e.m.f. between slip rings is 100 V. find the rotor current per phase and power factor assuming the slip rings are short-circuited.](https://reader031.fdocuments.in/reader031/viewer/2022030405/5a7df6a27f8b9a2e358df33b/html5/thumbnails/11.jpg)
Three Phasc lnduotion Motors
.l
3
^-t.\Lr \ /-'1-C, +(-\,/p1 'V
€ ,n.lI -'-.'z
a/ Cos urt- + (- Sin -t)'
O'l rinCup l,e BRHAilTfi0t 0{ 2045000 . 0t 0t 2046000"4 o@
-;,e- -=
-.^FJ\ */! ^r\,-Jt ,A, q ,\,. c)Gdt Jr,. _l
\-rl dJf J-q. St*tor Jl ui;J_
* "C 1rt1 rotnr -J I crUf- ,LA -^j(- - .-V I -";"|,ll d;\ l:-a-rzot
y^otor J\ .-,GJ-1;t u.^ ?. );; dbL_ ,f,-*i ,,_*,
dLrl, G {,artr"..,} -+ ro tof J\ a -?\-, - \ "t; - 3_d
J
Jl O Y^e:-rJL )4c1JJl '-a l--^--' -4
,G\c (rotor) Jl "'-t-!'Y.-=
()A d;\ ,, -/EJJ 4-V b/!cbt o.-D rk -o3-> tr--,-
-t
-L,l € P6to r
", )r.t
t\; tt:
d#.\
i 8l
![Page 12: E{ectricat jvt&cfrines - ECED Mansoura · PDF file01-05-2014 · e.m.f. between slip rings is 100 V. find the rotor current per phase and power factor assuming the slip rings are short-circuited.](https://reader031.fdocuments.in/reader031/viewer/2022030405/5a7df6a27f8b9a2e358df33b/html5/thumbnails/12.jpg)
-I'hrco Phocp Inrlr rnfinn I\lntorcl lll vv r lrguv lllvuvLrv^. , ' ^-.-^ J
ffiffiffi&ffi0t 0t 2045000 . 0t 01 2046000
ROTATION OF STATOR FIELD
/t)I
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GL roto r"G] q-; -ul)"
-t; -t -
)\ -:
Sl^p t_: Dy)l
rotor )\c)*:- e ,? Ot--o -{;i U,i.o[af J ! t]+f d ;uL=- e.rn P :3cs <J_
1ep ^a^/l e t-:J'{+t QJt-o * {-t .-- e."n.P J\ tj ,s,-,l^otor S\ t--DLi_:_ ,A. &; (\_^r_" eJLo *{
(o'l-- 3or S)'l
?J^.I.d rot,i;5 ,^ rg^J;. P,.r"t sp"*l
yD, U )* ut' ",3J -J
U !. t'' '" tl JL: ''ll \ -A--,a-
dt+1 b'bb'
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lel
![Page 13: E{ectricat jvt&cfrines - ECED Mansoura · PDF file01-05-2014 · e.m.f. between slip rings is 100 V. find the rotor current per phase and power factor assuming the slip rings are short-circuited.](https://reader031.fdocuments.in/reader031/viewer/2022030405/5a7df6a27f8b9a2e358df33b/html5/thumbnails/13.jpg)
Three Phase induction Motors
Q, trr Currerrt- _IZl-.n3
NS_AJD'
)?o I
,tr st"^clstt |.L
NsNN,
---_---_>.
,P.
\?O PSN. a
D,, I7?<.?D=
S = I -- P'=f
= 5o HV, N = B7o [.e.rn
N), = lzo P-
rD
-dL'<)o \}.l-Lt Ofn
\ ooo f , P.rn
E*(r ) DREATffi0t0{2045000 . 0{0{2046000
i r11 !I \!-r I
![Page 14: E{ectricat jvt&cfrines - ECED Mansoura · PDF file01-05-2014 · e.m.f. between slip rings is 100 V. find the rotor current per phase and power factor assuming the slip rings are short-circuited.](https://reader031.fdocuments.in/reader031/viewer/2022030405/5a7df6a27f8b9a2e358df33b/html5/thumbnails/14.jpg)
Three Phase lnduction Motors
f)= 4,Fx (zl
L) N5
vlz )
5 = /t'/.t
P=5o
D1zo l
NJ=
o'I
MRffi&HWfi0{0,12045000, 0,l0t2046000
L) AJs
ii) ru
iii) .P'
= ?.?
7?
J_
o-L Prn??
Sot*lion
fi) 6 =,l
o.o4
Li L )
AJs - A,
AJs
l5oo r P'r.n
Nr = I ++o f'P. rn
6oa
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E^ (3)
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Iooo
'7 .-)
r' P. rn l----' *)Stnnn..'t"r
1, \--' ,:- <9 i'^ai- fnOt '
i il 1
![Page 15: E{ectricat jvt&cfrines - ECED Mansoura · PDF file01-05-2014 · e.m.f. between slip rings is 100 V. find the rotor current per phase and power factor assuming the slip rings are short-circuited.](https://reader031.fdocuments.in/reader031/viewer/2022030405/5a7df6a27f8b9a2e358df33b/html5/thumbnails/15.jpg)
Three Phase Induction Motors
rl- t.Q-l,t€r^qlof
s-(P
A/ f) looer rt 6
l7o, \2e,
1?o P
5o Vz
\zo * 5o
Ito ?
[)
I t|- 4- o f 'Q.^rv-'
P
= 7 so r. P.rn
at',)oA
//N)s - ft)
2q.;
?7)
HZ /
77= 5o
c') S =
Ns* Nl
AJrN, = 731 . ?.5 r. P.nt
= 4 ) P' d7.
ia ) /\i
E^ (4)
.'=
,-)
4 "/"
- .-l^*[i ^Ns
/\r =
6,^pp! ft% F
5-+ ,."^A. rr,ot. AJs
SJ
0{012045000 . 0{0t2046000
Ns-____9
I tz 1
15oo r'P.rn
![Page 16: E{ectricat jvt&cfrines - ECED Mansoura · PDF file01-05-2014 · e.m.f. between slip rings is 100 V. find the rotor current per phase and power factor assuming the slip rings are short-circuited.](https://reader031.fdocuments.in/reader031/viewer/2022030405/5a7df6a27f8b9a2e358df33b/html5/thumbnails/16.jpg)
\
Three Phase Induction Motors
E f F.&- 4 stP on the Rto, e."a-..r
Etondsti(l S = I P' PrIrL-7 e ,^.P. P<,r pLSe
rea1to,.6p lDen p\oSe
"t st-fr s<t P'= Er
Cr-oh.z t-otol- e.- .-F. kr pLse ,
: S X. : ro to t- reacto^( e {-&,r pL.a.s< .
J.ro Lor
I-otor
t_l-z
x;'
mffiffi&rkT0{0{2045000 . 0t0t2046000
E" (s)
l-FL-L
oo
?)
6,??
Hz) E.=4vJt_l-
o-L AJ = 3oo r?ln
\2o P
S"{*Iiw\
\ ?oof\J s (rI rr I
r, P. rn
![Page 17: E{ectricat jvt&cfrines - ECED Mansoura · PDF file01-05-2014 · e.m.f. between slip rings is 100 V. find the rotor current per phase and power factor assuming the slip rings are short-circuited.](https://reader031.fdocuments.in/reader031/viewer/2022030405/5a7df6a27f8b9a2e358df33b/html5/thumbnails/17.jpg)
.\
Three Phase lnduction Motors
ffi| *"'i, 1j'd,,
34Sunoly .-__t-,L..\}' 4'," \,14,\
# Stfir Iwincino l
,\i'
,r"'t nt
s E,'to,l I
."'-L:---i,A{ ?to
ghori€irtUtGJRotor Winding
,f St.clstiL( ri*t^t**-\c)-lq(-..+ L ?"(,)
"t runrull
-Jt( 8r
--,.)Ns-N_
Ns
-
14
= .i> C.
= sr
= o,75
F.L-z
P'
3
A-5
\o(i
A7 Itttt'
*(P' , X, ,
* (f?., , *., ,
p<r PLr^se7,, Er)
7. , E-)
L-. tL-e :t.to-r
.,., Pgtof
5t**15 titt '|et
7), tt.uditL
R/r pL..l< rotc,1-
,t- twnNr!
(,/v\* (R,, E;)
tr+ l
s t+ "s''
![Page 18: E{ectricat jvt&cfrines - ECED Mansoura · PDF file01-05-2014 · e.m.f. between slip rings is 100 V. find the rotor current per phase and power factor assuming the slip rings are short-circuited.](https://reader031.fdocuments.in/reader031/viewer/2022030405/5a7df6a27f8b9a2e358df33b/html5/thumbnails/18.jpg)
Thnee Phasc Induction Motors
5t",^Asti I
Y-ot or G,-rre,^t [:er PV.^se . T- .
rotor P. P. (F)7
R,
--(2
,?t
6t Yu^rt,y of SLp 'S "
Yator Ctxryrev^t. , T-. =
Ibtor P,F. Co, +- =R.
1,
F. EL1
ot P,'Gt
/='t-2
--t-L2_
5E-.
E* (6)
Tlt|tr. t *.I
N.(R.tor
-Er-<
t15r
![Page 19: E{ectricat jvt&cfrines - ECED Mansoura · PDF file01-05-2014 · e.m.f. between slip rings is 100 V. find the rotor current per phase and power factor assuming the slip rings are short-circuited.](https://reader031.fdocuments.in/reader031/viewer/2022030405/5a7df6a27f8b9a2e358df33b/html5/thumbnails/19.jpg)
Three Phase lnduction Motors
a/v,
{- = \f--L
G- (oc, J'rCzU^e
P=
-tL
-:'
\-Dz
X,'
'f)-z
.a+ x;
o,o4 ,( \oca
Fo. o + r( 1.5 =
=48 fu? = 74
- I L,
) 6-^"1^f t O1r1.
t_Lz Z oo V"Li
E^ (7) DME&ffi0,1012045000 . 0{012046000
E, = 4oo
6)
o,2 5
I,.
V"(t , N,
?tr U'oe
G+B
E 1L+ v*j.t
()=
R.
S"J^Jiorn
? 3l
o,o 6
\ "tt.-rL_
f(- z
9A{
5e Hz , g = 4'/. ) Y- G".*<f-rA rotor,
Xr = 1- 5 n ./ E.r"-. = loo \J*ti',
p. P^+
cr^. fwr',nt-g G^"L+i-n
SE.
S*.
ftSl
![Page 20: E{ectricat jvt&cfrines - ECED Mansoura · PDF file01-05-2014 · e.m.f. between slip rings is 100 V. find the rotor current per phase and power factor assuming the slip rings are short-circuited.](https://reader031.fdocuments.in/reader031/viewer/2022030405/5a7df6a27f8b9a2e358df33b/html5/thumbnails/20.jpg)
Three Phase Induction Motors
G'C= o,37 t,3R,-' * X.''
E.^(s)
=+
N: 1460
L') 5 =??
l?o P
O)f 5o H? .,
X. =
,Y- G,-^ecteJ
75L,-J?_
.|-.O rn
ii ) Liil x; 2
q- aT?U)
,
G.
--a5o
AJs()
+-tt
Ns- N\ +c) "/,
n/'Ar-
ilr^tisr,lI 5oo r,p. rn
N( ? 66
Ioo.F r. s4 V.{i
: o,ot66 J( ?-
J-t'b \oy )
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Three Phase lnduction Motcrs
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Three Phase Induction Motors
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Three Phase Induction Motors
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