EDXChemAS_008140
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Transcript of EDXChemAS_008140
7/30/2019 EDXChemAS_008140
http://slidepdf.com/reader/full/edxchemas008140 1/1
Answers15 Alcohols and halogenoalkanes
The preparation of 1-bromobutane from butan-1-ol
1 a) Possible hazards: sulfuric acid is
corrosive; the bromine which forms
during the reaction is corrosive and
toxic; butan-1-ol is a flammableliquid; heating a liquid in a small
flask can lead to bumping; pressure
can build up in a tap funnel when
gases are evolved.
b) Wear eye protection. Carry out the
heating under reflux in a fume
cupboard. Heat with an electrical
heater instead of a flame. Release
the pressure in the tap funnel by
inverting it and opening the tap fromtime to time.
2 NaBr(s) + H2SO4(l) → NaHSO4(s) +
HBr(g)
3 Concentrated sulfuric acid rapidly
oxidises bromide ions or hydrogen
bromide to bromine (see Section 11.8
in the Student’s Book).
4 Possible explanations: the reaction is
slow and more time is needed for it to
go to completion; some of the butan-1-ol forms by-products.
5 The reflux condenser prevents the loss
of volatile liquids from the reaction
mixture during heating.
6 1-bromobutane, unchanged butan-1-ol
and hydrogen bromide are volatile;
they distil over. The two ionic salts are
involatile and remain in the flask.
7 1-bromobutane does not mix with
water. 8 Hydrochloric acid is an acid which can
transfer a hydrogen ion to the −OH
group in the alcohol
turning it into −OH2+. In this ionic form,
the compound is more soluble in water.
9 Aqueous sodium hydrogencarbonate is
a weak alkali that neutralises acidswithout hydrolysing the product.
Sodium hydroxide is a strong alkali
which tends to hydrolyse
halogenoalkanes.
10 Fractional distillation separates liquids
according to their boiling
temperatures. Each fraction contains
the compounds that distil over in a
narrow range of boiling temperatures.
The boiling temperature of the productis 102 °C.
11 1 mol butan-1-ol from 1 mol 1-
bromobutane.
Amount of butan-1-ol =
1
33
cm5.7cmg0.81−
−
×
= 0.08 mol
Theoretical yield of 1-bromobutane
= 0.082 mol × 137 g mol–1 = 11.2 gPercentage yield = g11.2
g8.6 × 100% =
61%
12 There is a variety of explanations:
some unchanged butan-1-ol remains in
this preparation even with an excess of
sodium bromide and concentrated
sulfuric acid; some of the butan-1-ol is
converted to by-products; some of the
product is lost during the process as
the chemicals are mixed, heated,distilled, transferred from one
container to another, washed, dried
and redistilled.
1 of 1
© G. Hill and A. Hunt 2008 Edexcel Chemistry for AS CD-ROM