Design of Silos & Tanks

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    FA CUL TV OF SCII:N CI: AND t: N G INI: J:KIN G

    aVIL ENGINEERING 4

    CML ENGINEERING 4M

    CIVIL AND ENVIRONMENTAL ENGINEERING 4

    CIVIL AND ENVIRONMENTAL ENGINEERING 4M

    ~ ENGINEERING AND CONSTRUCTION MANAGEMENT 4

    CIVIL ENGINEERING AND CONSTRUcnON MANAGEMENT 4M

    CIVIL ENGINEERING SM

    CIVIL AND ENVIRONMENTAL ENGINEERING SM

    M17 -DESIGN OF SILOS AND TANKS

    CONVINOR ' nil BoARDo' EXAMINDS:

    EXTl.RNAL I.XAMINER:

    UN)VI:RSITV OF

    URGH

    DINB

    Wednesd8Y 6th M8rt"h 2002

    3.00pm - 4.30pm

    Professor 0 A Barry

    ProfessorH. D. Wricbt

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    On-ground silos

    When building structuresare designed, he ultimate limit state s related o the

    characteristichighest oad state,which might be the highest ive load or wind

    load. However. n silo design,different extremevalues of the propertiesof the

    storedmaterialsmust be considered s different load cases. Give the reason or

    this, and state he extremes f storedsolid properties hat shouldbe used or each

    condition. [8]

    1.

    a)

    Determine he design wall loads for the following cylindrical on-ground mild

    steel silo. The silo is constructed rom rolled stnM:tural teel plate and has a

    vertical wall height of 25.0 m and a diameter of 10.0 m. It is ~ to store

    alumina,and is concentrically illed and discharged.The roof slopesat an angle

    of 300 o the horizontaland he silo is filled until the solid ust touches he top of

    the vertical wall.

    i) Identify the design value of the angle of repose,and the stnICturaldesign

    value of the unit weight r [2]

    ii) Find the Wlit weight hat shouldbe used or the purposeof detelmining he

    reliable storage apacityof the silo, anddeduce his capacity. [3]

    iii) Determine the surface c~ of the wall for which the silo should be

    designed. [2]

    iv) Identify the upper and lower values of wall friction angle that should be

    used or the design. Deduce he upper and lower characteristic alues of

    wall friction coefficientJL [3]

    v) Identify the upperand ower characteristic aluesof lateral pressure atio ).,

    as given n the able ofpro petties. [2]

    vi) Identify the upper and lower characteristicvalues of effective internal

    friction

    ~

    for the solid from the table of properties, nd then use an

    appropriateequation o deduce he upperand ower characteristic aJues f

    lateralpressureatio).. Comparehese aJcu1atedalueswith thosegiven n

    the table of properties. Statewhy the equation s given at all, if it can ead

    to different values rom those n the able.

    Note: Use he values rom the able n all subsequentaJculations. [5]

    vii) Find the total weight of solid that can be placed n the silo at the structural

    designunit weight, and determine he height of the effective surfaceabove

    the base. [3]

    b)

    University of fAinoorgh

    Schoolof Civil and EnvironmentalEngineering

    HODoun Module M.t7: Designof Silos

    mination April 2002

    egreeExa

    Answer any two questions

    Eachquestion s worth 40 marks

    IIf2 hours

    ime allowed:

    This exam s open book

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    viii) FCX'he colXlition of maximmn normal ~ against the silo

    identify the appropriate aluesof wall friction coefficient, ateral pI'1

    ratio and Wtit weight o be used.

    f

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    Patch loads and discharge

    All standards hat define silo pressures egin by defining a filling pressureand

    then modify it to obtain a dischargepressure. Briefly explain why this is, and

    indicate he differences etween illing and discharge ressures. [4]

    2.

    a)

    The Europeailsilos loading stalxlardENV 1991-4also requires silo designs o

    include a "patch" pressure o be placedat any position on the silo wall. Briefly

    explain its purposeand the featuresof real silo pressureshat it is intended o

    reprexnl [4]

    A cylindrical on-groundsilo of diameter 12.0m s made rom polished stainless

    steel and is used o store barley flour. The condition to be considered n your

    design s the maximum pressure ase,and for this the appropriatepropertiesare

    as follows: unit weight 8.5 kN m3; .u

    = 0.255; A.=

    0.550; internal friction angle

    ;; =

    28. It has a vertical wall height 18 metresand s concentrically illed level

    (flat top surface) o the top of this wall. Discharge s through an outlet which is

    slightly eccentric o the silo axis, with eo= 1.2 m.

    i) A patch ~sure load will be applied o the tilling pressures. Locate he

    position of the centreof this patch as a depth zp below the surfaceof the

    flour. [4]

    ii) Determine he filling vaJueof normal pressure gainst he wall at the level

    of the centreof the patch, gnoringpatchpressures. [4]

    iii) Determine he filling value of the co-ex.isteDt atch pressureand identify

    the vertical and horizontalextentof the patch. [4]

    iv) Deduce he total horizontal orce appliedby the filling patchpressure. 4}

    v) Find the flow pressuremultiplier C for normal pressures. nd so d~. ~.e he

    flow pressure t the evel zp. gnoringpatchpressures uring discharge.4]

    vi) Determine he dischargevaJueof the co-existentpatch pressureand the

    total force appliedby the filling patchpressure. [4]

    vii) Find the vertical stress esultantN,rSdeveloped t the baseof the silo wall

    at the most highly stressed osition causedby the dischargepatch alone,

    using he appropriate artial safety actor YF. [6]

    viii) If the wall is made of stainlesssteel of thickness = 12 mm, deduce he

    corresponding ertical stress ue o the patch oad aJooe. [2]

    3

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    3. Elevated ilos1rit~ boppen

    a) Name the two principal modes of solids flow from a silo, and st8te the key

    differences between them, with the aid of sketches. An elevated silo with a

    hopper can be designed so that the flow of M)1ids n diJCblrge is in either of these

    two m

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    Strength of metal silo walls

    Where a metal silo is symmetrically illed and discharged,he cylindrical walls

    must be designedagainst two key failure modes due to bulk solid loading.

    Identify the two modesand ndicate he aspects f bulk solids oading which are

    most important n inducing that failure mode. Deduce he bulk solids property

    limits which shouldbe usedwhen assessinghe silo for resistance gainst he two

    modesof failure. [8]

    4.

    a)

    A cylindrical on-groundsilo of diameter 12 m is made rom mild steel with a

    yield stressof 230 MPa and Young's modulusof 2xlOSMPa. It bas a vertical

    wall height 18 m and s concentrically illed level (flat top surface) o the top of

    this wall. The stress esultants valuated or the silo wall at threedifferent levels,

    including the partial factor on actions, YF, re shown n Table 1. The internal

    pressure,without a partial factor, s also shown.

    b)

    If the wall thickness at z

    = 10m is proposedo be t = 6 mID,detennine he

    safety margin against a yielding (bursting) failuret using the partial

    resistance factor YM

    =

    1.10. To what value could the wall thickness be

    reduced f this is the key failure mode? [10]

    The silo is built to FabricationQuality Class B "High quali~tt and the

    proposed wall thickness at z = 12.5 m is t = 8 min. Ignoring the

    strengtheningeffect of internal pressure,determine the safety margin

    againsta buckling failure, using he partial resi~ce factor YM 1.10. Is

    the designadequate? [22]

    ii)

    5

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    2. Patch oads and dischup

    a) All standards hat define silo pressuresbegin by defining a filling pressureand

    then modify it to obtain a dischargepressure. Br~j1y explain why this is, and

    indicate he differencesbetweenilling and discharge ressures. [4]

    Underconditionsof filling, the pressure egime s relatively well definedand matches

    values given by Janssen's heory quite well, provided appropriateval~s for the

    material properties are used. This is therefore used as the referencecase when

    defining silo pressures, nd all other pressure onditionsare nonnally referredback o

    this as a basis. However, when dischargebegins, parts of the silo wall may be

    ex}X)sed

    o significant increasesn pressure,hough someof thesemay be transient

    However. heir duration s sufficiently ong for them o be classedas static short enD

    loads rather than dynamic oads, and the flow pressuremultiplier, or flow pressure

    factor s used o attempt o relate he discharge ressureo the filling pressure. n the

    Eurocode, he value of the flow pressuremultiplier dependson the solid being

    considered its angle of internal friction) and the aspect atio of the silo (squat or

    slender).

    b) 1'18e uropeansilos loading standard ENV 1991-4aho requires silo designs o

    include a "patch" pressure o be placed at any position on the silo wall. Briefly

    explain its purpose and the eatures of real silo pressures hat it I.s ntended o

    [4J ., 111.

    Underboth filling and discharge onditions, he pressures gainst he walls of silos are

    not symmetrical with respect o the silo axis, even under apparentlysymmetrical

    conditions. The loss of symmetry s causedby geometric mperfections n the silo

    walls, andKCidentalasymmetriesn the filling and granularsolids packingprocesses.

    To account or this asymmetryand to ensure hat the structural design has some

    margin of safety againstunsymmetrical oads, he E\D'ocode efinesa patch pressure

    that must be added o the filling pressures, nd a secondpatch pressuremust be

    applied to the dischargepreSS\D'Cs. hilst in principle the patch pressuremay act

    anywhere, he standarddefines he position at which it should act to give the worst

    effect.

    A cylindrical on-ground silo of diameter 12.Om f made rom polished stainless

    steel and is used to store barley flour. The corJdition to be considered in your

    design is the moxim"", prUSfl1'e CD8e, nd for this the appropriate properties are

    as ollows: unit weight 8.5 k;NW; ,II

    =

    0.255; .4.

    =

    0.550; nternal riction angle

    ;; - 280: It has a vertical wall height 18 metres and is concentrically filled level

    (flat top surface) to the top of this wall. Discharge is thrmlgh an outlet which is

    slightly eccentric to the silo axis, with eo = 1.2 In.

    i) A patch pressure load will be applied to the filling pressures. Locate the

    position of the centre of this patch as a depth zp below the surface of the

    }lour. [4J

    c)

    Locationoftbe patch s given by z,: Eq. 7.17: z, is the esserof Zo and hJ2

    For theseproperties,Zo=R/2~ =

    6.0/(2xO.2SSxO.SSO)

    21.39m

    The height s identical o heso bJ2 - 18/2 9.0 m

    9

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    Thus patch pessure is p,,- 02x P xi"l - 0.2xl.10x46.37-

    The total borimntal force applied by the patch plaS\D'e is Ppc

    Ppc

    =

    1[ s

    R p,. =

    [ x 2.4 6.0

    10.20= 461.5 N

    KsRp,.

    vii} FlIwl 1M verlical.Jtn-u ".nIlt- N&t.-."loped ,. 1111 of 1111ilo wall

    at 1M most highly stn.f.redposition CaU.f.d y 1M dLrcharrepatch alont,

    IIIIng the apprOpI'iDIecrtlDl s.afetyaclor 'fF. [6]

    ~ of die a..e of thesilo wall belowdiee:rtive ~ -

    z

    - 18m

    The most bisbiY U ~ position s at e - 0, when~ ~ 1.0

    Vertical tIe8I resultantN&t.- eveloped t the molt highly .~ position n the wall

    at z (Eq. 10.20)

    Val~ of YF s taken fnMn Table 10.2: this is . ~ 8:tion. uotber solids"

    \mfavourable ':f~~ ~ die vaI~ is YF 1.50.

    N~ = - 'YF , sz

    ,)/R) COt 9 - 1.SOxI0.20x2.4x18.0-9.0)'6.0) -

    SS.08 kN/m

    viii}

    If lilt 'MIalJ.f ... of 1tGtMc.ulftl of

    iI.::.~-==-~

    2-. ~ 1M

    correSINJrwlingrticaI.rtre.uue 0Iw chDIId.. [2]

    {5]

    Vertical~brane stressn thewall s liven by ~

    - N.sJ1

    - -SS.08/12

    - ..S9 MPa

    {5]

    V mica membrane ftSS n the wall is given by

    ,

    Units: (kN/m)/mm - (N/mm)/mm N/mm:

    11

    10.20Pa

    where

    ,= Nasi'

    =MPa

    ~-

    2 -'

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    3. Elevated .ilos wit~ lIoppen

    a) Name he two principal modes f solldf flow fro," a Itlo, and .ftatl the by

    differetk"Ubetweenhem.with the aid of It.tcllu. All ekUed IUD with a

    hoPIWr Q1Iedesignedo hai tile low of solidi. 4SlCUp i.r ll "" of tIIt.JI

    two1IIodes. [8]

    The ~ ~peI flow mc:NIesn silos are Mass Flow and FUlmeIFlow. The key

    differencebetween hem s IS follows. In Mass Flow all ~cles of the storedsolid

    are n motian when he outlet is o~. In FunnelFlow, only someof the solid is in

    motion: different peuemscan occur n ft8mel flow, with the moving solid IOmetimes

    entirely internal to the silo: in other ciICumstances,he Oowina ~ will spread

    outwards rom the outlet and reach the wall, above which all material will be in

    motion.

    If

    a circIIlIr pi.,.. sUo Iwu a conica/1tOppeT with a 1IDIIangle of 100 aIwJ he

    wall fHction angle between he solid a1ki 1M #tDppIr .f 15, dele""ine the

    IN'O~ modeofjlow ill 1111Uo according o EIII'c* J Part 4. [4]

    b)

    The DM)(ie f flow can be fOtBMIrom die chart of flow mode predictions:Fig. 6.2 w

    Fig. 1.5:

    The hopper is conical so Fig. 6.2c applies.

    The wall 6'ictiOI1qie is I 50

    -

    Using the iKJPper alf qIe of 200 8M ... = I So, t is clear hat this hopperwill

    exhibit MassFlow.

    c) A" ,.J.YQted silo, COIUI1'.:ted e8ftiy from all.iIIi.-, Iwu a ~/er of

    8.3",.tres and is used o storematz,.with a unit wig#rl r

    -

    8.5 k,N1",J. It is

    COIICe.,.;caliy tJ/d aIKl dUchDI-geil /rough a hopper with QII apex JWJlf ngle of

    200. n. wrtica/

    .rIre.J.fwlthill tile solid at tIle trtDI.rilicm Iwu bee" ,.~d Q$

    45.1 kPa wi... tIle Of'OJ"'iDle 1Itat,.rlG/ W'Opertiel wnJe." Kfed (A -

    0.45 aIKl

    .u-

    0.268).

    (I) o.tet-- WMtMr,. .""" I.r.rlftpM.tWIow,. [5J

    Eq. 7.26 8i'\'a a'iterion for --=-+~~

    The hoppei' s shallow if:

    tm.8>{ :&}

    2P11

    that is if t8I2OO> (1-O.4S)I(2xO.268)

    (fI)

    ,... ,. wGll

    r8io F .for lU,. co.JlIjONJo ~

    Eq.7.31:Tt. hopperwall pressureatio or filling is

    Ff

    - ~.~~;;;~

    (I + 0.8xO.268xCQC200)I(1

    0.268x~)

    -

    0.915

    12

    O

    0

    1

    . . .

    ,

    ._~ .~~

    0.364> 1.026 No, m this IM~ is steep.

    .

    (S)

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    (Iii) FIIwl ,1M ."" NI JWWS.I~ . "

    ,.",

    ,. f '" r N/

    "..,. flam,. (6]

    The nonna1 ressure n the wall on filling me (Eq. 7.27)p. F PY/

    in whichhe~ P-1s aivmby

    ~{(~-(fJ}h

    n - 2(F~co~+Ff-l)

    Pvf - D-Il~~-~~ J . ~t~

    ~ n - 2(F~ cotp + Ff- I)

    and he raDSitionertical tress aabeen iven n thequestion s Pvft- 45.2 kPa

    In this ~ the ~ to be ~ areat the top of the oopper.10

    X - ~ ~1Ih ~ ~~ may IXJt ecoIn~ tb8t Ibis Ie.Is to . coasidcrable JX)rt

    cut in the questicxl:

    ~

    { n}

    n

    Ifx - ~ thenPvf= -;;:t 1.0 1.0 + Pvft1.0 - Pvft - 45.2 kPa

    The normal JXaSUIe XI fi11iIII at .. TOP of the OOAJel's then

    PM- F(Pvf- O.915x4S.2 41.4kPa

    If the It.xIaIt ck>es Ot~lIIise that aUother ams ~ tIxn it is i:~:~~ -,. to ~

    ~ density, o determine he hopperheipt, to look up the appr\Jf'i:'aateal~ ofoopper

    wall friction angle taking cognisance f whether his should be an upper or lower

    bow1dva1~, to evaluate he hopper wall friction coefficient, and to use aU these o

    find n - ~ thepessure t anyheightp.r. Sadly ll dleseermswill cancelo

    leaveonly die above,aIKIdlis hugeeffort will be ratherwasted n this question. This

    question s dlerefore athereasy or tOOIewho have8 aood mderstanding onerous

    for thosewho lack it.

    Give" 1.IkIt M ,."..,. 'wall rlclloll angle is ;.,

    - J O, IftlIM iIIIenkll friction

    angle of 1M solid I.J~

    -

    18,

    l""

    "" designwall ,...,/ JW'e.f.nl1'e"'" ~ry lOp

    of 1M hopperwall dwl"g di.Jclrarp. [11]

    d)

    TheditcI.- ~ ia .. IMw- i81i'w81y Eq8.1 )

    Pac FePw

    ~Pw -

    ~{(~

    ( J}

    P.I( J

    1

    +_a8

    IIxt Fe - 1

    - lint ~2P+e)

    .:

    =+-+ sin-'{~}

    Onc:e gain, he vertical ~ at the TOP of the hopper~~ to:

    Pw=Pvft

    However, he val.. of F am must be fotmd.

    The hopperwall friction is given by 1.111tan .. - tan 1So 0.261

    The ntaD81 riction angle s +1 280

    13

    ".(rJ

    - 45.2 Pa

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    so E -..+

    sin-I{~} -15+ sin-I{~} -15+ 33.46 -48.460

    Now Fc = 1 _1

    :"'-=+8)

    (1 + 1iD2rc0e48.46~ I - siD2JOcoI(2x200+48.46

    - .328

    at the iMJPPerop, PM

    -

    . - 8M

    1.321~S.2

    -

    O.0kPa

    Now

    PM-

    14

    Pw

    -,.. m

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    Strength of metal sUo waUs

    Where a metal silo is symmetrically filled and discharged, the cylindrical walls

    must be designed against two key failure modes due to bulk solid loading.

    Identify the two modes and indicate the aspects of bulk solids loading which are

    most important in inducing that failure mode. Deduce the bulk solid\' property

    limits which should be ILJedwhen assessing he silo for resistance against the two

    modes offailwe. [8)

    4-

    II)

    The two key modesare:

    + plasticcollapse, uptureor bursting

    + buckling underaxial compression

    Key aspects:

    + Plastic failure: high internal pressures, induced by solids flow (so discharge is

    critical). Low wall friction causes ncreases n these pressures

    + Buckling under axial compression: high wall frictio~ leading to cumulative vertical

    loads in the wall. Geometric imperfections seriously affect the strength.

    + Plastic failure verification must be perfonned using a von Mises check

    + Buckling under axial compression verification may include the effect of a patch load

    on the wall, and the strengthening effect of internal pressm'eat all positions

    The material property extremes which are needed o address hese two modes are:

    + Plastic failure: Maximum lateral pressure ratio A, and minimum wall friction

    coefficient ~

    + Buckling: Maximwn lateral pressme ratio

    ~ and maximumwall friction coefficient

    1.1

    A cylindrical on-ground silo of diameter 12m is made rom mild steel with a

    y;eldstress of 230 MPa and Young'smodulusof2xloS MPa. It has a vertical

    wall heighl 18 m and ;s concentrically illed level (flat top surface) o the top of

    this wall. Thestress esultantsevaluatedor the silo wall at three different evels,

    including the partial factor on actions. YF.are shown n Table I. The internal

    pressure,without a partial factor, is also shown.

    b)

    IS

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    Jfthe wall thickness t z - 10 m is proposedo be t = 6 mm, determine

    the safety margin against a yielding (bursting) ailure, using the partwl

    resistanceactor ru = 1.10. To what value could the wall thicknessbe

    reduced f this is the Uy failure mode? [10]

    I)

    Choose he valuesarising rom Max. PreIS1ft.

    NeSd 444 kN/m andNxSd=1~ kN/m.

    So NvmSd

    =

    ..J(NeSd2Ne~xSd + NxSd2)

    389kN/m

    Check or 6mm wall: Nv8Rd 230.6/1.1

    =

    1254kN/m

    So safetymarginagainstbursting s 1254/389 3.23

    Requiredwall thickness s given by:

    ~uired =

    (NvmSdfrM)/fy

    - 1.71mm

    This value is too thin to be realistic on a diameter of 12 m. so JX'Obably mm wall

    would be used f this were he critical

    ii) The silo is built to Fabrication Quality Class B "High quality", and the

    proposed wall thickness at z = 12.5 In is t - 8 mm. Ignoring the

    strengthening effect of intemaJ presnlFe, determine the safety margin

    against a buckling failure, using the partial resistance actor YM

    = 1.10. Is

    the designadequate? [16J

    Choose he valuesarising rom Max. Friction.

    NOSd

    = 445kN/m andNxSd 230kN/m.

    Buckling assessment:

    Radius to thickness ratio: R/t = 6(XM)I8 750

    Fabrication quality class is High, so Q

    =

    25

    Characteristicmperfectionamplitude

    =Wk

    Unpressurised lastic mperfection eduction actor a cr(

    For uniform meridional compression", =1.0, 80 ~ - 0.195.

    Elastic critical stress

    =

    O'xRt

    = 0.605Ei = 161.33MPa

    Dimensionless lenderness: .. ..J(f.,lO'xaIt) ..J(230, 161.33)=

    1.194

    Limiting dimensionless ler.derness:

    ..,

    -

    ..J(2.5aJ

    ="'(2.5.0.194)-

    0.698

    Since 1..>

    1.., .

    this silo wall is in the mne 3, elasticb~kling

    Kx=aJ~2 = (0.195/1.1941-0.137

    Characteristic uckling strength s giVal by

    xn

    = Kx' fy = 0.137.230 31.46MPa

    So buckling resistances NxRd (O~)~ - (31.46/1.1.8 - 228.8kN/m

    Compare esignvalue of stress esultant:NxSd

    =

    230 kN/m

    Safetymarginagainstbuckling s 228.8/230

    =

    0.995 ust unsafe But JX'Obably K.

    16

    verysafe

    consideration.

    .LI

    \J

    = 8.005)

    ..J(7S0)

    =8.76 mID

    - 0.62

    ~-;:;~;:;