Design Project - Georgia Institute of...

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Design Project ECE4445 – Audio Engineering November 27 th , 2006 Franklin Falcon 901-95-6137 [email protected] Juan O'Connell 570-575-8161 [email protected]

Transcript of Design Project - Georgia Institute of...

Page 1: Design Project - Georgia Institute of Technologyusers.ece.gatech.edu/.../SignedAudioProjectReport.pdfDesign Project ECE4445 – Audio Engineering November 27th, 2006 Franklin Falcon

Design Project ECE4445 – Audio Engineering

November 27th, 2006

Franklin Falcon 901-95-6137

[email protected]

Juan O'Connell 570-575-8161

[email protected]

Page 2: Design Project - Georgia Institute of Technologyusers.ece.gatech.edu/.../SignedAudioProjectReport.pdfDesign Project ECE4445 – Audio Engineering November 27th, 2006 Franklin Falcon

In this design project, various simulations were performed. The simulations are:

1. Loudspeaker mounted on infinite baffle. 2. Loudspeaker mounted inside a closed box. 3. Loudspeaker with matching network mounted inside a closed box. 4. Loudspeaker with matching network and 2nd order crossover network

mounted inside a closed box. 5. Loudspeaker with matching network and 3rd order crossover network mounted

inside a closed box. 6. Loudspeaker mounted inside a vented box.

All the simulations were performed using PSPICE. The SPICE circuits and netlists are attached at the end of the report.

Page 3: Design Project - Georgia Institute of Technologyusers.ece.gatech.edu/.../SignedAudioProjectReport.pdfDesign Project ECE4445 – Audio Engineering November 27th, 2006 Franklin Falcon

Zoff READPRN "off.txt"( ):= Zon READPRN "on.txt"( ):=

Zoff

0 1 2

0

1

2

3

4

5

6

7

8

9

10

11

12

13

14

15

9.994 8.258 40.046

10.244 8.39 40.636

10.517 8.555 40.839

10.792 8.704 41.537

11.067 8.876 41.815

11.34 9.034 42.706

11.64 9.225 43.056

11.939 9.436 42.956

12.239 9.61 44.423

12.538 9.815 45.014

12.873 10.048 45.625

13.222 10.31 45.932

13.546 10.558 46.356

13.895 10.827 46.886

14.245 11.117 47.236

14.619 11.432 47.697

= Zon

0 1 2

0

1

2

3

4

5

6

7

8

9

10

11

12

13

14

15

9.994 6.021 10.063

10.244 6.03 10.058

10.518 6.039 10.25

10.792 6.049 10.568

11.067 6.058 10.728

11.341 6.066 11.26

11.641 6.077 11.345

11.94 6.088 11.499

12.239 6.097 11.906

12.538 6.108 12.123

12.873 6.12 12.43

13.222 6.135 12.743

13.546 6.147 13.018

13.896 6.16 13.357

14.245 6.174 13.608

14.619 6.191 13.935

=

RE 5.33:= DC resistance VT 1.56:= Test box volume

N 300:= Number of data points minus 1 Zp x y,( )x y⋅

x y+:= Parallel combinaton

From the Zoff array:

fS 30.482:= RES 43.614 RE−:= RES 38.284= R1 RE RE RES+( )⋅:=

R1 15.247= f1 18.36:= f2 50.582:= f1 f2⋅ 30.474=

QMSfS

f2 f1−

RE RES+

RE⋅:= QMS 2.706= QES

RE

RESQMS⋅:= QES 0.377=

QTSRE

RE RES+QMS⋅:= QTS 0.331=

Page 4: Design Project - Georgia Institute of Technologyusers.ece.gatech.edu/.../SignedAudioProjectReport.pdfDesign Project ECE4445 – Audio Engineering November 27th, 2006 Franklin Falcon

ne2π

arg Zoff 250 1, cos Zoff 250 2,π

180⋅⎛⎜

⎝⎞⎟⎠

⋅ RE− j Zoff 250 1,⋅ sin Zoff 250 2,π

180⋅⎛⎜

⎝⎞⎟⎠

⋅+⎛⎜⎝

⎞⎟⎠

⋅:= ne 0.65=

Le

Zoff 250 1, cos Zoff 250 2,π

180⋅⎛⎜

⎝⎞⎟⎠

⋅ RE−⎛⎜⎝

⎞⎟⎠

2Zoff 250 1, sin Zoff 250 2,

π

180⋅⎛⎜

⎝⎞⎟⎠

⋅⎛⎜⎝

⎞⎟⎠

2+

2 π⋅ Zoff 250 0,⋅( )ne

:= Le 0.03=

n 0 N..:= fn 1020000

10⎛⎜⎝

⎞⎟⎠

n

N⋅:= Frequency range variable for calculating Zvc(f)

LE 13 10 3−⋅:= "Tweaked" value of parallel lossless inductor in Allen Robinson's model

Zvc f( ) RE Zp j 2⋅ π⋅ f⋅ LE⋅ Le j 2⋅ π⋅ f⋅( )ne⋅,

⎡⎣

⎤⎦+ RES

1QMS

j f⋅fS

⎛⎜⎝

⎞⎟⎠

1ffS

⎛⎜⎝

⎞⎟⎠

2−

1QMS

j f⋅fS

⎛⎜⎝

⎞⎟⎠

⋅+

⋅+:=

From the Zon array:

fCT 75.889:= RECT 34.353 RE−:= RECT 29.023= R1 RE RE RECT+( )⋅:=

R1 13.531= f1T 55.988:= f2T 95.33:= f1T f2T⋅ 73.057=

QMCTfCT

f2T f1T−

RE RECT+

RE⋅:= QMCT 4.897=

QECTRE

RECTQMCT⋅:= QECT 0.899= QTCT

RE

RE RECT+QMCT⋅:= QTCT 0.76=

VAS VTfCT

fS

QECT

QES⋅ 1−

⎛⎜⎝

⎞⎟⎠

⋅:= VAS 7.711=

Page 5: Design Project - Georgia Institute of Technologyusers.ece.gatech.edu/.../SignedAudioProjectReport.pdfDesign Project ECE4445 – Audio Engineering November 27th, 2006 Franklin Falcon

1 10 100 1 .103 1 .104 1 .1051

10

100

MeasuredCalculatedMeasuredCalculated

Impedance Magnitude

Frequency [Hz]

Impe

danc

e [o

hms]

1 10 100 1 .103 1 .104 1 .10560

40

20

0

20

40

60

MeasuredCalculatedMeasuredCalculated

Impedance Phase

Frequency [Hz]

Phas

e [d

eg.]

Page 6: Design Project - Georgia Institute of Technologyusers.ece.gatech.edu/.../SignedAudioProjectReport.pdfDesign Project ECE4445 – Audio Engineering November 27th, 2006 Franklin Falcon

Infinite Baffle:

In this section, parameters are calculated to construct the electrical circuits which simulate the speaker mounted on an infinite baffle. From these electrical circuits, it is possible to obtain the input impedance, the sound pressure level produced by the loudspeaker, and the diaphragm peakdisplacement. The equations used for the calculations are shown below. Also, the graphics showthe parameters measured from the SPICE simulation.

QMS 2.706= QES 0.377= QTS 0.331=

ρo 1.18:= c 345:= a 0.12:= VAS 0.218:= ---> in m^3

fS 30.482= VAS 0.218= SD πa2:= SD 0.045=

CMSVAS

ρo c2⋅ SD

2⋅

:= CMS 7.584 10 4−×=

MMS1

2π fS⋅( )2 CMS⋅

:= MMS 0.036=

RMS1

QMS

MMS

CMS⋅:= RMS 2.544=

BlRE

QES

MMS

CMS⋅:= Bl 9.869=

MMD MMS 28 ρo⋅

3π2

a( )⋅

⋅ SD2

⋅−:= MMD 0.025=

MA18 ρo⋅

3 π2

⋅ a( )⋅

:= MA1 2.657=

RA2ρo c⋅

π a2⋅

:= RA2 8.999 103×=

RA1128 ρo⋅ c⋅

9 π3

⋅ a2⋅

RA2−:= RA1 3.969 103×=

CA15.94 a3

ρo c2⋅

:= CA1 7.308 10 8−×=

Page 7: Design Project - Georgia Institute of Technologyusers.ece.gatech.edu/.../SignedAudioProjectReport.pdfDesign Project ECE4445 – Audio Engineering November 27th, 2006 Franklin Falcon

SpcIBZin READPRN "SpiceIBZin.txt"( ):=

1 10 100 1 .103 1 .104 1 .1051

10

100

MeasuredSpiceMeasuredSpice

Electrical Input Impedance

Frequency [Hz]

Impe

danc

e [O

hms]

SpcIBSPL READPRN "SpiceIBSPL.txt"( ):=

10 100 1 .103 1 .104 1 .10550

63.33

76.67

90On-Axis SPL

Frequency [Hz]

SPL

[dB

]

Page 8: Design Project - Georgia Institute of Technologyusers.ece.gatech.edu/.../SignedAudioProjectReport.pdfDesign Project ECE4445 – Audio Engineering November 27th, 2006 Franklin Falcon

SpcIBXpp READPRN "SpiceIBXpp.txt"( ):=

10 100 1 .103 1 .104 1 .1051 .10 10

1 .10 9

1 .10 8

1 .10 7

1 .10 6

1 .10 5

1 .10 4

1 .10 3

0.01

0.1Peak to Peak Diaphragm Displacement

Frequency [Hz]

Peak

Dis

plac

emen

t [m

]

Page 9: Design Project - Georgia Institute of Technologyusers.ece.gatech.edu/.../SignedAudioProjectReport.pdfDesign Project ECE4445 – Audio Engineering November 27th, 2006 Franklin Falcon

Closed Box:

In this section, parameters are calculated to build the circuits that model the loudspeaker mountedinside a closed box. The first three graphs show the results of the SPICE measurements. A matchingnetwork was designed with the purpose of making the input impedance behave like if it was only thevoice coil resistor RE, the graph shown under "Matching Network Design" shows the electrical inputimpedance before and after adding the matching network. Also, 2nd and 3rd order crossover networkswere designed with the purpose of only allowing low frequencies to reach the woofer. The measuredsound pressure levels without crossover network, with a 2nd order network, and with a 3rd ordernetwork, are shown in the graph under "Crossover Network Design".

αQECT

QES

⎛⎜⎝

⎞⎟⎠

2

1−:=α 4.698=

VABVAS

α:= VAB 0.046=

CABVAB

ρo c2⋅

:= CAB 3.304 10 7−×=

RAB 1 α+QMS

QMCT⋅

⎛⎜⎝

⎞⎟⎠

RMS

SD2

⋅:= RAB 1.64 103×=

MMCBl2 QECT⋅

π a2⋅ c⋅ RE⋅

⎛⎜⎜⎝

⎞⎟⎟⎠

2VAS

ρo 1 α+( )⋅⋅:= MMC 0.036=

RMS1

QMS

MMC

CMS⋅:= RMS 2.544=

MABMMC MMD−

π2

a4⋅

MA1−:= MAB 2.657=

RAL1

2π .1( ) CAB⋅:= RAL 4.818 106

×=

SpcCBZin READPRN "SpiceCBZin.txt"( ):=

SpcCBSPL READPRN "SpiceCBSPL.txt"( ):=

SpcCBXpp READPRN "SpiceCBXpp.txt"( ):=

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10 100 1 .1030

20

40

Electrical Input Impedance

Frequency [Hz]

Impe

danc

e [O

hms]

10 100 1 .103

60

80

On-Axis SPL

Frequency [Hz]

SPL

[dB

]

10 100 1 .1031 .10 81 .10 71 .10 61 .10 51 .10 41 .10 3

0.01Peak to Peak Diaphragm Displacement

Frequency [Hz]

Dis

plac

emen

t [m

]

Page 11: Design Project - Georgia Institute of Technologyusers.ece.gatech.edu/.../SignedAudioProjectReport.pdfDesign Project ECE4445 – Audio Engineering November 27th, 2006 Franklin Falcon

Matching Network Design:

fc fS 1 α+⋅:= fc 72.764= f1mn 2000:= f2mn 20 103⋅:= Le 0.03= ne 0.65=

RE 5.33= QMCT 4.897= QECT 0.899= QEC QES 1 α+⋅:=

R1.mn RE:= C1.mnLe

2π( ) 1 ne−( )RE

2⋅ f1mn

ne f2mn2 ne+( )

⋅⎡⎣

⎤⎦

1 ne−( )2 1 ne+( )

:=

C2.mnLe

2π( )1 ne−RE

2⋅ f1mn

2 ne+( )f2mn

ne⋅

⎡⎣

⎤⎦

1 ne−

2 1 ne+( )⋅

C1.mn−:= R2.mn1

2πf1mn

1

1 ne+( )f2mn

ne

1 ne+( )⋅ C2.mn⋅

:=

R3.mn RE 1QECT

QMCT+

⎛⎜⎝

⎞⎟⎠

⋅:= L1.mnRE QECT⋅

2πfc:= C3.mn

12πfc RE⋅ QECT⋅

:=

R1.mn 5.33= C1.mn 2.054 10 5−×= C2.mn 1.293 10 5−

×= R2.mn 2.484=

R3.mn 6.309= L1.mn 0.01= C3.mn 4.563 10 4−×=

SpcCBwMNZin READPRN "SpiceCBwMNZin.txt"( ):=

10 100 1 .1030

20

40

Without Matching NetworkWith Matching NetworkWithout Matching NetworkWith Matching Network

Electrical Input Impedance

Frequency [Hz]

Impe

danc

e [O

hms]

Page 12: Design Project - Georgia Institute of Technologyusers.ece.gatech.edu/.../SignedAudioProjectReport.pdfDesign Project ECE4445 – Audio Engineering November 27th, 2006 Franklin Falcon

Crossover Network Design:

. 2nd Order Network:

Assuming Qw 0.5:= fw 800:= RE 5.33=

LwRE

2πfw Qw⋅:= Cw

Qw

2πfw RE⋅:= Lw 2.121 10 3−

×= Cw 1.866 10 5−×=

. 3rd Order Network:

fc 72.764= fw 800=

L2RE

4πfw:= L1 3L2:= C3

23πfw RE⋅

:=

L1 1.591 10 3−×= L2 5.302 10 4−

×= C3 4.977 10 5−×=

SpcCBw2COSPL READPRN "SpiceCBwMN2COSPL.txt"( ):=

SpcCBw3COSPL READPRN "SpiceCBwMN3COSPL.txt"( ):=

10 100 1 .103

40

60

80

Without C/O NetWith 2nd Order C/O NetWith 3rd Order C/O Net

Without C/O NetWith 2nd Order C/O NetWith 3rd Order C/O Net

On-Axis SPL

Frequency [Hz]

SPL

[dB

]

Page 13: Design Project - Georgia Institute of Technologyusers.ece.gatech.edu/.../SignedAudioProjectReport.pdfDesign Project ECE4445 – Audio Engineering November 27th, 2006 Franklin Falcon

Vented Box:

In this section, parameters are calculated to build the circuits that will simulate the behavior of theloudspeaker mounted inside a vented box. The electrical input impedance was measured, along withthe sound presure level and the peak displacement. The graph labeled "On-Axis SPL" shows thesound pressure levels produced by the diaphragm and the air in the vent, along with the total SPL.The plot labeled "Peak-to-Peak Displacement" shows the displacement of the diaphragm as well asthe displacement of the air in the port.

dw 0.305:= --> 12 in = woofer frame diameter

aw 0.12:= --> 12 cm = piston radius

ap 0.04:= --> 4 cm = port radius

woofer-port spacing assumed to be 1.6 times the woofer frame radius, then:

d1 0.8dw:= d1 0.244=

Sw πaw2

:= Sw 0.045=

B 0.65:= . --> Assumed Value (p.114)

MABB ρo⋅

π aw⋅:= MAB 2.035= Old Mab was 2.657

CAB 3.304 10 7−×=

QTS 0.331= QL 7:=

With assumed QL=7 and Alignment Chart on p.138:

h 1.1998:= fB h fS⋅:= fB 36.572=

RALQL

2πfB CAB⋅:= RAL 9.221 104

×=

MA1P8ρo

3π2

ap⋅

:= MA1P 7.971=

MAP1

2πfB( )2 CAB⋅

MA1P−:= MAP 49.355=

Page 14: Design Project - Georgia Institute of Technologyusers.ece.gatech.edu/.../SignedAudioProjectReport.pdfDesign Project ECE4445 – Audio Engineering November 27th, 2006 Franklin Falcon

RA2Pρo c⋅

πap2

:= RA2P 8.099 104×=

RA1P128ρo c⋅

9π3

ap2

RA2P−:= RA1P 3.572 104×=

CA1P5.94ap

3

ρo c2⋅

:= CA1P 2.707 10 9−×=

kp3πap

16d1:= kp 0.097=

SP πap2

:= SP 5.027 10 3−×=

MA1W8ρo

3π2

aw⋅

:= MA1W 2.657=

RA2Wρo c⋅

πaw2

:= RA2W 8.999 103×=

RA1W128ρo c⋅

9π3

aw2

RA2W−:= RA1W 3.969 103×=

CA1W5.94aw

3

ρo c2⋅

:= CA1W 7.308 10 8−×=

kw3πaw

16d1:= kw 0.29=

SpcVBZin READPRN "SpiceVBZin.txt"( ):= SpcVBSPLv READPRN "SpiceVBSPLv.txt"( ):=

SpcVBSPLw READPRN "SpiceVBSPLw.txt"( ):= SpcVBSPL READPRN "SpiceVBSPL.txt"( ):=

SpcVBXppD READPRN "SpiceVBXppD.txt"( ):= SpcVBXppP READPRN "SpiceVBXppP.txt"( ):=

Page 15: Design Project - Georgia Institute of Technologyusers.ece.gatech.edu/.../SignedAudioProjectReport.pdfDesign Project ECE4445 – Audio Engineering November 27th, 2006 Franklin Falcon

10 100 1 .103 1 .1040

20

40Electrical Input Impedance

Frequency [Hz]

Impe

danc

e [O

hms]

10 100 1 .103 1 .104

60

80

TotalWooferVent

TotalWooferVent

On-Axis SPL

Frequency [Hz]

SPL

[dB

]

10 100 1 .103 1 .1041 .10 6

1 .10 5

1 .10 4

1 .10 3

0.01DiaphragmPort AirDiaphragmPort Air

Peak to Peak Displacement

Frequency [Hz]

Dis

plac

emen

t [m

]

Page 16: Design Project - Georgia Institute of Technologyusers.ece.gatech.edu/.../SignedAudioProjectReport.pdfDesign Project ECE4445 – Audio Engineering November 27th, 2006 Franklin Falcon

Summary and Conclusions

This report shows the result of simulating the behavior of a loudspeaker under different operating conditions. In the case of the closed box simulation, a matching network was placed in parallel with the voice coil. The purpose of this network is to cause the voice coil impedance to behave as if it were purely resistive, i.e. to cancel the peak at the resonant frequency as well as the high frequency rise due to the voice coil inductance. Furthermore, 2nd and 3rd order crossover networks were placed at the input of the voice coil circuit, i.e. before the matching network. The purpose of these networks is to allow only low frequencies to reach the woofer. The plots of the sound pressure level when using the crossover networks show how the slope of the magnitude Bode plot changes from -20 dB per decade (without C/O network) to -40 dB per decade (with 2nd order network) and -60 db per decade (with a 3rd order crossover network).

In the case of the vented box, it is important to notice that the sound pressure level that we hear is the result of adding the SPL produced by the diaphragm and the SPL produced by the air in the port. In the plot showing the SPL of the vented box system, it is easy to notice that at some frequencies, the SPL produced by the air in the vent is considerably larger that the SPL produced by the diaphragm.

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Appendix SPICE Circuits and Netlists

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Infinite Baffle Circuits

Electrical

+

2RA1+pD_

UD

SDuD 2MA1

+

2RA2

Sweep +- AC

VD3

Acoustical

+

0.5CA1

Ze(jw)

+-

BluD

Sw eep

+

-

AC

eg

+

RE

Sweep +- AC

VD2

ic

VD1

MMD

+-

Blic

-+

+-

SDpD+

CMS

1u+

RMSSweep +- AC

VD2

Mechanical

uD

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Closed Box Circuits

Electrical

UD

+

RA1+

RAL

SDuDMAB

MA1+

RAB

+

CAB

+

RA2

Sweep +- AC

VD3

Acoustical

+

CA1

- pD +

Ze(jw)

+-

BluD

Sw eep

+

-

AC

eg

+

RE

Sweep +- AC

VD2

ic

VD1

MMD

+-

Blic

-+

+-

SDpD+

CMS

1u+

RMS

Sweep +- AC

VD2

Mechanical

uD

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+C1

Electrical With Matching Network

+

RE

Sw eep

+

-

ACeg +-

BluD

Ze(jw)

+

R1

L1

+

R2

+ C2

+

R3

Sweep +- AC

VD1+ C3

ic

+

C1

Electrical With Matching Networkand 2nd Order Crossover Network

+

RE

Sw eep

+

-

ACeg +-

BluD

Ze(jw)

+

R1

ic

L1

+

R2+

C1co

+ C2

L1co

+

R3

Sweep +- AC

VD1+ C3

Page 21: Design Project - Georgia Institute of Technologyusers.ece.gatech.edu/.../SignedAudioProjectReport.pdfDesign Project ECE4445 – Audio Engineering November 27th, 2006 Franklin Falcon

+

C1

Electrical With Matching Networkand 3rd Order Crossover Network

+

RE

Sw eep

+

-

ACeg +-

BluD

Ze(jw)

+

R1

L2coic

L1

+

R2+

C1co

+ C2

L1co

+

R3

Sweep +- AC

VD1+ C3

Page 22: Design Project - Georgia Institute of Technologyusers.ece.gatech.edu/.../SignedAudioProjectReport.pdfDesign Project ECE4445 – Audio Engineering November 27th, 2006 Franklin Falcon

Vented Box Circuits

Electrical

Ze(jw)

+-

BluD

Sw eep

+

-

AC

eg

+

RE

Sweep +- AC

VD2

ic

V1W

MMD

+-

Blic

-+

+-

SDpD+

CMS

1u+

RMS

Sweep +- AC

VD2

Mechanical

uD

V2W

Page 23: Design Project - Georgia Institute of Technologyusers.ece.gatech.edu/.../SignedAudioProjectReport.pdfDesign Project ECE4445 – Audio Engineering November 27th, 2006 Franklin Falcon

UwMAB

MA1P

U'p

Uo - pw +

Acoustical

Sweep

+

-

ACV3w

UL

+

RA2w

Swuw

+

RA1P + CA1w

+ CABSw

eep

+ -AC

V5w

U'w

+

RA2P

+

CA1P

Up

kwU'p+

RAL

kpU'wMA1w

Sweep +- ACV7w

Sweep +- AC

V6w

+

RA1w

Swee

p

+ -AC

V4w

M'AP

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AllNets.txt*-------------------------------------------------*Infinite Baffle*-------------------------------------------------*INFINITE BAFFLE NETLIST*DISPLAY VM(1)/IM(VD1) FOR INPUT IMPEDANCE*DISPLAY 20*LOG10(VM(13)) FOR ON-AXIS PRESSURE*DISPLAY VM(14) FOR DIAPHRAGM DISPLACEMENT

*ELECTRICAL CIRCUITVEG 1 0 AC 1VRE 1 2 5.33*LOSSY VOICE-COIL INDUCTANCEGZE 2 3 LAPLACE {V(2,3)} = {1/(0.03*PWR(S,0.65))}HBLUD 3 4 VD2 9.869VD1 4 0 AC 0V

*MECHANICAL CIRCUITLMMD 5 6 0.025 RMS 6 7 2.544CMS 7 8 7.584E-4HBLIC 5 0 VD1 9.869ESDPD 8 9 10 0 0.045VD2 9 0 AC 0V

*ACOUSTICAL CIRCUITLMA1 10 12 5.314RA1 10 11 7.938E3RA2 11 12 17.998E3CA1 10 11 3.654E-8VD3 12 0 AC 0VFSDUD 0 10 VD2 0.045

*ON-AXIS PRESSURE SOURCE EPD 13 0 LAPLACE {I(VD3)} = {9390*S} *DIAPHRAGM DISPLACEMENT SOURCE EXD 14 0 LAPLACE {I(VD3)} = {1/S}

.AC DEC 77 10 100K

.PROBE

.END

*--------------------------------------------------*CLOSED-BOX*--------------------------------------------------*DISPLAY VM(1)/IM(VD1) FOR INPUT IMPEDANCE*DISPLAY 20*LOG10(16) FOR ON-AXIS PRESSURE*DISPLAY VM(17) FOR DIAPHRAGM DISPLACEMENT

*ELECTRICAL CIRCUITVEG 1 0 AC 1VRE 1 2 5.33*LOSSY VOICE-COIL INDUCTANCEGZE 2 3 LAPLACE {V(2,3)}={1/(0.03*PWR(S,0.65))}HBLUD 3 4 VD2 9.869VD1 4 0 AC 0

*MECHANICAL CIRCUITHBLI 5 0 VD1 9.869LMMD 5 6 0.025RMS 6 7 2.544CMS 7 8 7.584E-4

Page 1

Page 25: Design Project - Georgia Institute of Technologyusers.ece.gatech.edu/.../SignedAudioProjectReport.pdfDesign Project ECE4445 – Audio Engineering November 27th, 2006 Franklin Falcon

AllNets.txtESDPD 8 9 10 13 0.045VD2 9 0 AC 0

*ACOUSTICAL CIRCUITFSDUD 13 10 VD2 0.045LMA1 10 12 2.657RA1 10 11 3.969E3RA2 11 12 9E3CA1 10 11 7.308E-8VD3 12 0 AC 0LMAB 13 14 2.657RAB 14 15 1.64E3CAB 15 0 3.304E-7RAL 15 0 4.818E6

*ON-AXIS PRESSURE DISPLAYS IN PROBE WITH 20*LOG10(VM(16))EXP 16 0 LAPLACE {I(VD3)} = {59E3*S}*DIAPHRAGM DISPLACEMENT DISPLAYS IN PROBE WITH VM(17)EXD 17 0 LAPLACE {I(VD2)}={1/S}.AC DEC 50 10 10K.PROBE.END

*--------------------------------------------------*CLOSED-BOX WITH MATCHING NETWORK*--------------------------------------------------*DISPLAY VM(1)/IM(VD1) FOR INPUT IMPEDANCE*DISPLAY 20*LOG10(16) FOR ON-AXIS PRESSURE*DISPLAY VM(17) FOR DIAPHRAGM DISPLACEMENT

*ELECTRICAL CIRCUITVEG 1 0 AC 1VRE 1 2 5.33*LOSSY VOICE-COIL INDUCTANCEGZE 2 3 LAPLACE {V(2,3)}={1/(0.03*PWR(S,0.65))}HBLUD 3 4 VD2 9.869VD1 4 0 AC 0*--------------------------*Matching NetworkRR1 1 18 5.33CC1 18 0 2.054E-5RR2 18 19 2.484CC2 19 0 1.293E-5RR3 1 20 6.309LL1 20 21 0.01CC3 21 0 4.563E-4*----------------------------

*MECHANICAL CIRCUITHBLI 5 0 VD1 9.869LMMD 5 6 0.025RMS 6 7 2.544CMS 7 8 7.584E-4ESDPD 8 9 10 13 0.045VD2 9 0 AC 0

*ACOUSTICAL CIRCUITFSDUD 13 10 VD2 0.045LMA1 10 12 2.657RA1 10 11 3.969E3RA2 11 12 9E3CA1 10 11 7.308E-8

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Page 26: Design Project - Georgia Institute of Technologyusers.ece.gatech.edu/.../SignedAudioProjectReport.pdfDesign Project ECE4445 – Audio Engineering November 27th, 2006 Franklin Falcon

AllNets.txtVD3 12 0 AC 0LMAB 13 14 2.657RAB 14 15 1.64E3CAB 15 0 3.304E-7RAL 15 0 4.818E6

*ON-AXIS PRESSURE DISPLAYS IN PROBE WITH 20*LOG10(VM(16))EXP 16 0 LAPLACE {I(VD3)} = {59E3*S}*DIAPHRAGM DISPLACEMENT DISPLAYS IN PROBE WITH VM(17)EXD 17 0 LAPLACE {I(VD2)}={1/S}.AC DEC 50 10 10K.PROBE.END

*-----------------------------------------------------------*CLOSED-BOX WITH MATCHING NETWORK AND 2ND ORDER C/O NETWORK*-----------------------------------------------------------*DISPLAY VM(1)/IM(VD1) FOR INPUT IMPEDANCE*DISPLAY 20*LOG10(16) FOR ON-AXIS PRESSURE*DISPLAY VM(17) FOR DIAPHRAGM DISPLACEMENT

*ELECTRICAL CIRCUITVEG 1 0 AC 1V*--------------------------*2nd Order C/O NetworkLLw 1 2 2.121E-3CCw 2 0 1.866E-5*---------------------------*Matching Network RR1 2 3 5.33CC1 3 0 2.054E-5RR2 3 4 2.484CC2 4 0 1.293E-5RR3 2 18 6.309LL1 18 19 0.01CC3 19 0 4.563E-4*----------------------------RE 2 20 5.33*LOSSY VOICE-COIL INDUCTANCEGZE 20 21 LAPLACE {V(20,21)}={1/(0.03*PWR(S,0.65))}HBLUD 21 22 VD2 9.869VD1 22 0 AC 0*--------------------------

*MECHANICAL CIRCUITHBLI 5 0 VD1 9.869LMMD 5 6 0.025RMS 6 7 2.544CMS 7 8 7.584E-4ESDPD 8 9 10 13 0.045VD2 9 0 AC 0

*ACOUSTICAL CIRCUITFSDUD 13 10 VD2 0.045LMA1 10 12 2.657RA1 10 11 3.969E3RA2 11 12 9E3CA1 10 11 7.308E-8VD3 12 0 AC 0LMAB 13 14 2.657RAB 14 15 1.64E3CAB 15 0 3.304E-7

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Page 27: Design Project - Georgia Institute of Technologyusers.ece.gatech.edu/.../SignedAudioProjectReport.pdfDesign Project ECE4445 – Audio Engineering November 27th, 2006 Franklin Falcon

AllNets.txtRAL 15 0 4.818E6

*ON-AXIS PRESSURE DISPLAYS IN PROBE WITH 20*LOG10(VM(16))EXP 16 0 LAPLACE {I(VD3)} = {59E3*S}*DIAPHRAGM DISPLACEMENT DISPLAYS IN PROBE WITH VM(17)EXD 17 0 LAPLACE {I(VD2)}={1/S}.AC DEC 50 10 10K.PROBE.END

*----------------------------------------------------------*CLOSED-BOX WITH MATCHING NETWORK AND 3RD ORDER C/O NETWORK*----------------------------------------------------------*DISPLAY VM(1)/IM(VD1) FOR INPUT IMPEDANCE*DISPLAY 20*LOG10(16) FOR ON-AXIS PRESSURE*DISPLAY VM(17) FOR DIAPHRAGM DISPLACEMENT

*ELECTRICAL CIRCUITVEG 1 0 AC 1V*--------------------------*3rd Order C/O NetworkLLco1 1 2 1.591E-3CCco 2 0 4.977E-5LLco2 2 3 5.302E-4*---------------------------*Matching Network RR1 3 4 5.33CC1 4 0 2.054E-5RR2 4 18 2.484CC2 18 0 1.293E-5RR3 3 19 6.309LL1 19 20 0.01CC3 20 0 4.563E-4*----------------------------RE 3 21 5.33*LOSSY VOICE-COIL INDUCTANCEGZE 21 22 LAPLACE {V(21,22)}={1/(0.03*PWR(S,0.65))}HBLUD 22 23 VD2 9.869VD1 23 0 AC 0*--------------------------

*MECHANICAL CIRCUITHBLI 5 0 VD1 9.869LMMD 5 6 0.025RMS 6 7 2.544CMS 7 8 7.584E-4ESDPD 8 9 10 13 0.045VD2 9 0 AC 0

*ACOUSTICAL CIRCUITFSDUD 13 10 VD2 0.045LMA1 10 12 2.657RA1 10 11 3.969E3RA2 11 12 9E3CA1 10 11 7.308E-8VD3 12 0 AC 0LMAB 13 14 2.657RAB 14 15 1.64E3CAB 15 0 3.304E-7RAL 15 0 4.818E6

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Page 28: Design Project - Georgia Institute of Technologyusers.ece.gatech.edu/.../SignedAudioProjectReport.pdfDesign Project ECE4445 – Audio Engineering November 27th, 2006 Franklin Falcon

AllNets.txt*ON-AXIS PRESSURE DISPLAYS IN PROBE WITH 20*LOG10(VM(16))EXP 16 0 LAPLACE {I(VD3)} = {59E3*S}*DIAPHRAGM DISPLACEMENT DISPLAYS IN PROBE WITH VM(17)EXD 17 0 LAPLACE {I(VD2)}={1/S}.AC DEC 50 10 10K.PROBE.END

*------------------------------------------------------*VENTED-BOX*------------------------------------------------------*DISPLAY VM(1)/IM(VD1) FOR INPUT IMPEDANCE*DISPLAY VM(21) FOR DIAPHRAGM DISPLACEMENT*DISPLAY VM(22) FOR PORT DISPLACEMENT*DISPLAY 20*LOG10(VM(23)) FOR ON-AXIS PRESSURE*DISPLAY 20*LOG10(VM(24)) FOR DIAPHRAGM PRESSURE*DISPLAY 20*LOG10(VM(25)) FOR PORT PRESSURE

*ELECTRICAL CIRCUIT

VEG 1 0 AC 1VREW 1 2 5.33*LOSSY VOICE-COIL INDUCTANCEGRA 2 3 LAPLACE {V(2,3)}={1/(0.03*PWR(S,0.65))}HBLUW 3 4 V2W 9.869V1W 4 0 AC 0V

*Mechanical Ckt

HBLIW 5 0 V1W 9.869LMMDW 5 6 0.025RMSW 6 7 2.544CMSW 7 8 7.584E-4ESDPW 8 9 17 10 0.045V2W 9 0 AC 0V

*Acoustical CKT

FSDUW 10 17 V2W 0.045LMABW 10 11 2.035CABW 11 12 3.304E-7V3W 0 12 AC 0RALW 11 0 9.221E4LMAP 11 13 49.355FKP 15 13 V6W 0.097LMA1P 13 15 7.971RA1P 13 14 3.572E4CA1P 13 14 2.707E-9RA2P 14 16 8.099E4V4W 15 16 AC 0VV5W 16 0 AC 0VFKWUP 19 17 V4W 0.29LMA1W 17 19 2.657RA1W 17 18 3.969E3CA1W 17 18 7.308E-8RA2W 18 20 9E3V6W 19 20 AC 0VV7W 20 0 AC 0V

*DIAPHRAGM DISPLACEMENT SOURCEEXD 21 0 LAPLACE {I(V2W)}={1/S}

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Page 29: Design Project - Georgia Institute of Technologyusers.ece.gatech.edu/.../SignedAudioProjectReport.pdfDesign Project ECE4445 – Audio Engineering November 27th, 2006 Franklin Falcon

AllNets.txt*PORT DISPLACEMENT SOURCEEXP 22 0 LAPLACE {I(V5W)}={1/(5.027E-3*S)}*ON-AXIS PRESSURE SOURCEEPSUM 23 0 LAPLACE {I(V3W)}={9390*S}*DIAPHRAGM PRESSURE SOURCEEPD 24 0 LAPLACE {I(V7W)}={9390*S}*VENT PRESSURE SOURCEEPV 25 0 LAPLACE {I(V5W)}={9390*S}.AC DEC 100 10 10K.PROBE.END

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