Des of Beams

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INPUT DATA: Breadth of the beam = 230 mm Depth of the beam = 450 mm Factored bending moment,(M = 78 kNm Factored shear force,(Vu) = 54 kN Grade of concrete (fck) = 40 Grade of steel (Fy) = 415 Clear Cover = 50 mm Diameter of Main Bar = 16 mm Design data: Mulim = 203.14 kNm Design the Beam as Singly Reinforced Section Design for Singly Reinforced Section = 2.12 Percentage of Steel = 0.628 % Ast of steel @ Tension = 578.04 Number of Main bars = 2.88 N/mm 2 N/mm 2 Mu/bd 2 mm 2 DESIGN OF B

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Transcript of Des of Beams

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INPUT DATA:Breadth of the beam=230mmDepth of the beam=450mmFactored bending moment,(Mu)=78kNmFactored shear force,(Vu)=54kNGrade of concrete (fck)=40N/mm2Grade of steel (Fy)=415N/mm2Clear Cover=50mmDiameter of Main Bar=16mmDesign data:Mulim=203.14kNmDesign the Beam as Singly Reinforced SectionDesign for Singly Reinforced SectionMu/bd2=2.12Percentage of Steel=0.628%Ast of steel @ Tension=578.04mm2Number of Main bars=2.88fscDesign for Doubly Reinforced Section0.050.10d'/d=0.148355353Stress in Compression Reinf. (fsc)=354N/mm2Area of Compression Reinf. (Asc)=-884.09mm2Area of steel2=-866.83mm2Area of total Tensile Reinf. (Ast)=1761.73mm2

Design of Shear ReinforcementDiameter of shear reinf.=10
Muhsin: Muhsin:Please note the dia of shear RnftmmNominal Shear stress v=0.60N/mm2Permissible Shear stress c (Rfer IS 456 table 20, page No72)=0.50Shear Rnft reqdFor Min Shear RnftSpacing of Stirrups=616mmProvide the spacing @=300In the case of Shear Rnft reqdShear strength of concrete section=46KNShear Rnft to carry the shear of (Vus)=8Spacing of vertical stirrups (in Calcu)=2834Provide the spacing @=300c/cNote: Designed shear reinforcement can be provided for both singly and doubly cases.Provide Rnft from Shear Rnft reqd at Support Min at Mid-span

DESIGN OF BEAMS