Detail Cut and Fill
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OVERALL VOLUME TO BE CUT IS 691.5118m3 In these case, I using the cross sectional area to calculate the volu a) find the height displament between two point and devide by 2 to ge eg: (4.864+4.5373)/2=4.70065m b)then calulate the no. of suare space in between the two points, and eg: 34.25*2=68.5m c) taking the actual volume to be subract by the propose volume to ta eg:648.98905-589.01=54.88905m3 d) add all the volumeat the cut and fill section: total volume=691.5118m3
Transcript of Detail Cut and Fill
OVERALL VOLUME TO BE CUT IS 691.5118m3 In these case, I usn! the c"#ss sect#na$ a"ea t# ca$cu$ate the %#$ume t# &e cut an' ($$.a) (n' the he!ht 's*$ament &et+een t+# *#nt an' 'e%'e &, - t# !et the same he!ht at actua$ he!ht.e!/ 01.86121.5333)4-51.36665m&)then ca$u$ate the n#. #7 sua"e s*ace n &et+een the t+# *#nts, an' tmes - that s the 'satnce an' assume #7 s8ua"e s*ace as -m *e" s8ua"e.e!/ 31.-59-568.5mc) ta:n! the actua$ %#$ume t# &e su&"act &, the *"#*#se %#$ume t# ta:e the cut an' ($$ %#$ume. ;e!at%e state t# &e ($$ an' *#st%e state 7#" cute!/618.98965
