Lifting Lug Calculation 1Horizontal liftingProject Name : NCPOCProject No : 836Tag Number : Bio TankDate : 2/6/2013

Material of Lifting/Tailing Lug M = SA 516 70Minimum specified yield strength y = 262 N/mm2

Thickness of Lug T = 32 mmWidth Lug B = 120 mmLug outer radius R = 60 mmDiameter lug hole D = 40 mmHeight from lug base to hole center H = 139 mmEffective moment arm height h = 50 mmFillet weld leg FW = 15 mm

Partial Groove weld GW = 0 mmCritical weld size CW= 15.00 mmJoint efficiency E = 1Cheek Plate Thickness T2 = 0 mmCheek Plate OD D2 = 0 mm

Erection weight, We = 19000 kgImpact factor, C = 4.00Design weight, Wd = C*We Wd = 76000 kgNumber of lugs, N = 4Design weight per lug, W = 19000 kgLifting angle, ß = 60 deg.

Tension in sling, Ft = W / Sin ß = 215159 NForce, Fx = Ft*Cos ß = 107579 N

Fy = Ft*Sin ß = 186333 NFz = 0.05*Ft = 10758 N

Build up of impact factor 4.0Factor of safety = 360/40 spread for sling length = 1.2Allowance for overweight = 1.1 (10%)Sump of impact factor = 3.96

≈ 4

2Stresses on lug Calculations

1) Shear Stress at lug eyeSse = Ft/((2*(R-D/2)*T)+(2*(D2-D)*T2))= 84.05 N/mm2 < 104.80 N/mm2

Stress result is PASS 0.4*Sy

2) Tensile Stress at Lug eyeSte = Fy/((2*(R-D/2)*T)+(2*(D2-D)*T2))= 72.79 < 157.20 N/mm2

Stress result is PASS 0.6*Sy

Lug Section Modulus (Out Plane)

(B^2 x T)/6 Zo = 76800 mm3

3) Bending Stress OutplaneSbo = Fx x (h)/Zo= 70.04 < 157.20 N/mm2

Stress result is PASS 0.6*Sy

Lug Section Modulus (Out Plane)

(T^2 x B)/6 Zi = 20480 mm3

4) Bending Stress InplaneSbo = Fz x h/Zi= 26.26 < 157.20 N/mm2

Stress result is PASS 0.6*Sy

5) Tensile Stress at lug baseStb = Fs / B*T= 56.03 < 157.20 N/mm2

Stress result is PASS 0.6*Sy

6) Shear Stress at lug baseSsb = Fx / B*T= 28.02 < 104.80 N/mm2

Stress result is PASS 0.4*Sy

7) Combined Stress

= 80.47 < 172.92 N/mm2Stress result is PASS 0.66*Sy

3Stresses on weld calculations

1) Bending from force FxZw= CW*B^2/3= 72000 mm3Aw= (2*CW*B)+(4*CW*(H-h))= 8940.00 mm2

Swbx = (Fx*h) / Zw = 74.71 < 157.20 N/mm2

Stress result is PASS E*0.6*Sy

2) Shear from force FxSwsx = (Fx / Aw) / E= 12.03 < 104.80 N/mm2

Stress result is PASS E*0.4*Sy

3) Combined Shear and Bending from force FxSwx = Sqrt (Swbx^2 + Swsx^2)= 75.67 < 172.92 N/mm2

Stress result is PASS E*0.66*Sy

4) Shear from force Fy

Swsy = (Fy/Aw)= 20.84 < 104.80 N/mm2

Stress result is PASS E*0.4*Sy

5) Combined stress due to Fx and Fy

Swxy = SQRT[(Swsx+Swsy)^2+Swbx^2]= 78.49 < 172.92 N/mm2

Stress result is PASS E*0.66*Sy

Lifting Lug Calculation on skid baseVertical liftingProject Name : HY7-1/7-IN(CX-N) OFFSHORE GAS FIELD DEVELOPMENTProject No : 849Tag Number : MEG SURGE DRUM SKIDDate : 5/29/2013

Material of Lifting/Tailing Lug M = SS 400Minimum specified yield strength y = 248 N/mm2

Thickness of Lug T = 35 mmWidth Lug B = 200 mmLug outer radius R = 68 mmDiameter lug hole D = 45 mmHeight from lug base to hole center H = 387 mmEffective moment arm height h = 151 mmFillet weld leg FW = 10 mm

Partial Groove weld GW = 10 mmCritical weld size CW= 17.07 mmJoint efficiency E = 1Cheek Plate Thickness T2 = 0 mmCheek Plate OD D2 = 0 mm

Erection weight, We = 23000 kgImpact factor, C = 3.00Design weight, Wd = C*We Wd = 69000 kgNumber of lugs, N = 4Design weight per lug, W = 17250 kgLifting angle, ß = 60 deg.

Tension in sling, Ft = W / Sin ß = 195342 NForce, Fx = Ft*Cos ß = 97671 N

Fy = Ft*Sin ß = 169171 NFz = 0.05*Ft = 9767 N

Stresses on lug Calculations

1) Shear Stress at lug eyeSse = Ft/((2*(R-D/2)*T)+(2*(D2-D)*T2))= 61.33 N/mm2 < 99.20 N/mm2

Stress result is PASS 0.4*Sy

2) Tensile Stress at Lug eyeSte = Fy/((2*(R-D/2)*T)+(2*(D2-D)*T2))= 53.11 < 148.80 N/mm2

Stress result is PASS 0.6*Sy

Lug Section Modulus (Out Plane)

(B^2 x T)/6 Zo = 233333.333 mm3

3) Bending Stress OutplaneSbo = Fx x (h)/Zo= 63.21 < 148.80 N/mm2

Stress result is PASS 0.6*Sy

Lug Section Modulus (Out Plane)

(T^2 x B)/6 Zi = 40833.3333 mm3

4) Bending Stress InplaneSbo = Fz x h/Zi= 36.12 < 148.80 N/mm2

Stress result is PASS 0.6*Sy

5) Tensile Stress at lug baseStb = Fs / B*T= 27.91 < 148.80 N/mm2

Stress result is PASS 0.6*Sy

6) Shear Stress at lug baseSsb = Fx / B*T= 13.95 < 99.20 N/mm2

Stress result is PASS 0.4*Sy

7) Combined Stress

= 59.95 < 163.68 N/mm2Stress result is PASS 0.66*Sy

Stresses on weld calculations

1) Bending from force FxZw= CW*B^2/3= 227614.24 mm3Aw= (2*CW*B)+(4*CW*(H-h))= 22943.52 mm2

Swbx = (Fx*h) / Zw = 64.80 < 148.80 N/mm2

Stress result is PASS E*0.6*Sy

2) Shear from force FxSwsx = (Fx / Aw) / E= 4.26 < 99.20 N/mm2

Stress result is PASS E*0.4*Sy

3) Combined Shear and Bending from force FxSwx = Sqrt (Swbx^2 + Swsx^2)= 64.93 < 163.68 N/mm2

Stress result is PASS E*0.66*Sy

4) Shear from force Fy

Swsy = (Fy/Aw)= 7.37 < 99.20 N/mm2

Stress result is PASS E*0.4*Sy

5) Combined stress due to Fx and Fy

Swxy = SQRT[(Swsx+Swsy)^2+Swbx^2]= 65.35 < 163.68 N/mm2

Stress result is PASS E*0.66*Sy

Lifting Lug Calculation (Typical for all 3 units STHE)Vertical liftingProject Name : RECOVERY COMPRESSOR PACKAGEProject No : 875Tag Number : E-2530 1ST STAGE DISCHARGE COOLERDate : 17-Jun-15

Material of Lifting/Tailing Lug M = SS 400Minimum specified yield strength y = 248 N/mm2

Thickness of Lug T = 20 mmWidth Lug B = 120 mmLug outer radius R = 32 mmDiameter lug hole D = 25 mmHeight from lug base to hole center H = 100 mmEffective moment arm height h = 100 mmFillet weld leg FW = 10 mm

Partial Groove weld GW = 10 mmCritical weld size CW= 17.07 mmJoint efficiency E = 1Cheek Plate Thickness T2 = 0 mmCheek Plate OD D2 = 0 mm

Erection weight, We = 4300 kgImpact factor, C = 3.00Design weight, Wd = C*We Wd = 12900 kgNumber of lugs, N = 2Design weight per lug, W = 6450 kgLifting angle, ß = 60 deg.

Tension in sling, Ft = W / Sin ß = 73041 NForce, Fx = Ft*Cos ß = 36520 N

Fy = Ft*Sin ß = 63255 NFz = 0.05*Ft = 3652 N

Stresses on lug Calculations

1) Shear Stress at lug eyeSse = Ft/((2*(R-D/2)*T)+(2*(D2-D)*T2))= 93.64 N/mm2 < 99.20 N/mm2

Stress result is PASS 0.4*Sy

2) Tensile Stress at Lug eyeSte = Fy/((2*(R-D/2)*T)+(2*(D2-D)*T2))= 81.10 < 148.80 N/mm2

Stress result is PASS 0.6*Sy

Lug Section Modulus (Out Plane)

(B^2 x T)/6 Zo = 48000 mm3

3) Bending Stress OutplaneSbo = Fx x (h)/Zo= 76.08 < 148.80 N/mm2

Stress result is PASS 0.6*Sy

Lug Section Modulus (Out Plane)

(T^2 x B)/6 Zi = 8000 mm3

4) Bending Stress InplaneSbo = Fz x h/Zi= 45.65 < 148.80 N/mm2

Stress result is PASS 0.6*Sy

5) Tensile Stress at lug baseStb = Fs / B*T= 30.43 < 148.80 N/mm2

Stress result is PASS 0.6*Sy

6) Shear Stress at lug baseSsb = Fx / B*T= 15.22 < 99.20 N/mm2

Stress result is PASS 0.4*Sy

7) Combined Stress

= 71.37 < 163.68 N/mm2Stress result is PASS 0.66*Sy

Stresses on weld calculations

1) Bending from force FxZw= CW*B^2/3= 81941.125 mm3Aw= (2*CW*B)+(4*CW*(H-h))= 4097.06 mm2

Swbx = (Fx*h) / Zw = 44.57 < 148.80 N/mm2

Stress result is PASS E*0.6*Sy

2) Shear from force FxSwsx = (Fx / Aw) / E= 8.91 < 99.20 N/mm2

Stress result is PASS E*0.4*Sy

3) Combined Shear and Bending from force FxSwx = Sqrt (Swbx^2 + Swsx^2)= 45.45 < 163.68 N/mm2

Stress result is PASS E*0.66*Sy

4) Shear from force Fy

Swsy = (Fy/Aw)= 15.44 < 99.20 N/mm2

Stress result is PASS E*0.4*Sy

5) Combined stress due to Fx and Fy

Swxy = SQRT[(Swsx+Swsy)^2+Swbx^2]= 48.00 < 163.68 N/mm2

Stress result is PASS E*0.66*Sy

Lifting Lug Calculation 7Tailing LugProject Name : NCPOCProject No : 836Tag Number : Bio TankDate : 2/6/2013

Material of Lifting/Tailing Lug M = SA 516 70Minimum specified yield strength y = 262 N/mm2

Thickness of Lug T = 32 mmWidth Lug B = 120 mmLug outer radius R = 60 mmDiameter lug hole D = 40 mmHeight from lug base to hole center H = 139 mmEffective moment arm height h = 50 mmFillet weld leg FW = 15 mm

Partial Groove weld GW = 0 mmCritical weld size CW= 15.00 mmJoint efficiency E = 1Cheek Plate Thickness T2 = 0 mmCheek Plate OD D2 = 0 mm

Erection weight, We = 19000 kgImpact factor, C = 2.00Design weight, Wd = C*We Wd = 38000 kgNumber of lugs, N = 4Design weight per lug, W = 9500 kgLifting angle, ß = 5 deg.

Tension in sling, Ft = W / Cos ß = 93522 NForce, Fx = W = 93167 N

Fy = Ft*Sin ß = 8151 NFz = 0.05*Ft = 4676 N

Build up of impact factor 2.0Factor of safety = 1.560/40 spread for sling length = 1.2Allowance for overweight = 1.1 (10%)Sump of impact factor = 1.98

≈ 2

8Stresses on lug Calculations

1) Shear Stress at lug eyeSse = Ft/((2*(R-D/2)*T)+(2*(D2-D)*T2))= 36.53 N/mm2 < 104.80 N/mm2

Stress result is PASS 0.4*Sy

2) Tensile Stress at Lug eyeSte = Fx/((2*(R-D/2)*T)+(2*(D2-D)*T2))= 36.39 < 157.20 N/mm2

Stress result is PASS 0.6*Sy

Lug Section Modulus (Out Plane)

(B^2 x T)/6 Zo = 76800 mm3

3) Bending Stress OutplaneSbo = Fx x (h)/Zo= 60.66 < 157.20 N/mm2

Stress result is PASS 0.6*Sy

Lug Section Modulus (Out Plane)

(T^2 x B)/6 Zi = 20480 mm3

4) Bending Stress InplaneSbo = Fz x h/Zi= 11.42 < 157.20 N/mm2

Stress result is PASS 0.6*Sy

5) Tensile Stress at lug baseStb = Ft / B*T= 24.35 < 157.20 N/mm2

Stress result is PASS 0.6*Sy

6) Shear Stress at lug baseSsb = Fx / B*T= 24.26 < 104.80 N/mm2

Stress result is PASS 0.4*Sy

7) Combined Stress

= 67.53 < 172.92 N/mm2Stress result is PASS 0.66*Sy

9Stresses on weld calculations

1) Bending from force FxZw= CW*B^2/3= 72000 mm3Aw= (2*CW*B)+(4*CW*(H-h))= 8940.00 mm2

Swbx = (Fx*h) / Zw = 64.70 < 157.20 N/mm2

Stress result is PASS E*0.6*Sy

2) Shear from force FxSwsx = (Fx / Aw) / E= 10.42 < 104.80 N/mm2

Stress result is PASS E*0.4*Sy

3) Combined Shear and Bending from force FxSwx = Sqrt (Swbx^2 + Swsx^2)= 65.53 < 172.92 N/mm2

Stress result is PASS E*0.66*Sy

4) Shear from force Fy

Swsy = (Fy/Aw)= 0.91 < 104.80 N/mm2

Stress result is PASS E*0.4*Sy

5) Combined stress due to Fx and Fy

Swxy = SQRT[(Swsx+Swsy)^2+Swbx^2]= 65.54 < 172.92 N/mm2

Stress result is PASS E*0.66*Sy

Lifting Lug Calculation 10Tailing Lug on Vertical ConditionProject Name : NCPOCProject No : 836Tag Number : Bio TankDate : 2/6/2013

Material of Lifting/Tailing Lug M = SA 516 70Minimum specified yield strength y = 262 N/mm2

Thickness of Lug T = 32 mmWidth Lug B = 120 mmLug outer radius R = 60 mmDiameter lug hole D = 40 mmHeight from lug base to hole center H = 139 mmEffective moment arm height h = 50 mmFillet weld leg FW = 15 mm

Partial Groove weld GW = 0 mmCritical weld size CW= 15.00 mmJoint efficiency E = 1Cheek Plate Thickness T2 = 0 mmCheek Plate OD D2 = 0 mm

Gusset plate thickness Pt= 20Gusset plate quantity Pn= 4Gusset plate width Pl= 72Gusset Plate Height Ph= 139Gusset Plate weld Size Pw= 10

Erection weight, We = 19000 kgImpact factor, C = 2.00Design weight, Wd = C*We Wd = 38000 kgNumber of lugs, N = 2Design weight per lug, W = 19000 kgLifting angle, ß = 60 deg.

Tension in sling, Ft = W / Sin ß = 215159 NForce, Fx = Ft*Cos ß = 107579 N

Fy = Ft*Sin ß = 186333 NFz = 0.05*Ft = 10758 N

Build up of impact factor 2.0Factor of safety = 1.560/40 spread for sling length = 1.2Allowance for overweight = 1.1 (10%)Sump of impact factor = 1.98

≈ 2

Stresses on lug Calculations 11

1) Shear Stress at lug eyeSse = Ft/((2*(R-D/2)*T)+(2*(D2-D)*T2))= 84.05 < 104.80 N/mm2

Stress result is PASS 0.4*Sy

2) Tensile Stress at Lug eyeSte = Fy/((2*(R-D/2)*T)+(2*(D2-D)*T2))= 72.79 < 157.20 N/mm2

Stress result is PASS 0.6*Sy

Lug Section Modulus (Out Plane)

(B^2 x T)/6 Zo = 76800 mm3

3) Bending Stress OutplaneSbo = Fx x (h)/Zo= 70.04 < 157.20 N/mm2

Stress result is PASS 0.6*Sy

Lug Section Modulus (Out Plane)

(T^2 x B)/6 Zi = 20480 mm3

4) Bending Stress InplaneSbo = Fz x h/Zi= 26.26 < 157.20 N/mm2

Stress result is PASS 0.6*Sy

5) Tensile Stress at lug baseStb = Fs / B*T= 56.03 < 157.20 N/mm2

Stress result is PASS 0.6*Sy

6) Shear Stress at lug baseSsb = Fx / B*T= 28.02 < 104.80 N/mm2

Stress result is PASS 0.4*Sy

7) Combined Stress

= 80.47 < 172.92 N/mm2Stress result is PASS 0.66*Sy

12Stresses on weld calculations

1) Bending from force FxZw= CW*B^2/3= 72000 mm3Aw= (2*CW*B)+(4*CW*(H-h))= 8940.00 mm2

Swbx = (Fx*h) / Zw = 74.71 < 157.20 N/mm2

Stress result is PASS E*0.6*Sy

2) Shear from force FxSwsx = (Fx / Aw) / E= 12.03 < 104.80 N/mm2

Stress result is PASS E*0.4*Sy

3) Combined Shear and Bending from force FxSwx = Sqrt (Swbx^2 + Swsx^2)= 75.67 < 172.92 N/mm2

Stress result is PASS E*0.66*Sy

4) Shear from force Fy

Swsy = (Fy/Aw)= 20.84 < 104.80 N/mm2

Stress result is PASS E*0.4*Sy

5) Combined stress due to Fx and Fy

Swxy = SQRT[(Swsx+Swsy)^2+Swbx^2]= 78.49 < 172.92 N/mm2

Stress result is PASS E*0.66*Sy

Gusset Plate calculation 13

1) Tensile stress from force Fy

Spy=Fy/(PnxPlxPt)= 32.35 < 157.20 N/mm2

Stress result is PASS 0.6*Sy

2) Weld stress from force Fy

= 45.76 < 157.20 N/mm2Stress result is PASS 0.6*Sy

3) Uplift and down stress due to moment

Fld, Uplift and down force of lug 251000 N/mm2

Spy=Fy/(Pn/2xPlxPt)= 87.15 < 157.20 N/mm2

Stress result is PASS 0.6*Sy

4) Weld stress from force Fld

= 123.27 < 157.20 N/mm2Stress result is PASS 0.6*Sy

Wpy=Fy/(2x0.707xPwxPnxPl）

Wpy=Fld/(0.707xPwxPnxPl）

8.1 SPREADER PIPE DESIGN

PROPERTIES OF SPREADER

Type of spreader : PipeSize : 8" Sch.80Pipe material : A 333 6Minimum specified yield strength, Fy = 241.32 N/mm2Modulus of elasticity, E = 200000 N/mm2Pipe OD, D = 219.10 mmPipe thickness, t = 12.70 mmPipe ID, d = 193.70 mmCross sectional area, A = 8234.99 mm2Moment of inertia, I = 4.39E+07 mm4Setion modulus, Z = 4.01E+05 mm3Radius of gyration, r = 73.05 mmLength of pipe, l = 2.736 mmEffective end factor, K = 1.0Slenderness ratio K*l/r = 0.04

Allowable compressive stress -API RP2A (for 0 < Kl/r < Cc)

[1 - (K*l/r)²/(2*Cc²)]*FyFc = ------------------------------------ 144.78 N/mm2

5/3+3(K*l/r)/(8*Cc)-(K*l/r)^3/(8*Cc^3)

where, Cc = \/ (2*pi^2*E/Fy ) = 127.90

COMPRESSIVE STRESS IN PIPE

Sling angle to horizontal, ß = 60 Deg.Actual Structural Weight : 19000 kgDesign Structural Weight : 20000 kgDesign Lifting Factor : 4.00Design sling force, Fs = 452966 NCompressive force on pipe, Fp = Fs*Cos ß = 226483 NMoment, Me = 40665023 NmmCompressive stress due to Fp, Sp = Fp / A = 27.50 N/mm2Bending stress due to Me, Sb = Me / Z = 101.38 N/mm2

Stress interaction ratio,Sp/Fc +Cm*Sb/[(1-Sp/Fe')*0.6*Fy] = 0.890 < 1.00OK!

where, = 12*pi^2*E/(23*(K*l/r)^2) = 734087295 N/mm2Cm = 1

Welding check on Davit Arm Support Plate(V-T2421 HP SEP HYDROCYCLONE)

Dimension of support plate

Material of support plate M = SS 400 Material of Lifting/Tailing Lug Minimum specified yield strength y = 248 N/mm2 Minimum specified yield strengthWeight on Davit arm support W= 1085 kgForce on support lug Fs= 10643.85 N Wx9.81Width 63 mmLength 345 mmThickness 25 mmWeld size groove 12.5 mmWeld size fillet 12.5 mmArea of weldment 12075 mm2Factor of weld 0.7

Shear Stress Act on Davit arm support plate1.26 N/mm2 (Mpa,145 PsiG)

Shear allowable stress= 0.4 x y 99.2 N/mm2

Minimum specified yield strength

Support plate & Welding check on Davit Arm Support Plate(V-T2421 HP SEP HYDROCYCLONE)Blind Flange LocationDimension of support plate

Material of support plate M = SS 400 Material of support plateMinimum specified yield strength y = 248 N/mm2 Minimum specified yield strengthWeight on Davit arm support W= 1085 kgForce on support lug Fx= 10643.85 N Wx9.81Width 63 mmLength L= 345 mmThickness T= 25 mmWeld size groove Wg= 12.5 mmWeld size fillet Wf= 12.5 mmFactor of weld F= 0.7

Shear Strength Check On Support Plate 25mm ThicknessArea of plate on shear force = =L x T

8625 mm2Shear Stress Act on Davit arm support plate

Fs = 1.23 N/mm2 (Mpa)Shear allowable stress

= 0.4 x y = 99.2 N/mm2

Shear stress is lower than the allowable stress.Plate size sufficient for the design

Shear Strength Check On Weld Joint

Area of weld = =L x Weld Size6037.5 mm2

Shear Stress Act on Davit arm support plateFs = 1.76 N/mm2 (Mpa)

Shear allowable stress= 0.4 x y = 99.2 N/mm2

Shear stress is lower than the allowable stress.Weld size sufficient for support plate .

Support plate & Welding check on Davit Arm Support Plate(V-T2421 HP SEP HYDROCYCLONE)Dished Head LocationDimension of support plate

Material of support plate M = SS 400 Material of support plateMinimum specified yield strength y = 248 N/mm2 Minimum specified yield strengthWeight on Davit arm support W= 850 kgForce on support lug Fx= 8338.5 N Wx9.81Width 63 mmLength L= 345 mmThickness T= 25 mmWeld size groove Wg= 12.5 mmWeld size fillet Wf= 12.5 mmFactor of weld F= 0.7

Shear Strength Check On Support Plate 25mm ThicknessArea of plate on shear force = =L x T

8625 mm2Shear Stress Act on Davit arm support plate

Fs = 0.97 N/mm2 (Mpa)Shear allowable stress

= 0.4 x y = 99.2 N/mm2

Shear stress is lower than the allowable stress.Plate size sufficient for the design

Shear Strength Check On Weld Joint

Area of weld = =L x Weld Size6037.5 mm2

Shear Stress Act on Davit arm support plateFs = 1.38 N/mm2 (Mpa)

Shear allowable stress= 0.4 x y = 99.2 N/mm2

Shear stress is lower than the allowable stress.Weld size sufficient for support plate .