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Transcript of d.comm Pass Band
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1 Dr. Uri Mahlab
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INTRODUCTION
In order to transmit digital information over *
bandpass channels, we have to transferthe information to a carrier wave of
.appropriate frequency
We will study some of the most commonly *
used digital modulation techniques wherein
the digital information modifies the amplitude
the phase, or the frequency of the carrier in
.discrete steps
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transmittingThe modulation waveforms for
binary information over bandpass channels:
ASK
FSK
PSK
DSB
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OPTIMUM RECEIVER FOR BINARY
DIGITAL MODULATION SCHEMS:
The function of a receiver in a binary communication *system is to distinguish between two transmitted signals
.S1(t) and S2(t) in the presence of noise
The performance of the receiver is usually measured *
in terms of the probability of error and the receiver
is said to be optimum if it yields the minimum
.probability of error
In this section, we will derive the structure of an optimum *
receiver that can be used for demodulating binary
.ASK,PSK,and FSK signals4 Dr. Uri Mahlab
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Description of binary ASK,PSK, and
FSK schemes:
-Bandpass binary data transmission system
ModulatorChannel
(Hc(f
Demodulator
(receiver)
{bk}
Binary
data
Input
{bk}
Transmit
carrier Clock pulses Noise(n(t Clock pulses
Local carrier
Binary data output(Z(t +
+
(V(t
+
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*Explanation:The input of the system is a binary bit sequence {bk} with a *
.bit rate r b and bit duration Tb
The output of the modulator during the Kth bit interval *
.depends on the Kth input bit bk
The modulator output Z(t) during the Kth bit interval is *
a shifted version of one of two basic waveforms S1(t) or S2(t) and
:Z(t) is a random process defined by
bb kTtTkfor )1(:
1bif])1([
0bif])1([)(
k2
k1
b
b
Tkts
TktstZ
.1
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The waveforms S1(t) and S2(t) have a duration *
of Tb and have finite energy,that is,S1(t) and S2(t) =0
],0[ bTtif and
b
b
T
T
dttsE
dttsE
0
2
22
0
2
11
)]([
)]([Energy
:Term
7 Dr. Uri Mahlab
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:The received signal + noise
dbdb
db
db
tkTttTk
tntTkt
tntTkt
tV
)1(
)(])1([s
or
)(])1([s
)(
2
1
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Choice of signaling waveforms for various types of digital*
modulation schemes
for0(t)=2(t),S1S
2];,0[ ccb fTt
.The frequency of the carrier fc is assumed to be a multiple of rb
Type of
modulation
ASK
PSK
FSK
bTtTS 0);(1 bTtts 0);(2
)sinor(
cos
twA
twA
c
c
)sin(
cos
twAor
twA
c
c
0
)sin(
cos
twA
twA
c
c
}])sin{([(
})cos{(
twwAor
twwA
dc
dc
}])sin{(or[
})cos{(
twwA
twwA
dc
dc
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Receiver structure:
Threshold
device or A/D
converter
(V0(t
Filter
(H(f output
Sample every
Tb seconds
)()()( tntztv
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:{Probability of Error-{Pe*
The measure of performance used for comparing *
probability of error!!!digital modulation schemes is the
The receiver makes errors in the decoding process *!!! due to the noise present at its input
The receiver parameters as H(f) and threshold setting are *
minimize the probability of error!!!chosen to
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*can be written asbThe output of the filter at t=kT:
)()()( 000 bbb kTnkTskTV
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b:The signal component in the output at t=kT
bkT
bb dkThZkTs )()()(0
termsISI)()()1
dkThZ b
kT
Tk
b
b
h( ) is the impulse response of the receiver filter*
ISI=0*
b
b
kT
Tk
bb dkThZkTs)1(
0 )()()(
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and making*1Substituting Z(t) from equation
change of the variable, the signal component
:will look like that
b
b
T
bb
T
bb
b
kTsdThs
kTsdThskTs
0
k012
0
k011
0
1bwhen)()()(
0bwhen)()()()(
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:The noise component n0(kTb) is given by *
bkT
bbdkThnkTn )()()(
0
he output noise n0(t) is a stationary zero mean Gaussian random process
:The variance of n0(t) is*
dffHfGtnEN n22
00 )()()}({
:The probability density function of n0(t) is*
n
NNnfn ;
2
n-exp
2
1)(
0
2
0
0
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The probability that the kth bit is incorrectly decoded*
:is given by
}1|)({2
1
}0|)({2
1
})(Vand1
)(Vand0{
00
00
00
00
kb
kb
bk
bke
bTkTVP
bTkTVP
TkTbor
TkTbPP.2
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:The conditional pdf of V0 given bk = 0 is given by*
0
0
2
020
0
01\
0
0
2010
0
00\
-,
2
)(V-exp
2
1)(
-,2
)(V-exp
2
1)(
0
0
V
N
s
N
Vf
VN
s
NVf
k
k
bV
bV
:It is similarly when bk is 1*
.3
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Combining equation 2 and 3 , we obtain an*
:expression for the probability of error- Pe as
0
0
0
0
2
020
0
0
0
2
010
0
2
)(V-exp
2
1
2
1
2
)(V-exp
2
1
2
1
T
T
e
dVN
S
N
dVN
S
NP
.4
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:Conditional pdf of V0 given bk
:The optimum value of the threshold T0* is*
2
0201*0
SST
)( 0
00
v
kv bf )(
k0
01b vvf
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Substituting the value of T*0 for T0 in equation 4*
we can rewrite the expression for the probability
:of error as
00102
0102
2/)(
2
2/)(
0
0
2
010
0
2exp
21
2
)(exp
2
1
Nss
sse
dZZ
dV
N
sV
NP
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If we let P(t) =S2(t)-S1(t), then the numerator of the*
:quantity to be maximized is
bT
bb
bbb
dThPdThP
TPTSTS
0
00102
)()()()(
)()()(
Since P(t)=0 for t
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:Hence can be written as*22
2
2
)()(
)2exp()()(
dffGfH
dffTjfPfH
n
b
(*)
We can maximize by applying Schwarzs*
:inequality which has the form
dffX
dffX
dffXfX2
2
2
2
1
21
)(
)(
)()(
(**)
2
24 Dr. Uri Mahlab
A l i S h i li E i (**) i h
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Applying Schwarzs inequality to Equation(**) with-
)(
)2exp()()(
)()()(
2
1
fG
fTjfPfX
fGfHfX
n
b
n
and
We see that H(f), which maximizes ,is given by-
)()2exp()()(
*
fGfTjfPKfH
n
b
!!! Where K is an arbitrary constant
(***)
2
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Substituting equation (***) in(*) , we obtain-
:the maximum value of as2
dffG
fP
n )(
)(2
max2
:And the minimum probability of error is given by-
22exp
21 max
2
2max/
QdZZPe
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:Matched Filter Receiver*
If the channel noise is white, that is, Gn(f)= /2 ,then the transfer -
:function of the optimum receiver is given by
)2exp()()( * bfTjfPfH
From Equation (***) with the arbitrary constant K set equal to /2-
:The impulse response of the optimum filter is
dfjftjfTfPth b )2exp()]2exp()([)(
*
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Recognizing the fact that the inverse Fourier *
of P*(f) is P(-t) and that exp(-2 jfTb) represent
:a delay of Tb we obtain h(t) as
)()( tTpth b :Since p(t)=S1(t)-S2(t) , we have*
)()()( 12 tTStTSth bb
The impulse response h(t) is matched to the signal *
:S1(t) and S2(t) and for this reason the filter is called
MATCHED FILTER28 Dr. Uri Mahlab
I l f th M t h d Filt *
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:Impulse response of the Matched Filter *
(S2(t
(S1(t 2 \Tb
2 \Tb
1
0
0
1-
2
0
Tb
t
t
t
t
t
(a)
(b)
(c)
2 \Tb(P(t)=S2(t)-S1(t
(P(-tTb- 0
2
(d)
2 \Tb0
Tb
(h(Tb-t)=p(t
2
(e)
(h(t)=p(Tb-t
29 Dr. Uri Mahlab
C l ti R i *
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:Correlation Receiver*
bT
bb dThVTV )()()(0
The output of the receiver at t=Tb*
Where V( ) is the noisy input to the receiver
Substituting and noting *: that we can rewrite the preceding expression as
)()()( 12 bb TSTSh
)T(0,for0)( b h
b b
b
T T
T
b
dSVdSV
dSSVTV
0 0
12
0120
)()()()(
)]()()[()(
(# #)
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Equation(# #) suggested that the optimum receiver can be implemented *
as shown in Figure 1 .This form of the receiver is called
A Correlation Receiver
Threshold
device
(A\D)
integrator
integrator
-
+Sample
every Tb
seconds
bT
0
bT
0
)(1 tS
)(2 tS
)()(
)()(
)(
2
1
tntS
or
tntS
tV
Figure 1
31 Dr. Uri Mahlab
In actual practice the receiver shown in Figure 1 is actually *
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In actual practice, the receiver shown in Figure 1 is actually *
.implemented as shown in Figure 2
In this implementation, the integrator has to be reset at the
- (end of each signaling interval in order to ovoid (I.S.I
!!! Inter symbol interference
:Integrate and dump correlation receiver
Filterto
limit
noise
power
Threshold
device
(A/D)R(Signal z(t
+
(n(t
+
White
Gaussiannoise
High gainamplifier)()( 21 tStS
Closed every Tb seconds
c
Figure 2
The bandwidth of the filter preceding the integrator is assumed *
!!! to be wide enough to pass z(t) without distortion
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Example: A band pass data transmission schemeuses a PSK signaling scheme with
sec2.0T,Tt0,cos)(
/10,Tt0,cos)(
bb1
b2
mtwAtS
TwtwAtS
c
bcc
The carrier amplitude at the receiver input is 1 mvolt and
the psd of the A.W.G.N at input is watt/Hz. Assumethat an ideal correlation receiver is used. Calculate the
.average bit error rate of the receiver
11
10
33 Dr. Uri Mahlab
S l ti
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:Solution
34 Dr. Uri Mahlab
:Solution Continue
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=Probability of error = Pe *
:Solution Continue
35 Dr. Uri Mahlab
* Binary ASK signaling
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* Binary ASK signaling
schemes:
1bif])1([1)T-(k
0bif])1([
)(k2
b
k1
b
b
b
TktskTt
Tkts
tz
The binary ASK waveform can be described as
Where andtAtS ccos)(2 0)(1 ts
We can represent
:Z(t) as
)cos)(()( tAtDtZ c
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Where D(t) is a lowpass pulse waveform consisting of
.rectangular pulses
:The model for D(t) is
k
bk Tktgbtd 1or0b],)1([)( k
elswhere0
Tt01)(
btg
)()( TtdtD
37 Dr. Uri Mahlab
Th l d i i i b
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:The power spectral density is given by
)()([4
)(2
cDcDzffGffG
AfG
The autocorrelation function and the power spectral density
:is given by
b
bD
b
bb
b
DD
Tf
fTffG
T
TT
T
R
22
2sin
)(
4
1)(
for0
for44
1
)(
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:The psd of Z(t) is given by
)
2
2
22
2
2
()(sin
)(
)(sin
)()((16
)(
cb
cB
cb
cb
cz
ffTffT
ffT
ffT
ffffA
fG
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If we use a pulse waveform D(t) in which the individual pulses
g(t) have the shape
elsewere0
Tt0)2cos(12)(
b tra
tgb
40 Dr. Uri Mahlab
C h t ASK
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Coherent ASKWe start with
The signal components of the receiver output at the
:of a signaling interval are
0)(andcos)(12
tstAts c
b
b
T
bb
T
b
TA
dttststskT
dttststskTs
0
2
122O2
0
12101
2)]()()[()(S
and
0)]()()[()(
41 Dr. Uri Mahlab
:The optimum threshold setting in the receiver is
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:The optimum threshold setting in the receiver is
b
bb TAkTskTs
T42
)()( 20201*0
:The probability of error can be computed aseP
max2
1
22
22
max
42exp
2
1
be
b
TAQdz
zp
TA
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:The average signal power at the receiver input is given by
4
2A
sav We can express the probability of error in terms of the
:average signal power
bave
TSQp
The probability of error is sometimes expressed in *
: terms of the average signal energy per bit , as
bavav TsE )(
av
eEQP
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N h t ASK R i
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Noncoharent ASK Receiver
filterbandpasstheof
outputat thenoisetheisn(t)when
0Aand1bbitdtransmitte
kthwhen theAwheresin)(
cos)(cos
)(cos)(
:haveoutput wefilterAt the
kk
k
Attn
ttntA
tntAtY
cs
ccck
ck
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:The pdf is
0r,2
exp)(
0r,2
exp)(
0
22
0
0
0
1|
0
2
0
0|
N
Ar
N
ArI
N
rrf
N
r
N
rrf
k
k
bR
bR
B
TTBN
N
2
filter.bandpasstheofoutputat thepowernoise
0
0
2
0
0 ))cos(exp(
2
1)( duuxXI
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pdfs of the envelope of the noise and the signal
:pulse noise
47 Dr. Uri Mahlab
:The probability of error is given by
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2
2exp
)(
ionapproximattheUsing
22
)(exp
2
1
and
8exp
2exp
where
2
1
2
1
)1b|error(2
1)0b|error(
2
1
2
2
00
2
0
1
2
0
2
0
2
0
0
10
kk
x
x
xQ
N
AQdr
N
Ar
N
p
N
Adr
N
r
N
rp
pp
ppp
A
e
A
e
ee
e
:The probability of error is given by
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0
2
0
2
0
2
2
0
0
2
2
01
1
Aif8
exp2
1
8exp
2
41
2
1
Hence,
8exp
24
toreducecanwex,largefor
NN
A
N
A
A
Np
NA
ANp
p
e
e
e
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BINERY PSK SIGNALING
SCHEMES:The waveforms are *
0bforcos)(
1bforcos)(
k2
k1
tAts
tAts
c
c
:The binary PSK waveform Z(t) can be described by *
)cos)(()( tAtDtZ c
.D(t) - random binary waveform *
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:The power spectral density of PSK signal is
b
bD
cDcDZ
TffTfG
Where
ffGffGA
fG
22
2
2
sin)(
,
)]()([4
)(
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Coherent PSK:The signal components of the receiver output are
b
b
b
b
kT
Tk
bb
kT
Tk
bb
TAdttststskTs
TAdttststskTs
)1(
212202
)1(
212101
)]()()[()(
)]()()[()(
52 Dr. Uri Mahlab
:The probability of error is given by
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:The probability of error is given by
bav
av
av
be
T
bc
e
TA
E
A
E
s
TAQp
TAdttA
QP
b
2
and
2s
arescheme
PSKfor thebitperenergysignal
theendpowersignalaverageThe
or
4)cos2(
2
where
2
2
2
av
2
0
222
max
max
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av
bave
E
Q
Tsp
2
2
:errorofyprobabilittheexpresscanwe
54 Dr. Uri Mahlab
DIFFERENTIALLY COHERENT *
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DELAY
LOGIC
NETWORK
LEVEL
SHIFT
bT
BINERY
SEQUENCE
1oro
dk
1kd
1
tA ccos
tA Ccos
Z(t)
DIFFERENTIALLY COHERENT
:PSK
DPSK modulator
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DPSK demodulator
Filter to
limit noise
power
Delay
Lowpass
filter orintegrator
Threshold
device
(A/D)
Z(t)
)(tn
bT
kb
bkTatsample
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Differential encoding & decoding
Input
Seque-nce
1 1 0 1 0 0 0 1 1
Encodedsequence 1 1 1 0 0 1 0 1 1 1
Transmit
Phase 0 0 0 pi pi 0 pi 0 0 0
PhaseCompari-son
output+ + - + - - - + +
Output
Bit
sequence1 1 0 1 0 0 0 1 1
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* BINARY FSK SIGNALING
SCHEMES ::The waveforms of FSK signaling
1bfor)cos()(
0bfor)cos()(
k2
k1
ttAtS
ttAtS
dC
dc
:Mathematically it can be represented as
')'(cos)( dttDtAtZ dc
0bfor1
1bfor1)(
k
ktD
58 Dr. Uri Mahlab
P t l d it f FSK i l
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Power spectral density of FSK signals
Power spectral density of a binary FSK signal
with bd rf 2
59
2
2
ee
dd
wf
wf
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Coherent FSK:The local carrier signal required is
)cos()cos()()( 12 ttAttAtsts dcdc
The input to the A/D converter at sampling timewhere)(or)(is 0201 bbb kTskTskTt
b
b
T
b
T
b
dttststskTs
dttststskTs
0
12101
0
12202
)]()()[()(
)]()()[()(
60 Dr. Uri Mahlab
Th b bilit f f th l ti i i
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The probability of error for the correlation receiver is
:given by
)cos()(
and)cos()(when
)]()([2
where
2
1
2
0
2
12
2
max
max
ttAts
ttAts
dttsts
QP
dc
dc
T
e
b
61 Dr. Uri Mahlab
.Which are usually encountered in practical system
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y p y
:We now have
bd
bdb
TTTA
22sin12
22
max
62dbc wTw cw,1
:When
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Noncoherent FSK
0r,2
exp)(
and
0r,2
exp)(
:isfilterbottomtheof)(Renvelopetheofpdftheinterval,
signalingkththeduringmittedbeen transhas)cos()(thatAssuming
2
0
2
2
0
22|
1
0
22
1
0
10
0
11)(|
1
1
12
11
N
r
N
rrf
nAr
NArI
Nrrf
kT
tAts
sR
tsR
b
dc
63 Dr. Uri Mahlab
N h d d l t f bi FSK
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Noncoharenr demodulator of binary FSK
ENVELOPE
DETECTOR
ENVELOPE
DETECTOR
THRESHOLD
DEVICE
(A/D)
dc ff
filter
Bandpass
dc ff
filter
bandpass
+
-
)(2 bkTR
)(1 bkTR
0*0 T
Z(t)+n(t)
0
2
4exp
2
1
N
APe
64 Dr. Uri Mahlab
P b bilit f f bi di it l d l ti *
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Probability of error for binary digital modulation *
:schemes
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M-ARY SIGNALING
SCHEMESARY coherent PSK-:MThe M possible signalsthat would be transmitted
:during each signaling interval of duration Ts are
sTt0,1,...1,0,2
cos)(
Mk
M
ktAtS ck
:The digital M-ary PSK waveform can be represented
k
kcs tkTtgAtZ )cos()()(
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k k
skcskc kTtgtAkTtgtAtZ )()(sinsin)()(coscos)(
:In four-phase PSK (QPSK), the waveform are
S
c
c
c
c
Tt
tAtS
tAtS
tAtS
tAtS
0allfor
sin)(
cos)(
sin)(
cos)(
4
3
2
1
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If th t S th t itt d i l
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If we assume that S 1 was the transmitted signal
:during the signaling interval (0,Ts),then we have
0
2
0
01
4cos2
)4
cos()cos()(
LTA
dttAtATS
s
T
ccs
s
0
2
0
02
4cos
2
A
4cos)cos()(
LT
dttAtATS
s
T
ccs
s
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QPSK i h
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Z(t)
)(tn
)45cos( tA c
)45cos( tA c
ST
0
ST
0
)(01 SkTV
)(02 SkTV
QPSK receiver scheme
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:The outputs of the correlators at time t=TS are
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:The outputs of the correlators at time t TS are
S
s
T
cs
T
cs
ss
sss
sss
dttAtnTn
dttAtnTn
TnTn
TnTSTV
TnTSTV
0
0
02
0
0
01
0201
020202
010101
)45cos()()(
)45cos()()(
bydefinedvariablesrandomGaussianmeanzeroare)(&)(where
)()()(
)()()(
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Probability of error of
QPSK:
2
2
0
0
002
0011
2NLQ
))((
))((
ecs
s
sec
PTAQ
LTnP
LTnPP
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correctlyreceivedissignaledtransmitty that theprobabilitThe-Pc
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sin2
4Mfor
2221
:issystemfor the
)1)(1(
ygyp
22
2
1
21
M
TAQP
TAQPPP
P
PPP
se
s
ecce
e
ececc
c
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Phasor diagram for M-ary PSK ; M=8
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Phasor diagram for M-ary PSK ; M=8
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The average power requirement of a binary PSK
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The average power requirement of a binary PSK
:scheme are given by
sin
1)()(
Z&smallveryisIf
sin
1
Z)(
)(
2
21
22
2
2
1
M
SS
ZP
M
Z
S
S
bav
Mav
e
bav
Mav
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* COMPARISION OF POWER-BANDWIDTH
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* COMPARISION OF POWER-BANDWIDTH
:FOR M-ARY PSK4
10
eP
Value
of M bM
Bandwidth
Bandwidth
)(
)(
bav
mav
S
S
)(
)(
4
8
16
32
0.5
0.333
0.25
0.2
0.34 dB
3.91 dB
8.52 dB
13.52 dB
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* M ary for four phase
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* M-ary for four-phase
Differential PSK:RECEIVER FOR FOUR PHASE DIFFERENTIAL PSK
Integrate
and dump
filter
STDelay
ST
Delay
shiftphase
090
Integrate
and dump
filter
)(01 tV
)(02 tV
)(tn
Z(t)
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:The probability of error in M-ary differential PS
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:The probability of error in M-ary differential PS
M
TAQP Se2
sin22 22
:The differential PSK waveform is
)cos()()( kk
cS tkTtgAtZ
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:Transmitter for differential PSK*
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:Transmitter for differential PSK*
Serial to
parallel
converter
Diff
phase
mod.
Envelope
modulatorBPF
(Z(t
3
4
2400br
Data
Binary
Clock
signal
2400 Hz
4
1200
M
rsHzfc 1800
600 Hz
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* M Wid b d FSK
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* M-ary Wideband FSK
Schemas:Let us consider an FSK scheme witch have the: following properties
ST
0
2
s
FOR0
FOR2)()(
elsewhere0Tt0cos)(
ji
jiTAtStS
and
tAtS
S
ji
ii
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:Orthogonal Wideband FSK receiver
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g
MAXIMUM
SELECTORST
0
ST
0
ST
0
Z(t)
)(tn
noise
gausian
)(1 tS
)(2 tS
)(tSM
.
.
.
.
)(1 tY
)(2 tY
)(tYM
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:The filter outputs are
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p
componentnoiseThe-)(
outputfilterth-jtheofcomponentsignalThe-)(
where
)()(
)()()()(
M1,2,....,j,)]()()[()(
0
0
0 0
1
0
1
S
sj
sj
sjsj
T T
jj
T
jsj
Tn
TS
TnTS
dttntSdttStS
dttStntSTY
S S
s
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:N0 is given by
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4
20
sTAN
:The probability of correct decoding as
-
11|andsent
112
1113121
)(}|,...,{
}|,...,,{
11
1
11dyyfyYyYP
sentSYYYYYYpP
SY
s
yYM
Mc
:In the preceding step we made use of the identity
dyyfyYyXPYXP Y )()|()(
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The joint pdf of Y2 Y3 YM *
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The joint pdf of Y2 ,Y3 ,,YM
:is given by
M
i
iYMyYSYY yfyyf iM2
2:|...2 )(),...,(111
84 Dr. Uri Mahlab
ii
iY yy
yf ,exp1
)(2
where
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s
s
SY
Y
SY
My
Y
SY
y y M
iiiYc
iiY
TA
S
TA
N
yN
Sy
Nyf
yN
y
Nyf
dyyfdyyf
dyyfdyyfP
yNN
yf
i
i
2
22
and
,2
)(exp
2
1)(
,2
exp2
1)(
where
)()(
)()(...
and
,2
p2
)(
2
01
2
0
1
0
2
011
0
1|
0
2
0
-
11|
1
11|2
1
00
11
11
1
11
1 1
85 Dr. Uri Mahlab
Probability of error for M-ary orthogonal *
i i
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: signaling scheme
86 Dr. Uri Mahlab
The probability that the receiver incorrectly *
d d d h i i i l S ( ) i
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decoded the incoming signal S1(t) is
Pe1 = 1-Pe1The probability that the receiver makes *
an error in decoding is
Pe = Pe1
assume that , and
can see that increasing values of M lead to smaller poweruirements and also to more complex transmitting
eiving equipment.
2M )inteegrpositivea(log 2 ssb rMrr
87 Dr. Uri Mahlab
In the limiting case as M the probability of error Pe satisfies
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g p y
7.0r/Sif0
7.0/Sif1
bav
av
b
e
r
P
The maximum errorless rb at W data can be transmitted
using an M- ary orthogonal FSK signaling scheme
e
SS
ravav
b 2log7.0