Detail at 1 and 2------- Splice for 400 x 400 x 10

parent plate 400 mm 10

cover plate 360 mm 12

tensile strength of parent plate 400 x 10 x 150 =

thk of weld 8 mm

weld strength/sq mm 100 Mpa

weld strength / mm = 0.75 x 8 x 100 = 600

weld length required = tensile strength of plate/ weld strength/mm

600000/600 1000 mm

weld length for top and bottom plate

( 200 + 200 + 400 ) x 2 = 2000 mm

provided intermitant welding of 60 % length = 1200 mm > 1000 mm hence ok

Shear strength of 8.8 grade bolt = 0.67 x 800 =

use 32 dia bolts 8.8 grade

bolts are in double shear

stregth of single bolt (working condition ) = 3.14159/4 x 32 x 32 x 536 /2

= 215538.2 N

for two bolts in double shear the strength is = 215538.2 x 4 =

mm

mm 2 nos

400 x 10 x 150 = 600000 N

N/mm

weld length required = tensile strength of plate/ weld strength/mm

provided intermitant welding of 60 % length = 1200 mm > 1000 mm hence ok

536 Mpa

stregth of single bolt (working condition ) = 3.14159/4 x 32 x 32 x 536 /2

for two bolts in double shear the strength is = 215538.2 x 4 = 1724306 N

> strength of plate hence ok

connection between internal members and outermost ring

Max force in member ---- 277

section to be connected 260 x 150 x 8

plates connected to this section

capacity of plate in tension = 250 x 12 x 2 x 150 =

capacity single plate 12 thk x 250 = 250 x 12 x 150/1000 =

thk of weld 8 mm

weld strength = 600 N/mm

weld lenth required = force in member/weld strength =

weld length provided = 2 x 250 =

bolt provided ----- 24 mm dia in double shear, grade 8.8

shear strength of bolt in double shear =

= 3.14159/4 x 32 x 32 x 536/2

431.0764 kN > force in member hence OK

connection between internal members and outermost ring

kN member 61 load case 18

260 x 150 x 8

12 thk x 250 x 200

capacity of plate in tension = 250 x 12 x 2 x 150 = 900 kN > force in member

capacity single plate 12 thk x 250 = 250 x 12 x 150/1000 = 450 kN > force in member

weld lenth required = force in member/weld strength = 461.6667 mm

500 mm > required

mm dia in double shear, grade 8.8

shear strength of bolt in double shear =

> force in member hence OK

Detail at 4

connection at support with a single bolt

max reaction at support

Fx 104.7 kN

Fy 110.2 kN

resultant reaction = sqrt(104.7 ^2 + 110.2^2)

152.007 kN

Bolt provided M24 --- 8.8 grade

bolt is in double shear

strength of bolt in double shear = 3.14159 /4 x24 x 24 x 536/2 x 2

242.4805 kN > reaction hence ok

strength of bolt in double shear = 3.14159 /4 x24 x 24 x 536/2 x 2

kN > reaction hence ok