Day 40 Ppt Batfink Momentum
Transcript of Day 40 Ppt Batfink Momentum
#1 All students must perform all of the work of the activity in their science journals even though you are working in your lab group.
#2 When you are sure of your answer, transfer the information onto individual mini whiteboards.
#3 The whiteboard work is to remain on the white board until it is approved.
The mad scientist, Hugo A-go-go has developed a way to disrupt the electrical service to Chicago.
The mass of the Eastbound (traveling to your right) CTA is 40,000 kg while the mass of the Westbound CTA is 30,000kg.
The Eastbound transit is traveling at 20 m/s and the Westbound transit is traveling at 25 m/s.
There are two separate, stationary cars also on the same track. They are 10,000 kg each.
P = mvKnown Want
m = 40,000 kg P (momentum)v = 20 m/s
P = mvP = (40,000 kg )(20 m/s) P = 800,000 (kg)( m/s)
P = mvKnown Want
m = 30,000 kg P (momentum)v = 25 m/s
P = mvP = (30,000 kg )(25 m/s) P = 750,000 (kg)( m/s)
P = mvKnown Want
m = 10,000 kg P (momentum)
v = 0 m/s
P = mv
P = (10,000 kg )(0 m/s)
P = 0 (kg)( m/s)
The Eastbound train collides with one of the stationary transits. Draw a momentum vector diagram that represents the above scenario just before the collision.
The Eastbound train collides with one of the stationary transits. Draw a momentum vector diagram that represents the above scenario just after the collision.
The Eastbound train collides with one of the stationary transits. Sticking together, they continue to roll along the track. What is their velocity after the collision?
Net Momentum before = Net Momentum after
Known Wantme = 40,000 kg P beforeve = 20 m/s v afterms = 10,000 kgvs = 0 m/s
Pnet = (mv)net
P = me ve + ms vs
P = (40,000 kg )(20 m/s) + (10,000 kg )(0 m/s) P = 800,000 (kg)( m/s)
v = P/mv = 800,000 (kg)( m/s) / (40,000 kg ) + (10,000 kg )v = 16 m/s E
The Westbound train collides with one of the stationary transits. Sticking together, they continue to roll along the track. What is their velocity after the collision?
Net Momentum before = Net Momentum after
Known Want
mw = 30,000 kg P beforevw = 25m/s v afterms = 10,000 kgvs = 0 m/s
Pnet = (mv)net
P = mw vw + ms vs
P = (30,000 kg )(25 m/s) + (10,000 kg )(0 m/s) P = 750,000 (kg)( m/s)
v = P/m
v = 750,000 (kg)( m/s) / (30,000 kg ) + (10,000 kg )v = 18.75 m/s W
The Westbound train, after the initial impact with the stationary transit collides with the Eastbound train also after its initial impact with one of the stationary transits. Calculate the velocity after the crash between the two trains if they stuck together.
Net Momentum before = Net Momentum after
Known WantPw = 750,000 (kg)( m/s) Pnet beforePe = -800,000 (kg)( m/s) v after
Pnet = Pe - Pw
Pnet = 800,000 (kg)( m/s) - 750,000 (kg)( m/s) Pnet = 50,000 (kg)( m/s) v = P/mv = 50,000 (kg)( m/s) / (40,000 kg ) + (50,000 kg )v = .56 m/s E
The Battalac, which has a mass of 1500 kg is occupied by batfink, 50 kg, and Karate, 150kg and is traveling at 50 m/s when it is forced off the road and down a 50 meter embankment.
Known Want
mB = 1,500 kg v
vohB = 50 m/s
mb = 50 kg
mk = 150 kg
vf2 = vo
2 + 2a∆y
vf2 = 0 m/s + 2(9.8 m/s2)(50m)
v = 31.3 m/s
y
50 m/s
31.3 m/s x
a2 + b2 = c2
502 + 31.32 = 58.99 m/s
or
TAN -1= 31.3/50
= 32.05*
Vf = Vx/COS 32.05*
= 58.99 m/s
or
Vf = Vy/SIN 32.05*
= 58.98 m/s
Known Want
mB = 1,500 kg P
vfB = 58.99 m/s
mb = 50 kg
mk = 150 kg
P = mv
P = (1700 kg)(58.99 m/s)
P = 100,283 (kg)(m/s)