definition of a midpoint definition of an angle bisector
description
Transcript of definition of a midpoint definition of an angle bisector
definition of a midpoint
definition of an angle bisector
A B C
Given: B is midpoint of ACProve: AB = BC
Statement Reason
B is midpoint of AC given
A B C
Given: B is midpoint of ACProve: AB = BC
Statement Reason
B is midpoint of AC givenAB = BC definition of midpoint
A B C
Given: B is midpoint of ACProve: AC = 2(BC)
Statement Reason
B is midpoint of AC given
A B C
Given: B is midpoint of ACProve: AC = 2(BC)
Statement Reason
B is midpoint of AC givenAB = BC definition of midpoint
A B C
Given: B is midpoint of ACProve: AC = 2(BC)
Statement Reason
B is midpoint of AC givenAB = BC definition of midpointAC = AB + BC segment addition postulate
A B C
Given: B is midpoint of ACProve: AC = 2(BC)
Statement Reason
B is midpoint of AC givenAB = BC definition of midpointAC = AB + BC segment addition postulateAC = BC + BC substitution
A B C
Given: B is midpoint of ACProve: AC = 2(BC)
Statement Reason
B is midpoint of AC givenAB = BC definition of midpointAC = AB + BC segment addition postulateAC = BC + BC substitutionAC = 2(BC) combine like terms
A B C
Given: B is midpoint of ACProve: BC = (1/2)AC
Statement Reason
B is midpoint of AC given
A B C
Given: B is midpoint of ACProve: BC = (1/2)AC
Statement Reason
B is midpoint of AC givenAB = BC definition of midpoint
A B C
Given: B is midpoint of ACProve: BC = (1/2)AC
Statement Reason
B is midpoint of AC givenAB = BC definition of midpointAC = AB + BC segment addition postulate
A B C
Given: B is midpoint of ACProve: BC = (1/2)AC
Statement Reason
B is midpoint of AC givenAB = BC definition of midpointAC = AB + BC segment addition postulateAC = BC + BC substitution
A B C
Given: B is midpoint of ACProve: BC = (1/2)AC
Statement Reason
B is midpoint of AC givenAB = BC definition of midpointAC = AB + BC segment addition postulateAC = BC + BC substitutionAC = 2(BC) combine like terms
A B C
Given: B is midpoint of ACProve: BC = (1/2)AC
Statement Reason
B is midpoint of AC givenAB = BC definition of midpointAC = AB + BC segment addition postulateAC = BC + BC substitutionAC = 2(BC) combine like terms(1/2)AC = BC division property
A B C
Given: B is midpoint of ACProve: BC = (1/2)AC
Statement Reason
B is midpoint of AC givenAB = BC definition of midpointAC = AB + BC segment addition postulateAC = BC + BC substitutionAC = 2(BC) combine like terms(1/2)AC = BC division propertyBC = (1/2)AC symmetric property
<1
<2
AB
CD
Statement Reason
BD bisects <ABC given
Given: BD bisects <ABCProve: <1 = <2
<1
<2
AB
CD
Statement Reason
BD bisects <ABC given<1 = <2 definition of angle bisector
Given: BD bisects <ABCProve: <1 = <2
<1
<2
AB
CD
Statement Reason
BD bisects <ABC given
Given: BD bisects <ABCProve: <ABC = 2(<1)
<1
<2
AB
CD
Statement Reason
BD bisects <ABC given<1 = <2 definition of angle bisector
Given: BD bisects <ABCProve: <ABC = 2(<1)
<1
<2
AB
CD
Statement Reason
BD bisects <ABC given<1 = <2 definition of angle bisector<ABC = <1 + <2 angle addition postulate
Given: BD bisects <ABCProve: <ABC = 2(<1)
<1
<2
AB
CD
Statement Reason
BD bisects <ABC given<1 = <2 definition of angle bisector<ABC = <1 + <2 angle addition postulate<ABC = <1 + <1 substitution
Given: BD bisects <ABCProve: <ABC = 2(<1)
<1
<2
AB
CD
Statement Reason
BD bisects <ABC given<1 = <2 definition of angle bisector<ABC = <1 + <2 angle addition postulate<ABC = <1 + <1 substitution<ABC = 2(<1) combine like terms
Given: BD bisects <ABCProve: <ABC = 2(<1)
<1
<2
AB
CD
Statement Reason
BD bisects <ABC given
Given: BD bisects <ABCProve: <1 = (1/2)<ABC
<1
<2
AB
CD
Statement Reason
BD bisects <ABC given<1 = <2 definition of angle bisector
Given: BD bisects <ABCProve: <1 = (1/2)<ABC
<1
<2
AB
CD
Statement Reason
BD bisects <ABC given<1 = <2 definition of angle bisector<ABC = <1 + <2 angle addition postulate
Given: BD bisects <ABCProve: <1 = (1/2)<ABC
<1
<2
AB
CD
Statement Reason
BD bisects <ABC given<1 = <2 definition of angle bisector<ABC = <1 + <2 angle addition postulate<ABC = <1 + <1 substitution
Given: BD bisects <ABCProve: <1 = (1/2)<ABC
<1
<2
AB
CD
Statement Reason
BD bisects <ABC given<1 = <2 definition of angle bisector<ABC = <1 + <2 angle addition postulate<ABC = <1 + <1 substitution<ABC = 2(<1) combine like terms
Given: BD bisects <ABCProve: <1 = (1/2)<ABC
<1
<2
AB
CD
Statement Reason
BD bisects <ABC given<1 = <2 definition of angle bisector<ABC = <1 + <2 angle addition postulate<ABC = <1 + <1 substitution<ABC = 2(<1) combine like terms(1/2)<ABC = <1 division property
Given: BD bisects <ABCProve: <1 = (1/2)<ABC
<1
<2
AB
CD
Statement Reason
BD bisects <ABC given<1 = <2 definition of angle bisector<ABC = <1 + <2 angle addition postulate<ABC = <1 + <1 substitution<ABC = 2(<1) combine like terms(1/2)<ABC = <1 division property<1 = (1/2)<ABC symmetric property
Given: BD bisects <ABCProve: <1 = (1/2)<ABC