MAPUA INSTITUTE OF TECHNOLOGYDepartment of Physics

E401: MAGNETIC FIELD AND MAGNETIC FORCE

REYES, Mary Grace G.2013108107 BSCpE-2 Group 5PHY13L-B5

Engr. Ericson D. DimaunahanInstructorJuly 31, 2015ANALYSISCONCLUSION

SCORE:

Title Page /30Sample Computation/GraphsSigned Data Sheet

Analysis /15Conclusion /20Application /15Presentation /20

TOTAL

After the experiment was done we must be familiarized with the behaviour of magnetic fields around the combination of poles of permanent magnets, figure out the magnetic force’s magnitude on a current-carrying wire, discern about the characteristics of the relationships between magnetic field and magnetic force, length, current, and orientation of current carrying wire.

APPLICATION

REFERENCES

Part 1. Magnetic Field of Permanent Magnets

Low Voltage AC/DC Power Supply Setting: digital balance initial reading: Voltage: maximum 0 gram Current: I= 5 Amps Current Loop: (choose if any), SF _41__

Number of magnets Magnetic force in gram

Magnetic force in Newton,

____ g x ( 1kg1000g

) x (9.8

m/s2)2 0.6 g 5.88 x 10-3 N

Low Voltage AC/DC Power Supply Setting: digital balance initial reading: Voltage: maximum 0 gram Current: 0 to 5 Amps with 0.5 incrementCurrent Loop: (choose if any), SF _41__

Current, I (Amps) Magnetic force in gram

Magnetic force in Newton,

____ g x ( 1kg1000g

) x (9.8

m/s2)0.5 0.2 g 1.96x10-3 N1.0 0.5 g 4.9x10-3 N

Low Voltage AC/DC Power Supply Setting: digital balance initial reading: Voltage: maximum 0 gram Current: 2 Amps

Current Loop: all

Current LoopLength, L

Magnetic force in gram

Magnetic force in Newton,

____ g x ( 1kg1000g

) x (9.8

m/s2)SF 40 1.2 cm 0.1 g 9.8x10-4 NSF 37 2.2 cm 0.2 g 1.96x10-3 N

Magnetic force in Newton, ____ g x ( 1kg1000g

) x (9.8 m/s2)

Low Voltage AC/DC Power Supply Setting: digital balance initial reading: Voltage: maximum 0 gram Current: 2 Amps (maximum allowable current)Coil: Current Balance Accessory Unit

Angle Magnetic force in gram

Magnetic force in Newton,

____ g x ( 1kg1000g

) x (9.8

m/s2)10 0.1 g 9.8x10-4 N20 0.2 g 1.96x10-3 N

Sample Computation

Computing Magnetic force in Newton from grams

Part 2a.

Magnetic Force = 0.6 g

0.6g x x (1kg1000g

) x (9.8 m/s2) = 5.88x10-3 N

Magnetic Force= 5.88x10-3

Part 2. Magnetic force on current- carrying conductor a. Magnetic Force and Magnetic Fieldb. Magnetic Force and Currentc. Magnetic Force Length of Current Loopd. Magnetic Force and Orientation of Coil