Design of Silos & Tanks
Transcript of Design of Silos & Tanks
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FA CUL TV OF SCII:N CI: AND t: N G INI: J:KIN G
aVIL ENGINEERING 4
CML ENGINEERING 4M
CIVIL AND ENVIRONMENTAL ENGINEERING 4
CIVIL AND ENVIRONMENTAL ENGINEERING 4M
~ ENGINEERING AND CONSTRUCTION MANAGEMENT 4
CIVIL ENGINEERING AND CONSTRUcnON MANAGEMENT 4M
CIVIL ENGINEERING SM
CIVIL AND ENVIRONMENTAL ENGINEERING SM
M17 -DESIGN OF SILOS AND TANKS
CONVINOR ' nil BoARDo' EXAMINDS:
EXTl.RNAL I.XAMINER:
UN)VI:RSITV OF
URGH
DINB
Wednesd8Y 6th M8rt"h 2002
3.00pm - 4.30pm
Professor 0 A Barry
ProfessorH. D. Wricbt
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On-ground silos
When building structuresare designed, he ultimate limit state s related o the
characteristichighest oad state,which might be the highest ive load or wind
load. However. n silo design,different extremevalues of the propertiesof the
storedmaterialsmust be considered s different load cases. Give the reason or
this, and state he extremes f storedsolid properties hat shouldbe used or each
condition. [8]
1.
a)
Determine he design wall loads for the following cylindrical on-ground mild
steel silo. The silo is constructed rom rolled stnM:tural teel plate and has a
vertical wall height of 25.0 m and a diameter of 10.0 m. It is ~ to store
alumina,and is concentrically illed and discharged.The roof slopesat an angle
of 300 o the horizontaland he silo is filled until the solid ust touches he top of
the vertical wall.
i) Identify the design value of the angle of repose,and the stnICturaldesign
value of the unit weight r [2]
ii) Find the Wlit weight hat shouldbe used or the purposeof detelmining he
reliable storage apacityof the silo, anddeduce his capacity. [3]
iii) Determine the surface c~ of the wall for which the silo should be
designed. [2]
iv) Identify the upper and lower values of wall friction angle that should be
used or the design. Deduce he upper and lower characteristic alues of
wall friction coefficientJL [3]
v) Identify the upperand ower characteristic aluesof lateral pressure atio ).,
as given n the able ofpro petties. [2]
vi) Identify the upper and lower characteristicvalues of effective internal
friction
~
for the solid from the table of properties, nd then use an
appropriateequation o deduce he upperand ower characteristic aJues f
lateralpressureatio).. Comparehese aJcu1atedalueswith thosegiven n
the table of properties. Statewhy the equation s given at all, if it can ead
to different values rom those n the able.
Note: Use he values rom the able n all subsequentaJculations. [5]
vii) Find the total weight of solid that can be placed n the silo at the structural
designunit weight, and determine he height of the effective surfaceabove
the base. [3]
b)
University of fAinoorgh
Schoolof Civil and EnvironmentalEngineering
HODoun Module M.t7: Designof Silos
mination April 2002
egreeExa
Answer any two questions
Eachquestion s worth 40 marks
IIf2 hours
ime allowed:
This exam s open book
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viii) FCX'he colXlition of maximmn normal ~ against the silo
identify the appropriate aluesof wall friction coefficient, ateral pI'1
ratio and Wtit weight o be used.
f
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Patch loads and discharge
All standards hat define silo pressures egin by defining a filling pressureand
then modify it to obtain a dischargepressure. Briefly explain why this is, and
indicate he differences etween illing and discharge ressures. [4]
2.
a)
The Europeailsilos loading stalxlardENV 1991-4also requires silo designs o
include a "patch" pressure o be placedat any position on the silo wall. Briefly
explain its purposeand the featuresof real silo pressureshat it is intended o
reprexnl [4]
A cylindrical on-groundsilo of diameter 12.0m s made rom polished stainless
steel and is used o store barley flour. The condition to be considered n your
design s the maximum pressure ase,and for this the appropriatepropertiesare
as follows: unit weight 8.5 kN m3; .u
= 0.255; A.=
0.550; internal friction angle
;; =
28. It has a vertical wall height 18 metresand s concentrically illed level
(flat top surface) o the top of this wall. Discharge s through an outlet which is
slightly eccentric o the silo axis, with eo= 1.2 m.
i) A patch ~sure load will be applied o the tilling pressures. Locate he
position of the centreof this patch as a depth zp below the surfaceof the
flour. [4]
ii) Determine he filling vaJueof normal pressure gainst he wall at the level
of the centreof the patch, gnoringpatchpressures. [4]
iii) Determine he filling value of the co-ex.isteDt atch pressureand identify
the vertical and horizontalextentof the patch. [4]
iv) Deduce he total horizontal orce appliedby the filling patchpressure. 4}
v) Find the flow pressuremultiplier C for normal pressures. nd so d~. ~.e he
flow pressure t the evel zp. gnoringpatchpressures uring discharge.4]
vi) Determine he dischargevaJueof the co-existentpatch pressureand the
total force appliedby the filling patchpressure. [4]
vii) Find the vertical stress esultantN,rSdeveloped t the baseof the silo wall
at the most highly stressed osition causedby the dischargepatch alone,
using he appropriate artial safety actor YF. [6]
viii) If the wall is made of stainlesssteel of thickness = 12 mm, deduce he
corresponding ertical stress ue o the patch oad aJooe. [2]
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3. Elevated ilos1rit~ boppen
a) Name the two principal modes of solids flow from a silo, and st8te the key
differences between them, with the aid of sketches. An elevated silo with a
hopper can be designed so that the flow of M)1ids n diJCblrge is in either of these
two m
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Strength of metal silo walls
Where a metal silo is symmetrically illed and discharged,he cylindrical walls
must be designedagainst two key failure modes due to bulk solid loading.
Identify the two modesand ndicate he aspects f bulk solids oading which are
most important n inducing that failure mode. Deduce he bulk solids property
limits which shouldbe usedwhen assessinghe silo for resistance gainst he two
modesof failure. [8]
4.
a)
A cylindrical on-groundsilo of diameter 12 m is made rom mild steel with a
yield stressof 230 MPa and Young's modulusof 2xlOSMPa. It bas a vertical
wall height 18 m and s concentrically illed level (flat top surface) o the top of
this wall. The stress esultants valuated or the silo wall at threedifferent levels,
including the partial factor on actions, YF, re shown n Table 1. The internal
pressure,without a partial factor, s also shown.
b)
If the wall thickness at z
= 10m is proposedo be t = 6 mID,detennine he
safety margin against a yielding (bursting) failuret using the partial
resistance factor YM
=
1.10. To what value could the wall thickness be
reduced f this is the key failure mode? [10]
The silo is built to FabricationQuality Class B "High quali~tt and the
proposed wall thickness at z = 12.5 m is t = 8 min. Ignoring the
strengtheningeffect of internal pressure,determine the safety margin
againsta buckling failure, using he partial resi~ce factor YM 1.10. Is
the designadequate? [22]
ii)
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2. Patch oads and dischup
a) All standards hat define silo pressuresbegin by defining a filling pressureand
then modify it to obtain a dischargepressure. Br~j1y explain why this is, and
indicate he differencesbetweenilling and discharge ressures. [4]
Underconditionsof filling, the pressure egime s relatively well definedand matches
values given by Janssen's heory quite well, provided appropriateval~s for the
material properties are used. This is therefore used as the referencecase when
defining silo pressures, nd all other pressure onditionsare nonnally referredback o
this as a basis. However, when dischargebegins, parts of the silo wall may be
ex}X)sed
o significant increasesn pressure,hough someof thesemay be transient
However. heir duration s sufficiently ong for them o be classedas static short enD
loads rather than dynamic oads, and the flow pressuremultiplier, or flow pressure
factor s used o attempt o relate he discharge ressureo the filling pressure. n the
Eurocode, he value of the flow pressuremultiplier dependson the solid being
considered its angle of internal friction) and the aspect atio of the silo (squat or
slender).
b) 1'18e uropeansilos loading standard ENV 1991-4aho requires silo designs o
include a "patch" pressure o be placed at any position on the silo wall. Briefly
explain its purpose and the eatures of real silo pressures hat it I.s ntended o
[4J ., 111.
Underboth filling and discharge onditions, he pressures gainst he walls of silos are
not symmetrical with respect o the silo axis, even under apparentlysymmetrical
conditions. The loss of symmetry s causedby geometric mperfections n the silo
walls, andKCidentalasymmetriesn the filling and granularsolids packingprocesses.
To account or this asymmetryand to ensure hat the structural design has some
margin of safety againstunsymmetrical oads, he E\D'ocode efinesa patch pressure
that must be added o the filling pressures, nd a secondpatch pressuremust be
applied to the dischargepreSS\D'Cs. hilst in principle the patch pressuremay act
anywhere, he standarddefines he position at which it should act to give the worst
effect.
A cylindrical on-ground silo of diameter 12.Om f made rom polished stainless
steel and is used to store barley flour. The corJdition to be considered in your
design is the moxim"", prUSfl1'e CD8e, nd for this the appropriate properties are
as ollows: unit weight 8.5 k;NW; ,II
=
0.255; .4.
=
0.550; nternal riction angle
;; - 280: It has a vertical wall height 18 metres and is concentrically filled level
(flat top surface) to the top of this wall. Discharge is thrmlgh an outlet which is
slightly eccentric to the silo axis, with eo = 1.2 In.
i) A patch pressure load will be applied to the filling pressures. Locate the
position of the centre of this patch as a depth zp below the surface of the
}lour. [4J
c)
Locationoftbe patch s given by z,: Eq. 7.17: z, is the esserof Zo and hJ2
For theseproperties,Zo=R/2~ =
6.0/(2xO.2SSxO.SSO)
21.39m
The height s identical o heso bJ2 - 18/2 9.0 m
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Thus patch pessure is p,,- 02x P xi"l - 0.2xl.10x46.37-
The total borimntal force applied by the patch plaS\D'e is Ppc
Ppc
=
1[ s
R p,. =
[ x 2.4 6.0
10.20= 461.5 N
KsRp,.
vii} FlIwl 1M verlical.Jtn-u ".nIlt- N&t.-."loped ,. 1111 of 1111ilo wall
at 1M most highly stn.f.redposition CaU.f.d y 1M dLrcharrepatch alont,
IIIIng the apprOpI'iDIecrtlDl s.afetyaclor 'fF. [6]
~ of die a..e of thesilo wall belowdiee:rtive ~ -
z
- 18m
The most bisbiY U ~ position s at e - 0, when~ ~ 1.0
Vertical tIe8I resultantN&t.- eveloped t the molt highly .~ position n the wall
at z (Eq. 10.20)
Val~ of YF s taken fnMn Table 10.2: this is . ~ 8:tion. uotber solids"
\mfavourable ':f~~ ~ die vaI~ is YF 1.50.
N~ = - 'YF , sz
,)/R) COt 9 - 1.SOxI0.20x2.4x18.0-9.0)'6.0) -
SS.08 kN/m
viii}
If lilt 'MIalJ.f ... of 1tGtMc.ulftl of
iI.::.~-==-~
2-. ~ 1M
correSINJrwlingrticaI.rtre.uue 0Iw chDIId.. [2]
{5]
Vertical~brane stressn thewall s liven by ~
- N.sJ1
- -SS.08/12
- ..S9 MPa
{5]
V mica membrane ftSS n the wall is given by
,
Units: (kN/m)/mm - (N/mm)/mm N/mm:
11
10.20Pa
where
,= Nasi'
=MPa
~-
2 -'
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3. Elevated .ilos wit~ lIoppen
a) Name he two principal modes f solldf flow fro," a Itlo, and .ftatl the by
differetk"Ubetweenhem.with the aid of It.tcllu. All ekUed IUD with a
hoPIWr Q1Iedesignedo hai tile low of solidi. 4SlCUp i.r ll "" of tIIt.JI
two1IIodes. [8]
The ~ ~peI flow mc:NIesn silos are Mass Flow and FUlmeIFlow. The key
differencebetween hem s IS follows. In Mass Flow all ~cles of the storedsolid
are n motian when he outlet is o~. In FunnelFlow, only someof the solid is in
motion: different peuemscan occur n ft8mel flow, with the moving solid IOmetimes
entirely internal to the silo: in other ciICumstances,he Oowina ~ will spread
outwards rom the outlet and reach the wall, above which all material will be in
motion.
If
a circIIlIr pi.,.. sUo Iwu a conica/1tOppeT with a 1IDIIangle of 100 aIwJ he
wall fHction angle between he solid a1ki 1M #tDppIr .f 15, dele""ine the
IN'O~ modeofjlow ill 1111Uo according o EIII'c* J Part 4. [4]
b)
The DM)(ie f flow can be fOtBMIrom die chart of flow mode predictions:Fig. 6.2 w
Fig. 1.5:
The hopper is conical so Fig. 6.2c applies.
The wall 6'ictiOI1qie is I 50
-
Using the iKJPper alf qIe of 200 8M ... = I So, t is clear hat this hopperwill
exhibit MassFlow.
c) A" ,.J.YQted silo, COIUI1'.:ted e8ftiy from all.iIIi.-, Iwu a ~/er of
8.3",.tres and is used o storematz,.with a unit wig#rl r
-
8.5 k,N1",J. It is
COIICe.,.;caliy tJ/d aIKl dUchDI-geil /rough a hopper with QII apex JWJlf ngle of
200. n. wrtica/
.rIre.J.fwlthill tile solid at tIle trtDI.rilicm Iwu bee" ,.~d Q$
45.1 kPa wi... tIle Of'OJ"'iDle 1Itat,.rlG/ W'Opertiel wnJe." Kfed (A -
0.45 aIKl
.u-
0.268).
(I) o.tet-- WMtMr,. .""" I.r.rlftpM.tWIow,. [5J
Eq. 7.26 8i'\'a a'iterion for --=-+~~
The hoppei' s shallow if:
tm.8>{ :&}
2P11
that is if t8I2OO> (1-O.4S)I(2xO.268)
(fI)
,... ,. wGll
r8io F .for lU,. co.JlIjONJo ~
Eq.7.31:Tt. hopperwall pressureatio or filling is
Ff
- ~.~~;;;~
(I + 0.8xO.268xCQC200)I(1
0.268x~)
-
0.915
12
O
0
1
. . .
,
._~ .~~
0.364> 1.026 No, m this IM~ is steep.
.
(S)
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(Iii) FIIwl ,1M ."" NI JWWS.I~ . "
,.",
,. f '" r N/
"..,. flam,. (6]
The nonna1 ressure n the wall on filling me (Eq. 7.27)p. F PY/
in whichhe~ P-1s aivmby
~{(~-(fJ}h
n - 2(F~co~+Ff-l)
Pvf - D-Il~~-~~ J . ~t~
~ n - 2(F~ cotp + Ff- I)
and he raDSitionertical tress aabeen iven n thequestion s Pvft- 45.2 kPa
In this ~ the ~ to be ~ areat the top of the oopper.10
X - ~ ~1Ih ~ ~~ may IXJt ecoIn~ tb8t Ibis Ie.Is to . coasidcrable JX)rt
cut in the questicxl:
~
{ n}
n
Ifx - ~ thenPvf= -;;:t 1.0 1.0 + Pvft1.0 - Pvft - 45.2 kPa
The normal JXaSUIe XI fi11iIII at .. TOP of the OOAJel's then
PM- F(Pvf- O.915x4S.2 41.4kPa
If the It.xIaIt ck>es Ot~lIIise that aUother ams ~ tIxn it is i:~:~~ -,. to ~
~ density, o determine he hopperheipt, to look up the appr\Jf'i:'aateal~ ofoopper
wall friction angle taking cognisance f whether his should be an upper or lower
bow1dva1~, to evaluate he hopper wall friction coefficient, and to use aU these o
find n - ~ thepessure t anyheightp.r. Sadly ll dleseermswill cancelo
leaveonly die above,aIKIdlis hugeeffort will be ratherwasted n this question. This
question s dlerefore athereasy or tOOIewho have8 aood mderstanding onerous
for thosewho lack it.
Give" 1.IkIt M ,."..,. 'wall rlclloll angle is ;.,
- J O, IftlIM iIIIenkll friction
angle of 1M solid I.J~
-
18,
l""
"" designwall ,...,/ JW'e.f.nl1'e"'" ~ry lOp
of 1M hopperwall dwl"g di.Jclrarp. [11]
d)
TheditcI.- ~ ia .. IMw- i81i'w81y Eq8.1 )
Pac FePw
~Pw -
~{(~
( J}
P.I( J
1
+_a8
IIxt Fe - 1
- lint ~2P+e)
.:
=+-+ sin-'{~}
Onc:e gain, he vertical ~ at the TOP of the hopper~~ to:
Pw=Pvft
However, he val.. of F am must be fotmd.
The hopperwall friction is given by 1.111tan .. - tan 1So 0.261
The ntaD81 riction angle s +1 280
13
".(rJ
- 45.2 Pa
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so E -..+
sin-I{~} -15+ sin-I{~} -15+ 33.46 -48.460
Now Fc = 1 _1
:"'-=+8)
(1 + 1iD2rc0e48.46~ I - siD2JOcoI(2x200+48.46
- .328
at the iMJPPerop, PM
-
. - 8M
1.321~S.2
-
O.0kPa
Now
PM-
14
Pw
-,.. m
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Strength of metal sUo waUs
Where a metal silo is symmetrically filled and discharged, the cylindrical walls
must be designed against two key failure modes due to bulk solid loading.
Identify the two modes and indicate the aspects of bulk solids loading which are
most important in inducing that failure mode. Deduce the bulk solid\' property
limits which should be ILJedwhen assessing he silo for resistance against the two
modes offailwe. [8)
4-
II)
The two key modesare:
+ plasticcollapse, uptureor bursting
+ buckling underaxial compression
Key aspects:
+ Plastic failure: high internal pressures, induced by solids flow (so discharge is
critical). Low wall friction causes ncreases n these pressures
+ Buckling under axial compression: high wall frictio~ leading to cumulative vertical
loads in the wall. Geometric imperfections seriously affect the strength.
+ Plastic failure verification must be perfonned using a von Mises check
+ Buckling under axial compression verification may include the effect of a patch load
on the wall, and the strengthening effect of internal pressm'eat all positions
The material property extremes which are needed o address hese two modes are:
+ Plastic failure: Maximum lateral pressure ratio A, and minimum wall friction
coefficient ~
+ Buckling: Maximwn lateral pressme ratio
~ and maximumwall friction coefficient
1.1
A cylindrical on-ground silo of diameter 12m is made rom mild steel with a
y;eldstress of 230 MPa and Young'smodulusof2xloS MPa. It has a vertical
wall heighl 18 m and ;s concentrically illed level (flat top surface) o the top of
this wall. Thestress esultantsevaluatedor the silo wall at three different evels,
including the partial factor on actions. YF.are shown n Table I. The internal
pressure,without a partial factor, is also shown.
b)
IS
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Jfthe wall thickness t z - 10 m is proposedo be t = 6 mm, determine
the safety margin against a yielding (bursting) ailure, using the partwl
resistanceactor ru = 1.10. To what value could the wall thicknessbe
reduced f this is the Uy failure mode? [10]
I)
Choose he valuesarising rom Max. PreIS1ft.
NeSd 444 kN/m andNxSd=1~ kN/m.
So NvmSd
=
..J(NeSd2Ne~xSd + NxSd2)
389kN/m
Check or 6mm wall: Nv8Rd 230.6/1.1
=
1254kN/m
So safetymarginagainstbursting s 1254/389 3.23
Requiredwall thickness s given by:
~uired =
(NvmSdfrM)/fy
- 1.71mm
This value is too thin to be realistic on a diameter of 12 m. so JX'Obably mm wall
would be used f this were he critical
ii) The silo is built to Fabrication Quality Class B "High quality", and the
proposed wall thickness at z = 12.5 In is t - 8 mm. Ignoring the
strengthening effect of intemaJ presnlFe, determine the safety margin
against a buckling failure, using the partial resistance actor YM
= 1.10. Is
the designadequate? [16J
Choose he valuesarising rom Max. Friction.
NOSd
= 445kN/m andNxSd 230kN/m.
Buckling assessment:
Radius to thickness ratio: R/t = 6(XM)I8 750
Fabrication quality class is High, so Q
=
25
Characteristicmperfectionamplitude
=Wk
Unpressurised lastic mperfection eduction actor a cr(
For uniform meridional compression", =1.0, 80 ~ - 0.195.
Elastic critical stress
=
O'xRt
= 0.605Ei = 161.33MPa
Dimensionless lenderness: .. ..J(f.,lO'xaIt) ..J(230, 161.33)=
1.194
Limiting dimensionless ler.derness:
..,
-
..J(2.5aJ
="'(2.5.0.194)-
0.698
Since 1..>
1.., .
this silo wall is in the mne 3, elasticb~kling
Kx=aJ~2 = (0.195/1.1941-0.137
Characteristic uckling strength s giVal by
xn
= Kx' fy = 0.137.230 31.46MPa
So buckling resistances NxRd (O~)~ - (31.46/1.1.8 - 228.8kN/m
Compare esignvalue of stress esultant:NxSd
=
230 kN/m
Safetymarginagainstbuckling s 228.8/230
=
0.995 ust unsafe But JX'Obably K.
16
verysafe
consideration.
.LI
\J
= 8.005)
..J(7S0)
=8.76 mID
- 0.62
~-;:;~;:;