Dynamic response of concrete funicular shells with a ...

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Scientia Iranica A (2020) 27(4), 1714{1727

Sharif University of TechnologyScientia Iranica

Transactions A: Civil Engineeringhttp://scientiairanica.sharif.edu

Dynamic response of concrete funicular shells with arectangular base under impulse loads

H. Sabermahany, A. Vafai, and M. Mo�d�

Department of Civil Engineering, Sharif University of Technology, Tehran, Iran.

Received 30 July 2017; received in revised form 4 April 2018; accepted 2 July 2018

KEYWORDSForced linearvibration;Doubly curved shallowshells;Funicular shells;Lagrange equations;Finite elementmethod.

Abstract. Funicular shells are thin, doubly curved shallow shells that are in compressionunder dead weight due to their shape. In this study, an analytical approach is employedto consider the forced linear vibration of concrete funicular shells with a rectangular baseunder impulse loads based on shallow shells theory. Two boundary conditions, simplysupported and clamped, are considered. The solution is obtained by Lagrangian approach.The accuracy of the results was considered by comparing the results with those of �niteelement method. The results indicated that tensile stresses in addition to compressivestresses formed in funicular shells under impulse loads.© 2020 Sharif University of Technology. All rights reserved.

1. Introduction

Reinforced concrete shells are frequently used as roof-ing elements. Shell structures carry load through theirshape rather than material strength. Funicular shellsrepresent a type of shells with a particular shape suchthat, in their membrane state, they carry a speci�cload by pure compression (this load is the shell's deadweight). Concrete is an appropriate material for theconstruction of funicular shells for two reasons. First,funicular shells are primarily subjected to compres-sion, and concrete compressive strength is favorable.Second, concrete has the exibility to form into anyshape, which is necessary for obtaining funicular shellgeometry. The performance of funicular shells sub-jected to dead weight is compressive; nevertheless,other types of stresses may be generated under otherloads. Therefore, investigating the performance of

*. Corresponding author. Tel.: +98 21 6602-2727, Ext. 4214;Fax: +98 21 6601-4828E-mail addresses: [email protected] (H.Sabermahany); [email protected] (A. Vafai);mo�[email protected] (M. Mo�d)

doi: 10.24200/sci.2018.20643

funicular shells subjected to dynamic loads appearsessential. Many researchers have proposed the analysisof funicular shells under various static loads. On theother hand, for dynamic loads, no research is available.However, funicular shells with a rectangular plan aremostly shallow, and the analysis of doubly curvedshallow shells under dynamic loads has been presented.For instance, Bhimaraddi [1] investigated free vibrationof homogenous and laminated doubly curved shallowshells over a rectangular plan form. By applying three-dimensional elasticity equations alongside the assump-tion where the ratio of shell thickness to its middlesurface radius is negligible, as compared to unity, thegoverning equilibrium equations have been reduced todi�erential equations with constant coe�cients. Infact, the complex mathematical manipulations canbe avoided by reducing the governing equations tothose with constant coe�cients and retaining 3-Dcharacteristics of the problem. This goes against thereduction of the governing equations to 2-D cases.The nonlinear free vibration behavior of single/doublycurved composite shallow shell panels was studied bySingh and Panda [2]. A general mathematical model,including the nonlinear higher order terms, was devel-oped. The governing equations were determined by

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H. Sabermahany et al./Scientia Iranica, Transactions A: Civil Engineering 27 (2020) 1714{1727 1715

Hamilton's principle and analyzed through nonlinearFinite Element Method (FEM) steps. The e�ect ofchanging constraint conditions upon the frequenciesof shallow shells with rectangular boundaries wascarried out by Qatu and Leissa [3]. Three edgeswere completely free and the attention was given toa single edge with clamped, simply supported, and freeedge conditions. The Ritz method was employed inorder to obtain accurate results. It was found thatreleasing the constraint of the u-displacement compo-nent (displacement component in x direction) had thelargest e�ect on the fundamental frequencies. Abeet al. [4] presented nonlinear vibration characteristicsof clamped laminated shallow shells. Moreover, both�rst-order shear deformation theory and classical shelltheory were used. Nonlinear equations of motionwere obtained by Hamilton's principle and analyzedby Galerkin's procedure. It was shown that the secondmode responses were very dependent on the �rst mode.Amabili [5] studied geometrically nonlinear vibration ofshallow shells subjected to harmonic excitation. Sim-ply supported boundary conditions were considered.Furthermore, the nonlinear equations of motion weregenerated by Lagrangian approach and solved throughnumerical techniques. Large-amplitude free vibrationof magneto-electro-elastic curved panels was studiedby Shooshtari and Razavi [6]. Electrostatics andmagnetostatics were considered by Gauss's laws, andthe equations of motion were obtained by Donnell shelltheory. Displacements and rotations were presented bytrial functions. Governing nonlinear partial di�erentialequations were transformed into nonlinear ordinarydi�erential equations by using Galerkin method; there-after, they were solved by the perturbation method.The analysis of funicular shells due to various staticloads was carried out in many pieces of research. Vafaiet al. [7] compared experimental values of membranestresses and vertical de ections with FEM results,where good agreement was obtained. Forty-�ve con-crete funicular shells (square bases supported at fouredges) with di�erent rises and types of reinforcementwere loaded up to the failure point with a concentratedcentral load. It was observed that the crack and failureloads were signi�cantly related to the rise of shells.Weber et al. [8] investigated ultimate load for concretefunicular shells by testing ten models with di�erentgeometric features. It was found that the ultimate loadwas dependent on the rise and thickness of the shell;by increasing the rise parameter (square of the ratio ofrise to thickness), the ultimate load will also increase.Moreover, Vafai and Farshad [9] indicated that thefailure load of funicular shells was a�ected by the ageof concrete shell and the amount of reinforcement.Elangovan [10] applied the FEM in order to analyzefunicular shells with clamped boundaries loaded witha uniformly distributed load. The eight-node isopara-

metric elements along with �ve degrees of freedomfor each node were used. The analysis de�nes thezone in which tension is generated and reinforcementis required. Rajasekaran and Sujatha [11] studieddeep funicular shells using Boundary Integral ElementMethod (BIEM). Due to the governing equation fordeep funicular shells being nonlinear, it is di�cult toobtain a closed-form solution in order to determinethe con�guration of deep funicular shells. In addition,an incremental iterative technique along with BIEMwas applied to solve the nonlinear di�erential equation.Lakshmikandhan et al. [12] presented the e�ect ofthe span-to-rise ratio on the performance of concretefunicular shells by applying FEM The results indicatedthat a reduction in the span-to-rise ratio resulted ina reduction in de ection, maximum compression, andmaximum edge beam tension with improved sti�ness.Similar to the previous study, Sivakumar et al. [13]considered the behavior of concrete funicular shellswith a rectangular base under uniformly distributedload. A reduction in membrane stresses and de ectionswas discovered when the rise and thickness increased.Siddesh et al. [14] compared the performances of con-crete funicular shells under concentrated load and theslabs. Analysis was performed via FEM. Six funicularshell units with a rectangular plan of 1� 0:7 m, rise of5 and 10 cm, and thicknesses of 5, 4, and 2 cm wereconsidered. Each shell unit was compared with a slabof the same thickness and dimension. The de ection ofthe shell models was found to be 34% to 83% less thanthat of the slab models. Sachithanantham [15] studiedconcrete funicular shells over a square plan with 0% to16% openings under concentrated load using FEM. Itwas concluded that with an increase in percentage ofopenings, the de ection, membrane stress, and bendingstress of concrete funicular shells also increased up to800%, 6%, and 60%, respectively. Moreover, someother researchers considered the ultimate load alongwith the de ection of concrete funicular shells overa rectangular plan of di�erent dimensions under aconcentrated static load [16{19].

In this paper, a closed-form analytical solution tothe forced linear vibration of concrete funicular shellswith a rectangular base under impulse loads is inves-tigated. Two boundary conditions, simply supportedand clamped, are considered. Step pulse, triangularpulse, and sine pulse are considered as impulse loadtypes that are applied to a rectangular area. Theanalysis is based on the expansion of each displacementcomponent in a double Fourier series, which satis�esthe boundary conditions. Strain-displacement rela-tionships based on shallow shells theory are used tocompute elastic strain energy. After computing kineticenergy, elastic strain energy, and the virtual workcompleted by external forces in terms of displacementcomponents, the equations of motion are obtained by

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Lagrangian approach. Moreover, the analytical solu-tions to the equations of motion are developed via themodal analysis technique. The e�ciency of the analysishas been examined by comparing the results with thoseof FEM. At the same time, the results indicate thattensile stresses in addition to compressive stresses formin funicular shells under impulse loads. On the otherhand, displacements and stresses, especially tensilestresses, under dynamic impulse loads are negligibleup to an amplitude of the load, which is computable.Furthermore, the e�ect of rise and span of the funicularshell pertaining to the time response of the shell isshown.

2. Funicular shell surface over a rectangularground plan

The surface equation of a shallow funicular shell ofdouble curvature, which carries dead weight in itsmembrane state by pure compression, could be givenas follows [20]:

@2Z@x2 +

@2Z@y2 =

gN; (1)

where Z = f(x; y) is the surface equation of thefunicular shell, N is the desired compressive stress,and g is the dead weight of the shell. The followingequation, which is an approximate solution to Eq. (1),is used to de�ne the funicular shell surface over arectangular ground plan [12]:

Z =58gN

1a2 + b2

ha2 � (x� a)2

i �b2 � �y � b�2

�=H

"1� (x� a)2

a2

#2641��y � b�2

b2

375 ; (2)

where a = a=2, b = b=2, and a, b are the lengths ofedges in x and y directions, respectively. H is also therise of the funicular shell. Moreover, Figure 1 showsthe surface generated through Eq. (2). Displacementsof an arbitrary point on the middle surface in x, y, andz directions are u, v, and w, respectively; w is takenpositive inwards.

3. Kinetic energy, strain energy, and virtualwork done by external loads

3.1. Kinetic energyThe kinetic energy T of the shell, by neglecting rotaryinertia, is given by:

T =12�h

aZ0

bZ0

�_u2 + _v2 + _w2� dxdy; (3)

Figure 1. Funicular surface and coordinate system.

where � is the mass density, and h is the thickness ofthe shell. The over dot means a time derivative.

3.2. Strain energyAccording to the shallow shells theory presented inthe work of Velasov, the relationships between middlesurface strains and changes in curvatures with middlesurface displacement components are as follows [20]:

"x =@u@x� rw; (4)

"y =@v@x� tw; (5)

xy =@u@y

+@v@x� 2sw; (6)

�x =@2w@x2 ; (7)

�y =@2w@y2 ; (8)

�xy =@2w@x@y

; (9)

where:

r =@2Z@x2 ; t =

@2Z@y2 ; s =

@2Z@x@y

: (10)

"x, "y, and xy are the middle surface strains, and �x,�y, and �xy are the changes in curvatures and twist ofthe middle surface.

The stress components (�x, �y, and �xy) arelinearly distributed across the thickness of the elasticshell. In addition, the stress resultants alongside thestress couples of the middle surface that are also namedinternal forces (Nx, Ny, and Nxy) and moments (Mx,My, and Mxy) are obtained through the integration of

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the stress distribution over the shell thickness. Therelationships between stress components and internalforces, as well as moments, are [21]:

�zx =Nxh

+12Mx

h3 z; (11)

�zy =Nyh

+12My

h3 z; (12)

�zxy =1

2h(Nxy +Nyx) +

6h3 (Mxy +Myx)z; (13)

where z is the distance from the middle surface.The stress resultant-strain and stress couple-

curvature relations are [20]:

Nx =Eh

1� �2 ("x + �"y); (14)

Ny =Eh

1� �2 ("y + �"x); (15)

Nxy = Nyx =Eh2

1� �1� �2 xy; (16)

Mx = �D(�x + ��y); (17)

My = �D(�y + ��x); (18)

Mxy = �D(1� �)�xy; (19)

where E is Young's modulus, � is the Poisson's ratio,and D = Eh3=[12(1� �2)].

If the displacement components are calculated,the middle surface strains and changes in curvatures byEqs. (4) to (10) and the internal forces along with theinternal moments and stress components by Eqs. (11)to (19) can be obtained.

The following equation presented the strain en-ergy with reference to the middle surface strains andchanges in curvatures [21]:

U=Eh

2(1��2)

aZ0

bZ0

""2x+"2

y+2�"x"y+1� �

2 2xy

#dxdy

+Eh3

24(1� �2)

aZ0

bZ0

��2x + �2

y + 2��x�y

+2(1� �)�2xy�dxdy: (20)

The �rst integral represents the membrane strain en-ergy, whereas the second term indicates the bendingstrain energy. Through Eqs. (4) to (10), the strainenergy can be presented in terms of displacementcomponents:

U=Eh

2(1��2)

aZ0

bZ0

(�@u@x

�2

�2@u@xrw+r2w2+

�@v@y

�2

�2@v@ytw+t2w2+2�

@u@x

@v@y�2�

@u@xtw�2�

@v@yrw

+ 2�rtw2 +1� �

2

"�@u@y

�2

+�@v@x

�2

+ 4s2w2

+2@u@y

@v@x� 4

@u@ysw � 4

@v@xsw��

dxdy

+Eh3

24(1� �2)

aZ0

bZ0

"�@2w@x2

�2

+�@2w@y2

�2

+2�@2w@x2

@2w@y2 + 2(1� �)

�@2w@x@y

�2#dxdy: (21)

3.3. Virtual work done by external loadsThe virtual work, W , completed by external forces isobtained as follows:

W =aZ

0

bZ0

(qxu+ qyv + qzw)dxdy; (22)

where qx, qy, and qz are the distributed forces per unitarea in x, y, and z directions, respectively. In thepresent study, the applied impulsive load is distributedover a rectangular area and considered to be in thez direction. The applied load area, whose centercorresponds to the center of the shell, is shown inFigure 2. Furthermore, Eq. (22) can be rewritten inthe following form:

W =0:6aZ

0:4a

0:6bZ0:4b

qzwdxdy: (23)

The external, normal impulsive load qz is considered

Figure 2. The area of applied load in plan.

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1718 H. Sabermahany et al./Scientia Iranica, Transactions A: Civil Engineering 27 (2020) 1714{1727

by three types: step pulse, triangular pulse, and sinepulse. In general:

A. Step pulse:(qz(t) = F0; 0 � t � tdqz(t) = 0; t � td

B. Triangular pulse:(qz(t) = F0(1� t=td); 0 � t � tdqz(t) = 0; t � td

C. Sine pulse:(qz(t) = F0 sin(�t=td); 0 � t � tdqz(t) = 0; t � td

where F0 is the magnitude of the force, and td is thetime duration of applying impulsive load.

4. Boundary conditions and Fourier series ofdisplacement components

The following boundary conditions are considered inthis study.

Model A. Simply supported conditionsFor simply supported conditions where shell edges reston diaphragms that are rigid in their own plane and exible out of the plane, the boundary conditions aregiven by:

v = w = Nx = Mx = 0 at x = 0; a; (24)

u = w = Ny = My = 0 at y = 0; b; (25)

where N is the normal force, and M is the bendingmoment per unit length.

The displacements u, v, and w can be presentedin the following double Fourier series, satisfying theboundary conditions:

u(x; y; t)=MXm=1

NXn=1

um;n(t) cos�m�x

a

�sin�n�y

b

�;(26)

v(x; y; t)=MXm=1

NXn=1

vm;n(t) sin�m�x

a

�cos�n�y

b

�;(27)

w(x; y; t)=MXm=1

NXn=1

wm;n(t) sin�m�x

a

�sin�n�y

b

�;(28)

where m and n are the number of expressions used inthe Fourier series in x and y directions, respectively,and t is time. In addition, um;n, vm;n, and wm;n arethe generalized coordinates that are unknown functionsof t. The convergence of the solution can be consideredby using di�erent terms in Eqs. (26){(28);

Model B. Clamped edge conditions

u = v = w = 0; Mx = c@w@x

at x = 0; a; (29)

u = v = w = 0; My = c@w@y

at y = 0; b; (30)

where c is the sti�ness per unit length of the elasticand distributed rotational springs placed at four edges.Model B was developed in [22] and provides �xed edgein-plane with free rotation by c = 0 and a perfectlyclamped condition (@w=@x = 0 and @w=@y = 0)obtained for c!8. The displacements u, v, and wcan be presented in the following double Fourier series,which satisfy the boundary conditions:

u(x; y; t)=MXm=1

NXn=1

um;n(t) sin�m�x

a

�sin�n�y

b

�;

(31)

v(x; y; t)=MXm=1

NXn=1

vm;n(t) sin�m�x

a

�sin�n�y

b

�; (32)

w(x; y; t)=MXm=1

NXn=1

wm;n(t) sin�m�x

a

�sin�n�y

b

�:(33)

When c is not zero, an additional potential energy isgenerated in the rotational springs that must be addedto the elastic strain energy. This potential energy, UR,is given by:

UR =12

bZ0

c

(��@w@x

�x=0

�2

+��

@w@x

�x=a

�2)dy

+12

aZ0

c

8<:"�@w@y �y=0

#2

+

"�@w@y

�y=b

#29=; dx:

(34)

By substituting w from Eq. (33) and considering c asconstant, we get:

UR =MXm=1

NXn=1

cw2m;n

�m2�2b

2a2 +n2�2a

2b2

�: (35)

For both boundary conditions, through the sub-stitution of double Fourier series of displacement com-ponents in Eqs. (3), (21), and (23), the kinetic energy,the strain energy, and the virtual work performed byexternal loads will be obtained with regard to thegeneralized coordinates (um;n, vm;n, and wm;n), whichare suitable forms for them to use in Lagrange equa-tions of motion. After the substitution of displacementcomponents, the kinetic energy for both boundaryconditions is obtained as follows:

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T =12�hab4

MXm=1

NXn=1

�_u2m;n + _v2

m;n + _w2m;n�: (36)

Moreover, the strain energy for each of the boundaryconditions is obtained as follows:

Model A. Simply supported conditions

U =MXm=1

NXn=1

��1u2

m;n + �2v2m;n + �3w2

m;n

+�4um;nvm;n + �5um;nwm;n + �6vm;nwm;n]

+MXm=1

NXna=nb=1

[�7wm;nawm;nb + �8um;nawm;nb

+�9vm;nawm;nb] +MX

mi;mj=1

NXn=1

[�10wmi;nwmj;n

+�11vmi;nwmj;n + �12umi;nwmj;n]

+MX

mi=mj=1

NXna=nb=1

[�13wmi;nawmj;nb

+�14umi;nawmj;nb + �15vmi;nawmj;nb] : (37)

Model B. Clamped edge conditions

U =MXm=1

NXn=1

��1u2

m;n + �2v2m;n + �3w2

m;n�

+MXm=1

NXna;nb=1

[�7wm;nawm;nb+�16vm;nawm;nb]

+MX

mi;mj=1

NXn=1

[�10wmi;nwmj;n+�17umi;nwmj;n]

+MX

mi=mj=1

NXna=nb=1

[�13wmi;nawmj;nb

+ �18umi;navmj;nb + �19umi;nawmj;nb

+�20vmi;nawmj;nb] + UR: (38)

Basically, UR is the additional potential energy that isgenerated in the rotational springs. The coe�cients �1to �20 are presented in the appendix.

For both boundary conditions, W is:

W =MXm=1

NXn=1

qzwm;n(t)ab

mn�2 [cos(0:4m�)

� cos(0:6m�)][cos(0:4n�)� cos(0:6n�)]: (39)

5. Lagrange equations of motion

The Lagrange equations of motion are:

ddt

�@T@ _qj

�� @T@qj

+@U@qj

= Qj ; j = 1; � � � ; dofs;(40)

where q = fum;n; vm;n; wm;ngT , m = 1; � � � ;M ,n = 1; � � � ; N , and dofs = M�; N . Moreover, thegeneralized forces Qj are presented in the followingequation by assuming viscous type for the nonconser-vative damping forces:

Qj = � @F@ _qj

+@W@qj

: (41)

Nonconservative damping forces of viscous type arepresented as follows:

F =12c

aZ0

bZ0

�_u2 + _v2 + _w2� dxdy

=12ab4

MXm=1

NXn=1

cm;n�

_u2m;n + _v2

m;n + _w2m;n�; (42)

�m;n =cm;n

(2�m;n!m;n); (43)

where �m;n, �m;n, and !m;n are modal dampingratio, natural frequency, and modal mass of mode(m;n). Damping forces have insigni�cant e�ect on theresponses of impact load; therefore, one can neglectdamping forces.

For both boundary conditions, the kinetic energywas determined through Eq. (36). In addition, thevirtual work completed by external forces was deter-mined through Eq. (39). Therefore, three terms of theLagrange equations are the same for both boundaryconditions. In particular:

ddt

�@T@ _qj

�= �h

ab4

�qj ; (44)

@T@qj

= 0; (45)

Qj = � @F@ _qj

+@W@qj

= ��ab4

�cj _qj

+

8>>>>>><>>>>>>:0 if qj = um;n; vm;n

qzab

mn�2 [cos(0:4m�)� cos(0:6m�)][cos(0:4n�)� cos(0:6n�)]

if qj = wm;n

(46)

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The strain energy was determined through Eqs. (37)and (38) for simply supported and clamped edgeconditions, respectively. Therefore, one can write thefollowing for each boundary condition:

@U@qj

=dofsXk=1

qk�j;k; (47)

where coe�cients �j;k can be determined with regardto coe�cients �1 to �20.

6. Results and discussion of numerical analysis

The equations of motion that are obtained through theLagrangian approach and regardless of damping forcescan be presented in the following matrix form:

[m] [�q] + [k][q] = [F ]; (48)

and:

[q] = [q1 � � � qj � � � qM;N ]T : (49)

The system presented above for di�erential equationscan be solved by the modal technique. In Eq. (48), [m]and [k] can be considered as mass and sti�ness ma-trices, respectively. Thus, with these two matrices,one can determine natural frequencies of the funicularshell. By solving this system of di�erential equations,generalized coordinates um;n, vm;n, and wm;n are ob-tained in terms of time. Then, by using Fourier series,displacement components are determined. By deter-mining displacement components, strains and stressesgenerated in the shell are acquired. In order to obtainthe numerical results, a computer code was written.Furthermore, as mentioned earlier, no study is availablefor the dynamic response of funicular shells. Therefore,the dynamic analysis of funicular shells is completedFEM in order to compare its results with those of theanalytical approach. In the present study, geometricand material properties of the funicular shell are givenas follows (material is concrete):

a = 1 m; b = 1 m; E = 17:8 GPa;

� = 0:2; � = 2400 kg/m; h = 0:03 m;

H = 0:09 m:

The magnitude of force (F0) is equal to 60 kPa, thearea of applied load is 0:2�0:2 = 0:04 m2, and the timeduration of the applied load is 0.01 sec. In addition,the number of considered degrees of freedom usedin the mode expansion of displacement components(m;n) is (3 � 15) for simply supported conditionsand (4 � 15) for clamped edge conditions. Moreover,there are 10 considered modes in the modal analysistechnique for both methods, i.e., analytical and FEM.Evidently, Figure 3 indicates the comparison of the

Figure 3. Comparison of center normal displacement ofsimply supported conditions for two di�erent cases.

Table 1. Natural frequency of mode (1,1) for di�erentboundary conditions.

Boundary conditionsNatural frequency

(Hz)Analytical FEM

Simply supported 197.77 195.57ClampedEdge

c = 0 362.84 380.39c = 180000 (N/rad) 379.85 380.39

center de ection of a simply supported funicular shellfor two di�erent cases. In case 1, the number of degreesof freedom used in the mode expansion is (3� 15) andin case 2 is (5 � 20). The good agreement betweenthe results shown in Figure 3 shows the convergence ofFourier series of displacement components.

Table 1 shows the natural frequency of mode (1,1)that is obtained with analytical and FEMs for each ofthe two di�erent boundary conditions. The agreementbetween the analytical solution and FEM solution isexcellent, as is clearly shown in Table 1. For clampededge conditions, good agreement is obtained for c =180000. All of the results of the analytical method per-taining to clamped edge conditions that are presentedsubsequently are obtained for c = 180000 N/rad.

Tables 2 and 3 present a comparison of themaximum values of center normal de ection along withthe center stresses found in x direction with FEM fordi�erent impulse loads.

Figure 4 shows the center normal displacementof simply supported in comparison with the FEM.Figure 5 also shows this comparison for clamped edgeconditions.

The good agreement between the results found inTables 2 and 3 along with Figures 4 and 5 indicates

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Table 2. Comparison of the maximum values of centernormal de ection and center stresses of simply supportedconditions for di�erent pulses.

Impulse load De ection(�10�4 m)

�x (MPa)C� T��

Step pulse Analytical 1.6 {1.9 0.66FEM 1.6 {1.7 0.84

Triangularpulse

Analytical 1.3 {1.6 1FEM 1.3 {1.4 0.87

Sine pulse Analytical 0.94 {1.1 0.24FEM 0.95 {0.92 0.19

�: Compression; ��: Tension.

Table 3. Comparison of the maximum values of centernormal de ection and center stresses of clamped edge fordi�erent pulses.

Impulse load De ection(�10�4 m)

�x (MPa)C� T��

Step pulse Analytical 0.92 {1.6 1FEM 1 {1.8 0.87

Triangularpulse

Analytical 0.83 {1.5 0.83FEM 0.88 {1.6 0.95

Sine pulse Analytical 0.51 {0.89 0.19FEM 0.59 {1 0.2

�: Compression; ��: Tension.

Figure 4. Center normal displacement of simplysupported conditions for sine pulse.

Figure 5. Center normal displacement of clamped edgeconditions for sine pulse.

Figure 6. Center normal displacement of simplysupported conditions for harmonic load.

the validity of the proposed method. In Figure 5, thecomparison of the proposed method and �nite elementshows a phase di�erence between the results that couldbe related to the value of the sti�ness c (sti�ness ofrotational springs). In order to simulate clamped edges,the value of the sti�ness c is determined only withregard to the natural frequency of mode (1,1).

Figure 6 shows the comparison of center de ectionof simply supported and the FEM for a harmonicforce, qz = F0 sin(!t), where the load frequency (!)is equal to 1:2 !1;1 (!1;1 is the natural frequency ofthe fundamental mode). In regard to the harmonicload, the e�ect of damping should be considered. The

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1722 H. Sabermahany et al./Scientia Iranica, Transactions A: Civil Engineering 27 (2020) 1714{1727

Figure 7. Center normal displacement of simplysupported conditions for di�erent pulses.

Figure 8. Center normal displacement of clamped edgeconditions for di�erent pulses.

modal damping ratio of all modes is to be assumed4%, and the magnitude of force (F0) is equal to 6 kPa.Figure 6 shows good convergence between the resultsof two methods for harmonic load.

Figures 7 and 8 show the time response of thecenter point displacement of the funicular shell withvarious pulses for simply supported and clamped edgeconditions, respectively. The largest de ection occursunder step pulse due to the area under the load-timecurve being greater than other pulses.

Tables 4 and 5 indicate the maximum and mini-mum values of internal forces and moments for simplysupported and clamped edge conditions, respectively.

Tables 6 and 7 also indicate the maximum values

Table 4. The maximum and minimum values of internalforces and moments of simply supported conditions fordi�erent pulses.

Internal forcesand moments

Steppulse

Triangularpulse

Sinepulse

Nx (kN/m) Max 5.45 11.8 3.73Min {23.1 {19.2 {13.5

Ny (kN/m) Max 5.99 12.5 3.71Min {23.9 {19.5 {13.5

Nxy (kN/m) Max 9.52 18.3 8.82Min {31.6 {28.7 {20

Mx (N.M/M) Max 176 160 97.1Min {122 {105 {43.4

My (N.M/M) Max 164 155 93.5Min {116 {102 {43

Mxy (N.M/M) Max 34.9 77.5 31.5Min {115 {108 {55.6

Table 5. The maximum and minimum values of internalforces and moments of clamped edge for di�erent pulses.

Internal forcesand moments

Steppulse

Triangularpulse

Sinepulse

Nx (kN/m) Max 8.9 9.92 1.94Min {19.3 {17.8 {10.8

Ny (kN/m) Max 10.8 10.8 2.09Min {21.4 {18.9 {11.6

Nxy (kN/m) Max 8.31 7.72 1.37Min {12.6 {11.5 {7.03

Mx (N.M/M) Max 151 135 80.9Min {108 {75 {44.1

My (N.M/M) Max 141 131 78Min {101 {79.4 {46.4

Mxy (N.M/M) Max 30.4 26.1 9.32Min {40.7 {37.2 {22.2

of compressive, tensile, and shear stresses found in thefunicular shell for two boundary conditions.

Tables 4 to 7 show that, under impulse loads,internal moments form and, thus, tensile and shearstresses in addition to compressive stresses form. Inthis paper, for a plate with the same geometric andmaterial features and for the same load applied, the dy-

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H. Sabermahany et al./Scientia Iranica, Transactions A: Civil Engineering 27 (2020) 1714{1727 1723

Table 6. The maximum values of stresses of simplysupported conditions for di�erent pulses.

Stresses Steppulse

Triangularpulse

Sinepulse

�x(MPa)

Tension 0.69 1.02 0.267

Compression {1.94 {1.61 {1.06

�y(MPa)

Tension 0.674 0.968 0.312

Compression {1.88 {1.6 {1.04

�xy (MPa) 1.38 1.16 0.866

Table 7. The maximum values of stresses of clampededge for di�erent pulses.

Stresses Steppulse

Triangularpulse

Sinepulse

�x(MPa)

Tension 1.01 0.828 0.193

Compression {1.65 {1.48 {0.895

�y(MPa)

Tension 1.03 0.831 0.151

Compression {1.65 {1.5 {0.902

�xy (MPa) 0.613 0.556 0.338

Table 8. Comparison of the maximum values of centernormal de ection and center stresses of simply supportedconditions.

Impulse load De ection(�10�4 m)

�x (MPa)

C� T��

Steppulse

Funicular shell 1.56 {1.67 0.842

Plate 12.2 {4.6 4.6

Sinepulse

Funicular shell 0.948 {0.924 0.192

Plate 10.3 {3.64 3.64

�: Compression; ��: Tension.

namic responses are obtained with the FEM. Tables 8and 9 show the comparison of the maximum valuesof center normal de ection, center compressive, andtensile stresses between the funicular shell and the platefor simply supported and clamped edge conditions,respectively.

Tables 8 and 9 indicate that, in regard to theplate, the compressive and tensile stresses are the samedue to the bending performance of the plate. Thetables also indicate that the normal de ection and

Table 9. Comparison of the maximum values of centernormal de ection and center stresses of clamped edgeconditions.

Impulse load De ection(�10�4 m)

�x (MPa)

C� T��

Steppulse

Funicular shell 1.04 {1.83 0.871

Plate 5.33 {3.49 3.49

Sinepulse

Funicular shell0.591 {1.03 0.195

Plate

�: Compression; ��: Tension.

Figure 9. Center normal displacement of simplysupported conditions for sine pulse and also for di�erentrises.

stresses, especially tensile stresses found in the plate,are larger than those of funicular shell. In other words,tensile stresses found in the plate are 4 to 15 timeslarger than those found in the funicular shell.

Essentially, as mentioned in the introduction, therise of the funicular shell is an important parameterin the performance of the funicular shell under staticloads. Here, the e�ect of the rise of the funicularshell is considered for dynamic load. By increasing therise of the shell, the maximum value of center normaldisplacement and the corresponding time response willdecrease (Figure 9).

If the dimension of plan (a) increases, the maxi-mum values of center normal displacement and stressesalong with time response of normal displacement willincrease (Table 10 and Figure 10).

Table 10 indicates that, for a = 3 m, the centertensile stress of the funicular shell is 9.8 MPa. Byincreasing the shell rise from H = 0:15 m to H =

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1724 H. Sabermahany et al./Scientia Iranica, Transactions A: Civil Engineering 27 (2020) 1714{1727

Table 10. Comparison of the maximum value of centerstresses of simply supported conditions for sine pulse andalso for di�erent plan dimensions.

Plandimension (a)

�x (MPa)

Compression Tension

1.5 {1.72 0.495

2 {3.71 0.617

2.5 {6.92 5.16

3 {10.2 9.8

Figure 10. Center normal displacement of simplysupported conditions for sine pulse and also for di�erentplan dimensions.

0:27 m, the center tensile stress of the shell decreasesto 3.3 MPa, which shows a 67% reduction. Thus,the span-to-rise ratio signi�cantly a�ects the stresses,particularly tensile stresses.

7. Summary and conclusions

In this study, an analytical solution in regard to theforced linear vibration of concrete funicular shells ona rectangular ground plan under impulse loads for twodi�erent boundary conditions was presented based onthe shallow shells theory. The results, successfullyveri�ed against �nite element technique, reveal that:

- The largest de ection occurs under step pulse dueto the area under time-load curve being greater thanthe other two pulses;

- The performance of the funicular shell under impulseloads is much better than that of the rectangular atplate;

- Under impulse loads, tensile stresses in addition tocompressive stresses form in funicular shells;

- The de ections and stresses, especially tensilestresses, under dynamic impulse loads are negligibleup to an amplitude of the load that is computable;

- The e�ect of rise and span on the time responseof the shell has been considered. From a generalperspective, the smaller the ratio of span to riseis, the smaller the displacements and stresses willbe. In fact, by choosing an appropriate span-to-rise ratio, the displacements and stresses, especiallytensile stresses, will decrease signi�cantly.

References

1. Bhimaraddi, A. \Free vibration analysis of doublycurved shallow shells on rectangular planform usingthree-dimensional elasticity theory", Int. J. SolidsStruct., 27(7), pp. 897{913 (1991).

2. Singh, V.K. and Panda, S.K. \Nonlinear free vibrationanalysis of single/doubly curved composite shallowshell panels", Thin Walled Struct., 85, pp. 341{349(2014).

3. Qatu, M.S. and Leissa, A.W. \E�ects of edge con-straint upon shallow shell frequencies", Thin WalledStruct., 14(5), pp. 347{379 (1992).

4. Abe, A., Kobayashi, Y., and Yamada, G. \Non-linearvibration characteristics of clamped laminated shallowshells", J. Sound Vib., 234(3), pp. 405{426 (2000).

5. Amabili, M. \Non-linear vibrations of doubly curvedshallow shells", Int. J. Non Linear Mech., 40, pp. 683{710 (2005).

6. Shoshtari, A. and Razavi, S. \Large-amplitude freevibration of magneto-electro-static curved panels",Scientia Iranica, 23(6), pp. 2606{2615 (2016).

7. Vafai, A., Mo�d, M., and Estekanchi, H.E. \Exper-imental study of prefabricated funicular shell units",Eng. Struct., 19(9), pp. 748{759 (1997).

8. Weber, J.W., Wu, K.C., and Vafai, A. \Ultimate loadsfor shallow funicular concrete shells", Northwest Sci.,58(3), pp. 187{194 (1984).

9. Vafai, A. and Farshad, M. \Theoretical and experi-mental study of prefabricated funicular shell units",Build. Environ., 14, pp. 209{216 (1979).

10. Elangovan, S. \Analysis of funicular shells by theisoparametric �nite element", Comput. Struct., 34(2),pp. 303{311 (1990).

11. Rajasekaran, S. and Sujatha, P. \Con�guration of deepfunicular shells by boundary integral element method",Comput. Struct., 44(1/2), pp. 213{221 (1992).

12. Lakshmikandhan, K.N., Sivakumar, P., Jose, L.T.,Sivasubramanian, K., Balasubramanian, S.R., andSaibabu, S. \Parametric study on development, testing

Page 12: Dynamic response of concrete funicular shells with a ...

H. Sabermahany et al./Scientia Iranica, Transactions A: Civil Engineering 27 (2020) 1714{1727 1725

and evaluation of concrete funicular shells", Interna-tional Journal of Engineering and Innovative Technol-ogy (IJEIT), 3(12), pp. 183{191 (2014).

13. Sivakumar, P., Manjunatha, K., and Harish, B.A.\Experimental and FE analysis of funicular shells",International Journal of Engineering and InnovativeTechnology (IJEIT), 4(9), pp. 178{186 (2015).

14. Siddesh, T.M., Harish, B.A., and Manjunatha, K.\Finite element analysis of funicular shells with rect-angular plan ratio 1:0.7 under concentrated load usingSAP2000", International Research Journal of Engi-neering and Technology (IRJET), 3(9), pp. 873{878(2016).

15. Sachithanantham, P. \Study of shallow funicular con-crete shells of plan to rise ratio 1:2", InternationalJournal of Biotech Trends and Technology (IJBTT),2(3), pp. 53{64 (2012).

16. Tarunkumar, T. and Sachithanantham, P. \Studyon shallow funicular concrete shells over rectangularground plan ratio 1:0.8", International Journal ofComputer Trends and Technology (IJCTT), 3(6), pp.29{49 (2012).

17. Sachithanantham, P. \Study of geo-grid reinforcedshallow funicular concrete shells subjected to ultimateloads", International Journal of Biotech Trends andTechnology (IJBTT), 2(2), pp. 34{46 (2012).

18. Sachithanantham, P., Sankaran, S., and Elavenil, S.\Study on shallow funicular concrete shells over rect-angular ground plan ratio 1:0.6", International Journalof Computer Trends and Technology (IJCTT), 3(6),pp. 19{28 (2012).

19. Sachithanantham, P., Sankaran, S., and Elavenil, S.\Study on shallow funicular concrete shells over rect-angular ground plan ratio 1:0.9", International Journalof Emerging Technology and Advanced Engineering(IJETAE), 4(4), pp. 102{107 (2014).

20. Ramaswamy, G.S., Design and Construction of Con-crete Shell Roofs, McGraw-Hill, New York, USA(1968).

21. Ventsel, E. and Krauthammer, T., Thin Plates andShells, Theory, Analysis, and Applications, MarcelDekker, New York, USA (2001).

22. Amabili, M. \E�ect of boundary conditions on nonlin-ear vibrations of circular cylindrical panels", J. Appl.Mech., 74, pp. 645{657 (2007).

Appendix

De�nitions of �1 � �20:

�1 =Eh

2(1� �2)

�m2�2b

4a+ (1� �)

n2�2a8b

�;

�2 =Eh

2(1� �2)

�n2�2a

4b+ (1� �)

m2�2b8a

�;

�3 =Eh3

24(1� �2)

�m4�4b

4a3 +n4�4a

4b3+m2n2�4

2ab

�+

Eh2(1� �2)

"25g2

2N2

�1

a2 + b2

�2#

�a�b5

60+

3b5

4n4�4

�+ b

�a5

60+

3a5

4m4�4

�+ 4�

�b3

12+

b3

4n2�2

� �a3

12+

a3

4m2�2

�+(1� �)

�a3

6� a3

m2�2

� �b3

6� b3

n2�2

��;

�4 =Eh

2(1� �2)

�(1 + �)

mn�2

4

�;

�5 =Eh

2(1��2)

�5gN

1(a2+b2)

���m�

�b3

12+

b3

4n2�2

���m�b

a

�a3

12+

a3

4m2�2

�� (1� �)

a2b4m�

�;

�6 =Eh

2(1��2)

�5gN

1(a2+b2)

���n�

�a3

12+

a3

4m2�2

��� n�a

b

�b3

12+

b3

4n2�2

�� (1� �)

b2a4n�

�;

�7 =Eh

2(1� �2)

"�25

�gN

1(a2 + b2)

�2#

�16�b3nanb�2(n2

a � n2b)2

�a3

12+

a3

4m2�2

�+

96ab5nanb(n2a + n2

b)�4(n2

a � n2b)4

�(1� �)16b3nanb

�2(n2a � n2

b)2

�a3

6� a3

m2�2

��;

�8 =Eh

2(1� �2)

�gN

1(a2 + b2)

� �20mb3nanb�(n2

a � n2b)2

+5(1� �)a2bnanbm�(n2

a � n2b)

�;

�9 =Eh

2(1� �2)

�gN

1(a2 + b2)

� �20�ab2n2

anb�(n2

a � n2b)2

+5(1� �)ab2nb�(n2

a � n2b)

�;

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1726 H. Sabermahany et al./Scientia Iranica, Transactions A: Civil Engineering 27 (2020) 1714{1727

�10 =Eh

2(1� �2)

"�25

�gN

1(a2 + b2)

�2#

(16�a3mimj

�2(m2i �m2

j )2

�b3

12+

b3

4n2�2

�+

96ba5mimj(m2i +m2

j )�4(m2

i �m2j )4

�(1� �)16a3mimj

�2(m2i �m2

j )2

�b3

6� b3

n2�2

�);

�11 =Eh

2(1� �2)

�gN

1(a2 + b2)

� "20na3mimj

�(m2i �m2

j )2

+5(1� �)b2amimj

n�(m2i �m2

j )

#;

�12 =Eh

2(1� �2)

�gN

1(a2 + b2)

� "20�ba2m2

imj

�(m2i �m2

j )2

+5(1� �)ba2mj

�(m2i �m2

j )

#:

�13 =Eh

2(1� �2)

�gN

1(a2 + b2)

�2

"1600�a3b3mimjnanb

�4(m2i �m2

j )2(n2a � n2

b)2

+6400(1� �)a3b3mimjnanb�2(m2

i �m2j )2(n2

a � n2b)2

#;

�14 =Eh

2(1��2)

�gN

1(a2+b2)

�"20(1��)a2bmjnanb�(m2

i�m2j )(n2

a�n2b)

#;

�15 =Eh

2(1��2)

�gN

1(a2+b2)

�"20(1��)b2amimjnb�(m2

i�m2j )(n2

a�n2b)

#:

For �7 � �15, indices of m (i; j) and indices of n,(a; b) should be either even or odd. Otherwise, thesecoe�cients will be zero.

�16 =Eh

2(1� �2)

��20

gN

1(a2 + b2)

���ab2nanb(3n2

a + n2b)

�2(n2a � n2

b)3 +nanb

(n2a � n2

b)�a3

12+

a3

4m2�2

�+ (1� �)

b2ananb�2(n2

a � n2b)2

�:

In the above equation, one of the indices of n, a orb should be even, and the other one should be odd.Otherwise, this equation will be equal to zero.

�17 =Eh

2(1� �2)

��20

gN

1(a2 + b2)

�(�ba2mimj(3m2

i +m2j )

�2(m2i �m2

j )3 +mimj

(m2i �m2

j )�b3

12+

b3

4n2�2

�+ (1� �)

a2bmimj

�2(m2i �m2

j )2

):

In the above equation, one of the indices of m, i orj should be even, and the other one should be odd.Otherwise, this equation will be equal to zero.

�18 =Eh

2(1� �2)

"�4(1 + �)

mimjnanb(m2

i �m2j )(n2

a � n2b)

#:

In the above equation, one of the indices of m, i orj should be even, and the other one should be odd;similarly, one of the indices of n, a or b should beeven, and the other one should be odd. Otherwise,this equation will be equal to zero.

�19 =Eh

2(1��2)

�80

gN

1(a2+b2)

�"b3mimjnanb

�2(n2a�n2

b)2(m2i�m2

j )

+(1� �)a2bmimjnanb�2(m2

i �m2j )2(n2

a � n2b)

#:

In the above equation, one of the indices of m, i or jshould be even, the other one should be odd, and bothindices of n, a and b should be even or odd. Otherwise,this equation will be equal to zero.

�20 =Eh

2(1��2)

�80

gN

1(a2+b2)

�"a3mimjnanb

�2(m2i�m2

j )2(n2a�n2

b)

+(1� �)b2amimjnanb�2(n2

a � n2b)2(m2

i �m2j )

#:

In the above equation, both indices of m, i and j shouldbe even or odd, one of the indices of n, a or b shouldbe even, and the other one should be odd. Otherwise,this equation will be equal to zero.

Biographies

Hadi Sabermahany is a PhD scholar at Civil En-gineering Department, University of Tehran, Tehran,Iran. He received his MSc from Sharif University of

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H. Sabermahany et al./Scientia Iranica, Transactions A: Civil Engineering 27 (2020) 1714{1727 1727

Technology, Tehran, Iran in 2015. His MSc thesis wasabout analysis of funicular shells.

Abolhassan Vafai is a Professor of Civil Engineeringat Sharif University of Technology, Iran. He hasauthored/coauthored numerous papers in di�erent�eld of engineering. He has also been active in thearea of higher education and has delivered lectures and

published papers on challenges of higher education,the future of science and technology, and humanresources development.

Massood Mo�d is a Professor of Civil and StructuralEngineering at Sharif University of Technology, Iran.He received his MS and PhD degrees from Rise Uni-versity, Houston, Texas.