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    PAP 118 Physics Lab 1aExperiment 1

    Motion in a Viscous Medium

    Name of Student : EDWIN ANG CHING JITTName of Partner : CHENG SHENG DA JOWELLDate of Experiment: 24-AUG-2011

    Date of Report : 27-AUG-2011

    Aim

    The aim of this experiment is to measure the terminal velocity of spherical beads falling

    under gravity in a liquid, and hence determine its viscosity using Stokes law.

    Int roduct ion

    When a stationary solid object is complete or partially immersed in a fluid, it experiences

    an upthrust or buoyant force. According to Archimedes principle, this buoyant forceBis given by

    ,gVB s

    where is the density of the fluid, Vsis the immersed volume of the solid object, andgis

    the acceleration due to gravity. As its name implies, this force acting on the solid object

    by the fluid is always directed upwards.If the solid object now moves through the fluid, it will have to push the fluid out

    of the way. By Newtons third law, the fluid pushes back on the object with an equally

    strong reaction in the opposite direction. This is experienced by the object as fluidresistancef to its motion. Depending on the speed vof the solid object, as well as the

    nature of the fluid, this fluid resistance can be proportional to the speed, i.e. f~ v(skin

    drag or viscous drag), or proportional to the square of the speed, i.e. f ~ v2(form drag or

    inertial drag). Viscous drag is the dominant fluid resistance at low Reynolds numbers,

    whereas inertial drag is the dominant fluid resistance at high Reynolds numbers. The

    Reynolds number

    vLRe

    is a dimensionless ratio of inertial forces to viscous forces. Here, is the density of the

    fluid, vis the typical speed of the fluid flow, Lis the typical distance the fluid has to flow

    around, and is the viscosity of the fluid.

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    For a sphere of radius rmoving with speed vin an infinite fluid with viscosity ,

    the viscous drag has been worked out by Sir George Stokes in 1851 to be

    ,6 vrf (1)

    if the fluid at the surface of the sphere is always at rest with respect to the sphere. This

    has since come to be known as Stokes law. In this experiment, spherical beads aredropped into a highly viscous liquid detergent and allowed to reach terminal velocity vT.

    At terminal velocity, the three forces acting on the bead (see Figure 1) balance each other,

    and we have

    ,3

    46 3 grvrBfmg T

    which can be rewritten as

    .6

    3

    4 3

    Trv

    grmg

    (2)

    Through careful measurements of m, the mass of the bead, r, the radius of the bead, and

    vT, the terminal velocity of the bead, this equation can be used to determine , theviscosity of the liquid detergent.

    Figure 1. Freebody diagram of spherical bead falling under gravity through a viscous fluid. Besides its

    weight W= mg, the bead is also acted upon by the buoyant forceB, and the drag forcef.

    Experimental

    Preliminary Observations

    In the first part of the experiment, we weighed beads of 3 different sizes (B1, B2 and B3)

    immersed in a beaker of liquid detergent, when it is (a) suspended on a thread; (b) resting

    on the bottom of the beaker; (c) suspended on the same thread as in (a); (d) pulledupwards slowly; and (e) allowed to fall slowly. These are recorded as (a) R1, (b) R2, (c)

    R3, (d) R4 and (e) R5 respectively, where R1 to R5 represents the readings on the

    electronic balance for each of the 5 cases from (a) to (e) respectively. Before each

    reading is taken, the beaker of liquid detergent is allowed to settle on the electronicbalance without the bead until a steady reading is observed; then, the electronic balance is

    tared for calibration. Also, the side window of the casing on top of the electronic balance

    is closed before any reading is taken to minimize the effect of moving air on the accuracyof the readings by applying undue downward force on the balance, thus, introducing new

    variables that might add on to the true readings.

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    Before recording R1, R2 and R3, we took care to allow the bead to come to rest, and the

    reading on the electronic balance to stabilize. While recording R4 and R5, we noted the

    extent of the fluctuations in the electronic balance readings, and also any increasing ordecreasing trends in the average reading. Consider 5 readings from R1 to R5 respectively

    to be one complete set of readings, 3 sets of readings (i.e. 1st, 2

    nd, 3

    rdreading) are taken

    for bead of each size. For reading R1, the average from the 3 sets of readings arecalculated; then, the averages of R2 to R5 are also calculated. The list of averages fromR1 to R5 are tabulated as the 4

    thset of reading. The 4

    threading for beads B1, B2, and B3

    respectively are taken as the data to support the explanation of the physical forces present

    for all cases (a) to (e).

    Measurement of Terminal Velocity

    To measure the terminal velocities of beads falling through the Mama Lemon liquid

    detergent, we set up the experiment as shown in Figure 2. First we ensured that the

    column is vertical, by viewing it from three different angles. Then we dropped five beads

    of each size, each as close to the centre of the column as possible. If a bead drifted tooclose to the wall of the column, the trial was rejected, and another bead of the same size

    was dropped again to replace the trial.

    Figure 2. Experimental setup to measure the terminal velocity of a bead falling through a liquid detergent.

    For each accepted trial, we recorded the stopwatch times t when the bottom of the bead

    reached each 2-cm mark x on the metric taped stuck to the column. We then plotted agraph of x against t for each accepted trial. Fitting the graph for large times to a straight

    line, we determined the terminal velocity vT for a trial as the slope of the straight line.

    For each bead size, we averaged vTover the five trials, before we use Equation (2) todetermine the viscosity of the liquid detergent.

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    Resul ts & Discussions

    Preliminary Observations

    Small Bead (B1)

    Case (1stReading)/g0.001

    (2n

    Reading)/g0.001

    (3r

    Reading)/g0.001

    (Mean Reading)/g0.001

    Compare

    R1 0.079 0.078 0.078 0.078 ~Same

    R2 0.067 0.068 0.069 0.068

    R3 0.080 0.081 0.079 0.080 ~Same

    R4 0.022 0.019 0.027 0.023 Lowest

    R5 0.086 0.084 0.083 0.084 Highest

    Medium Bead (B2)

    Case (1stReading)/g0.001

    (2n Reading)/g0.001

    (3r Reading)/g0.001

    (Mean Reading)/g0.001

    Compare

    R1 0.138 0.123 0.130 0.130 Same1R2 0.191 0.189 0.188 0.189 ~Highest

    R3 0.134 0.129 0.127 0.130 Same1R4 0.000 0.016 0.042 0.019 Lowest

    R5 0.190 0.189 0.191 0.190 ~Highest

    Large Bead (B3)

    Case (1stReading)/g

    0.001

    (2n

    Reading)/g

    0.001

    (3r

    Reading)/g

    0.001

    (Mean Reading)/g

    0.001

    Compare

    R1 0.702 0.703 0.704 0.703 ~Same

    R2 0.920 0.924 0.923 0.922

    R3 0.700 0.702 0.701 0.701 ~Same

    R4 0.470 0.599 0.522 0.530 Lowest

    R5 0.946 0.949 0.935 0.943 Highest

    Firstly, a beaker of detergent is placed on an electronic balance. Then, the balance is tared

    so that the effect of the weight of beaker is not reflected in the reading and the change isreading is solely due to the cases R1 to R5 respectively.

    The small bead (B1) was first used to test for cases R1 to R5. However, the data in R2

    showed a contradiction to the predicted result from the analysis of physical forces.

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    Analysis of Physical Forces

    R1/R3In figure 3, as the bead is in equilibrium, there

    should be zero net force acting on the bead. Thus,

    the forces follow the equation:

    such that, W=Weight of bead

    B =Buoyant Force on bead

    T =Tension of thread on bead

    According to Newtons 3rd

    Law, the buoyant

    force by detergent on bead will have an equal

    and opposite force by bead on detergent and, thus,

    on the electronic balance (B).

    In figure 4, as the bead is in equilibrium, there

    should be zero net force acting on the bead. Thus,the forces follow the equation:

    () ()

    such that: R =reaction force by table on

    electronic balanceB =reaction force of B

    W(eb) =weight of electronicbalanceW(bk)=weight of beaker

    From figure 4, the reading on the electronic

    balance is proportional to the sum of W(bk) andB, as both forces act downwards on the sensor of

    the balance. However, as the balance is tared, W(bk) equals constant zero. As such,

    reading is dependent only on B. From this, I can also deduce that, since B=B and B isconstant anywhere in the detergent, the reading should be independent of the relative

    position of bead in the detergent, provided the bead is fully submerged and the density of

    detergent is the same throughout.

    With this deduction, cases R1 and R3 are the same and can be represented in the same

    way. However, there is a possibility that R3 values may be lower than R1. As R2

    involved submerged part of the thread in the detergent, when the thread is then raised totake reading for R3, some detergent may stick to the thread and be lifted above the

    surface of the detergent. Thus, there may be a net decrease in the mass of detergent in the

    beaker. This can be proven if by lifting the bead out of the detergent, and allowing alldetergent to drip back into the beaker, the balance shows a negative reading.

    Figure 3: Free-body diagram of Bead(R1/R3)

    Figure 4: Free-body diagram of

    Electronic Balance (R1/R3)

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    R2In figure 5, as the bead is in equilibrium, there

    should be zero net force acting on the bead. Thus,the forces follow the equation:

    such that, W=Weight of bead

    B =Buoyant Force on beadN =Reaction Force by Electronic

    Balance on Bead

    According to Newtons 3rd

    Law, N will have anequal and opposite force by bead on electronic

    balance (N).

    In figure 6, as the bead is in equilibrium, thereshould be zero net force acting on the bead. Thus,

    the forces follow the equation:

    () ()

    such that: B =Reaction force of B

    N =Reaction force of N

    From figure 6, the reading on the electronicbalance is proportional to the sum of Band N,

    as all 3 forces act downwards on the sensor of thebalance. Comparing this to the reading in R1

    which is proportional to only B, the reading in

    R2 should be larger than R1. However, the R2

    reading for B1 in the table (mean = 0.068g) is

    lower than R1 (mean = 0.078g), thus, reflecting acontradiction with the predicted result.

    To address this contradiction, we regarded the reading for R2 in B1 as an anomaly, andrepeated the experiment with B2 and B3. The results in B2 and B3 show conclusively

    that the reading for R2 should be larger than R1.

    Figure 6: Free-Body Diagram of

    Electronic Balance (R2)

    Figure 5: Free-body diagram of Bead (R2)

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    R4

    In figure 7, as the bead is in equilibrium when itis travelling at constant velocity, there should be

    zero net force acting on the bead. Thus, the

    forces follow the equation:

    such that, W=Weight of bead

    B =Buoyant Force on bead

    T =Tension of thread on bead

    D = Drag on bead

    According to Newtons 3rd

    Law, D will have an

    equal and opposite force by bead on electronic

    balance (D).

    In figure 8, as the bead is in equilibrium, there

    should be zero net force acting on the bead. Thus,the forces follow the equation:

    ()()

    such that: B =Reaction force of B

    D =Reaction force of D

    From figure 6, the reading on the electronicbalance is proportional to (B-D), as D acts in

    the direction opposite to B. As it is impossible

    for a human hand to lift bead up continuously at

    exactly the same velocity, there is a large margin

    of human error, resulting in a large range offluctuating readings. However, the readings show a general decreasing trend as the

    upward velocity increases from rest. This is because Drag (D) is proportional to speed at

    relatively slow speeds; thus, as the magnitude of velocity (i.e. the speed) increases, D alsoincreases, resulting in a decrease in (B-D) for D=D.

    In addition, it is possible for the reading to turn negative because B

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    R5In figure 9, as the bead is initially in

    disequilibrium, there should be non-zero netforce acting on the bead. Thus, the forces follow

    the equation:

    such that, W =Weight of beadB =Buoyant Force on bead

    D =Drag of detergent on bead

    Drag Force(D) changes as the bead acceleratedownwards in the detergent due to gravity. As

    speed of bead increases, D increases and, thus,

    (B+D) increases. Equilibrium is attained when:

    Such that, = Drag on bead at its

    terminal velocity

    Then, bead will travel downwards at constant

    speed towards the base of the beaker.

    In Figure 10, as the bead is in equilibrium, thereshould be zero net force acting on the bead. Thus,

    the forces follow the equation:

    () ()

    Such that, B =Reaction force of BD =Reaction force of D

    From Figure 10, the reading on the electronic balance is proportional to (B+D). As such,the reading R5 should stabilise when the terminal velocity is reached, when drag(D) takes

    a fixed value .

    From R2, From R5, As such, N=;

    N= D at terminal velocity(vT);

    (B+N)=(B+Dat vT).

    Thus, reading R2=reading R5 at vT. This is supported by reading R2 (mean = 0.189g) and

    R5 (mean = 0.190g) in B2.

    Figure 10: Free-Body Diagram of

    Electronic Balance (R5)

    Figure 9: Free-Body Diagram of Bead (R5)

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    Measurement of Terminal Velocity

    The 3 tables below show the time taken for beads (B1, B2, B3) to travel a distance of5cm downwards for 9 different intervals along the plastic column. There are 5 repeated

    measurements for bead of each size.

    Reading x/cmT1/s for B1

    1a 1b 1c 1d 1e

    1 5--10 30.90 31.81 31.05 30.75 30.98

    2 11--16 29.97 31.10 30.80 30.30 30.75

    3 17--22 29.69 29.96 29.90 30.10 30.68

    4 23--28 29.41 30.19 30.18 30.15 30.70

    5 29--34 29.93 29.60 30.17 29.58 29.80

    6 35--40 29.69 29.50 29.61 28.67 28.96

    7 41--46 28.40 28.81 29.54 28.70 29.05

    8 47--52 28.53 28.57 28.89 29.03 28.939 53--58 28.40 28.53 28.87 28.90 28.80

    Reading x/cmT3/s for B3

    3a 3b 3c 3d 3e

    1 5--10 8.87 9.08 9.04 9.07 8.97

    2 11--16 8.74 8.34 8.56 8.89 8.89

    3 17--22 8.37 8.53 8.71 8.80 8.764 23--28 8.49 8.31 8.30 8.53 8.81

    5 29--34 8.29 8.37 8.19 8.19 8.56

    6 35--40 8.41 8.50 8.56 8.20 8.30

    7 41--46 8.30 8.75 8.74 8.75 8.42

    8 47--52 8.47 8.76 8.40 8.64 8.68

    9 53--58 8.23 8.65 8.35 8.56 8.54

    Reading x/cmT2/s for B2

    2a 2b 2c 2d 2e

    1 5--10 17.87 17.95 17.94 17.97 17.79

    2 11--16 17.33 17.90 17.79 17.97 17.60

    3 17--22 17.02 16.90 16.91 17.13 17.35

    4 23--28 16.60 16.98 17.03 16.88 17.00

    5 29--34 16.80 17.03 16.97 16.85 17.106 35--40 16.50 16.98 17.04 16.92 17.16

    7 41--46 16.88 17.22 17.12 16.68 16.95

    8 47--52 16.79 16.97 17.09 16.85 16.62

    9 53--58 16.84 17.03 16.99 16.89 16.73

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    Graph of time taken for a bead to travel 5cm (s) against reading number, which represents

    the distance (x) along the plastic column, is plotted for B1, B2, and B3 respectively.

    Small Bead B1

    Medium Bead B2

    T1

    T2

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    The 3 graphs above show the rough fit of a downward trend for the initial readings. From

    the graphs, time (T) appears to approach a particular constant as the gradient of graph

    tend towards zero. As velocity is displacement per unit time, by fixing the value of

    displacement for each reading at 5cm, when the change in time taken(T) for multiple

    subsequent readings (near the final reading9

    th

    reading) becomes increasingly smaller,this means that the velocity of bead also approaches a constant value i.e. terminal

    velocity (vt).

    Referring to all 3 graphs above, the time taken (T) generally appears to approach a

    constant after the 5th

    reading (29-34cm). Therefore, the average time taken can becalculated by taking only the values of (T) for the last 5 readings5

    th, 6

    th, 7

    th, 8

    th, and 9

    th

    reading.

    Large Bead (B3)T3

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    The 3 tables below show the mean time taken for a bead to travel 5cm for measurements

    of time when value of x exceeds 29cmaverage of readings 5 to 9for all 5 sets of

    measurements respectively.

    Small Bead (B1)

    Reading 1a 1b 1c 1d 1eAverage reading

    for x>29/s28.99 29.00 29.42 28.98 29.11

    Final Average/s 29.10

    Medium Bead (B2)

    Reading 2a 2b 2c 2d 2e

    Average reading

    for x>29/s16.76 17.05 17.04 16.84 16.91

    Final Average/s 16.92

    Large Bead (B3)

    Reading 3a 3b 3c 3d 3e

    Average reading

    for x>29/s8.34 8.61 8.45 8.47 8.50

    Final Average/s 8.47

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    The table below shows the measurement of mass of bead B1, B2, and B3 respectively

    with 3 repeated readings, in order to calculate the average mass of bead. Calibrated

    electronic balance was used.

    M1/g 0.001 M2/g 0.001 M3/g 0.001 /g 0.001

    B1 0.069 0.070 0.070 0.070B2 0.182 0.182 0.182 0.182

    B3 0.937 0.936 0.937 0.937

    The table below shows the measurement of diameter of bead B1, B2 and B3 respectively

    with 3 repeated readings, in order to calculate the average diameter of bead. Micrometer

    Screw Gauge was used. Then, the average radius of bead for all 3 sizes are determined.

    D1/mm 0.01 D2/mm 0.01 D3/mm 0.01 /mm 0.01 /mm 0.005B1 4.58 4.58 4.59 4.58 2.290

    B2 6.31 6.31 6.32 6.31 3.155

    B3 10.95 10.95 10.95 10.95 5.575

    Computation of uncertainty values

    Calculate of absolute uncertainty of VT

    VT

    x

    x

    2

    t

    t

    2

    V

    T

    For small bead (B1),

    )17182.0(10.29

    01.0

    0.5

    1.0 22

    TV

    = 3.436933 x 10-3

    cm s-1

    = 3.4 x 10-5

    m s-1

    For medium bead (B2),

    )29551.0(92.16

    01.0

    0.5

    1.0 22

    TV

    = 5.91278 x 10-3

    cm s-1

    = 5.9 x 10-5m s-1

    For large bead (B3),

    )590319.0(47.8

    01.0

    0.5

    1.0 22

    TV

    = 1.18269 x 10-2

    cm s-1

    = 1.2 x 10-4

    m s-1

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    Calculation of absolute uncertainty of radius

    rd

    2, Where dis diameter of bead, r is radius of bead

    For beads of all sizes

    2

    01.0r

    = 0.005 mm

    = 5 x 10-3

    m

    Calculation of absolute uncertainty of volume of sphere

    Vb 3

    r

    r

    2

    Vb, Where Vbis volume of bead

    For small bead (B1),

    )3031.50()290.2(

    )005.0(3

    2

    bV

    = 0.329497 mm3

    = 3.3 x 10-10

    m3

    For medium bead (B2),

    )549.131()155.3(

    )005.0(3

    2

    bV

    = 0.625430 mm3

    = 6.3 x 10-10m3

    For large bead (B3),

    )810.725()575.5(

    )005.0(3

    2

    bV

    = 1.95285 mm3

    = 2.0 x 10-9

    m3

    Calculation of ViscosityUsing the average values of VT, the radius of the beads, mass of the bead, density of the

    detergent, we can calculate the viscosity using equation (2);

    For smallest bead

    .)17182.0)(229.0(6

    )981)(207.1()229.0(3

    4)981(070.0

    3

    = 12.2800 g cm s-2

    / cm2s

    -1

    = 1.22800 Pa s

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    = 1228.0 m Pa s

    = 1228 cps

    Difference compared to accepted reading = (14101228)/(1410) x 100%

    = 12.9%

    For medium bead

    .)29551.0)(3155.0(6

    )981)(207.1()3155.0(3

    4)981(182.0

    3

    = 12.9620 g cm s-2

    / cm2s

    -1

    = 1.29620 Pa s

    = 1296.20 m Pa s

    = 1296 cps

    Difference compared to accepted reading = (14101296)/(1410) x 100%

    = 8.08511%For large bead

    .)590319.0)(5575.0(6

    )981)(207.1()5575.0(3

    4)981(937.0 3

    = 9.63800 g cm s-2

    / cm2s

    -1

    = 0.963800 Pa s= 963.800 m Pa s

    = 964 cps

    Difference compared to accepted reading = (1410964)/(1410) x 100%= 31.6%

    Average = (1228.0 + 1296.2 + 963.8) / 3

    = 1162.7 m Pa s

    = 1163 cps

    Difference compared to accepted reading = (14101163)/(1410) x 100%

    = 17.5%

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    Calculation of absolute uncertainty of viscosity

    V

    b

    Vb

    2

    r

    r

    2

    V

    T

    VT

    2

    For small bead,

    1228172.0

    10*4.3

    290.2

    005.0

    10*0.5

    10*3.32

    522

    8

    10

    = 8.5 cps

    For medium bead,

    1296296.0

    10*9.5

    3155.0

    005.0

    10*3.1

    10*3.62

    522

    7

    10

    = 21.5 cps

    For large bead,

    964590.0

    10*2.1

    5575.0

    005.0

    10*3.7

    10*0.22

    422

    7

    9

    = 9.04 cps

    As such, average of = (8.5 + 21.5 + 9.04) / 3= 13.0 cps

    From the calculated results above, we can see that the viscosity values for the small andmedium beads are relatively nearer to the actual value of 1410cps, whereas the viscosityvalue for the large bead drifted quite far away from the actual value, with a deviation of

    31.6% (highest among the 3).

    In overall, this deviation can also be seen as possible evidence to prove the direct causal

    relationship between size of bead and the viscosity of the liquid detergent. This means

    that change in bead size may directly cause a change in the viscosity of detergent aroundits motion pathway.

    On the other hand, the constant negative deviation from the actual viscosity for all 3

    values of viscosity being lower than the actual valuecan also suggest that detergent is anon-Newtonian fluid, making the procedure of determination of viscosity in this

    experiment less ideal as the final value would be less predictable.

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    Systematic errorThe true viscosity value of 1410cps is most determined in a highly controlled

    environment where factors like surrounding temperature, and pressure are carefullymaintained to be constant. Besides, the equipment that we use may be inferior to the

    equipment used to determine the true value in terms of accuracy and precision.

    Human errorIn the measurement of time with a stopwatch, human reaction error can be a significant

    factor in determining the accuracy of the measurement. For we have to take readings

    while the bead is in motionfalling through the column of detergent, the accuracy of thereadings really depend on the reaction time of the person measuring the time and his

    ability to multi-task as he needs to measure time with a stopwatch, while observing the

    scale on column. This effect is amplified with the large bead, as it has a higher terminal

    velocity and will travel faster through the column. As the ratio of human reaction time tothe final measurement of time increases, there is a higher percentage error which might

    explain the large deviation for the large bead (B3) of 31.6% for calculated viscosity value

    through this experiment.

    Conclus ions

    We measured the terminal velocities of beads of three different sizes falling through a

    column of Mama Lemon liquid detergent, and found these to be vT= (171.83.4)*10-5

    m/s, (295.55.9)*10

    -5 m/s, and (59.01.2)*10

    -4 m/s for the small, medium, and large

    beads respectively. Assuming that the viscous drag experienced by the bead is given by

    Stokes law in Equation (1), we inferred the viscosity of the liquid detergent to be1162.713.0 cps. This differs by 17.5% from the accepted value of 1410 cps. We

    believe this deviation is largely due to human error as the time needed for humans toreact consistently produce a random error to our measurement of time. As such, we

    cannot accurately determine the viscosity value as time is one of the few most importantfactors that is used to calculate the final value of viscosity.

    References

    Physics for Scientists and Engineers with Modern Physics 8th

    Edition, by John W. Jewett,Jr. Raymond A. Serway.

    Wikipedia.org

    http://www.physics.unc.edu