DO NOT DETACH ANY PAGE(S) FROM THE EXAMINATION...
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UNIVERSITY OF TORONTO
FACULTY OF APPLIED SCIENCE AND ENGINEERING
WINTER TERM FINAL EXAMINATION
MIE222H1 S - Mechanics of Solids I
April 18, 2017 Time Allowed: 2 '/2 hours
Examiner - Professor S. A. Meguid
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INSTRUCTIONS
This paper contains FIVE (5) questions and comprises TWENTY-TWO (22) pages.
Attempt ALL questions
Please answer each question in the space provided.
Candidates must support their arguments with the appropriate expressions/figures
Only non-programmable and non-communicating calculators are allowed.
Pages 20 to 22 contain information you may find useful.
This is a CLOSED BOOK examination.
Page 1 of 22
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QUESTION #1: (20 Marks)
Starting from point A, the built-in support, calculate the slope and the deflection of the beam AC at point B using Macaulay's singularity functions method. You may assume that the flexural rigidity of the beam E1 0.65 IVfNm2.
W0= 5 kNlm
ly
s';: I
4 4 5m 5m
A B C
Fig. Qi: Beam with applied uniformly distributed load and built-in support
Slope atB4OB
Deflection at B, YB = mJ
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QUESTION # 1 SOLUTION:
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Page 3 of 22
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QUESTION # 1 SOLUTION (continued):
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Page 4 of 22
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QUESTION # 1 SOLUTION (continued):
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Page 5 of 22
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QUESTION #2: (20 Marks)
The thick cylinder shown in Fig. Q2(a) is made of high strength steel with an internal diameter of 200 mn-i and an external diameter of 300 mm. It is subjected to an internal pressure Pi = 60 MPa. The cylinder is assumed to have closed ends, as depicted in Fig. Q2(b).
Determine the stress state acting on the element abcd located on the outer surface of the cylinder as a result of P1; see Fig. Q2(b) and the enlarged Fig. Q2(c). (8 Marks)
If the surface stress element abcd is rotated anticlockwise by 30°, as shown in Fig. Q2(c), find the new stress state acting on the newly rotated surface element a 'b 'c 'd'.
(6 Marks)
Verify your answer by accurately thawing Mohr' s circle to scale on the provided graph paper on Page 9. Show the positions of the surface elements abcd and a 'b 'c 'd' on your circle. (6 Marks)
Fig. Q2(a) Cross-section cut of thick-walled closed cylinder
101
r;i
Fig. Q2(b) Closed end thick walled cylinder Fig. Q2(c) Enlarged view of outer with outer surface stress elements surface stress elements
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Element abed Element a'b'c'd'
Hoop Stress, u00 = MPa Hoop Stress, o'' = MPa
Longitudinal Stress, r = MPa Longitudinal Stress, o'' = MPa
Shear Stress, To = MPa Shear Stress, r'' = MPa
QUESTION #2 SOLUTION:
Page 7 of 22
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QUESTION #2 SOLUTION (continued):
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Page 8 of 22
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QUESTION #2 SOLUTION (continued):
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Page 9 of 22
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QUESTION #3: (20 Marks)
Fig. Q3(a) shows a simply supported beam that carries a central concentrated load of 500 kN
together with a uniformly distributed load of 300 kN/m applied across the 3 m span of the
beam. Given the cross-section dimensions shown in Fig. Q3(b),
Calculate the shear stress distribution of a section 1 in from the left-hand support using Table Q3 provided on Page 10, and (15 Marks)
Draw the shear stress distribution acting in the cross-section in the provided space in Fig. Q3(b). (5 Marks)
500 kN 300 kN/m
1.5m 1.5m
Fig. Q3(a) Simply supported beam dimensions and loading details
Draw Shear Diagram Below S4 ---.-.---------.-------- T --------
- S4
S3 --------------------------------f --------f --------- E E
S2
Si
--------- [ 8
-- S 2
'--S
25 mm 25 ram
100 mm 4
Fig. Q3(b) Enlarged beam cross-section
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Section cut
Area (mm2) (mm) Q(mm3) q = VQ (N\
-i--- ) t (mm) r (MPa)
Si
S2
S3
S4
Table Q3: Shear stress calculation table
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QUESTION #3 SOLUTION:
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Page 12 of 22
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Question # 4: (20 Marks)
A 60 mm diameter shaft of 1.2 m in length is clamped at one end and is free at the other end. A
40 mm diameter concentric bore (hole) is machined out from the free end extending inwards.
The free end is subjected to a torque T. For this particular design, the maximum allowable angle
of twist is 2.5° and the tensile yield stress of the shaft material is 400 MPa, and its modulus of
rigidity is 85 GPa.
Determine the maximum allowable length of the bore LB and the maximum allowable
value of the applied torque T, if a factor of safety of 2 is assigned to the shaft. (14 Marks)
Determine the maximum permissible angle of rotation, if the bore length LB extends to
the full length of the shaft, and yielding is not permitted. (6 Marks)
III
Fig. Q4 Shaft with a concentric hole at one end
Maximum allowable Length of Bore, LB = mm
Maximum allowable Torque, T = Nm
Maximum Angle of Twist, 0 =
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QUESTION #4 SOLUTION:
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QUESTION # 4 SOLUTION (continued):
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Page 15 of 22
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Question # 5: (20 Marks)
A material is subjected to two mutually perpendicular direct stresses of 80 MPa tensile and
50 MPa compressive, together with a shear stress of 30 MPa. The shear stress couple acting on
planes carrying the 80 MPa stress is clockwise in effect. Assuming that Young's Modulus of the
material E = 200 GPa and Poisson's ratio v = 0.3,
Calculate the magnitude and nature (tensile or compressive) of the principal strains, (6 Marks)
Calculate the magnitude of the maximum and minimum shear strains in the plane of
the given system, (4 Marks)
Calculate the direction of the planes on which the principal strains act, and (4 Marks)
Using the graph paper provided on Page 19, confirm your answer by means of
Mobr's circle in terms of strains. Use Mohr's circle to determine the magnitude of the
normal and shear strains acting on a plane inclined 20° counter clockwise to the plane
on which the strain component of the 50 MPa stress acts. (6 Marks)
Principal Strain,
Principal Strain, E2 = IIE
Maximum Shear Strain, Ym
Minimum Shear Strain, Ymin = IIE
Principal Stress Angles, O =
Page 16 of 22
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QUESTION # 5 SOLUTION:
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Page 17 of 22
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QUESTION # 5 SOLUTION (continued):
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Page 18 of 22
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QUESTION 9 5 SOLUTION (continued):
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Page 19 of 22
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USEFUL FORMULA - DO NOT DETACH
e =(a — v(cy +a))
1 1 Yxz=jtxz '
E G=2(1) c EE
F My
Tr VQ J It
P=Tw
A =
7td 2 ird4 = j = 2irr3t
4 64 32
bh3 A=bh, 12
= I + Ad
qtt
T=2qA
TLds çb
4A2G
r
t
T = (dM/dx) Q/It
Page 20 of 22
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cr + L7yy o_xx - oyy
= 2 +
2 cos 28 + sin 28
Tx1y = -
a, sin 20 + cos 28
ozz = v(a. + ok,)
+
(x+ay) 2
2 - ~2 f
- a 2
tmax P 2 ) +) tan20 =
cr -
UY
M ab(3H2 - h2)
12
arr A-B/r2
a bH 2 Mf P
Pr Pr r00 =--, zz 2r
a09 = A + B / r2
tan20 = - a y 2rX),
M
Mpp
fp
6zz-
P1d - P2d
2 '- 1
°max
°max - °min - UY
-
2 2
[(aa)2+ 2 2]2oy 2
EI-=V(x) dx 2 dx 3
= q(x)
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M=EI- dr2
dv rM - = j- dx + C1 El
V = $J
dxjdx + C1 x + C2
f (x) = (x - a)
1 0 x~a;n>O f fl(x)=(x—a)= x>a ; n>0
Type of Loading Singularity Function Pictorial Representation
Concentrated Moment M(x)M0(x—a)° I x
(doublet function) 0 a 2M0 *1
Concentrated Force
(impulse or M(x) FO (x - a)1 x Dirac delta function) 0 a
Uniformly distributed w0 M(x)=<x—a>2
tW
fflflh1t load (step function) o
a
w
1 d _ dwldx Linearly Varying Load
- M(x) -- (x - a)3 6 dx
0 _______________________________
a un
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