Three Other Types of Counters (BCD Counter, Ring Counter, Johnson Counter)
EE457x5 P1 loop counter temp · 2018. 8. 20. · 1 Traffic Light Problem to practice counter...
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Transcript of EE457x5 P1 loop counter temp · 2018. 8. 20. · 1 Traffic Light Problem to practice counter...
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ee102_midterm1_Sp2005.fm
4/1/05 EE102L Midterm #1 - Spring 2005 4 / 8 C Copyright 2005 Gandhi Puvvada
4 ( 30 points) 20 min. Loop Counter incrementation and checking:
States: I = Initial; DA = Double A; DB = Double B;DAB = Double A as well as B;
The five diagrams on the side are similar. Pay attention to when I is incremented and when the NSL looks at I, possible rollover by counter, etc.
For each diagram, answer the following four questions:1. How many times A gets doubled? 2. How many times B gets doubled?3. Any state transition arrows that are NEVER taken?4. What is the value of I when you are in DONE state?
State Diagram #1 1. A gets doubled ___ times. 2. B gets doubled ___ times. 3. 4. I =
State Diagram #2 1. A gets doubled ___ times. 2. B gets doubled ___ times. 3. 4. I =
State Diagram #3 1. A gets doubled ___ times. 2. B gets doubled ___ times. 3. 4. I =
State Diagram #4 1. A gets doubled ___ times. 2. B gets doubled ___ times. 3. 4. I =
State Diagram #5 1. A gets doubled ___ times. 2. B gets doubled ___ times. 3. 4. I =
IA<=Ain;B<=Bin;I<= 0;
RESETS
S
I = 2I = 3
I = 2
I = 3
D
DA DBA<=2*A; B<=2*B;I<=I+1;
ACK
ACK
State Diagram #1
IA<=Ain;B<=Bin;I<= 0;
RESETS
S
I = 3I = 2
I = 3
I = 2
D
DA DBA<=2*A; B<=2*B;
I<=I+1;
ACK
ACK
State Diagram #2
IA<=Ain;B<=Bin;I<= 0;
RESETS
1
I = 3
I = 3
D
DA DBA<=2*A; B<=2*B;I<=I+1;
ACK
ACK
State Diagram #3
IA<=Ain;B<=Bin;I<= 0;
RESETS
S
I = 2
I = 2
D
DA DBA<=2*A; B<=2*B;I<=I+1;
ACK
ACK
State Diagram #4
S
1
IA<=Ain;B<=Bin;I<= 0;
RESETS
S
I = 2
I = 2
D
DABA<=2*A;B<=2*B;I<=I+1;
ACK
ACK
State Diagram #5
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February 13, 2017 8:24 am C Copyright 2017 Gandhi Puvvada
1 Traffic Light Problem to practice counter initialization, incrementing or decrementing, and terminal value checking
1.1 HW#7 problem
1.2 EE254L Fall 2015 Final Question: A single 5-bit up/down counter is used in the state machine on the side to control the Jefferson/Vermont lights (Green and Yellow). It start with I == 0 in JG. The clock frequency is 1c/s. Find the number of seconds for each of the four light together with the range of values of the counter in that light.JG: 30 sec. Irange = [00:29]JY: __ sec. I range = [__:__] VG: __ sec. I range = [__:__] VY: __ sec. I range = [__:__]
1.2.1 Redesign the above traffic light controller with an up-only counter and a down-only counter, both starting with (I==0) in JG state.We want the same number of clocks (seconds) spent in each of the 4 states:
A
B
C
D
ENP ENT
EGC
GC
LOAD CLR
QA
QB
QC
QD
RCOCK
VCC
MAX-JG
MAX-VG
~C_CLR
74LS163A
A
B
C
D
ENP ENT
EYC
YC
LOAD CLR
QA
QB
QC
QD
RCOCK
VCC
MAX-JY
MAX-VY
~C_CLR
74LS163A
JYJG
VY VG
RESETif I==26I <= I +1;
(I=29)
(I=29)I <= 10;
else I<= I -1;
I <= I -1;
(I=26)
(I=26)
(I=0)
(I=0)
if I==26I <= 0;
else I< =I -1;
(I=26)(I=26)
JYJG
VY VG
RESETJYJG
VY VG
RESET
JG: 30 sec. I range = [00 : ]JY: 5 sec. I range = [__ : __] VG: 11 sec. I range = [__ : __] VY: 6 sec. I range = [__ : __]
JG: 30 sec. I range = [00 : ]JY: 5 sec. I range = [__ : __] VG: 11 sec. I range = [__ : __] VY: 6 sec. I range = [__ : __]
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February 13, 2017 8:24 am C Copyright 2017 Gandhi Puvvada
1 Traffic Light Problem to practice counter initialization, incrementing or decrementing, and terminal value checking
1.1 HW#7 problem
1.2 EE254L Fall 2015 Final Question: A single 5-bit up/down counter is used in the state machine on the side to control the Jefferson/Vermont lights (Green and Yellow). It start with I == 0 in JG. The clock frequency is 1c/s. Find the number of seconds for each of the four light together with the range of values of the counter in that light.JG: 30 sec. Irange = [00:29]JY: __ sec. I range = [__:__] VG: __ sec. I range = [__:__] VY: __ sec. I range = [__:__]
1.2.1 Redesign the above traffic light controller with an up-only counter and a down-only counter, both starting with (I==0) in JG state.We want the same number of clocks (seconds) spent in each of the 4 states:
A
B
C
D
ENP ENT
EGC
GC
LOAD CLR
QA
QB
QC
QD
RCOCK
VCC
MAX-JG
MAX-VG
~C_CLR
74LS163A
A
B
C
D
ENP ENT
EYC
YC
LOAD CLR
QA
QB
QC
QD
RCOCK
VCC
MAX-JY
MAX-VY
~C_CLR
74LS163A
JYJG
VY VG
RESETif I==26I <= I +1;
(I=29)
(I=29)I <= 10;
else I<= I -1;
I <= I -1;
(I=26)
(I=26)
(I=0)
(I=0)
if I==26I <= 0;
else I< =I -1;
(I=26)(I=26)
JYJG
VY VG
RESETJYJG
VY VG
RESET
JG: 30 sec. I range = [00 : ]JY: 5 sec. I range = [__ : __] VG: 11 sec. I range = [__ : __] VY: 6 sec. I range = [__ : __]
JG: 30 sec. I range = [00 : ]JY: 5 sec. I range = [__ : __] VG: 11 sec. I range = [__ : __] VY: 6 sec. I range = [__ : __]
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