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A C

C

M , ME . M (A C ) C

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LI E

D C C D

, :

D

C

C

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D

A ; ?

D

( ),

,

M C D

,

6

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M C

M = ( )

M =

M =

7

C MEA A

, 5, 4, 6, 5, 3 ,7, 5 35/7 5

( ) 5

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( )

MEDIA

5, 4, 6, 8, 9, 7 4, 5, 6, 7, 8, 9 A : 6 + 7 = 13 D : 13/2 = 6.5

6.5

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C MEDIA

5, 4, 6, 5, 3, 7, 5 3, 4, 5, 5, 5, 6, 7 ,

5

C M DE

3, 4, 5, 5, 5, 6, 7

5 3, 4, 5, 5, 5, 6, 7, 8, 9, 9, 9

5 9

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Lets Calculate TheseMeasures

A

C

,

F r e q u e n c y

Mean,Median

Mode

14

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A

( )

( )

. C

.

15

A

16

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I

17

M

;

()

D

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A GE

5, 4, 6, 5, 3, 7, 5 7 3 4

4 I

A DA D DE IA I ( ) I ,

I

A

A

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D

A M DC D

M ( ) = = / = =

=

C A DA D DE IA I

F , (2) =

I

A E AGE

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C

5, 4, 6, 5, 3, 7, 5 F ; 7

35/7 = 5 ( )

(5 5) + (4 5) + (6 5) + (5 5) + (3 5) + (7 5) +

(5 5)

(0)2 + ( 1)2 + (1)2 + (0)2 + ( 2)2 + (2)2 + (0)2

C ( )

A : 0 + 1 +1 +0 + 4 + 4 +0 10

D 1

10 (7 1) 10/6 1.67

1.67

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A DA D DE IA I

,

1.67 1.29

1.29

C D

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C EFFICIE F A IA I

C (C ) D

I D

100 %C = 1.67/5 100 = 8.35%

C

F H LE EL HCG LE ELC D C C . D C

1 0.09 9.0 10 0.8 8.0

10 0.40 4.0 1,000 52.0 5.2

100 3.8 3.8 1,00,000 4,897,0 4.9

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A M :

G M C

C L I (LI ) I C

29

..

D E , :

M M M

C

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DD C

G

I , ,

The Normal Distribution

Performance Measurement in HIV Care

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H C L

A 1 = 68.3% 2 = 95.5% 3 = 99.7%

L . 1

: M +/ 1

E AM LE LDH 117.4 /LL

5.03 /L

1 = 117.4 /L 5.03 /L = 112.4 /L117.4 /L + 5.03 /L = 122.4 /L

1 112.4 122.4 /

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E AM LE

2 = M +/ 211.7.4 /L (2 5.03 /L) = 107.3 /L11.7.4 /L + (2 5.03 /L) = 127.5 /L

2 107.3 127.5 /L 4.5% 107 /

127.5 / ( 1 20 )

0.3% 102.3 / (3 ) 132.5 /L

D A M ?

.

I I I

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C

E

E

E

( )

37

MMA A

D

, ,

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