Deadlock Chapter 3 R1 R2 P2P1 Allocated Requested.
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Transcript of Deadlock Chapter 3 R1 R2 P2P1 Allocated Requested.
DeadlockChapter 3
R1
R2
P2P1
Allocated
Requested
Resources
• Processes compete for system resources– CPU cycles– I/O devices– Printers– Tape drives – Files– Tables– Database records
Resources: Preemptible vs. Nonpreemptible
• Preemptible– Can be taken away from a process without ill
effect• Examples?
• Nonpreemptible– Taking it away from a process causes the
process to fail
• We are concerned with nonpreemptable resources
How a process relates to a (nonpreemptible) resource
• It requests the resource– What can it do if it isn’t available?
• It uses the resource
• It releases the resource, making it available to another process
Using a semaphore to protect resources
One resource Two resources
Using semaphores to protect resources
Deadlock-free Deadlock-prone
The problem of deadlock
• If a process is waiting for a resource that is held by another process that is waiting for another resource held by another process…– A set of processes is in a deadlocked state when
every process is waiting for an event that can be caused only by another process in the set
The four necessary conditions for deadlock to occur
• Mutual exclusion– the resource can be used by only one process at a time
• Hold & wait or resource holding– processes are permitted to hold onto their current
resources while they wait for others
• No preemption– no process can bump another for its resource
• Circular wait – can show that there is a cycle
Resource allocation graphs for deadlock modeling
a) Resource R is assigned to Process Ab) Process B is waiting for Resource Sc) Processes C & D are in deadlock over Resources T & U
Creating deadlock
A B C
Avoiding deadlock
Addressing the issue of deadlock
• Ignorance– Ostrich algorithm
• Detection & recovery– Scan the system looking for cycles of hold & wait– Implement recovery algorithms
• Avoidance– If it seems that deadlock is a possibility, do something to
keep it from happening
• Prevention– negate one of the four necessary conditions
Ignorance: Ostrich Algorithm
• Pretend there is no problem
• Reasonable if – deadlocks occur very rarely – cost of prevention is high
• UNIX and Windows takes this approach
• It is a trade off between – convenience– correctness
Deadlock detection in a graph
• Find a process not waiting for any resource.– Remove its allocation arrows & reallocate its resources
• Find a process that is waiting only for resources that are not completely allocated.– Remove these allocation arrows & reallocate the
resources
• Repeat until all lines have been removed or you determine that they cannot all be removed.
Resource graph: detection with one resource of each type
A cycle can be found within the graph, denoting deadlock
T
Resource graph: detection with multiple resources of each type
R1 R3
R2 R4
P1 P2 P3
Data structures needed for detection with multiple resources of each type
n
Σ Cij + Aj = Eji=1
Fig. 3-6
Detection with multiple resources of each type
Resources in existence Resources available
See pp. 172-173
Recovery from deadlock
• Recovery through preemption– take a resource from some other process– depends on nature of the resource
• Recovery through rollback– checkpoint a process periodically– use this saved state – restart the process if it is found deadlocked
Recovery from deadlock
• Recovery through killing processes– crudest but simplest way to break a deadlock– kill one of the processes in the deadlock cycle– the other processes get its resources – choose process that can be rerun from the beginning
Avoidance – Banker’s algorithm
• Use an algorithm similar to what a bank uses to ensure that it always has funds on hand to satisfy its customers’ eventual needs– Each process must state upfront what its
maximum resource needs will be
• Deal with safe and unsafe states– avoid unsafe states
• Working with multiple instances of resources
Safe state
State (a) is safe because • It is not deadlocked• There is a scheduling order for each process to run to completion
(a) (b) (c) (d) (e)
We have a total of 10 instances of a given resource, with processes A, B, C holding & eventually needing what is indicated here:
Unsafe states
State (b) is unsafe because
• There is no way to satisfy all processes after it
(a) (b) (c) (d)
Banker's Algorithm for multiple instances of a single resource
(a) (b) (c)
Are each of these states safe or unsafe?
Banker's Algorithm for multiple resources
Prevention
• Don’t allow mutual exclusion
• Eliminate resource holding
• Allow preemption
• Modify circular wait
Preventing the “mutual exclusion” condition
• Devices, such as printer, can be spooled– only the printer daemon uses printer resource– thus deadlock for printer eliminated
• But not all devices can be spooled, so abide by the principle:– Allow as few processes as possible to actually
claim the resource
Preventing the “hold and wait” condition
• Require processes to request all resources before starting– Then, a process never has to wait for what it
needs
• Problems– Process may not know required resources at start– Ties up resources other processes could be using
Preventing the “no preemption” condition
• This is not usually a viable option
• Consider a process given the printer– halfway through its job– now forcibly take away printer– !!??
Preventing the “circular wait” condition
Order resources Allocate in order
Summary of approaches to deadlock prevention
Related issues
• Two-phase locking in databases
• Deadlocking on semaphores
• Starvation in CPU scheduling