EC2259 LAB Manual

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    EC2259 Electrical Engineering And Control System Lab Manual

    EC 2259 ELECTRICAL ENGINEERING AND CONTROL SYSTEM LAB 0 0 3 2

    AIM

    To expose the students to the basic operations of electrical machines and help them todevelop experimental skills.

    1. To study the concepts, performance characteristics, time and frequency response oflinear systems.

    2. To study the effects of controllers.

    1. Open circuit and load characteristics of separately excited and self excited D.C.generator.

    2. Load test on D.C. shunt motor.

    3. Swinburnes test and speed control of D.C. shunt motor.

    4. Load test on single phase transformer and open circuit and short circuit test on singlephase transformer

    5. Regulation of three phase alternator by EMF and MMF methods.6. Load test on three phase induction motor.

    7. No load and blocked rotor tests on three phase induction motor (Determination ofequivalent circuit parameters)

    8. Study of D.C. motor and induction motor starters.

    9. Digital simulation of linear systems.

    10.Stability Analysis of Linear system using Mat lab.

    11.Study the effect of P, PI, PID controllers using Mat lab.

    12.Design of Lead and Lag compensator.

    13.Transfer Function of separately excited D.C.Generator.14.Transfer Function of armature and Field Controller D.C.Motor.

    P = 45 Total = 45

    1. Open circuit and load characteristics of separately excited and self excited D.C.

    generator.

    Sl. No. Apparatus Range Quantity1 Motor Generator set - 12 Rheostat 200, 5A

    175, 1.5A

    1

    23 Voltmeter DC 300V

    30V11

    4 Ammeter DC 30A2A

    12

    5 DPST switch 26 Three point starter 17 Tachometer 1

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    2. Load test on D.C. shunt motor.

    Sl. No. Apparatus Range Quantity

    1 DC Motor - 1

    2 Rheostat 175, 1.5A 13 Voltmeter DC 300V 1

    4 Ammeter DC 30A 1

    5 DPST switch 1

    6 Three point starter 1

    7 Tachometer 1

    3. Swinburnes test and speed control of D.C. shunt motor

    Sl. No. Apparatus Range Quantity1 DC Motor - 1

    2 Rheostat 100, 5A & 175, 1.5A 11

    3 Voltmeter DC 300V 1

    4 Ammeter DC 5A2A

    11

    5 DPST switch 1

    6 Tachometer 1

    4. Load test on single-phase transformer and open circuit and short circuit test on

    single-phase transformer.

    Sl. No. Apparatus Range Quantity1 Single phase Transformer - 12 Wattmeter 300V, 5A,UPF & 300V,

    5A,LPF

    1

    13 Voltmeter AC 300V 24 Ammeter AC 5A

    30A11

    5 Single phase auto-transformer 16 Resistive load 1

    5. Regulation of three-phase alternator by EMF and MMF method.

    Sl. No. Apparatus Range Quantity

    1 Motor Alternator set - 1

    2 Rheostat 200, 5A &175, 1.5A 11

    3 Voltmeter DCVoltmeter AC

    300V600V

    11

    4 Ammeter DCAmmeter AC

    2A30A

    11

    5 DPST switchTPST switch

    11

    6 Tachometer 1

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    6. Load test on three phase Induction motor.

    Sl. No. Apparatus Range Quantity1 Three Phase Induction Motor - 12 Wattmeter 600V, 10A,UPF 23 Voltmeter AC 600V 1

    4 Ammeter AC 10A 15 Brake drum arrangement6 Star delta starter 17 Tachometer 1

    7. No load and blocked rotor test on three-phase induction motor (Determination of

    equivalent circuit parameters)

    Sl. No. Apparatus Range Quantity1 Three Phase Induction Motor - 12 Wattmeter 600V, 10A,UPF

    600V, 5A,LPF22

    3 Voltmeter AC 600V150V

    11

    4 Ammeter AC 10A5A

    11

    5 Brake drum arrangement6 Three phase auto-transformer 1

    8. Study of D.C. motor and Induction motor starters.

    Sl. No. Apparatus Quantity1 Three point starter 12 Four point starter 1

    3 Star-delta starter 14 DOL starter 15 Three phase auto-transformer 1

    9. Digital simulation of linear systems.

    Simulink software for minimum 3 users license

    10. Stability analysis of linear system using Mat lab.

    Matlab software for minimum 3 users license

    11. Study of effect of P, PI, PID controllers using Mat lab.

    Matlab software for minimum 3 users license

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    12. Design of lead and lag compensator.

    Sl. No. Apparatus

    1 Resistor

    2 Capacitor

    3 Function generator

    4 Bread Board

    13. Transfer function of separately excited D.C. generator.

    Sl. No. Apparatus Range Quantity1 Motor Generator set - 12 Rheostat 200, 5A

    175, 1.5A12

    3 Voltmeter DC 300V30V

    11

    4 Ammeter DC 30A

    2A

    1

    25 DPST switch 26 Three point starter 17 Tachometer 1

    14. Transfer function of armature and field controller D.C. motor.

    Sl. No. Apparatus Range Quantity1 DC Motor - 12 Rheostat 175, 1.5A 1

    3 Voltmeter DC 300V 14 Ammeter DC 30A 15 DPST switch 16 Three point starter 17 Tachometer 1

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    LOAD TEST ON DC SHUNT MOTOR

    AIM

    To conduct the load test on a given dc shunt motor and draw its performance curves.

    NAME PLATE DETAILS

    FUSE RATING

    125% of rated current (full load current)

    APPRATUS REQUIRED

    S. NONAME OF THE

    APPARATUSTYPE RANGE QUANTITY

    1

    2

    3

    4

    Ammeter

    Voltmeter

    Rheostat

    Tachometer

    MC

    MC

    Wire wound

    Digital

    (0-20A)

    (0-300V)

    250, 2A

    1

    1

    1

    1

    FORMULAE

    1. Torque T = (S1~S2) (R+t/2) 9.81 in N-m.

    Where R- Radius of the Break drum in m.

    t- Thickness of the Belt in m.

    S1,S2- Spring balance reading in Kg.

    2. Input power = VL IL in Watts.

    Where VL Load Voltage in Volts.

    IL- Load current in Amps.

    3. Output power = 2NT/60 in Watts.

    Where N- Speed of the armature in rpm.

    T- Torque in N-m.

    4. Percentage of Efficiency = (Output power/Input power) 100

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    CIRCUIT DIAGRAM FOR LOAD TEST ON DC SHUNT MOTOR

    Model Graph

    (A) Electrical characteristics (B) Mechanical characteristics

    (C) Torque, Speed Vs Load Current

    Fuse

    BRAKE DRUM

    S1 S2

    220VDC SUPPLY

    L F A

    3 POINT STARTER

    D

    P

    S

    T

    S

    250, 2AF

    FF

    M

    A

    AA

    V(0-300V)

    MC

    A

    (0-20A)MC

    Output power in watts

    N

    N in rpm

    ILin Amps

    T in N-m

    %T

    IL %

    Speedinrpm

    Torque in N-m

    Torque Vs Speed

    Speedin

    rpm

    Load Current in Amps

    Speed

    TorqueinN-m

    Torque

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    PRECAUTION

    The motor field rheostat should be kept at minimum resistance position. At the time of starting, the motor should be in no load condition. The motor should be run in anticlockwise direction.

    PROCEDURE

    Connections are given as per the circuit diagram. Using the three-point starter the motor is started to run at the rated speed by adjusting the

    field rheostat if necessary.

    The meter readings are noted at no load condition. By using the Break drum with spring balance arrangement the motor is loaded and the

    corresponding readings are noted up to the rated current.

    After the observation of all the readings the load is released gradually. The motor is switched off by using the DPIC switch.

    GRAPH

    The graphs are drawn as

    Output power Vs Efficiency Output power Vs Armature current Output power Vs Torque Output power Vs Speed Torque Vs Speed

    Torque Vs Armature current Speed Vs Armature current

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    Tabulation for load test on DC shunt motor

    Radius of the brake dram = Thickness of the belt =

    Spring balance readingLoadCurrent

    (IL)

    LoadVoltage

    (VL)

    Speed ofthe motor

    (N)

    S1S2

    S1~S2

    Torque (T)(S1~S2)(R+t/2)(9.81)

    Outputpower

    2NT/60S.No

    Amps Volts Rpm Kg Kg Kg N-m Watts

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    MODEL CALCULATION

    RESULT

    Thus the load test on DC shunt motor and its performance curves are drawn.

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    SPEED CONTROL OF DC SHUNT MOTOR

    AIM

    To conduct an experiment to control the speed of the given dc shunt motor by field andarmature control method also to draw its characteristic curves.

    NAME PLATE DETAILS

    FUSE RATING

    10% of rated current (full load current)

    APPRATUS REQUIRED

    S.NONAME OF THE

    APPARATUSTYPE RANGE QUANTITY

    1

    2

    3

    4

    5

    6

    Ammeter

    Ammeter

    Voltmeter

    Rheostat

    Rheostat

    Tachometer

    MC

    MC

    MC

    Wire wound

    Wire wound

    Digital

    (0-2A)

    (0-10A)

    (0-300V)

    250, 2A

    50, 5A

    1

    1

    1

    1

    1

    1

    PRECAUTION

    The motor field rheostat should be kept at minimum resistance position. The motor armature rheostat should be kept at maximum resistance position. The motor should be in no load condition throughout the experiment. The motor should be run in anticlockwise direction.

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    CIRCUIT DIAGRAM FOR SPEED CONTROL OF DC SHUNT MOTOR

    Tabulation for Speed control of DC Shunt motor

    Armature Control Method Field Control Method

    Field Current: Armature Current:

    Armature

    Voltage (Va)

    Speed

    (N)

    Field Current

    (If)

    Speed

    (N)

    S.No.

    Volts RPM Amps RPM

    Fuse

    Fuse

    220VDC SUPPLY

    L F A3 POINT STARTER

    D

    P

    S

    T

    S

    250, 2A F

    FF

    M

    A

    AA

    A

    (0-2A)MC

    50, 5A

    V (0-300V)MC

    A

    (0-10A)MC

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    Model Graph

    (A) Armature Control Method: (B) Field Control Method:

    PROCEDURE

    Field Control Method (Flux Control Method) Connections are given as per the circuit diagram. Using the three point starter the motor is started to run. The armature rheostat is adjusted to run the motor at rated speed by means of

    applying the rated voltage.

    The field rheostat is varied gradually and the corresponding field current and speedare noted up to 120% of the rated speed by keeping the Armature current asconstant.

    The motor is switched off using the DPIC switch after bringing all the rheostats totheir initial position.

    Armature Control Method (Voltage Control Method) Connections are given as per the circuit diagram. Using the three point starter the motor is started to run. The armature rheostat is adjusted to run the motor at rated speed by means of

    applying the rated voltage.

    The armature rheostat is varied gradually and the corresponding armature voltagearmature current and speed are noted up to the rated voltage.

    The motor is switched off using the DPIC switch after bringing all the rheostats totheir initial position

    GRAPHThe graph are drawn as

    Field current Vs Speed Armature current Vs Speed

    RESULTThus the speed control of the given DC shunt motor using field control and armature

    control method and its characteristic curves are drawn.

    Speedinrpm

    Armature Voltage in Volts

    Armature Voltage Vs Speed

    Speedinrpm Field Current Vs Speed

    Field Current in Amps

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    SWINBURNES TEST

    AIM

    To predetermine the efficiency of a given dc shunt machine when working as a motor as well

    as generator by Swinburnes test and also draw the characteristic curves.

    NAME PLATE DETAILS

    FUSE RATING

    10% of rated current (full load current)

    APPRATUS REQUIRED

    S.NONAME OF THE

    APPARATUSTYPE RANGE QUANTITY

    1

    2

    3

    4

    5

    Ammeter

    Ammeter

    Voltmeter

    Rheostat

    Tachometer

    MC

    MC

    MC

    Wire wound

    Digital

    (0-2A)

    (0-10A)

    0-300V

    250,2A

    1

    1

    1

    1

    1

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    CIRCUIT DIAGRAM FOR SWINEBURNS TEST

    Tabulation to find out the Constant loss (Wco)

    TerminalVoltage (V)

    No loadCurrent (I0)

    Field Current

    (If)

    No loadArmature

    Current (Ia0)

    Constant Loss

    WCO= VI0-Ia02Ra

    S.No. Volts Amps Amps Amps Watts

    Resultant tabulation to find out the Efficiency (Running as motor)

    Armature Resistance (Ra)= Rated Current (Ir)=

    Constant loss (WC)= Field Current (If) =

    LoadCurrent IL=

    XIr

    ArmatureCurrent

    Ia= IL- If

    ArmatureCu Loss

    WCu=Ia2Ra

    TotalLossWTotal

    InputPower

    Wi=VLIL

    Output Power

    Wo=Wi- WTotal

    Efficiency

    = Wo/WiS.No.

    Fractionof

    Load(X) Amps Amps Watts Watts Watts Watts %

    1 1/4

    2 1/2

    3 3/4

    4 1

    Fuse

    Fuse

    220VDC SUPPLY

    L F A

    3 POINT STARTER

    D

    P

    S

    T

    S

    250, 2AF

    FF

    M

    A

    AA

    V (0-300V)MC

    A

    (0-2A)MC

    A

    (0-10A)MC

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    FORMULAE

    1. Armature resistance (Ra) = 1.6 RDC in Ohms.

    Where,

    RDC Resistance of the Armature coil, when it is energized by DC supply.

    2. Constant loss (WCO) = (V Io-Iao2Ra) in Watts..

    Where V = Terminal Voltage in Volts

    Io = No Load Current in Amps

    Iao = No Load Armature Current. in Amps

    3. Armature Current (Ia) = (ILIf) in Amps.

    Where, + is used for Generator,

    - is used for Motor.

    4. Copper loss (WCU) = Ia

    2

    Ra in Watts.5. Total loss = Constant loss + Copper loss in Watts

    6. Input power for motor / Output power for generator = V I L in Watts

    Where, IL is Load current in Amps

    7. Output power for motor = Input power + losses

    Input power for Generator = Output power - losses

    8. Percentage of Efficiency = (Output power/Input power) 100

    PRECAUTION

    The motor field rheostat should be kept at minimum resistance position. The motor should be at no load condition through out the experiment. The motor should be run in anticlockwise direction.

    PROCEDURE

    Connections are given as per the circuit diagram.

    By using the three point starter the motor is started to run at the rated speed. The meter readings are noted at no load condition. The motor is switched off using the DPIC switch. After that the Armature resistive test is conducted as per the circuit diagram and the voltage

    and current are noted for various resistive loads.

    After the observation of readings the load is released gradually.

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    Running as generator

    Armature Resistance (Ra)= Rated Current (Ir)=

    Constant loss (WC)= Field Current (If)=

    LoadCurrent

    IL= XIr

    ArmatureCurrent

    Ia= IL+ If

    ArmatureCu Loss

    WCu=Ia2Ra

    TotalLossWTotal

    OutputPower

    Wo=VLIL

    Input Power

    Wi

    =Wo+WTotal

    Efficiency

    = Wo/Wi

    S.No.Fraction

    ofLoad(X)

    Amps Amps Watts Watts Watts Watts %

    1 1/4

    2 1/2

    3 3/4

    4 1

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    Model Graph

    GRAPH

    The graph drawn between Load current Vs Efficiency

    RESULT

    Thus the efficiency of the given DC shunt machine by Swinburnes test when working as a

    motor as well as generator and also draw the characteristic curves are drawn.

    Efficiency

    Output Power (Wo) in Watts

    Generator

    Motor

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    OPEN CIRCUIT TEST AND LOAD TEST ON SELF EXCITED DCSHUNT GENERATOR

    AIMTo conduct the open circuit test and the load test on a given self excited dc shunt generator anddraw the characteristic curves.

    NAME PLATE DETAILS

    FUSE RATING

    125% of rated current (full load current)

    APPRATUS REQUIRED

    S.NONAME OF THE

    APPARATUSTYPE RANGE QUANTITY

    1

    2

    3

    4

    5

    6

    7

    Ammeter

    Ammeter

    Voltmeter

    Rheostat

    Rheostat

    Tachometer

    Resistive Load

    MC

    MC

    MC

    Wire wound

    Wire wound

    Digital

    Variable

    (0-2A)

    (0-20A)

    (0-300V)

    250, 2A

    350, 1.5A

    -

    -

    1

    2

    1

    1

    1

    1

    1

    PRECAUTION

    The motor field rheostat should be kept at minimum resistance position. The generator field rheostat should be kept at maximum resistance position. At the time of starting, the generator should be in no load condition.

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    EC2259 Electrical Engineering And C

    Prepared by G.Panne

    CIRCUIT DIAGRAM FOR OPEN CIRCUIT AND LOAD TEST ON SELF DC SHUNT GENERATOR

    Fuse

    M

    A

    AA

    220VDC SUPPLY

    L F A

    3 POINT STARTER

    D

    P

    S

    T

    S

    250, 2AF

    FF

    G

    A

    AA

    F

    FF

    1050,

    1.5

    A

    V(0-300V)

    MC

    A

    (0-2A)MC

    A

    (0-20A)MC

    17

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    PROCEDURE

    Open circuit test

    Connections are given as per the circuit diagram. The Prime Mover is started with the help of the three point starter and it is made to

    run at rated speed when the Generator is disconnected from the load by DPSTswitch.

    By varying the Generator field rheostat gradually, the Open Circuit Voltage (Eo)and corresponding Field Current (If) are tabulated upto 150 % of Rated Voltage ofGenerator.

    The motor is switched off by using the DPIC switch after bringing all the rheostatsto their initial position.

    Load test

    Connections are given as per the circuit diagram.

    The Prime Mover is started with the help of the three point starter and it is made torun at rated speed when the Generator is disconnected from the load by DPSTswitch.

    By varying the Generator field rheostat gradually, the Rated Voltage (Eg) isobtained.

    The Ammeter and Voltmeter readings are observed at no load condition. The Ammeter and Voltmeter readings are observed for different loads up to the

    rated current by closing the DPST switch.

    After tabulating all the readings the load is brought to its initial position gradually. The Prime Mover is switched off using the DPIC switch after bringing all the

    rheostats to their initial position.

    GRAPH

    The graph are drawn as

    Open Circuit Voltage Vs Field Current Load Voltage Vs Load Current

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    Tabulation for OC and Load test on self excited DC Shunt Generator

    Generator Armature Resistance (Ra):

    OC Test Load TestOpen circuit

    Voltage(E0)

    Field

    Current(If)

    Load

    Voltage(VL)

    Load

    Current(IL)

    Armature

    Current(Ia)

    Armature

    DropIaRa

    Generated emf

    Eg=VL+ IaRaS.No.

    Volts Amps Volts Amps Amps Volts Volts

    Model Graph

    (A) Open Circuit Characteristics (B) Internal (EgVs Ia) and External (VLVs IL) Characteristics

    RESULT

    Thus the open circuit test and load test on a given self excited DC generator and thecharacteristic curves are drawn.

    OpenCircuitVoltage(E0)

    inVolts

    Field Current (If) in

    Amps

    (E0) Vs (If)

    LoadVoltage(VL)inVolts

    Load Current (IL) in Amps

    (VLVs IL)

    GeneratedEMF(Eg

    )inVo

    lts

    Armature Current (Ia)

    in Amps

    (EgVs Ia)

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    OPEN CIRCUIT TEST AND LOAD TEST ON SEPARATELY EXCITEDDC GENERATOR

    AIMTo conduct the open circuit test and the load test on a given separately excited dc generator anddraw the characteristic curves.

    NAME PLATE DETAILS

    FUSE RATING125% of rated current (full load current)

    APPRATUS REQUIRED

    S.NONAME OF THE

    APPARATUSTYPE RANGE QUANTITY

    12

    3

    4

    5

    6

    7

    AmmeterAmmeter

    Voltmeter

    Rheostat

    Rheostat

    Tachometer

    Resistive Load

    MCMC

    MC

    Wire wound

    Wire wound

    Digital

    Variable

    (0-2A)(0-20A)

    (0-300V)

    250, 2A

    350, 1.5A

    -

    -

    12

    1

    1

    1

    1

    1

    PRECAUTION

    The motor field rheostat should be kept at minimum resistance position. The generator field rheostat should be kept at maximum resistance position. At the time of starting, the generator should be in no load condition.

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    EC2259 Electrical Engineering And

    Prepared by G.Panne

    CIRCUIT DIAGRAM FOR OPEN CIRCUIT AND LOAD TEST ON SEPERATEDC GENERATOR

    220VDC SUPPLY

    D

    P

    S

    T

    S

    350, 1.5A

    Fuse

    M

    A

    AA

    220VDC SUPPLY

    L F A

    3 POINT STARTER

    D

    P

    S

    T

    S

    250, 2AF

    FF

    G

    A

    AA

    V

    (0-300V)MC

    FF

    F

    A(0-2A)

    MC

    A

    (0-20A)

    MC

    23

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    PROCEDURE

    Open circuit test

    Connections are given as per the circuit diagram. The Prime Mover is started with the help of the three point starter and it is made to run at rated

    speed when the Generator is disconnected from the load by DPST switch. By varying the Generator field rheostat gradually, the Open Circuit Voltage (Eo) and

    corresponding Field Current (If) are tabulated upto 150 % of Rated Voltage of Generator.

    The motor is switched off by using the DPIC switch after bringing all the rheostats to initialposition.

    Load test

    Connections are given as per the circuit diagram. The Prime Mover is started with the help of the three point starter and it is made to run at rated

    speed when the Generator is disconnected from the load by DPST switch..

    By varying the Generator field rheostat gradually, the Rated Voltage (Eg) is obtained. The Ammeter and Voltmeter readings are observed at no load condition. The Ammeter and Voltmeter readings are observed for different loads up to the rated current by

    closing the DPST switch..

    After tabulating all the readings the load is brought to initial position. The motor is switched off using the DPIC switch after bringing all the rheostats to initial position.

    GRAPH

    The graph drawn as

    Open Circuit Voltage Vs Field Current Load Voltage Vs Load Current

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    Tabulation for OC and Load test on separately excited DC Generator

    Generator Armature Resistance (Ra):

    OC Test Load Test

    Open circuitVoltage

    (E0)

    FieldCurrent

    (If)

    LoadVoltage

    (VL)

    LoadCurrent

    (IL)

    ArmatureCurrent

    (Ia)

    ArmatureDrop

    IaRa

    Generated emf

    Eg=VL+ IaRaS.No.

    Volts Amps Volts Amps Amps Volts Volts

    Model Graph

    (A) Open Circuit Characteristics (B) Internal (EgVs Ia) and External (VLVs IL) Characteristics

    RESULT

    Thus the open circuit test and load test on a given separately excited DC generator and thecharacteristic curves are drawn.

    OpenCircuitVoltage(E0)

    inVolts

    Field Current (If) in

    Amps

    (E0) Vs (If)

    LoadVoltage(VL)inVolts

    Load Current (IL) in Amps

    (VLVs IL)

    GeneratedEMF(Eg

    )inVolts

    Armature Current (Ia)in Amps

    (EgVs Ia)

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    LOAD TEST ON SINGLE PHASE TRANSFORMER

    AIM

    To conduct the load test on a given single phase transformer and draw its performance curves.

    NAME PLATE DETAILS

    FUSE RATING

    Primary Current = KVA Rating of the Transformer / Primary Voltage.

    Secondary Current = KVA Rating of the Transformer / Secondary Voltage.

    125% of Primary current (fuse rating for primary side)

    125% of Secondary current (fuse rating for secondary side)

    APPRATUS REQUIRED

    S.NONAME OF THE

    APPARATUSTYPE RANGE QUANTITY

    1

    2

    3

    4

    56

    Ammeter

    Ammeter

    Voltmeter

    Voltmeter

    Watt meter

    Auto Transformer

    MI

    MI

    MI

    MI

    UPF

    1

    (0-5A)

    (0-20A)

    (0-150V)

    (0-300V)

    300V, 5A

    230/(0-270V

    1

    1

    1

    1

    1

    1

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    CIRCUIT DIAGRAM FOR LOAD TEST ON SINGLE PHASE TRANSFO

    300V, 5A UPF

    LM

    CP1

    P2

    150V

    A

    V (0-300V)MI

    A

    C

    230/(0-270V)1 AUTO

    TRANSFORMER

    NL

    1, 230V, 50HzAC SUPPLY

    N

    P

    Fuse

    B

    SPSTS

    V

    (0-1M

    1 230/110V, 1KVASTEP DOWN

    TRANSFORMER

    (0-5A)

    MI

    S1

    S23

    3

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    FORMULAE

    1. Input Power =Wattmeter reading Multiplication factor in Watts

    Where,

    Multiplication factor =

    2.Output power = VSY ISY cosin Watts.

    Where VSY - Secondary Voltage in Volts.

    ISY- Secondary current in Amps.

    3.Percentage of Efficiency = 100 %

    4.Percentage of Regulation = 100 %

    Where, VO No Load Voltage in Volts

    VL Load Voltage in Volts

    PRECAUTION

    No Load Condition should be observed at the time of starting Meters are checked for proper Type and rating.

    PROCEDURE

    Connections are given as per the circuit diagram. The SPST Switch on the Primary side is closed and the DPST Switch on the Secondary side is

    opened.

    The Autotransformer is adjusted to Energize the transformer with rated Primary Voltage The Volt meters and Ammeters Readings are noted and tabulated at No load condition The DPST switch on the secondary side is closed. The transformer is loaded upto 130% of the Rated Load, corresponding Ammeters, Voltmeters

    and Wattmeters readings are noted and tabulated.

    After the observation of all the readings the load is released gradually to its initial position. The Autotransformer is brought to its initial position The Supply is switched off.

    GRAPH

    The graph drawn as

    Output power Vs Efficiency Output power Vs Regulation

    (Rating of pressure coil Rating of current coil pf )

    Full Scale Reading

    VO VLVO

    Output PowerInput Power

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    Tabulation for Load test on single phase transformer

    Multiplication Factor =

    Wattmeterreadings

    (W)

    PrimaryVoltage

    (VPy)

    PrimaryCurrent

    (IPy)

    SecondaryVoltage

    (VSy)

    SecondaryCurrent

    (ISy)

    Obs. Act.

    Inputpower(W)

    Output power

    VSyISycosS.No

    Volts Amps Volts Amps Watts Watts Watts

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    Model Graph

    RESULT

    Thus the load test on a given single phase transformer is done and the characteristic curves aredrawn.

    %OfEffeciency

    Effeciency

    Output power in watts

    %

    OfRegulation

    Regulation

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    OPEN CIRCUIT TEST AND SHORT CIRCUIT TEST

    ON SINGLE PHASE TRANSFORMER

    AIMTo Predetermine the Efficiency and Regulation on a given single phase transformer byconducting the Open Circuit test and Short Circuit test and also draw its Equivalent circuit.

    NAME PLATE DETAILS

    FUSE RATINGPrimary Current = KVA Rating of the Transformer / Primary Voltage.

    Secondary Current = KVA Rating of the Transformer / Secondary Voltage.

    10% of Primary current (fuse rating for Open Circuit test)

    125% of Secondary current (fuse rating for Short circuit test)

    APPARATUS REQUIRED

    S.No Name of the apparatus Type Range Quantity

    1

    2

    3

    4

    56

    7

    Ammeter

    Ammeter

    Voltmeter

    Voltmeter

    Watt meter

    Watt meter

    Auto Transformer

    MI

    MI

    MI

    MI

    UPF

    UPF

    1

    (0-1A)

    (0-10A)

    (0-150V)

    (0-300V)

    300V, 1A

    75V, 5A

    230/(0-270V)

    1

    1

    1

    1

    1

    1

    1

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    CIRCUIT DIAGRAM FOR OPEN CIRCUIT TEST ON SINGLE PHASE TRA

    1, 230V, 50HzAC SUPPLY

    A

    C

    230/(0-270V)1 AUTO

    TRANSFORMER

    NL

    N

    P

    Fuse

    B

    SPSTS150V

    150V, 5A LPF

    LM

    C

    A

    V (0-150V)MI

    1 110/2STE

    TRANS

    P1

    P2

    (0-5A)MI

    39

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    CIRCUIT DIAGRAM FOR SHORT CIRCUIT TEST ON SINGLE PHASE TRA

    (0-75V)MI

    75V

    300V, 10A UPF

    LM

    C

    A

    V

    A

    C

    230/(0-270V)1 AUTO

    TRANSFORMER

    NL

    1, 230V, 50HzAC SUPPLY

    N

    P

    Fuse

    B

    SPSTS

    P1

    P2

    (0-5A)MI

    1 230/11STEP

    TRANSF

    41

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    Tabulation for OC and SC test on Single phase transformer

    Open Circuit test Multiplication Factor =

    Short

    Circuit testMultiplication Factor =

    Short Circuit power (WSC)Short CircuitPrimary

    Current (ISC)

    Short circuitPrimary

    Voltage (VSC)Obs. Act.

    Short Circuitsecondary

    Current (I2S)S.No.

    Amps Volts Watts Watts Volts

    Resultant Tabulation to find out the Efficiency

    Core (Or) Iron Loss = A Rating of Transformer =Rated Short Circuit Current (ISC) = Short Circuit Power (WSC) =

    Output powerShortcircuitCurrent

    (ISCX)0.2 0.4 0.6 0.8 1

    CopperLoss

    (X2WSC)

    Total LossWT =

    Wi+WSC

    EfficiencyO/p

    O/p+TLFraction ofLoad (X)

    Amps Watts Watts Watts %

    1/4

    1/2

    3/4

    1

    Open Circuit power (WOC)Open CircuitPrimaryCurrent (IOC)

    Open circuitPrimaryVoltage (VOC) Obs. Act.

    Open CircuitsecondaryVoltage (V2O)

    S.No.

    Amps Volts Watts Watts Volts

    =

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    FORMULAE

    EQUIVALENT CIRCUIT

    Open Circuit Test

    1. No Load Power Factor (Coso) =

    Where, Woc Open Circuit Power in Watts

    Voc Open Circuit Voltage in Volts

    Ioc Open Circuit Current in Amps

    2.No Load Working Component Resistance (Ro) = in Ohms

    Where Voc Open Circuit Voltage in Volts.

    Ioc Open Circuit current in Amps.

    3. No Load Magnetizing Component Reactance( Xo) = in Ohms

    Where Voc Open Circuit Voltage in Volts.

    Ioc Open Circuit current in Amps.

    Short Circuit Test

    4. Equivalent impedance referred to HV side ( Z02) = in Ohms

    Where, Vsc Short circuit Voltage in Volts

    Isc Short circuit current in Amps

    5. Equivalent resistance referred to HV side (R02) = in Ohms

    Where, Wsc Short circuit Power in Watts

    6. Equivalent reactance referred to HV side (X02) =Z022- R022 in Ohms

    7. Transformation ratio (K) =

    Where, V1 Primary voltage in Volts

    V2 Secondary Voltage in Volts

    8. Equivalent resistance referred to LV side (R01)= in Ohms

    9. Equivalent reactance referred to LV side (X01)= in Ohms

    Efficiency and Regulation

    10. Output Power = X KVA cosin Watts.Where, X-Fraction of load

    KVA - power rating of Transformer and Cos- Power factor

    VscIsc

    WocVoc Ioc

    Voc

    Ioc Coso

    Voc

    Ioc Sino

    WscIsc2

    V2V1

    R02K2

    X02K2

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    11. Copper loss = X2 Wsc in WattsWhere, Wsc- Copper Loss in Short Circuit condition

    12. Total Loss = (Cu Loss + Iron Loss) in Watts

    13. Efficiency = x 100 in %

    14. Regulation = 100 in %

    Where, V2o Open Circuit Voltage on HV side.

    PRECAUTION

    No Load Condition should be observed at the time of starting Meters are checked for proper Type and rating.

    PROCEDURE

    OPEN CIRCUIT TEST

    Connections are given as per the circuit diagram. The SPST Switch on the Primary side is closed. The Autotransformer is adjusted to Energize the transformer with rated Primary Voltage

    on the LV side

    The Volt meter, Watt meter and Ammeter Readings are noted at No load condition The Autotransformer is brought to its initial position

    The Supply is switched off.

    SHORT CIRCUIT TEST

    Connections are given as per the circuit diagram. The SPST Switch on the Primary side is closed The Autotransformer is adjusted to energize the transformer with rated Primary Current on

    the HV side.

    The Voltmeter, Wattmeter and Ammeter Readings are noted down at short circuitcondition.

    The Autotransformer is brought to its initial position The Supply is switched off.

    GRAPH

    The graph are drawn as

    Output power Vs Efficiency Output power Vs Regulation

    Output power

    (Output power +Total Losses)

    X Isc [R02 x cos X02 x sin]V2o

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    Resultant Tabulation to find out the Regulation

    ISC = RO2= XO2 = % Of Reg

    Value of Cos Value of Sin 0.8 0.6 Fractionof Load

    (X) 1 0.8 0.6 0.4 0.2 1 0.8 0.6 0.4 0.2 1 Lag. Lead. Lag. Lead

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    LOAD TEST ON THREE PHASE SQUIRREL CAGEINDUCTION MOTOR

    AIM

    To conduct a load test on a three phase squirrel cage induction motor and to draw the

    performance characteristic curves.

    NAME PLATE DETAILS

    ! " "#$%"&'"

    FUSE RATING

    125% of rated current (Full load current)

    APPARATUS REQUIRED

    FORMULAE USED

    1.Torque = (S1-S2) (R+t/2) x 9.81 N-m

    Where, S1, S2 spring balance readings in Kg.

    R - Radius of brake drum in m.

    t - Thickness of belt in m.

    2. Output Power = 2 NT/60 watts.

    N- Rotor speed in rpm.

    T- Torque in N-m.

    S.NONAME OF THE

    APPARATUSTYPE RANGE QUANTITY

    1.2.

    3.4.

    AmmeterVoltmeter

    WattmeterTachometer

    MIMI

    UPF-

    (0-10 A)(0-600 V)

    (500V, 10A)-

    11

    1

    1

    3. Input Power = (W1+W2) Watts.

    W1, W2 Wattmeter readings in Watts.

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    CIRCUIT DIAGRAM FOR LOAD TEST ON THREE PHASE SQUIRRAL CAGE IN

    (0-10) AMI

    15V, 50Hz, 3AC SUPPLY

    R

    Y

    B

    N

    STAR-DELTASTARTER

    A

    T

    P

    S

    TS

    Fuse

    Fuse

    Fuse

    V (0-600) VMI

    600V, 10A UPF

    L

    600V

    M

    C

    R

    STATOR

    A1

    A2

    B1

    M

    600V, 10A UPF

    C

    L

    600V

    A1

    A2

    B1

    B2

    C1

    C2

    L2

    L3

    L1

    NLN

    51

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    4. Percentage of Efficiency = (Output Power/ Input Power) x 100%.

    5. Percentage of Slip = (NS-Nr)/Nsx 100%

    Ns-Synchronous speed in rpm.

    Nr-Rotor speed in rpm.

    6.Power factor = (W1+W2)/3 VLIL.

    PRECAUTION

    The motor should be started without any load

    PROCEDURE:

    Connections are given as per the circuit diagram. The TPSTS is closed and the motor is started using On Line starter to run at rated speed. At no load the speed, current, voltage and power are noted down. By applying the load for various values of current the above-mentioned readings are noted. The load is later released and the motor is switched off and the graph is drawn. .

    GRAPH

    The graph are drawn as

    Output Power Vs Speed

    Output Power Vs Line current Output Power Vs Torque Output Power Vs Power factor Output Power Vs % Efficiency Output Power Vs % Slip.

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    Tabulation for load test on three phase squirrel cage induction m

    Multipl

    Wattmeter readings

    W1 W2

    Inputpower

    Spring balancereading

    LoadCurren

    t(IL)

    LoadVoltage

    (VL)

    Obs. Act. Obs. Act.W1+W2

    Speedof themotor(N)

    S1 S2 S1~S2

    Torque (T(S1~S2) (R+t

    (9.81)S.No

    Amps Volts Watts Watts rpm Kg Kg Kg N-m

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    Load test on Three phase squirrel cage induction motor

    Model Graphs:

    (A) Mechanical characteristics

    (B) Electrical characteristics:

    RESULT

    Thus the load test on a given three phase squirrel cage induction motor is done and th

    characteristic curves are drawn.

    Speed in RPM

    Torque in N-m

    Torque Vs Speed

    O/P powerin watts

    N

    N in rpm

    ILin Amps

    T in N-m

    %T

    IL %

    Cos

    Cos

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    EQUIVALENT CIRCUIT OF THREE PHASE SQUIRREL CAGEINDUCTION MOTOR

    AIM

    To conduct a No Load test and Blocked Rotor test on three phase squirrel cage induction motorand to draw the equivalent circuit.

    NAME PLATE DETAILS

    ! " "#$%"&'"

    FUSE RATING

    No Load: 10 % of rated current (Full load current)

    Load: 125 % of rated current (Full load current)

    APPARATUS REQUIRED

    FORMULAE USED

    OC Test

    1. No load power factor (Cos 0) = P0/V0I0

    V0- No load voltage per phase in volts.

    I0- No load current per phase in amps.

    P0 - No load power per phase in watts.

    2. Working component current (Iw) = I0 (ph) X Cos 0

    3. Magnetizing current (Im) = I0 (ph) X Sin 0

    4. No load resistance (R0) =V0/I0 (ph) Cos 0 in.

    S.NO. NAME OF THE

    APPARATUS

    TYPE RANGE QUANTITY

    1.2.

    3.4.5.6.7.

    AmmeterAmmeter

    VoltmeterVoltmeterVoltmeterWattmeterWattmeter

    Tachometer

    MCMI

    MIMIMCLPFUPF

    -

    (0-10 A)(0-10 A)

    (0-150 V)(0-600 V)(0-50 V)

    (600V, 10A) (150V,10A)

    -

    12

    111221

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    CIRCUIT DIAGRAM FOR NO LOAD TEST ON THREE PHASE SQUIRRINDUCTION MOTOR

    (Equivalent circuit)

    57

    415V, 50Hz, 3AC SUPPLY

    R

    YB2

    B

    T

    P

    ST

    S

    N

    A1

    A3

    B3

    V (0-600) VMI

    A2

    B1

    Fuse

    415 / (0-470) V3 AUTO TRANSFORMER

    A

    (0-10) AMI

    600V, 10A LPF

    600V

    C2

    C3

    C1

    A2

    B1

    LM

    C

    M

    600V, 10A LPF

    C

    L

    600V

    Fuse

    Fuse

    NL

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    CIRCUIT DIAGRAM FOR BLOCKED ROTOR TEST ON THREE PHASE SQUINDUCTION MOTOR(Equivalent circuit)

    59

    A1

    A3

    B3

    Fuse

    A2

    415 / (0-470) V3 AUTO TRANSFORMER

    C2

    C3

    C1

    Fuse

    Fuse

    NL

    B1

    B2

    R415V, 50Hz, 3AC SUPPLY

    R

    Y

    B

    T

    P

    S

    TS

    N

    V (0-150) VMI

    STATOR

    A(0-10) A

    MI

    150V, 10A UPF

    L

    150V

    M

    C

    M

    150V, 10A UPF

    C

    L

    150V

    A1

    A2

    B1

    C

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    Tabulation for No Load test on three phase Squirrel cage Induct

    Speed of theType of the

    Mu

    Tabulation for Blocked rotor test on three phase Squirrel cage InduType of the Stator conne

    Multiplication F

    Short Circuit Power

    W1 W2

    ShortCircuitCurrent

    (ISC)

    ShortCircuitVoltage(VSC)

    Observed Actual Observed Actual

    Total ShortCircuit PowerPSC=(W1+W

    2)

    Short CircuitPower/Phase

    PSC

    (Ph)=(P0/3)

    S.No

    Amps Volts Watts Watts Watts Watts Watts Watts

    No Load Power

    W1

    W2

    No Load

    Current(I0)

    No Load

    Voltage(V0)

    Observed Actual Observed Actual

    Total No Load Power

    P0=(W1+W2)

    No Load Power/Phase

    P0 (Ph)=(P0/3)

    S.No

    Amps Volts Watts Watts Watts Watts Watts Watts

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    5. No load reactance (X0) = V0/I0(ph) Sin 0 in .

    SC Test

    6. Motor equivalent Impedance referred to stator (Zsc(ph)) = Vsc(ph)/ Isc(ph) in.

    7. Motor equivalent Resistance referred to stator (Rsc(ph)) = Psc(ph) / I2sc(ph) in.

    8. Motor equivalent Reactance referred to stator (Xsc(ph)) = (Z sc(ph)2- R sc(ph)2) in.

    9. Rotor Resistance referred to stator (R2(ph)) = Rsc(ph) R1 in.

    10. Rotor Reactance referred to stator (X2(ph)) = Xsc(ph)/ 2 = X1 in.

    Where R1 -stator resistance per phase

    X1 stator reactance per chapter

    R1 = R(ac) =1.6 x R(dc)

    11. Equivalent load resistance (RL)= R2 (1/s 1) in .

    Where Slip (S) = (Ns-Nr) / Ns

    Ns Synchronous speed in rpm.

    Nr Rotor speed in rpm.

    PRECAUTION

    The autotransformer should be kept at minimum voltage position

    PROCEDURE

    Connections are given as per the circuit diagram.

    For No-Load or open circuit test by adjusting autotransformer, apply rated voltage and

    Note down the ammeter and wattmeter readings. In this test rotor is free to rotate.

    For short circuit or blocked rotor test by adjusting autotransformer, apply rated current

    and note down the voltmeter and wattmeter readings. In this test rotor is blocked.

    After that make the connection to measure the stator resistance as per the circuit diagram.

    By adding the load through the loading rheostat note down the ammeter, voltmeter

    reading for various values of load.

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    Equivalent circuit for three phase squirrel cage induction motor

    RESULT

    Thus the no load and blocked rotor test on a given three phase squirrel cage induction motor and

    the equivalent circuit is drawn.

    P

    N

    1, 230V, 50Hz ACSupply

    R2'X

    2'

    RL' =R2' (1/s-1)

    R1 X1

    X0R0

    I0

    Iw I

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    REGULATION OF THREE PHASE ALTERNATOR BY EMF AND MMFMETHODS.

    AIM

    To predetermine the regulation of a given three phase Alternator by EMF and MMF method and also draw thevector diagrams.

    NAME PLATE DETAILS

    ('"#" ) "

    FUSE RATING

    125% of rated current (Full load current)

    For DC shunt motor:

    For Alternator:

    APPARATUS REQUIRED

    S.NO.NAME OF THE

    APPARATUSTYPE RANGE QUANTITY

    1.2.3.4.5.6.7.

    8.

    AmmeterAmmeterAmmeterVoltmeterVoltmeterRheostatRheostat

    Tachometer

    MCMCMIMIMC

    Wire WoundWire Wound

    -

    (0-2 A)(0-10 A)(0-10 A)(0-600V)(0-50V)

    (500, 1.2A)(300, 1.7A)

    -

    1111121

    1

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    CIRCUIT DIAGRAM FOR REGULATION OF THREE PHASE ALTBY EMF & MMF METHOD

    (Open circuit and Short circuit tests)

    V

    220VDCSUPPLY

    L F A

    3 POINT STARTER

    D

    P

    S

    T

    S

    250, 2A

    M

    F

    FF

    A

    AA

    (0-600) VMI

    XXX

    R

    B YN

    A(0-2) A

    MC

    Fuse

    Fuse

    220VDC SUPPLY

    D

    P

    S

    T

    S

    350, 1.5A

    79

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    FORMULAE USED

    EMF Method1. Armature Resistance Ra = 1.6 Rdc in ohms.

    Here, Rdc is the resistance in DC supply.

    2. Synchronous impedance Zs = (from the graph)

    3. Synchronous impedance Xs =(Zs -Ra) in ohms.

    4. Open circuit voltage Eo=(V cos + Isc Ra) + (V sin -Isc Xs) in Volts.(For lagging power factor)

    5. Open circuit voltage Eo=(V cos + Isc Ra) + (V sin -Isc Xs) in Volts(For leading power factor)

    7. Open circuit voltage Eo=(V + Isc Ra) + (Isc Xs) in Volts(For Unity power factor)

    6. Percentage regulation =

    PRECAUTION

    The motor field rheostat should be kept in the minimum resistance position. The Alternator field Potential divider should be in the maximum voltage position. Initially all Switches are in open position.

    PROCEDURE FOR BOTH EMF AND MMF METHOD

    Connections are made as per the circuit diagram. Give the supply by closing the DPST Switch. Using the Three Point starter, start the motor to run at the synchronous speed by varying the

    motor field rheostat.

    Conduct an Open Circuit Test by varying the Potential Divider for various values of FieldCurrent and tabulate the corresponding Open Circuit Voltage readings.

    Conduct a Short Circuit Test by closing the TPST switch and adjust the potential divider toset the rated Armature Current, tabulate the corresponding Field Current.

    Conduct a Stator Resistance Test by giving connection as per the circuit diagram andtabulate the Voltage and Current readings for various resistive loads.

    Open circuit voltage (E1 (ph))Short circuit current (Isc)

    Eo VratedVrated X 100 (both for EMF & MMF method)

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    PROCEDURE TO DRAW THE GRAPH FOR EMF METHOD

    Draw the Open Circuit Characteristics curve (Generated Voltage per phase Vs Field Current). Draw the Short Circuit Characteristics curve (Short Circuit Current Vs Field Current). From the graph find the open circuit voltage per phase (E1 (Ph)) for the rated Short Circuit Current

    (Isc).

    By using respective formulae find the Zs, Xs, Eoand percentage Regulation.

    PROCEDURE TO DRAW THE GRAPH FOR MMF METHOD

    Draw the Open Circuit Characteristics curve (Generated Voltage per phase Vs Field Current). Draw the Short Circuit Characteristics curve (Short Circuit Current Vs Field Current). Draw the line OL to represent If'which gives the rated generated voltage (V). Draw the line LA at an angle(90 )to represent If''which gives the rated full load current (Isc)

    on short circuit ((90 +) for lagging power factor and(90-) for leading power factor).

    Join the points O and A and find the field current (If) by measuring the distance OAthat gives theOpen Circuit Voltage (Eo) from the Open Circuit Characteristics.

    Find the percentage Regulation by using suitable formula.

    Tabulation for Regulation of three phase Alternator by EMF and MMF methods

    Open circuit test

    Field Current(If)

    Open Circuit LineVoltage (V0L)

    Open Circuit PhaseVoltage(V0 (Ph))S.No.

    Amps Volts Volts

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    Short circuit test

    Regulation of three phase Alternator by EMF and MMF methods

    Model Graph for EMF Method

    Field Current(If)

    Short Circuit Current(120 to 150 % of rated current)

    (ISC)

    S.No.

    Amps Amps

    OCC

    E1 (ph)

    Field Current (If) in Amps

    ShortCircuitCurrent(ISC)inAmps

    OpenCircuitVoltage(V0(Ph))inVolts

    SCC

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    Regulation of three phase Alternator by EMF and MMF methods

    Model Graph for MMF Method

    SCC

    OCC

    E0 (ph)Lead.

    Field Current (If) in Amps

    ShortCircui

    tCurrent(ISC)inAmps

    OpenCircuitVoltage(V0(Ph))inVolts

    O L

    A

    A

    A

    E0 (ph)Unity

    E0 (ph)Lag.

    Lead.Lag.

    Unity

    90- 90+

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    Resultant Tabulation for Regulation of three phase Alternator by EMF and MMFmethods

    Regulation curve of Alternator (EMF, MMF and Vector diagram)

    RESULT

    Thus the regulation of three phase alternator by EMF and MMF methods and the regulation curves aredrawn.

    Percentage of Regulation

    EMF Method MMF MethodS.No. PowerFactor Lagging Leading Unity Lagging Leading Unity

    1. 0.2 - -

    2. 0.4 - -

    3. 0.6 - -

    4. 0.8 - -

    5. 1.0

    Lagging pf

    Leading pf

    +%

    Regulation

    -

    %Regulation

    From EMF method

    From MMF method

    Unity pf

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    STABILITY ANALYSIS OF LINEAR SYSTEM

    AIM

    To analysis the stability of the given linear system using Bode Plot, Nyquist Plot and Root Locus.

    APPRATUS REQUIRED

    S.No Name of the apparatus Type Range Quantity

    1

    2

    Computer

    MATLAB Software

    -

    -

    -

    -

    1

    1

    THEORY

    POLAR PLOT

    The polar plot of a sinusoidal transfer function ( )G j on polar coordinates as is varied from zero to

    infinity. Thus the polar plot is the locus of vectors ( )G jw and ( )G jw as is varied from zero to infinity. The

    polar plot is also called Nyquist plot.

    NYQUIST STABILITY CRITERION

    If ( ) ( )G s H s contour in the ( ) ( )G s H s plane corresponding to Nyquist contour in s-plane encircles the

    point 1 0j + in the anti clockwise direction as many times as the number of right half s-plane of ( ) ( )G s H s .

    Then the closed loop system is stable.ROOT LOCUS

    The root locus technique is a powerful tool for adjusting the location of closed loop poles to achieve

    the desired system performance by varying one or more system parameters.

    The path taken by the roots of the characteristics equation when open loop gain K is varied from 0 to

    are called root loci (or the path taken by a root of characteristic equation when open loop gain K is varied

    from 0 to is called root locus.)

    FREQUENCY DOMAIN SPECIFICATIONS

    The performance and characteristics of a system in frequency domain are measured in term of frequency

    domain specifications. The requirements of a system to be designed are usually specified in terms of these

    specifications.

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    PROCEDURE

    Enter the command window of the MATLAB.

    Create a new M file by selecting File New M File.

    Type and save the program.

    Execute the program by either pressing F5 or Debug Run. View the results.

    Analysis the stability of the system for various values of gain.

    PROBLEM

    Obtain the Bode Plot, Nyquist Plot and Root Locus of the given open loop T.F is2

    3

    2( )

    2H s

    s s+=

    +

    Using Bode Plot

    num = [0 0 2]den = [1 3 2]bode (num,den)gridtitle (BODE DIAGRAM)% To Find out Gain Margin

    sys = tf (num, den)bode (sys)Margin (sys)[ gm, ph, wpc, wgc ] = margin (sys).

    Using Nyquist Plot

    num = [0 0 2]den = [1 3 2]nyquist (num,den)gridtitle (Nyquist Plot)

    Using Nyquist Plot

    num = [0 0 2]den = [1 3 2]rlocus (num,den)gridtitle (Root Locus Plot)

    RESULT

    Thus the stability of the given linear system using Bode Plot, Nyquist Plot and Root Locus was

    analyzed.

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    DIGITAL SIMULATION OF LINEAR SYSTEM

    AIM

    To simulate the time response characteristics of second order linear system using

    MATLAB.

    APPRATUS REQUIRED

    S.No Name of the apparatus Type Range Quantity

    1

    2

    Personal Computer

    MATLAB Software

    -

    -

    -

    -

    1

    1

    THEORYThe desired performance characteristics of control system are specified in terms of time

    domain specification. Systems with energy storage elements cannot respond instantaneously and

    will exhibit transient responses, whenever they are subjected to inputs or disturbances.

    The desired performance characteristics of a system pf any order may be specified in

    terms of the transient response to a unit step input signal.

    The transient response of a system to unit step input depends on the initial conditions.

    Therefore to compare the time response of various systems it is necessary to start with standard

    initial conditions. The most practical standard is to start with the system at rest and output andall time derivatives there of zero. The transient response of a practical control system often

    exhibits damped oscillations before reaching steady state.

    The transient response characteristics of a control system to a unit step input are

    specified in terms of the following time domain specifications.

    1. Delay timed

    t

    2. Rise timer

    t

    3. Peak timep

    t

    4. Maximum overshootp

    M

    5. Settling times

    t

    1. Delay Time

    It is the taken for response to reach 50% of the final value, for the very first time.

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    2. Rise Time

    It is the time taken for response to raise from 0 to 100% for the very first time. For under

    damped system, the rise time is calculated from 0 to 100%. But for over damped system it is the

    time taken by the response to raise from 10% to 90%. For critically damped system, it is the

    time taken for response to raise from 5% to 95%.

    Rise timer d

    t

    =

    Where,211

    tan

    =

    and

    Damped frequency of oscillation 21nd =

    3. Peak Time

    It is the time taken for the response to reach the peak value for the very first time. (or) It is the

    taken for the response to reach the peak overshootpt .

    Rise timep dt

    =

    4. Peak Overshoot (Mp)

    It is defined as the ration of the maximum peak value measured from final value to the final

    value.

    Let final value ( )c e=

    Maximum vale ( )c tp

    =

    Peak Overshoot,p

    M( ) ( )

    ( )

    c t c ep

    c e

    =

    21% 100M e

    p

    =

    5. Settling Time

    It is defined as the time taken by the response to reach and stay within a specified error. It is

    usually expressed as % of final value. The usual tolerable error is 2% or 5% of the final value.

    Settling Time4

    s nt

    = (For 2% error).

    Settling Time3

    s nt

    = (For 5% error).

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    PROCEDURE

    Enter the command window of the MATLAB.

    Create a new M file by selecting File New M File.

    Type and save the program.

    Execute the program by either pressing F5 or Debug Run.

    View the results.

    Analysis the time domain specifications of the system.

    PROBLEM

    Obtain the time domain specifications of the given open loop T.F is2

    2

    100( )

    100H s

    s s+=

    +

    MATLAB PROGRAM FOR UNIT IMPULSE PRSPONSE

    num = [ 0 0 100 ]

    den = [ 1 2 100 ]

    impulse (num, den)

    grid

    title ( unit impulse response plot)

    MATLAB PROGRAM FOR UNIT STEP PRSPONSEnum = [ 0 0 100 ]

    den = [ 1 2 100 ]

    step (num, den)

    grid on

    title (unit step response plot)

    RESULT

    Thus the time response characteristic of second order linear system was verified using

    MATLAB.

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    DESIGN OF P, PI, PID CONTROLLER

    AIM

    To design P, PI, and PID controllers for first order systems using MATLAB.

    APPARATUS REQUIRED1. Controller and system kit.

    2. Patch chords.

    3. Computer and Interference chord.

    THEORY

    Proportional Controller

    1. The Proportional Controller is a device that produces the control signal, u (t) which is

    Proportional to the input error signal e (t).

    In P controller, u (t) e (t).

    Therefore u (t) = Kp c (t).

    Where Kp Proportional gain or constant.

    2. The Proportional plus Integral Controller (PI Controller) produces an output signal

    consisting of two terms one on proportional to error signal and the other proportional to

    the integral of error signal

    In PI Controller, u (t) [e (t) + | e (t) dt]

    Therefore, u (t) = e (t) + Kp / Ti | e (t) dt

    Where Kp Proportional gain or constant,

    Ti Integral Time.

    3. The PID Controller produces an output signal consisting of three terms one on

    proportional to error signal and the another one proportional to the integral of error

    signal and the third one is proportional to derivative of error signal.

    In PID Controller, u (t) [e (t) + | e (t) + d /dt ((e (t))]

    Therefore, u (t) = e (t) + Kp / Ti | e (t) dt + Kp Td d /dt ((e(t))]

    Where Kp Proportional gain or constant,

    Ti Integral Time.

    Td Derivative Time.

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    Type 0 First Order System with P Controller

    Computer CH 0 Computer CH 1

    Step Input

    (FG)

    P Controller

    Level ShifterLevel Shifter

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    Type 0 First Order System with PI - Controller

    Computer CH 0 Computer CH 1

    Step Input

    (FG)

    PI Controller

    Level ShifterLevel Shifter

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    Type 0 First Order System with PID - Controller

    Computer CH 0 Computer CH 1

    Step Input

    (FG)

    PID Controller

    Level ShifterLevel Shifter

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    Procedure

    Type 0 First Order System with P Controller

    1. Connections are given as per the circuit diagram.

    2. Set Proportional Band = 80, Integral Time = 64000 and Derivative Time = 0.

    3. Measure the performance specifications.

    Type 0 First Order System with PI Controller

    1. Connections are given as per the circuit diagram.

    2. Set Proportional Band = 80, Integral Time = 30 and Derivative Time = 0.

    3. Measure the performance specifications.

    Type 0 First Order System with PI Controller

    1. Connections are given as per the circuit diagram.

    2. Set Proportional Band = 80, Integral Time = 30 and Derivative Time = 0.1.

    3. Measure the performance specifications.

    Transfer Function for P, PI, and PID Controller:

    P Controller: Transfer Function = Kp

    PI Controller: Transfer Function = Kp [1 + 1 / Ti S]

    PID Controller: Transfer Function = Kp [1 + 1 / Ti S + Td S]

    TABULAR COLUMN

    S. No Time Domain Specification P controller PI controller PID controller

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    Model Graph

    RESULT

    Thus the design of P, PI and PID controller was done.

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    DESIGN OF LAG AND LEAD COMPENSATOR

    AIM

    To design and implement the suitable lag and lead compensator for a given linear system

    to improve the performance.APPARATUS REQUIRED

    1. Transfer function and compensator

    2. Computer interface chord

    3. Patch chords

    THEORY

    LAG COMPENSATOR

    A compensator having the characteristics of a Lag network is called a lag

    compensator. If a sinusoidal signal is applied to a lag network, then in steady state the output

    will have a phase lag with respect to input.

    Lag compensation results in a large improvement in steady state performance but

    results in slower response due to reduced bandwidth. The attenuation due to the lag compensator

    will shift the gain cross over frequency to a lower frequency point where the phase margin is

    acceptable.

    The general form of lag compensator transfer function is given by:

    G(S) = (S+T) / (S+P) = (S + 1/T) / S + 1/BT Where, T > 0 and B >1

    LEAD COMPENSATOR

    A compensator having the characteristics of a Lead network is called a Lead

    compensator. If a sinusoidal signal is applied to the lead network, then in steady state the output

    will have a phase lead with respect to input.

    Lead compensation increases the bandwidth, which improves the speed of

    response and also reduces, whereas there is a small change in steady state accuracy. Generally,

    Lead compensation is provided to make an unstable system as a stable system.

    A Lead compensator is basically a high pass filter so it attenuates high frequency

    noise effects. If the pole introduced by the compensator is not cancelled by a zero in the system,

    then lead compensation increases the order of the system by one.

    The general form of Lead compensator transfer function is given by:

    G(S) = (S+T) / (S+P) = (S + 1/T) / S + 1/aT Where, T > 0 and a

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    Type II Order System Performance

    Without Lag Compensator

    1. Connections are given as per the circuit diagram.

    2. Switch on the power supply.

    3. Apply step input.

    4. Set Pb = 100%

    5. Measure the time domain specification of the II order system from the waveform.

    With Lag Compensator

    1. Connections are given as per the circuit diagram.

    2. Switch on the power supply.

    3. Apply step input.

    4. Set Pb = 100%

    5. Measure the time domain specification of the II order system from the waveform.

    6. Compare the performance with and without lag compensator.

    TABULAR COLUMN

    S. No Time Domain Specification Without Lag With Lag

    PROCEDURE

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    Type II Order System Performance

    Without Lead Compensator

    1. Connections are given as per the circuit diagram.

    2. Switch on the power supply.

    3. Apply step input.

    4. Set Pb = 100%.

    5. Measure the time domain specification of the I order system from the waveform.

    With Lead Compensator

    1. Connections are given as per the circuit diagram.

    2. Switch on the power supply.

    3. Apply step input.

    4. Set Pb = 100%

    5. Measure the time domain specification of the I order system from the waveform.

    6. Compare the performance with and without Lead compensator.

    TABULAR COLUMN

    S. No Time Domain Specification Without Lead With Lead

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    Model Graph (Lead Compensator)

    Model Graph (Lead Compensator)

    RESULT: Thus the lag and lead compensator of the given system is implemented and the

    performance was compared.

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    TRANSFER FUNCTION OF SEPARATELY EXCITED

    DC SHUNT GENERATOR

    AIM

    To determine the transfer function of the given Separately Excited DC Shunt generator.

    NAME PLATE DETAILS

    FUSE RATING

    Motor:125% of full load current (rated current)

    Generator:125% of full load current (rated current)

    APPARATUS REQUIRED

    S.No Name of the apparatus Type Range Quantity

    1

    2

    3

    4

    5

    6

    7

    8

    Ammeter

    Ammeter

    Ammeter

    Voltmeter

    Voltmeter

    Rheostat

    Rheostat

    Single Phase Variac

    MC

    MC

    MI

    MC

    MI

    Wire wound

    Wire wound

    -

    (0-10A)

    (0-2A)

    (0-300mA)

    (0-300V)

    (0-300V)

    250, 2A

    350, 1.5A

    230V/ (0-270V)

    1

    1

    1

    1

    1

    1

    1

    1

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    FORMULAE

    1.Generated EMF Constant (Kg) = Eg / Ifin Volts / Amps (From the Graphs)

    2. Field Resistance (Rf) = Vf/ If

    3. Effective Resistance (Reff) = VL/ IL inVolts / Amps (From the Graphs)

    Where, VL = Change in load voltage in volts

    IL = Change in load current in amps

    4. Load Resistance (RL) = PL/ IL2

    Where, RL =Load Resistance in Ohms

    PL = Power of Load in Watts

    IL = Total Load current in Amps

    5. Field Inductance Lf

    Where, Xf=(Zf2Rf

    2)

    Xf= 2f Lf

    Lf= Xf/ 2f

    f = frequency of applied source in hertz

    6.Transfer function

    Eg(s) Ef(s) = (No Load)

    Vt (s) / Ef(s) = (Load)

    PRECAUTION

    1. The motor field rheostat should be kept at minimum resistance position.

    2. The motor armature rheostat should be kept at maximum resistance position.

    3. At the time of starting, the motor should be in no load condition.

    (Kg/ Rf)

    (1+ (Lf/ Rf) S) (1+ (Reff/ RL))

    (Kg/ Rf)

    (1+ (Lf/Rf) S)

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    PROCEDURE

    To find out Generated EMF Constant (Kg)

    1. Connections are given as per the circuit diagram.

    2. The motor is made to run at the rated speed.

    3. The generated emf is noted for various values of field current.

    4. The voltage across the field winding is also measured

    5. From the OCC curve Back Emf constant is calculated.

    To find out Field Impedance (Zf)

    1. Connections are given as per the circuit diagram.

    2. Using single phase variac the supply voltage is varied.

    3. The corresponding reading of field currentis noted for different values of applied voltage.

    4. From the noted readings the field Impedance is calculated.

    RESULT

    Thus the transfer function of separately excited DC shunt generator is determined.

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    TRANSFER FUNCTION OF ARMATURE AND FIELDCONTROLLED DC SHUNT MOTOR

    AIM

    To determine the transfer function of the given armature and field controlled DC shuntmotor.

    NAME PLATE DETAILS

    FUSE RATING:

    125% of rated current (full load current)

    APPRATUS REQUIRED

    S.No Name of the apparatus Type Range Quantity

    1

    2

    3

    4

    5

    6

    7

    8

    9

    10

    11

    Ammeter

    Ammeter

    Ammeter

    Voltmeter

    Voltmeter

    Voltmeter

    Rheostat

    Rheostat

    Rheostat

    Tachometer

    Single Phase Variac

    MC

    MC

    MI

    MC

    MC

    MI

    Wire wound

    Wire wound

    Loading

    Digital

    -

    (0-15A)

    (0-2A)

    (0-10A)

    (0-300V)

    (0-50V)

    (0-300V)

    250, 2A

    50, 5A

    10A, 230V

    -

    230V / (0-270V)

    1

    1

    1

    1

    1

    1

    1

    1

    1

    1

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    FORMULAE

    1. Inertia Constant (J) ={{(Vav* Iav) / (Nav* N)}(60/2)2((t1*t2) /(t1-t2))} Kg-m

    2

    Where, Vav (V1+V2) / 2

    Iav (I1+I2) / 2Nav(N1+N2) / 2

    NSmall Change in Speed (i.e) N1~N2

    t1Time for fall of speed from 1500 rpm to 750 rpm in no load conditionin seconds.

    t2Time for fall of speed from 1500rpm to 750rpm in load condition inSeconds

    2. Viscous Friction Co-Efficient (f) =(2/60)2(J /2) (N12~N22) in N-m / rad /Sec

    Where, JInertia Constant in Kg-m2

    Angular displacement in rad / Sec

    = (2Nav/60)

    3. Back EMF Constant (Kb) =(Va-IaRa) / (2N/60) in N-m / Amps

    4. Torque T = (S1~S2) (R+ t/2) 9.81 in N-m.

    Where, R- Radius of the Break drum in m.

    t- Thickness of the Belt in m.

    S1, S2- Spring balance reading in Kg.

    5. Motor Gain Constant (Km) = KT/ (Raf)

    Where KT= KT' (Current through the Armature / Rated Current of the Motor)

    KT'= T/ Ia(From the Graphs)

    6. Motor Time Constant (a) = La/ Ra.

    Where, Xa=(Za2

    -Ra

    2

    )

    Xa= 2f La

    La= Xa/ 2f

    7. Transfer function Q(s) / E(s) =[KT/ (Raf)]

    S{ [1+ (La/Ra) S] [1+ (J/f) S]+ [KTKb/(Raf)]}

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    THEORY

    Ra = Armature resistance in ohms.

    La= Armature inductance of the winding in Henry.

    Ia= Armature current in Amps.

    If = Field current in Amps

    E= Applied voltage in Volts.

    Eb=Backemf in Volts.

    Tm =Torque developed by the motor in N-m

    =Angular displacement of motor shaft in radian.

    J= Equivalent of moment of inertia of motor and load referred to motor shaft in kg-m2

    f=Equivalent viscous friction coefficient of motor and load referred to motor shaft inN-m / rad / Sec.

    Air gap flux is proportional to the field current because the DC motor should operatein linear magnetization curve for servo application.

    (i.e) If KfIf Where, Kf is the Proportionality constant

    The torque developed by the motor is proportional to the product of armature currentand air gap flux.

    (i.e) Tm Ia

    IaKfIf

    = K1Ia KfIf

    We know that Ifis constant for armature controlled motor.

    (i.e) Tm = (K1 Kf If ) Ia

    Tm= KT Ia Where, KTis themotor torque constant

    Back emf of the emf of motor is proportional to the speed.

    (i.e) Eb d ()/ dt

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    Prepared by G.Panneerselvam, Vel Tech Multi Tech

    Eb = Kb d ()/ dt -------------------------1Where, Kbis the back emf constant in volt / rad /sec

    Loop equation of armature circuit

    Va= Lad (Ia)/dt +RaIa+Eb ------------------ 2

    Torque equation is

    J d2/dt2 +f d/dt = Tm

    =KTIa--------------3

    Taking Laplace transform of Equations 1,2, & 3

    From Eq (1) Eb(s) = KbS (s)------------ 4

    From Eq (2) LaS Ia(s) +RaIa(s) = V(s) - Eb(s)

    (LaS +Ra) Ia(s) = (V(s) - KbS (s))

    Ia(s) = {(V(s) - KbS (s) / (LaS +Ra)}

    From Eq (3) J S2 (s) +f S (s) = Tm(s)

    (J S2 +f S) (s) = Tm(s) = KTIa(s)

    (J S2 +f S) (s) = KTIa(s)

    (J S2 +f S) (s) = KT{(E(s) - KbS (s) / (LaS +Ra)}

    (JS2 +f S) (s) = KTE(s) - KTKbS (s)

    (LaS +Ra) (LaS +Ra)

    (JS2 +f S) (s) +KTKbS (s) = KTE(s)

    (La S +Ra) (LaS +Ra)

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    EC2259 Electrical Engineering And Control System Lab Manua

    To find out Torque Constant (KT)

    1. Connections are given as per the circuit diagram.

    2. The DC supply is given by closing the DPST switch.

    3. The field current is kept constant.

    4. The motor is made to run at the rated speed.

    5. The various values of Iaspring balance readings are noted

    6. Torque is calculated and plotted from the graph by adjusting the slope, torque constantKT is determined

    To find out Back Emf Constant (Kb)

    1.Connections are given as per the circuit diagram.

    2. The motor is made to run at the rated speed.

    3. At rated speed the supply voltage and armature value readings are noted.

    4. The Back Emf constant is calculated.

    To find out Armature resistance (Ra)

    1. Connections are given as per the circuit diagram.

    2. The DC supply is given by closing the DPST switch.

    3. By adjusting the loading rheostat the various values of Ia and Va are noted.

    4. The armature resistance is calculated by the application of formula.

    To find out Armature inductance (La)

    1. Connections are given as per the circuit diagram.

    2. Using single phase variac the supply voltage is varied.

    3. The corresponding reading of Ia are noted for different values of applied voltage

    4. Then Za and La are calculated by using the formula.