December-10-12 A cube has sides of length L and … Law pdf...Gauss's Law December-12-12 5:33 AM...

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A cube has sides of length L and sits on the coordinate axes. The electric field in the region is E=(a+bx)i+cj. Find the electric flux through each of the six cube faces and the total electric flux. Electric flux thru cube December-10-12 4:26 PM Chapter 22 Page 1

Transcript of December-10-12 A cube has sides of length L and … Law pdf...Gauss's Law December-12-12 5:33 AM...

Page 1: December-10-12 A cube has sides of length L and … Law pdf...Gauss's Law December-12-12 5:33 AM Chapter 22 Page 3 An insulating solid sphere of radius R has a uniform volume charge

A cube has sides of length L and sits on the coordinate axes. The electric field in the region is E=(a+bx)i+cj. Find the electric flux through each of the six cube faces and the total electric flux.

Electric flux thru cubeDecember-10-12

4:26 PM

Chapter 22 Page 1

Page 2: December-10-12 A cube has sides of length L and … Law pdf...Gauss's Law December-12-12 5:33 AM Chapter 22 Page 3 An insulating solid sphere of radius R has a uniform volume charge

A nonuniform electric field is given by the expression E=ayi+bzj+cxk where a, b, and c are constants. Determine the electric flux through a rectangular surface in the xy plane, extending from x=0 to x=w and from y=0 to y=h.

Electric flux integralDecember-11-12

10:39 AM

Chapter 22 Page 2

Page 3: December-10-12 A cube has sides of length L and … Law pdf...Gauss's Law December-12-12 5:33 AM Chapter 22 Page 3 An insulating solid sphere of radius R has a uniform volume charge

Use Gauss's Law to find the electric field due to a) a point charge, b) an infinite line of charge and c) an infinite sheet of charge. The working form of Gauss's Law is E=Q in/Aεo where Qin is the charge inside the Gaussian surface and A is the surface area of the Gaussian surface through which the electric field is parallel to the area vector.

Gauss's LawDecember-12-12

5:33 AM

Chapter 22 Page 3

Page 4: December-10-12 A cube has sides of length L and … Law pdf...Gauss's Law December-12-12 5:33 AM Chapter 22 Page 3 An insulating solid sphere of radius R has a uniform volume charge

An insulating solid sphere of radius R has a uniform volume charge density and carries a total positive charge Q. Find the electric field at a point outside the sphere and a point inside the sphere.

E insulating sphereNovember-09-1211:53 AM

Chapter 22 Page 4

Page 5: December-10-12 A cube has sides of length L and … Law pdf...Gauss's Law December-12-12 5:33 AM Chapter 22 Page 3 An insulating solid sphere of radius R has a uniform volume charge

A point charge 2Q is surrounded by a conducting spherical shell with a total charge of 4Q. The inner radius of the shell is a and the outer radius is b. Find the electric field for r<a, a<r<b and r>b.

acre b inside conductor

E conducting spheresNovember-25-123:38 PM

Chapter 22 Page 5

Page 6: December-10-12 A cube has sides of length L and … Law pdf...Gauss's Law December-12-12 5:33 AM Chapter 22 Page 3 An insulating solid sphere of radius R has a uniform volume charge

A spherically symmetric charge distribution with radius R has a nonuniform charge density given by ρ=5/r. Find the electric field for r>R and for r<R.

E nonuniform densityNovember-25-12

3:03 PM

Chapter 22 Page 6

Page 7: December-10-12 A cube has sides of length L and … Law pdf...Gauss's Law December-12-12 5:33 AM Chapter 22 Page 3 An insulating solid sphere of radius R has a uniform volume charge

When do you integrate to get electric flux?October-13-14

1:42 PM

Chapter 22 Page 7

Page 8: December-10-12 A cube has sides of length L and … Law pdf...Gauss's Law December-12-12 5:33 AM Chapter 22 Page 3 An insulating solid sphere of radius R has a uniform volume charge

Chapter 22 Page 8