Design Steel Beam Bridge F1.Nguyen the Huy
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Transcript of Design Steel Beam Bridge F1.Nguyen the Huy
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8/19/2019 Design Steel Beam Bridge F1.Nguyen the Huy
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THIẾT KẾ MÔN HỌC CẦU THI. S LI U CHUNG1.Data Tần suất TK P = 1
Số dầm chủ n = 6Chiều dài nhịp L = 25
Thông thuyền 25
3.5Khổ cầu
Bề rộng phần xe chy 1
!ề ng"#i $i %ộ 2
Bề rộng t&àn cầu 15
'&t t(i thi)t *) + '! ,-.-/0123- 4p5
2. !"t #$%& '() t*+ ,-6uy tr7nh thi)t *) + 88TC9 38:831;B< tông %5n m5t c5u+
4-11 c= >c?@ 3 M/a
tAg %
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Oi số Aàn n@8 th7 c= m@ 1
. C& t*+Chiều dài nhịp ch) t& Aà !nh@ 25
Kc tR $ầudầm $)n tim gối 5@ .3 2.
Số A"ng dầm chủ n= 6 ,-
E F&A t 't nJanJ '-&
Bề rộng phần xe chy
Số Aàn xe thi)t *)Bề rộng Aề $i %ộ
Bề rộng chn A5n c5n
Bề rộng t&àn cầuKh&(ng cUch giV5 cUc dầm chủ @0/8 38/Wm S=
Chiều dài phần cUnh hXng
Y ZUc $ịnh chiều c5& dầm chủ the& *inh nghiEmCông th[c +c= !\-1@ 1/]0------- m
]] cmChFn s^ %ộ nh" s5u +
Chiều c5& %(n %Png
Chieu d5y %5n c5nh tren
Chieu d5y %5n c5nh du&i
Chieu c5& t&5n %& d5m thepY C5u t5& %5n %e t&ng m5t c5uts@ 0_3 8; cm
Ch&n ts@ 81 cm`5y *ich thu&c c5u t5& %5n %e t&ng m5t c5u
Chieu d5y %5n %e t&ng
C($& ,$ n(/ t9n( t+n # Ltt=
:;&
=
,<=
t7=
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Chieu d5y %5n ut
Be r&ng ut %5n
Chieu d5i ph5n c5nh h5ngChieu d5i ph5n c5nh phi5 tr&ng S?2=
`5y c& t&ng h&p *ich thu&c thiet *e d5m chu:an &nJ
12 '
2. ':an 'an( t
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. Xác định mômen tĩnh của mặt cắt đv trục 0-0 ua đáy
3113.Kh&5ng c5ch tu d5y d5m den TT' m5t c5t Ha J
5.01 'Chieu c5& ph5n su&n d5m chiu nen
60.0 'Kh&5ng c5ch tu mep tren d5m thep den truc J3J
2.0 'Kh&5ng c5ch tu mep du&i d5m thep den truc J3J
5.01 '
. X! m"men uan tinh mc dam dv ##$ %-% 4ômen bu5n tinh %5n %Png
30622.2446T %5n c5nh chiu nen M C5u d5m gi5n d&n nen %5n c5
05.446T %5n c5nh chiu *e&
5.6
4&men bu5n tinh cu5 m5t c5t132223.13
4&men bu5n tinh cu5 m5t c5t
312.54&men tinh cu5 ph5n tren m5t
12.6
:anJ t+nJ (+/
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2. ]^ V' t_nJ (`n( (' t 't J$a$ V+*n II
& Xác định ' r"ng tinh t"an cua 'an 'et"ng . ZUc $inh %0
0\W !tt@ 3508/ts . m5xMQ@ 12.5S@ 125
`5y c& %0@ 125 '. Z5c dinh %8
tu&ng tu c& S\8@ 125
`5y c& %8 @ 125
Be r&ng tinh t&5n %5n %et&ng d5m %ien
Be r&ng tinh t&5n %5n %et&ng d5mtr&ngY Xac dinh he " uy d"i tu 'e t"ng ang thep
T' ng5n h5n n@ _/:,-T' d5i h5n n?@ -n
Tuy nhien the& tr5 %5g t5 c&
n= nb= 2
Y X! D#$$ của mặt cắt d*m 'i+n+ DTHH của cốt thép trong bản betong
!"Oi c&t thDp phL5 tr
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aT 0 th5nh a =S& th5nh n =Bu&c c&t thep c
T&ng aT c&t phi5 tren
Chieu d5y BT %5& e!"Oi c&t thDp phL5du&i
Hi&ng tren`y T&ng dien tich c&t thep tr&ng %
Kh&5ng cUch tR tr&ng t5m CT
. D#$$ mặt cắt ,i+n hp ngắn h.naien tich mft ctaien tich %5n BT
-1 aien tich ph5n ut cu5 %5n BT
aien tich t&5n %& %5n BT
`y dien tich c
44 tinh cu5 %5n BT 5 c&t thep d TT' J3J
66526.6
Kh&5ng c5ch tu tr&ng t5m tiet dien aT den tr
53.1Chieu c5& ph5n su&n d5m chiu nen d5n h&i
16.Kh&5ng c5ch tu mep tren d5m thep den truc J
10.Kh&5ng c5ch tu mep du&i d5m thep den truc J
Ot
=
at
=
O=
\=
O7+ =
O( =
O7=
O7t =
S1;
=
d1=
D'2
=
\tEII
=
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11.02
XD momen quan tinh tiet dien lien hop 4&men bu5n tinh cu5 ph5n a
446T cu5 ph5n %5n BT
446T cu5 ph5n ut %5n c5nh+
446T cu5 ph5n c&t thep tr&n
5̀y 446T cu
4&men tinh cu5 %5n BT &i truc JJ3JJ cu5 tiet
20.6+ D#$$ cua mat cat ,ien h"p dai han
aien tich %5n BT
5aien tich ph5n ut %5n BT
5aien tich t&5n %& ph5n BT
55aT cu5 m5t c5t Aien h&p d5i h5n
06.3
44 tinh cu5 %5n %e t&ng 5 CT %5n d&i &i210.06
Kc tu tr&ng t5m tiet dien d5m thep den tr&ng t
3.16Chieu c5& ph5n su&n d5m chiu nen d5n h&i
3.02
\EII
=
I2E NC =
I7 =
I( =
I =
IST =
S7 =
Ob7+ =
Ob(=
Ob7 =
OLT
=
Sb1E; =
db1 =
Db'2
=
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Kh&5ng c5ch tu mep tren d5m thep den truc J
1.02Kh&5ng c5ch tu mep du&i aT den truc Ji?3JJ?
.
Za m& men bu5n tinh cu5 tiet dien Aien h&p446T cu5 ph5n d5m thep
446T ph5n %5n Bt
446T ph5n ut %5n c5nh
446T ph5n c&t thep tr&ng %5
446T cu5 m5t c5t Aien h&p d
44 tinh cu5 %5n BT &i Truc JJ?3JJ? cu5 tiet d
:YnJ tenJ (f/ )t &Y t9n( ^THH 'ga
^' T_nJ (`n( (' 'ga ,- $[nMC nJ
K9 ($%&
Bề rộng cUnh tLnh t&Un củ5 %(n BT
aiEn tLch %(n BT
aiEn tLch phần t %(n
aiEn tLch t&àn %ộ %(n BT
aiEn tLch cốt thDp tr&ng %(n BT
aiEn tLch mft ct tLnh $ổi
4ômen tGnh củ5 4C $ trPc J3J
Kh&(ng cUch tR TT' J3J $)n JJ3JJ
446T củ5 dầm thDp Oi trPc JJ3JJ
\btEII =
\bEII
=
IbNCEII
=
Ib7 =
Ib(=
Ib =
IbLT =
Sb7=
7
O7+
O(
O7
OO7tS
1;
d1
INCE2
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446T củ5 %(n Oi trPc JJ3JJ
446T phần t %(n Oi trPc JJ3JJ
446T củ5 cốt thDp tr&ng %(n
446T mft ct Ai
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Xác định mômen ch
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2.50 '
1652613.2 KN.'1655.35 KN.
#3nh t"án ch" c< d*m 'i+n v4 d*m tr"ng nh9ng d" d*m 'i+n ,4 d
n+n ta ? ,=y giá trị của d4m 'i+n đ@ thiAt BA au n4y CC
ds @
M p @
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P
i
,-
T! củ5 BT 5sph5A Aà@ 8- KH\m
.0
.651
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1 '
2 #n '
5 '
15 '25 '
125 '
12 '
3 '
3 '
13 '
2 '
DR=
tt=
t=
H7
=
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12 '
12 '
125 '125 '
_:;1
-]0W8/]W]
1/0:_,__--;
400He he
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h tren A5 %5n chiu nen i %ieu d& m&men c& 0 d5uQ
5m thep d TT' J3J A5
5m thep d y
c5t d5m tep d&i &i TT' JJ
an IGIO TI DQN !I
53.6
3113
5.01 '
2.0 '
'
'
'3
'2
'3
600 he he
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5.01 '
30622.16
05.30
5.5132223.13
12.6
312.5
'''
'
25 '
25 '
D- t+nJ jjjjjjj Y X! D#$$ của+ DTHH c
!"Oi c&t1.2 '
'
'
'
'
'3
'
7 =
7 =
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1.13113 t(an(2 '
1.3
5 '!"Oi c&t
n BT
20.5en mep tren cu5 d5m thep
22 ' 22
. D#$$
5
5
55 '2
;-:/_5 mc Aien h&p ng5n h5n A5
1255.1 ủ5 tiet dien thep A5
ng t5m tiet dien Aien h&p M Kc tu J3J den JJ3JJQ
'
'3JJ A5
'J3JJ A5
'2
'2
'2
'2
'2
'2
'3
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'
+
2323.0-888W-/08_
1563.3 01:;W_-/8]W
--:W_-/W-08
212.0 %5n
061.0
m5t c5t Aien h&p ng5n h5n A5
13.5dien Aien h&p
+ D#$$
T' J3J cu5 tiet dien thep
5m tiet dien Aien h&p M *c tu truc J3J den JJ?3JJ?Q
'
'
'
'
'
'
'
'3
'2
'2
'2
'2
'2
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?3JJ?
'
'
111355.1
5253.
0633.2
1215.i h5n
230.ien Aien h&p d5i h5n A5
16215.6
t 't ,- $[n :Y
n (*n MC ,$ (*n^kn W ^' T_nJ (`n( ('G$ t K9 ($%& G$ t
25 25 ' Bề rộng cUnh tLnh t&
5 5 aiEn tLch %
5 5 aiEn tLch phầ
55 55 aiEn tLch t&àn
20.1 20.1 aiEn tLch cốt thDp
1255.1 06.3 aiEn tLch mft c
66526.6 22. 4ômen tGnh củ5
53.1 3.16 ' Kh&(ng cUch tR TT
2323. 111355.1 446T củ5 dầm thD
'
'
'
'
'
'3
7
O7+ '2
O( '2
O7 '2
O '2
O#t '2
Sb1; '3
db1
IbNCE2 '
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1563.3 5253. 446T củ5 %(n
213 0633 446T phần t %(
0610 12150 446T củ5 cốt th
13.5 230. 446T mft ct Ai>>>>>>>>
D- t+nJ jjjjjjj / 2ặt cắt d*m tr"ng
Xác định vị tr3 trY TLnh A
KN
KN0/;]
KN 0],0_W_/1
165535.312KN
$ộ 2 M/a
KN
KN
0];W:/81 00:_0/W8;:, Y aầm t152.2 KN135.23 KN
l 3c . 3r% . 3s . 3rt:Yn 'n( t[n
Xác định chiu c
Ib7 '
Ib( '
Ib '
ILT 'Sb7 '
@ A=
( )8 8
c p c s s rt s h rt r% h s
c
t c t s%
m4 / y t y m /My Q m /My t t C Q m /Mt t
8t
a tm /M t yQ m M' y Q
8 8
= + − + + + + + − + + +
+ + − + − −
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. 'mDI!? Xác định mômen
4ômen
i hn 4ômen
Dp 4ômen
qng suất tr&ng dầqng suất ti mDp tr
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81/;]:81,-
m '=t ,i h>n MSheet+ !&5dQ
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ặt cắt d*mtr"ng a cốt thép trong bản betong
thDp phL5 tr
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aT 0 th5nh a = 1.131S& th5nh n = 13 t(an(Bu&c c&t thep c 2 '
T&ng aT c&t phi5 tre 1.
Chieu d5y BT %5& 5 ' thDp phL5du&i
Hi&ng tren`y T&ng dien tich c&t thep tr&ng %5n BT
20.1Kh&5ng cUch tR tr&ng t5m CT den mep tren cu5 d5m thep
22 ' 22
ặt cắt ,i+n hp ngắn h.naien tich mft ctaien tich %5n BT
5aien tich ph5n ut cu5 %5n BT
5aien tich t&5n %& %5n BT
55 '2
`y dien tich cu5 mc Aien h&p ng5n h5n A5
1255.144 tinh cu5 %5n BT 5 c&t thep d TT' J3J củ5 tiet dien thep A5
66526.6
Kh&5ng c5ch tu tr&ng t5m tiet dien aT den tr&ng t5m tiet dien Aien h&p M Kc tu J3J d
53.1 'Chieu c5& ph5n su&n d5m chiu nen d5n h&i
16. 'Kh&5ng c5ch tu mep tren d5m thep den truc JJ3JJ A5
10. 'Kh&5ng c5ch tu mep du&i d5m thep den truc JJ3JJ A5
'2
Ot
= '2
at
=
O= '2
\=
O7+ = '2
O( = '2
O7=
O7t = '2
S1;
= '3
d1=
D'2
=
\tEII
=
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11.02 '
XD momen quan tinh tiet dien lien hop 4&men bu5n tinh cu5 ph5n aT +
2323.446T cu5 ph5n %5n BT
1563.3446T cu5 ph5n ut %5n c5nh+
212.0446T cu5 ph5n c&t thep tr&ng %5n
061.0
`5y 446T cu5 m5t c5t Aien h&p ng5n h5n A5
13.54&men tinh cu5 %5n BT &i truc JJ3JJ cu5 tiet dien Aien h&p
20.6 ua mat cat ,ien h"p dai han
aien tich %5n BT
5aien tich ph5n ut %5n BT
5aien tich t&5n %& ph5n BT
55aT cu5 m5t c5t Aien h&p d5i h5n
06.3
44 tinh cu5 %5n %e t&ng 5 CT %5n d&i &i TT' J3J cu5 tiet dien thep210.06
Kc tu tr&ng t5m tiet dien d5m thep den tr&ng t5m tiet dien Aien h&p M *c tu truc J3J d
3.16 'Chieu c5& ph5n su&n d5m chiu nen d5n h&i
3.02 '
\EII
=
I2E NC = '
I7 = '
I( = '
I = '
IST = '
S7 = '3
Ob7+ = '2
Ob(= '2
Ob7 = '2
OLT
= '2
Sb1E; = '2
db1 =
Db'2
=
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Kh&5ng c5ch tu mep tren d5m thep den truc JJ?3JJ?
1.02 'Kh&5ng c5ch tu mep du&i aT den truc Ji?3JJ?
. '
Za m& men bu5n tinh cu5 tiet dien Aien h&p446T cu5 ph5n d5m thep
111355.1446T ph5n %5n Bt
5253.446T ph5n ut %5n c5nh
0633.2
446T ph5n c&t thep tr&ng %5n1215.
446T cu5 m5t c5t Aien h&p d5i h5n
230.44 tinh cu5 %5n BT &i Truc JJ?3JJ? cu5 tiet dien Aien h&p d5i h5n A5
16215.6
nJ tenJ (f/ )t &Y t9n( ^THH 'ga t 't ,- t+nJ
'ga ,- $[nMC nJn (*n MC ,$ (*n
^kn WK9 ($%& G$ t K9 ($%& G$ t
Un củ5 %(n BT 25 25 '
n BT 5 5
t %(n 5 5
ộ %(n BT 55 55
r&ng %(n BT 20.1 20.1
t tLnh $ổi 1255.1 06.3
C $ trPc J3J 66526.6 22.
J3J $)n JJ3JJ 53.1 3.16 '
Oi trPc JJ3JJ 2323 111355
\btEII =
\bEII
=
IbNCEII
= '
Ib7 = '
Ib(= '
Ib = '
IbLT = '
Sb7= '3
7
7
O7+
O7+ '2
O(
O( '2
O7
O7 '2
O O '2
O7t O#t '2
S1;
Sb1; '3
d1
db1
INCE2
IbNCE2 '
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Oi trPc JJ3JJ 1563 525
Oi trPc JJ3JJ 213 0633
p tr&ng %(n 0610 12150
p Oi trPc JJ3JJ 130 2301^i trPc JJ3JJ 20.6 16215.6
D- t+nJ jjjjjjj
c trung h"4 d5" (678)c dj& củ5 cUc phần củ5 mft ct dầm +!c dj& ti %(n cUnh chịu *D& củ5 dầm+
515 KN!c dj& ti %(n cUnh chịu nen củ5 dầm+
315 KN!c dj& ti s"#n dầm thDp
126.2 KN
!c dj& ti trFng tm %(n BT135.2 KN
!c dj& xuất hiEn ti cốt thDp %(n phL5 tr
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1.1 'ch
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2.50 '
1626630.1 KN.'16266.30 KN.
ds @
M p @
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n JJ3JJQ
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n JJ?3JJ?Q
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1. ]' Vn( '' (% #$[n )t t+nJ KCN& $E ,i+n BAt ngang t.i mặt cắt gFi
aầm ng5ng ti mft ct gối Aà ch $ft *Lch $o nng h cUc cPm dầm tr&ng
ChFn dầm ng5ng ti mft ct gối Aà dầm $ịnh h7nh Aà +Cấu t& dầm ng5ng ti mft ct gối+ M tr5 %(ng thDp h7nh t5 c= Q
Chiều c5& dầm ng5ng +
Bề rộng %(n cUnh + 21
Chiều dày %(n cUnh + 2.
Chiều dày %(n %Png+ 1.3
aiEn tLch mft ct ng5ng+ 16
4ômen buUn tLnh mft ct 136TrFng A"ng dầm ng5ng tr
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Số th5nh ng5ng tr
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aiEn tLch mft ct ng5ng s"#n tng c"#ng +
TrFng A"ng 0 th5nh s"#n tng c"#ng
Kh&(ng cUch giV5 cUc s"#n tng c"#ng+
TrFng A"ng củ5 s"#n dầm tr
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.22 KN?TrFng A"ng d(i $ều củ5 %(n %
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L Xác định hE F phMn 'F ngang& #3nh hE F phMn 'F ngang the" ph9>ng pháp đNn 'Oy J
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#3nh hE F phMn 'F,Wc cắt 'E số phn %ố ng5ng tLnh ch& dầm tr&ng
T' x)p 0 Aàn
T' x)p 8 Aàn'E số phn %ố ng5ng tLnh ch& dầm %in 8 nJanJ
!X$ ,- $[n
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STT S8 #n H7 P:N K9 ($%&
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6600 19800
8800 17600
13200 13200
4 . 9
5
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0
ĐAH mômen mt !t "#4
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2. T9n( ,$%n t9'( V_nJ Yn( (_unJ
CvC ^wI LxyNG
M1 2. 3.5 21.35 2.6M2 2. 6.1 1.3 .5
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' Vn( nz$ #s' t*$ '' t 't1. T9n( nz$ #s' ,+ tn( tY$J tenJ (f/ nz$ #s' ,+ tn( tY$
Nz$ #s'[Ja DCt' Drt' [Ja DCt'
M1 32.56 10.13 5.5 622.M2 55.2 10.13 5.5 16.6M3 6.20 10.13 5.5 1220.M .2 10.13 5.5 123.5! 12.2 10.13 5.5 233.!1 0.15 10.13 5.5 15.
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B(ng *)t bu( tLnh nội Ac +CvC ^wI LxyNG
! t9 Vt tY$
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T&nJ Vz ^OH
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T&nJ Vz ^OH
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H% 78 P:N
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D+ (+*t tY$ t$[& '(&qn !t'E (} KN~D+ (+*t tY$ t9n( t+n !ttE(}KN~
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L #3nh ,Wc cắt t.i mặt cắt %%%-%%%( mặt cắt mFi nFi)
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CvC ^wI LxyNG
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M1 622.2 1.05 1.63 55.2M2 16.50 36.5 122. 01.20M3 1220. 353.35 12.20 1126.60M 123.5 0. 16.26 126.21
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:‚NG TƒNG HyP N„I L…C TI†U CHU‡N THBQ TTGH
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2 t(an(
2.36
2 t(an(
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22.
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1.22
dầm chủ + .3 KN?
11x011x01
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5n
KN?
KN?
iều c5& A^p phủ phần ng"#i $i %ộ Aà ; cmQ
dày cUc A^p Aần A"t giống h"Ong dXn củ5 thầyQ
g w chiều c5& A5n c5n $ều @ ;1 cm
p
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hMn 'F ngang ch" d*m 'i+nTung $ộ I'
H% 78 Jy8 y- yW !ần A"t x1/; 1. 1.5
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.60
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TY$ tnJ
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0 .
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DIỆN TŒCH ̂ OH
32.56 32.5655.2 55.2
6.20 6.20.2 .2
1. . 12.2 . 12.2. .13 0.3 .10 0.15.5 .25 6.6 .6 6.1.6 .32 5.1 1.22 .0.5 .5 3.5 3.5 .
^kn W[JaDrt' TenJ TenJ
10. 1. 1.5 21.0 100.3 KN36. 13.3 11.2 3.1 1.3 KN353.3 153.1 161.1 556.5 21.6 KN0. 132.5 16.3 6.2 2512.5 KN6. 3. 36.3 15.6 11.0 KN5.3 225.3 220. 0.2 3.0 KN
A1=}L;~?L
A2=;?L
[JaM}2~
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33.5 15.2 153.1 52. 25.0 KN2. 11. 112. 3.0 151. KN. . . . . KN
P:N
Nz$ #s' $
JNJ St'E #an St'EnJ&+$ SttE #an SttEnJ&+$ Sb#an SbnJ&+$1. 25.3 2.3 6.1 520. 25.3 2.31. 36.3 0.3 1.2 0.2 36.3 0.3
1. 52.2 560.30 022.01 16.25 52.2 560.301. 51.3 650.6 16.2 1211.3 51.3 650.61. 05.31 1. 15.12 10.53 05.31 1.1. 2.0 2.2 13.0 152.1 2.0 2.21. 53.61 6. 0.52 111.6 53.61 6.1. .61 5.5 1.0 02.0 .61 5.51. 23.3 2.1 3. 0.63 23.3 2.1
Nz$ #s' t$[& '(&qn} TTGH 7• ,€nJ~
Nz$ #s' t9n( t+n} TTGH C_nJ Vz
I~
ĐAH mômen mt !t "#$
23100
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]< tY$ t($)t ) ]< 2 t€' t($)t );1 ;2 ;3 ; ;5 ;6
1.25 3.5 .35 . 3.5 .25A1 A2 A3 A A5 A6
2.6 2.13 . 2.6 2.52
PtE3 PtE2 PtE1 PtE1 PtE2 PtE3
35 15 15 . 11 11
3.1 30.6 . 203.50 2.0
606. 5.6
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1.63 55.21611.5 1321.26
6.0 661.53
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ĐAH mômen mt !t "#4
19800
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1. 6.1 1. . 6.1 .3
A1 A2 A3 A A5 A6
1.35 .5 3.5 .5 .2
PtE3 PtE2 PtE1 PtE1 PtE2 PtE3
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121.13 03.5
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22.26 2253.0
112.51 112.
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145KN4.3
1.2m
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A1 A2 A3 A A5 A6
2.33 5.2 3.01 . 5.2 .0
PtE3 PtE2 PtE1 PtE1 PtE2 PtE3
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1.5 6.15 56.30 . 50. 53.112.00 111.
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15 15 35 11 11
15. 110.5 22.66 . 11. 1.50
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15 15 35 11 11
126. 11.32 1.20 . 06.25 0.
26.0 1.0
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2.6 1.50
5.6 33.16
25.2 216.
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15 15 35 11 11
1.5 3.2 13.01 . 2.5 .025.6 150.50
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2.51 16.
6.62 360.0
23.63 15.
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]< tY$ t($)t ) ]< 2 t€' t($)t );1 ;2 ;3 ; ;5 ;6
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A1 A2 A3 A A5 A6
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00.2 3.60 11.62 . 5.20 60.
1.55 15.16
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2.2 336.0
213.03 16.2
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4.3m 4.3m
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45KN
1.2m
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]< tY$ t($)t ) ]< 2 t€' t($)t );1 ;2 ;3 ; ;5 ;6
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A1 A2 A3 A A5 A6
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2.5 53.6 .21 . 55. 5.03
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30.1 25.25
155.66 122.0
Sˆ D‰NG$[& '(&qn
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25.3 2.3 26.15 1010.6 26.15 KN36.3 0.3 3532.53 325.05 3532.53 KN52.2 560.30 0.6 31.6 0.6 KN51.3 650.6 61.15 350.0 61.15 KN
05.31 1. 03.16 2.6 03.16 KN2.0 2.2 620.6 560.50 620.6 KN53.61 6. 2.1 25.6 2.1 KN.61 5.5 301. 352.1 301. KN23.3 2.1 15.6 15.62 15.6 KN
'_nJ Vzt9n( t+n
TH1 TH2 ^kn WLan< NJ_$
6.1 520. 3.15 31.5 3.15 KN1.2 0.2 61. 5.1 61. KN022.01 16.25 11.1 62.62 11.1 KN
16.2 1211.3 5.3 6.1 5.3 KN ]1]0/_;15.12 10.53 15.2 122.36 15.2 KN13.0 152.1 1165.6 12.16 1165.6 KN0.52 111.6 02.6 5.63 02.6 KN
1.0 02.0 53.01 662.2 53.01 KN3. 0.63 3.13 33.6 3.13 KN
#a t$
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& chc chn h^n ti cUc mft
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)p the& th[ t tR trUi bu5 ph(i nh5
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t "#4
!t mi ni % "#3&
t "#2
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^kn W
KNKN
KNKNKNKNKNKNKN
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145KN 35KN4.3m
ĐAH l! !t mt !t gi
0 .
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O. KIŽM TO TŒNH CN ]NG C‘O M{T C|T DẦM CH‘
1. K$’ ta t9n( '>n ;“nJ '(&nJ 'ga t 't .J3yc@ _:;1/11 cmW
J3y@ -]0W8/]W] cmWTz số @ 1/0:: It {{{{{{{
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Kiom t&Un ^*t
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1. S“' (nJ &8n 'ga t 't #$[n (f/ V' '('
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Mn= 12.6 KN
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Y S[c *hUng uốn tLnh t&Unhi3>@ 0`y 4r@ 0WW81/_8-8 K9m
Y Kiom t&Un *h( nng chịu Ac củ5 dầm
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a \ t@ ;0/______:*@ 01/0_;
Cn dài@ :_/:_;
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c@ 0Y S[c *hUng ct củ5 m(nh s"#n dầm phL5 tr&ng 8/W
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S& sUnh t5 thấy t9n( t(
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C. KIŽM TQvN DẦM THBQ TTGH M–I
1. CnJ t(“' $’ t+nac@ 0_/1] cm
8a3c\t3 0-/-,];/: Cn 0-:/8WS& sUnh SD 'nJ t(“' 1
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Y qng suất tr&ng dầm d& tGnh t(i ti
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Kiom t&Un+ ^*t n(_nJ t(Za (k$ n($& ($ ($
3. K$’ t+n “nJ 7&t $ ,+ 't
11.5 M/a
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D. KIŽM TQvN THBQ TTGH Sˆ D‰NG1. K$’ ta Vz W˜nJ )t '& n(/
Iiều *i
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hE số "t t(i
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230.5
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ng u=t d" h".t t
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ốn m ph(i th&( m€n+
L= 2.; = 12.2
J = .'E số xung *Lch củ5 h&t t(i IM1= 1.25
- 8 0 I^n ị15 15 35 K9.0 12.2 16.5 m
.56 .56 .116 cm1.1 cm
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1.522 '1.112 '
r5 ti mft ct giV5 nhịp Aà 1.522 ' &t t(i Aà 3.5 '
^*t
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132223.13
KN?' 13.5
DCt' =
Drt' =
INC
= '
IST = '
KN?'2
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mm
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11.TŒNH TQvN !™ :Ố TŒ SxN TšNG CxNG1. K$’ t+n STC t*$ t 't J8$
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Y Kiom t&Un s[c *hUng Dp mft3̀u@ 0W;1/8: K9 5.3333
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P= 6.3 KNS& sUnh t5 thấy ^*t
Y Kiom tr5 $ộ m(nh giOi hn
K!\r3s@ 0;/-0W-_S& sUnh
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pn
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`y + QK
12. TŒNH TQvN !™ :Ố TŒ NBQ LI†N KẾT Deign 'y #r*n #r
11 SWc tr9t danh định tác dụng ,+n ne" 3 Khi mft ct dầm phUt trion $)n gi5i $&n ch(y dj& th7 trPc trung h†5 dj& 9củ5 dầm chủ $i bu5 s"#n dầm n
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3 `y+ !c gy tr"t dFc d& h&t t(i+
1/ `p ,Wc phMn 'F d" t
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@ˆ C"#ng $ộ tLnh t&Un củ5 $"#ng hàng
13.3.%. X&c "'nh chi(u cao "!ng h$n 3 Chiều c5& củ5 $"#ng hàn+
3 Chiều c5& tối thiou củ5 $"#ng hàn+
15. TŒNH TQvN MỐI NỐI DẦM15.1. K(Y n›nJ '(& #s' 'ga nJ
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. S[c *hUng tr"t d5nh $ịnh+
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. g+ aiEn tLch ti)t diEn nguy exx
+ C"#ng $ộ phn A&i củ5 thDp $"#ng hàn
+ φ8
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15.2. T9n( t+n 8$ n8$ Yn €nJ1).%.1. C*u to mối nối d,m1).%.%. C*u to mối nối bản b-ng 3 Bố trL %uAông tr
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. Kh&(ng cUch tR %uAông x5 nhất $)n gốc tF5 $ộ+
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3 !c ct tUc dPng A
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'zt
3 !c tUc dPng A
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. Số cột %u Aông+
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3 KLch th"Oc %(n tUp+ . Chiều dày %(n t5p+
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cm
cm
cm
cm
cm
cm
cm
cm8
cmW
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ung $iAu
3
55
135.2 *9
20.0 4p55 4p5
, = 2 mm
1 cm
3.12
1.62 *9
152.3 *9
K)t #&"np !.t
125. *9
, = 2 mmN = 2115
α = .0350 Œ 0,d28.6
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@ 'b = *9\cm8
O7 = cm8
!( =
B' =@
&n
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135.2 *9
125. *9n = 111.5 ne&
ne&
3 ne&TnJ n= 202 ne&
/ = 160. mmC(n / = 1 cm
/ = 1 cm
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13.5
20.6
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K)t #&"np uá đ.tZ
132223
13.52
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= cmW
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= cm-
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230.
36.2 *9 ;:/,08,W_W8]_
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13.30 *9 -1/0_8,,:]];,6352.
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363.2
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γ = 1.5α = 1! = 1.062 *9\cm
10.62 *9\m
1
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φ
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5 4p5
.
232. 4p52.33B5 *9\m
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35 4p5, = 22 mm
2 mm
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1.
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2 mft
116.16 *9
116.16 *9
OJ = cm8
@
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3 %u Aông12 %uAông
n = 36 %uAông
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cm
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3132.
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J 61.2
2111. *9
n j= 1.166520 %uAông
2 %u Aông
%uAôngn = 16 %uAông
.5 cm
cm3.5 cm
1. cm
t = 2 cm
3 cm
13 cm
12. cm
12 mm
35 4p5
J 16.
36.6 *9
n j= 31.2 %uAông
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a
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%u Aông
%uAôngn = 2 %uAông
0 cm
cm
6 cm
1 cm
t = 2 cm
cm
23 cm
121 cm
n' =
n( =
a'=
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16. TŒNH TQvN :‚N M{T CẦU16.1. C& t*+ 'ga Yn t '-& 3 KLch th"Oc cấu t& %(n %< tông mft cầu+
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-
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S @00W1.1/]--ZMZ+ Kh&(ng cUch tR $iom $ft t(i trFng tOi gối %(n Z @ 5 mmQ
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-
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Nz$ #s' t+nJ Yn ,+ ;< tY$p
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*9 *9/m *9/m *9
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. aiEn tLch $5h m+
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y4 4tc 4tt y` `tc
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16.2..3. ]' Vn( nz$ #s' 'ga Yn (ŸnJ KF "L tMnhA D,m cng Non X&c "'nh tOnh tải t&c d-ng l0n bảnA
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Mtt
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hiEu *9/m cm cm cm cm mm
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KL h %
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KL h %
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1/0_ Œ 1/W8 _j
0/W8 ˆ 0/- _j :YnJ $’ t+n (Y n›nJ '(& 'tp
KL 1/; φ
hiEu *9 cm cm cm mm
HiU trị 0W_/- 0;0/; 0W/W1 ,,0/: _;WW8 8]/1 08/1
KL n α β θ
hiEu th5nh $ộ $ộ *9 *9
HiU trị 0-/11 8,/W0 ,1 8 W; 0,]-/W 0_;/;K)t Aun
0W:8/W- *9 j `u @
4u
g
5tp
d p
φs
cm8
5s ds s >s? nth? nA? Žs?
cm8
> ps
psc5n
nc5n
n %&tri
Ž ps
cm8
5tp
dtp
> ps
de
c\de
. c\de @
. 4r \4
u @
`u
%
d
1/0/> c? S
%t
`c .
̀p %
/d
%t
`c
`s
cm8
. Kiom t&Un *h( nng chịu ct `r
@
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2 cm12 cm
12 cm
125 cmS?2 = 125 cm
1IM = 1.25γ = 1.5P = 25 *9L = 361.6 mm
36.16 cm
1. cm
02.16 cm
L?S= 0.6 j 1.5
q Png
Sr = 235 mm @ 81-/; cm
Sr = 15 mm @ 0]W/; cm
t7 =t
( =
( =
,<+ =
/ =L
/=
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Sr = 151.5 mm @ 0;0/W]; cm
: = 2.35 m .H = .2 m
DC = 1.15
. m
Dr = 3.
.2353.2
.2160
1.3
.2
1.1
2.23 *9/m
2. *9/m
11.10 *9
13.00 *9
.2 *9/m1.23 *9/m
.12 *96.1 *9
O7an = m8
*9\m8
H'
=
*9\m8
ϖ
=ϖ
=
ϖ
M =
ϖ
=
ϖ
=
ϖ
! =
t'.ϖM =
= γ
.Mt'
=
t'.ϖ! =
= γ
.!t' =
t'.ϖM
= = γ
.Mt'
=
t'.ϖ! =
= γ
.t'
=
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*9
08_/]]88/,_1/111/11
0W,/]W
: = 1.5 m .360H = .2 m
DC = 0.225
. m
Dr = 3.30
.1511.5350
.331
1.3
`tt
O7an = m8
*9\m8
H'
=
*9\m8
ϖ
=ϖ
=
ϖ
M =
ϖ
=
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.2
1.1
3.55 *9/m.3 *9/m
1.15 *9
12.6 *9
1.3 *9/m
1.06 *9/m
3.3 *9 ;/;,,
5.6 *9
*908_/]]
88/,_1/111/11
0W,/]W
ϖ
=
ϖ
! =
t'
.ϖM =
= γ
.Mt' =
t'.ϖ! =
= γ
.!t'
=
t'.ϖM =
= γ
.Mt' =
t'.ϖ! =
= γ
.!t'
=
`tt
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1.25 m
1.51 m
.2 m
.33
.12 m
.5 *9/m
.1 *9/m
1.56 *9\m
.1 *9\m
2.52 *9
5.02 *9/m
. *9/m
0. *9
11.3 *9
1.1 *9/m
1.6 *9/m
3.1 *9. *9
2.52 *9/m
3. *9/m
Ltt
an =
7 =
t7 =
O7 = m8
H'
=
DCt' =
Drt' =
#'
=
'#' =
P#'
=
Ct'.#12?2 =
= γ
.Mt'
=
DCt'.#
1 =
= γ
.!t' =
t'.#22?2 =
= γ
.Mt'
=
Drt'.#2 = = γ
.!t' =
t' = P
#'.#
3=
= γ
.Mt' =
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2.52 *9
3. *9
2.5 *9
a = .5 m
32.63 *9/m
5.0 *9/m
2.5 *9
126. *9
23.5 cm
2 cm
.
-1
!t' = P#' =
= γ
.!t'
=
P =
2.5a =
= γ
.Mt' =
!t' =
= γ
.!t'
=
7=
t7 =
β
1 =
nth
nA
Žs
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th5nh A"Oi cm
, 0 8W/0, 216.
cm cm 655.1; ; 1/11
350.
1/11 ∆ = 353503.
a = .60*9/m *9/m
:;/- _:/: 0/;;_j
n s
nhUnh
1/_ 8/11 8/8_
*9 *9 *9
880;/_ 880;/_ 0,,W/1_j
0:1/10 *9
1.5 cm
2 cm
.
5s? d
s?
s?
cm8
ps
cm8
4n
4r
4r \4
tt
cần
cm8 cm8
`n
`n
`r
7 =
t7 =
β
1 =
?
0 c/1/];/> /%
8
β=
?
0 c p
B /1/];/> /%/d= −β
( )? ?tt s y p sC 4 /> / d d= − −
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-1
th5nh A"Oi cm
, 0 80/]0 106.50
cm cm 50.; ; 1/11
522.
1/11 ∆ = 3510632.102
a = .05*9/m *9/m
00W/1 018/_ 0/],_j
-1
n s
nhUnh
1/_ 8/11 8/8_
*9 *9 *9
0,,8/_ 0,,8/_ 0:,-/-_j
0_]/0- *9
151.5 cm
2 cm
.
nth
nA
Žs
5s? ds? s?
cm8
ps
cm8
4n
4r
4r \4
tt
cần
cm8 cm8
`n
`n
`r
7=
t7 =
β
1 =
?
0 c/1/];/> /%
8
β
=?
0 c pB /1/];/> /%/d= −β
( )? ?tt s y p sC 4 /> / d d= − −
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-1
th5nh A"Oi cm
, 0 0:/_, 161.1
cm cm 2.3; ; 1/11
2.5
1/11 ∆ = 105.525
a = 1.5*9/m *9/m
00W/11 018/_1 0/W8_j
-1
n s
nhUnh
1/; 8/11 8/8_
*9 *9 *9
0_-_/1 0_-_/1 0W:8/W_j
0W_/8: *9
nth
nA
Žs
5s? ds? s?
cm8
ps
cm8
4n
4r
4r \4
tt
cần
cm8 cm8
`n
`n
`r
?
0 c/1/];/> /%
8
β
=?
0 c pB /1/];/> /%/d= −β
( )? ?tt s y p sC 4 /> / d d= − −
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*9\cm
*9
*9/cm
cm
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*9\cm
*9
*9/cm
cm
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*9\cm
*9
*9/cm
cm
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