Do Now

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DO NOW 1. Complete a punnett square showing the cross between a heterozygous tall plant and a homozygous recessive plant .

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Do Now. Complete a punnett square showing the cross between a heterozygous tall plant and a homozygous recessive plant . . Announcements. Gonzaga is now ranked Quiz on Thursday I will not be here on Friday. . Agenda. Sex linked traits Sex linked punnett squares - PowerPoint PPT Presentation

Transcript of Do Now

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DO NOW1. Complete a punnett square

showing the cross between a heterozygous tall plant and a homozygous recessive plant .

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ANNOUNCEMENTS• Gonzaga is now ranked • Quiz on Thursday• I will not be here on Friday.

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AGENDA• Sex linked traits• Sex linked punnett squares• Article detailing sex linked

traits

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SEX LINKED TRAITS• Sex linked traits are those

traits that are found on either the X or Y chromosome.

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HEMOPHILIA• Hemophilia is a disease

where your blood doesn’t clot.

• It only occurs when all of the X chromosomes have a copy of the recessive gene.

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SEX LINKED TRAIT EXAMPLE

• XHXh: Female Carrier• XhXh: Female Hemophiliac• XHY: Normal Male• XhY: Hemophiliac Male

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SEX LINKED TRAIT PUNNETT SQUARE

• As we’re watching this video, let’s copy this professor’s example in our notes.

• http://www.youtube.com/watch?v=j35OALtS3Bk

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EXAMPLE• Colorblindness is inherited as a sex-

linked recessive disease. An affected male marries a heterozygous female. Draw a Punnett square of the possible offspring. What is the chance that they will have an affected child? Could any of their daughters be affected?

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EXAMPLEColorblindness is inherited as a sex-linked recessive disease. 1. Recognize how the disease in inherited.a. Sex-linked means that the gene is carried on the X chromosome. b. Recessive means that both alleles must be recessive for female to have the disease. Females could have a good backup copy because they have two X chromosomes. c. Males, who only have one X chromosome, will have the disease if their only X is mutant.

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EXAMPLEAn affected male marries a heterozygous female. 2. Determine the genotypes of the parents.Affected male is XA Y (since he is affected, his only X is mutant)Heterozygous female is XA X (heterozygous means one of each allele)

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EXAMPLE

Draw a Punnett square of the possible offspring.3. Set up the Punnett square with the genotypes of the above two parents. 

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EXAMPLEWhat is the chance that they will have an affected child? 4. Determine how many possibles would be affected according to how the disease in inherited (See help #1).  

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