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DATA TYPES - C++
DR.M.KARTHIKA, M.C.S. A.,M.PHIL.,PH.D.,Assistant Professor/MCA Department,
N M S S V N CollegeMadurai-19.
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Over view
Basic Program StructureBits/MemoryData TypesType ConversionOperatorsControl StructuresArrays
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Computers are Easy!
"Using a computer is just like riding a bike, except you don't have to wear the tight shorts and funny helmet. A water bottle is also a bad idea. Just about everyone agrees that computing is very simple, or will be in only a few more days.
David Lubar, 1995
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Basic Program Structure
// Program description #include directives int main(){ constant declarations variable declarations executable statements return 0;
}
Do you see a couple or a skull?
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A Data Type
• A data type is– A set of values AND– A set of operations on those values
• A data type is used to– Identify the type of a variable when the variable is declared– Identify the type of the return value of a function– Identify the type of a parameter expected by a function
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Design issues of data types
How is the domain of the values specified? What operations are defined and how are they
specified? What is the syntax of reference to the variables?
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Data Inside the Computer
All data types are transformed into a uniform representation
They are stored in a computer and transformed back to their original form when retrieved.
This universal representation is called a bit.
BIT
Binary Digit
•pattern or a sequence of 0s and 1s.
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Storage of Different Data Types
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Objective of Data Type
• Is to process data• Data is classified into specific types
NumericalAlphabeticalAudioVideo
C++ allows only certain operations to be performed on certain types of dataPrevents inappropriate programming operations
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Data Type:
A set of values together with a set of operations is called a data type.
C++ data types fall into three categories
• Simple Data Type.• Structured Data Type.• Address(Pointers).
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Set of values and operations that can be applied to these values
Example of a data type: IntegerThe values: set of all Integer (whole) numbersThe operations: familiar mathematical and comparison
operators
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Major Classification
User Defined data type Programmer-created data type
Set of acceptable values and operations defined by a programmer using C++ code
Built-in data typeProvided as an integral part of C++
Also known as a primitive type
Requires no external code
Consists of basic numerical types
Majority of operations are symbols (e.g. +,-,*,…)17
Basic Data Types
C++ Data Types
User-defined Type Built-in Type Derived Type
Integral Type Void Floating Type
structureunionclass
enumeration
arrayfunctionpointer
reference
int char float double18
C++ Data TypesC++ Data Types
structured
address
pointer reference
simple
integral enum floating
float double long double
char short int long bool
array struct union class
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C++ Primitive Data TypesC++ Primitive Data Types
Primitive types
integral floating
char short int long bool float double long double
unsigned
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Size Unique representable values
8-bit 256 = 28
16-bit 65 536 = 216
32-bit 4 294 967 296 = 232 (~4 billion)64-bit 18 446 744 073 709 551 616 = 264 (~18 billion billion)
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Data types in C++
Data Type Memory (ByteS) Minimum Value Maximum Value
Bool 1 Logical Value T/F Logical Value T/F
Char 1 -128 127
Unsigned Char 1 0 255
Short 2 -32768 32767
Unsigned Short 2 0 65535
int 2 -32768 32767
unsigned int 2 0 65535
Long 4 -2147483648 2147483647
unsigned long 4 0 4294967295
float 4 10-38 1038
double 8 10-308 10308
long double 10 10-4932 104932
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Simple Data Type
C++ simple data can be classified into three categories
1. Integral, which is a data type that deals with integers, or numbers without a decimal part.
2. Floating-point, which is a data type that deals with decimal numbers.
3. Enumeration type, which is a user-defined data type.
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Integer
An integer type is a number without a fractional part. It is also known as an integral number. C++ supports three different sizes of the integer data type: short int, int and long int.
sizeof(short int)<= sizeof(int)<= sizeof(long int)
Short int
int
long int
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AA numbernumber isis changedchanged toto thethe binarybinary systemsystem beforebefore beingbeing storedstored inin thethe computercomputer memorymemoryHowever,However, therethere areare stillstill twotwo issuesissues thatthat needneed toto bebe handled:handled:1.1. HowHow toto storestore thethe signsign ofof thethe number.number.2.2. HowHow toto showshow thethe decimaldecimal point.point.
STORING OF DATA TYPES
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Integers are whole numbers (numbers without a fractional part). For example, 134 and −125 are integers,
whereas134.23 and −0.235 are not. An integer can be thought of as a number in which the position of the decimal point is fixed: the decimal point is to the right of the least significant (rightmost) bit. For this reason, fixed-point representation is used to store an integer, as shown below.
Storing Integers
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An integer is normally stored in memory using fixed-point representation.
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An unsigned integer is an integer that can never be negative and can take only 0 or positive values. Its range is between 0 and positive infinity. An input device stores an unsigned integer using the following steps: 1. The integer is changed to binary.2. If the number of bits is less than n, 0s are added to the left.
Unsigned Representation
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Example
StoreStore 77 inin anan 8-bit8-bit memorymemory locationlocation usingusing unsignedunsigned representation.representation.SolutionSolutionFirstFirst changechange thethe integerinteger toto binary,binary, (111)(111)22.. AddAdd fivefive 0s0s toto makemake aa totaltotal ofof eighteight bits,bits, (00000111)(00000111)22.. TheThe integerinteger isis storedstored inin thethe memorymemory location.location. NoteNote thatthat thethe subscriptsubscript 22 isis usedused toto emphasizeemphasize thatthat thethe integerinteger isis binary,binary, butbut thethe subscriptsubscript isis notnot storedstored inin thethe computercomputer..
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Example:
StoreStore 258258 inin aa 16-bit16-bit memorymemory location.location.
SolutionSolution
FirstFirst changechange thethe integerinteger toto binarybinary (100000010)(100000010)22..
AddAdd sevenseven 0s0s toto makemake aa totaltotal ofof sixteensixteen bits,bits, (0000000100000010)(0000000100000010)22..
TheThe integerinteger isis storedstored inin thethe memorymemory location.location.
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Sign-and-Magnitude Representation
In this method, the available range for unsigned integers (0 to 2n−1) is divided into two equal sub-ranges.
The first half represents positive integers, the second half, negative integers.
Noted that there are two different representations for zero.
In sign-and-magnitude representation, the leftmost bit defines the sign of the integer. If it is 0, the integer is positive. If it is 1, the integer is negative.
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StoreStore +28+28 inin anan 8-bit8-bit memorymemory locationlocation usingusing sign-and-sign-and-magnitudemagnitude representation.representation.
SolutionSolutionTheThe integerinteger isis changedchanged toto 7-bit7-bit binary.binary. TheThe leftmostleftmost
bitbit isis setset toto 0.0. TheThe 8-bit8-bit numbernumber isis stored.stored.
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StoreStore −28−28 inin anan 8-bit8-bit memorymemory locationlocation usingusing sign-sign-and-magnitudeand-magnitude representation.representation.
SolutionSolutionTheThe integerinteger isis changedchanged toto 7-bit7-bit binary.binary. TheThe leftmostleftmost
bitbit isis setset toto 1.1. TheThe 8-bit8-bit numbernumber isis stored.stored.
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The bool Data Type
The data type bool has two values, true and false. The central purpose of this data type is to manipulate
logical (Boolean) expressions. We call true and false the logical (Boolean) values. In C++, bool, true, and false are reserved words.
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Char Data Type
char is the smallest integral data type. char data type is used to represent characters, that is letters, digits
and special symbols. Each character is enclosed within single quote marks. Some of the
values belonging to char data type are:
'A', 'a', '0', '*', '+', '$', '&‘
Blank space is a character and is written ' ', with a space left between the single quotes.
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The Most Common Character Sets: ASCII (American Standard Code for Information Interchange) and
EBCIDIC. (Extended Binary-Coded Decimal Interchange Code (IBM))
The ASCII character set has 128 values. EBCIDIC has 256 values and is used by IBM.
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ASCII Character Set
Each of the 128 values of the ASCII character set represents a different character. The value 65 represents 'A', and the value 43 represents '+'. Each character has a pre-defined ordering, which is called a collating sequence, in the
set. The collating sequence is used when you compare characters. The value representing 'B' is 66, so 'A' is smaller than 'B'. '+' is smaller than 'A' since 43 is smaller than 65. The first 32 characters in the ASCII character set are nonprintable.
The 14th character in the set is the new line character.
In C++, the new line character is represented as '\n'.
The horizontal tab character is represented in C++ as '\t'.
The null character is represented as '\0'.
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ASCII (American Standard Code for Information Interchange)
0 1 2 3 4 5 6 7 8 9
0 nul soh stx etx eot enq ack bel bs ht
1 lf vt ff cr so si del dc1 dc2 dc3
2 dc4 nak syn etb can em sub esc fs gs
3 rs us b ! “ # $ % & ‘
4 ( ) * + , - . / 0 1
5 2 3 4 5 6 7 8 9 : ;
6 < = > ? @ A B C D E
7 F G H I J K L M N O
8 P Q R S T U V W X Y
9 Z [ \ ] ^ _ ` a b c
10 d e f g h i j k l m
11 n o p q r s t u v w
12 x y z { | } ~ del39
Floating Point
A floating-point type is a number with a fractional part, such as 43.32. The C++ language supports three different sizes of floating-point: float, double and long double.
sizeof(float)<= sizeof(double)<= sizeof(long double)
float
double
long double
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Floating-Point Data Types
Scientific notation
43872918 = 4.3872918 *10^7 {10 to the power of seven},.0000265 = 2.65 * 10^(-5) {10 to the power of minus five},47.9832 = 4.7983 * 10^1 {10 to the power of one}
To represent real numbers C++ uses scientific notation called floating-point notation.
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float: The data type float is used in C++ to represent any real number between -3.4E+38 and 3.4E+38.The memory allocated for the float data type is 4 bytes.
double: The data type double is used in C++ to represent any real number between -1.7E+308 and 1.7E+308.The memory allocated for the double data type is 8 bytes.
On most newer compilers, the data types double and long double are the same. 42
The maximum number of significant digits—that is, the number of decimal places—in float values is 6 or 7.
The maximum number of significant digits in values belonging to the double type is 15.
The maximum number of significant digits is called the precision.
float values are called single precision double values are called double precision. 2
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The string Type
The data type string is a programmer-defined type and is not part of the C++ language. The C++ standard library supplies it.
A string is a sequence of zero or more characters. Strings in C++ are enclosed in double quote marks. A string with no characters is called a null or empty string.
"William Jacob"“Mickey""”
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"" is the empty string.
Every character in a string has a relative position in the string.
The position of the first character is 0, position of the second character is 1, and so on.
The length of a string is the number of characters in it.
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Example :String Position of a Character Length of the String
in the Sting
"William Jacob" Position of 'W' is 0. 13
Position of the first 'i' is 1.
Position of ' '
(the space) is 7.
Position of 'J' is 8.
Position of 'b' is 12.
“Mickey"Position of ‘M' is 0. 6
Position of 'i' is 1.
Position of 'c' is 2.
Position of 'k' is 3.
Position of 'e' is 4.
Position of 'y' is 5. 46
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Other Data Types
Enumeration Data TypesDeclarationAssignmentOperationsLooping with Enumeration Types
Anonymous Data TypesThe typedeftypedef statementNamespacesThe string string type
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Enumeration Data Types
A data type isA set of values together with A set of operations on those values.
In order to define a new simple data type, called enumeration type, we need:
A name for the data type.A set of values for the data type.A set of operations on the values.
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Enumeration Data Types
C++ allows the user to define a new simple data type by specifying:Its name and the valuesBut not the operations.
The values that we specify for the data type must be legal identifiers
The syntax for declaring an enumeration type is:
enum typeName{value1, value2, ...};enum typeName{value1, value2, ...};
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Declaration of Enumerated Types
Consider the colors of the rainbow as an enumerated type:enum rainbowColors = enum rainbowColors = { red, orange, yellow, green, { red, orange, yellow, green, blue, indigo, violate } blue, indigo, violate }
The identifiers between { } are called enumeratorsThe order of the declaration is significantred < orange < yellow … red < orange < yellow …
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Declaration of Enumerated Types
Why are the following illegal declarations?enum grades{'A', 'B', 'C', 'D', 'F'}; enum grades{'A', 'B', 'C', 'D', 'F'}; enum places{1st, 2nd, 3rd, 4th};enum places{1st, 2nd, 3rd, 4th};
They do not have legal identifiers in the list
• What could you do to make them legal?
enum grades{A, B, C, D, F};enum grades{A, B, C, D, F};enum places{first, second, third, fourth};enum places{first, second, third, fourth};
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Declaration of Enumerated Types
As with the declaration of any objectSpecify the type nameFollowed by the objects of that type
Given: enum daysOfWeek { Sun, Mon, enum daysOfWeek { Sun, Mon, Tue,Wed, Thu, Fri, Sat } Tue,Wed, Thu, Fri, Sat }
Then we declare: daysOfWeek Today, payDay, dayOff;daysOfWeek Today, payDay, dayOff;
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Assignment with Enumerated Types
Once an enumerated variable has been declaredIt may be assigned an enumerated valueAssignment statement works as expected
payDay = Fri; payDay = Fri; // note no quotes// note no quotes// Fri is a // Fri is a valuevalue, a constant, a constant
Enumerated variables may receive only values of that enumerated type
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Operations on Enumerated Type Objects
Incrementing variables of an enumerated type
Do NOT use workaday += 1;workaday += 1; NOR today++;today++;
Instead, use explicit type conversiontoday = daysOfWeek (today + 1);today = daysOfWeek (today + 1);
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Operations on Enumerated Type Objects
Comparisonnormal, OKin order of the enumeration definition
I/Ogenerally not possible to do directlycan be sort of done, indirectly
Used primarily for program control, branching, loopingPossible to have functions return an enumerated type
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Looping with Enumeration Types
Use an enumerated type variable as the loop control variable of a for loop
for (day = Mon; day < Sat; for (day = Mon; day < Sat; day = static_cast<daysOfWeek>(day + 1)) day = static_cast<daysOfWeek>(day + 1)) { { . . . . . . } }
This works because the values are represented internally as integers
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Functions with Enumerated Types
Enumeration type can be passed as parameters to functions either by value or by reference.
A function can return a value of the enumeration type.
daysOfWeek nextDay (daysOfWeek d)daysOfWeek nextDay (daysOfWeek d){{ return (daysOfWeek) ((d + 1)%7); return (daysOfWeek) ((d + 1)%7);}}
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Anonymous Data Types
Named Typeuser defined typedeclaration includes typedefAs with daysOfWeek or Boolean
Anonymous Typedoes not have an associated type
enum (MILD, MEDIUM, HOT) salsa_sizzle;
variable declared without typedef
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Anonymous Data Types
Disadvantages Cannot pass an anonymous type as a parameter to a function. A function cannot return a value of an anonymous type. Problems when:
enum {English, French, Spanish, German, Russian}
languages;
enum {English, French, Spanish, German, Russian}
foreignLanguages;
languages = foreignLanguages; //illegal
Same values used but variables treated as non compatible types
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The typedef typedef statement
Syntax:typedef existing_type_name new_type_name;
Example:typedef int Boolean;
Does not really create a new typeis a valuable tool for writing self-documenting programs
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Namespaces
Recall use of using namespace std;
Namespace is another word for scopeIn C++ it is a mechanism
programmer creates a "named scope"
namespace std{ int abs ( int ); . . .}
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Namespaces
Identifiers within a namespace can be used outside the body of the declaration only ifuse scope resolution operatorx = std::abs(y);
a using declarationusing std::abs;z = abs(q);
a using directiveusing namespace std;p = abs(t);
Note the distinction between declaration and directive
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Namespaces
We usually place the using directive in global scopeAll blocks { . . . } then have identifiers available from
the std namespace
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The string string type
We have used arrays of char to hold "string" information
char name[30];char name[30];cin >> name;cin >> name;
There are some problems with doing thisThere is no assignment statement
Must use strcpy (name, "Clyde");strcpy (name, "Clyde");Cannot do comparisons with < or == or >
Must use if (strcmp (s1, s2) == 0) …if (strcmp (s1, s2) == 0) …For all these must use #include <string.h>#include <string.h>
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The string string type
C++ has a string type which bypasses all the problems we've encountered
Gain these capabilities by#include <string> // note no .h#include <string> // note no .h
Now we can use statements as shown: string name = "Clyde";string name = "Clyde"; if (title1 < title2) …if (title1 < title2) … str1 = str1 + "Day"; str1 = str1 + "Day"; // assignment and concatenation// assignment and concatenation
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The string string type
Some functions are available string name, title;string name, title;name = "Alexander";name = "Alexander";cout << name.length()<<endl;cout << name.length()<<endl;cout << name.find('x') <<endl;cout << name.find('x') <<endl;cout << name.substr(1,3) <<endl;cout << name.substr(1,3) <<endl;title = "Big Cheese";title = "Big Cheese";title.swap(name);title.swap(name);cout << name<<endl;cout << name<<endl; Guess what will be the output of
these lines of code
ARITHMETIC OPERATORS AND OPERATOR PRECEDENCE
Arithmetic Operators+ addition- subtraction* multiplication/ division% remainder (mod operator)
The operators +, -, *, and / can be used with both integral and floating point data types, while % is used only for integral data type to find the remainder in ordinary division. 67
Arithmetic Expressions
3 + 42 + 3 * 55.6 + 6.2 * 3x + 2 * 5 + 6 / y
x and y are some unknown numbers
2
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Unary operator: An operator that has only one operand.
Binary Operator: An operator that two operands.
In the expression
–5
– has only one operand, which is 5 and so - acts as a unary operator.
In the expression
+27
+ is a unary operator. 69
Further, in the expressions
3 + 423 - 45both the operators + and – are binary operators.
– and + are both unary as well as binary arithmetic operators.
*, /, and % are binary arithmetic operators.
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Example 2-4
Arithmetic
Expression Result Description
2 + 5 713 + 89 10234 - 20 1445 - 90 -452 * 7 145/2 2 In the division 5/2, the quotient is
2 and the remainder is 1.
Therefore, 5/2 evaluates to the
quotient, which is 2.
14 / 7 2 71
34 % 5 4 In the division 34/5, the quotient is 6 and
the remainder is 4. Therefore, 34%5 evaluates to the remainder, which is 4-34 % 5 -4 In the division -34 / 5, the quotient is
-6 and the remainder is -4. Therefore,
-34 % 5 evaluates to the remainder,
which is -4.
34 % -5 4 In the division 34 / -5, the quotient
is –6 and the remainder is 4. Therefore
34 % -5 evaluates to the remainder,
which is 4.)
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-34 % -5 -4 In the division -34 / -5, the quotient
is 6 and the remainder is -4. Therefore, -34 % -5 evaluates to the
remainder, which is -4.)
4 % 6 4 In the division 4/6, the quotient is 0 and the remainder is 4. Now 4 % 6 evaluates to the remainder, which is 4.
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Example
Expression Result
5.0 + 3.5 8.53.0 + 9.4 12.416.3 - 5.2 11.14.2 * 2.5 10.505.0/2.0 2.5
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Order of Precedence
The precedence rules of arithmetic operators are:
*, /,%
are at a higher level of precedence than
+ , -
Operators *, /, and % have the same level of precedence. Operators + and - have the same level of precedence.
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When operators are all on the same level, they are performed from left to right.
To avoid confusion, the grouping symbol can be used. For example,
3*7-6+2*5/4+6 means
(3 * 7) - 6 + ( ( 2 * 5) / 4 ) + 6= 21 - 6 + (10 / 4) + 6 (Evaluate *)= 21 – 6 + 2 + 6 (Evaluate /)= 15 + 2 + 6 (Evaluate -)= 17 + 6 (Evaluate first +)= 23 (Evaluate +)
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Character Arithmetic
8+7 = 15 '8' + '7' = 56 + 55 = 111 '8' + 7 = 56 + 7 = 63 '8' * '7' is undefined in the ASCII character data set.
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EXPRESSIONS
If all operands (that is, numbers) in an expression are integers, the expression is called an integral expression.
If all operands in an expression are floating-point numbers, the expression is called a floating-point or decimal expression.
An integral expression yields an integral result; a floating-point expression yields a floating-point result.
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Example Some C++ integral expressions:
2 + 3 * 5 3 + x - y / 7 x + 2 * (y - z) + 18
Example Some C++ floating point expressions:
12.8 * 17.5 - 34.50x * 10.5 + y - 16.2
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Mixed ExpressionsAn expression that has operands of different data types is called a
mixed expression.
A mixed expression contains both integers and floating-point numbers.
Examples of mixed expressions
2 + 3.56 / 4 + 3.95.4 * 2 – 13.6 + 18 / 2
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Rules to evaluate a mixed expression1. When evaluating an operator in the mixed expression:
a. If the operator has the same types of operands (that is, either both integers or both floating-point numbers), the operator is evaluated according to the type of the operands.
b. If the operator has both types of operands (that is, one is an integer and the other is a floating-point number) then during calculation the integer is changed to a floating-point number with the decimal part of zero and the operator is evaluated. The result is a floating-point number.
2. The entire expression is evaluated according to the precedence rules; the multiplication, division, and modulus operators are evaluated before the addition and subtraction operators. Operators having the same level of precedence are evaluated from left to right. Grouping is allowed for clarity.
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Example
(a) 3 / 2 + 5.0
= 1 + 5.0 (3 / 2 = 1)
= 6.0 (1 + 5.0 = 1.0 + 5.0= 6.0)
(b) 15.6 / 2 + 5
= 7.8 + 5 (15.6 / 2 = 15.6 / 2.0 = 7.8)
= 12.8 (7.8 + 5.0 = 12.8)
(c) 4 * 3 + 7 / 5 – 25.6
= 12 + 7 / 5 – 25.6 (4 * 3 = 12)
= 12 + 1 – 25.6 (7 / 5 = 1)
= 13 – 25.6 (12 + 1 = 13)
= -12.6 (13 – 25.6 = 13.0 – 25.6
= - 12.6) 82
Implicit Type conversion Cast operator (type conversion or type casting)
Syntax Cast operator
static_cast<dataTypeName>(expression)
Expression is evaluated and its value is converted to value of the type specified by the dataTypeName.
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Example
static_cast<int>(7.9) = 7static_cast<int>(3.3) = 3static_cast<double>(25) = 25.0static_cast<double>(5+3) = static_cast<double>(8) = 8.0static_cast<double>(15)/2 = 15.0/2 = 15.0/2.0 = 7.5
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static_cast<double>(15/2) = static_cast<double>(7) = 7.0
static_cast<int>(7.8 + static_cast<double>(15)/2)= static_cast<int>(7.8 + 7.5) = static_cast<int>(15.3) = 15
static_cast<int>(7.8 + static_cast<double>(15/2)= static_cast<int>(7.8 + 7.0) = static_cast<int>(14.8) = 14
85
x = 15y = 23z = 3.75
Expression Valuestatic_cast<int>(7.9 + 6.7) 14
static_cast<int>(7.9) + static_cast<int>(6.7) 13
static_cast<double>(y / x) + z 4.75
static_cast<double>(y) / x + z 5.28333
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INPUT
Storing data in the computer’s memory is a two step process.
• Instruct the computer to allocate memory.• Include statements in the program to put data into the allocated
memory.
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Allocating Memory with Constants and Variables
Named Constant: A memory location whose content is not allowed to change during program execution.
Variable: A memory location whose content may change during program execution.
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Named Constant: The syntax to declare a named constant is
const dataType identifier = value;
In C++, const is a reserved word.
Exampleconst double conversion = 2.54;const int noOfStudents = 20;const char blank = ' ';const double payRate = 15.75;
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Variable
The syntax for declaring one variable or multiple variables is
dataType identifier, identifier, . . .;
Exampledouble amountDue;int counter;char ch;int x, y;string name;
90
1. In C++, all identifiers must be declared before they can be used. If we refer to an identifier without declaring it, the compiler will generate an error message indicating that the identifier is not declared.
2. A data type is called simple if the variable (or named constant) of that type can store only one value at a time. For example, if x is an, say, int variable. Then at a given time only one value can be stored in x.
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Putting Data into Variables
In C++ there are two ways that data can be placed into a variable:1. Using C++’s assignment statement, and2. Use input (read) statements.
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Assignment StatementThe assignment statement takes the form
variable = expression;
• The expression is evaluated and its value is assigned to the variable on the left side.
• In C++, = is called the assignment operator.
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Examples 2-13
int I, J;double sale;char first;string str;
I = 4;J = 4 * 5 - 11;sale = 0.02 * 1000;first = 'D';str = "It is a sunny day. ";
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A C++ statement like
I = I + 2;
means evaluate whatever is in I, add two to it, and assign the new value to the memory location I.
The sequence of C++ statements
I = 6;I = I + 2;
and the statement
I = 8;
both assigns 8 to I.
The statement
I = 5;
is read 'I becomes 5', or 'I gets 5'.
Each time a new value is assigned to I, the old value is erased.95
If the variables I, J, and K have been properly declared, then the sequence of statements
I = 12;I = I + 6;J = I;K = J / 2;K = K / 3;
results in 'K becoming 3', that is, in K having the value 3 stored in it.
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To save the value of an expression and use it in a later expression, do the following:1. Declare a variable of the appropriate data type. For example, if the
result of the expression is an integer, declare an int variable.2. Assign the value of the expression to the variable that was declared
using the assignment statement. This action saves the value of the expression into the variable.
3. Wherever the value of the expression is needed, use the variable holding the value.
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Example 2-14
int a, b, c, d;int x, y;
Evaluate the expressions -b+(b2-4ac)and -b-(b2-4ac), and assign the values of these expressions to x and y, respectively.
The expression b2-4ac appears in both expressionsFirst calculate the value of this expression and save its value in d. Use the value of d to evaluate the expressions as shown by the
following statements:
d = b * b – 4 * a * c;
x = -b + d;y = -b – d;
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Declaration and Initializing Variables
Variables can be initialized when they are declared
int first, second;
char ch;
double x, y;
first = 13;
second = 10;
ch = ' ';
x = 12.6;
y = 123.456;
Equivalently, we can write the following C++ statements.
int first=13, second=10;
char ch=' ';
double x=12.6, y=123.456;99
Input (Read) Statement
Syntax of cin together with >>:
cin>>variable>>variable. . .;
In C++, >> is called the extraction operator.
Suppose miles is a variable of the type double. The statement
cin>>miles;
causes the computer to get a value of the type double and place it in the memory cell miles.
100
By using more than one variable in cin, more than one value can be read at a time.
Suppose feet and inch are variables of the type int. A statement like
cin>>feet>>inch;
gets two integers (entered at the keyboard) and places them in the memory location feet and inch, respectively.
101
Variable Initialization
Assignment statement Read statement
int feet;
We can initialize feet to a value 35 either by using the assignment statement
feet = 35;
or by executing the statement
cin>>feet;
C++ does not automatically initialize the variables when they are declared. 102
Example 2-15int one, two;
double z;
char ch;
string name;
1. one = 4;
2. two = 2 * one + 6;
3. z = (one + 1) / 2.0;
4. ch = 'A';
5. cin>>two;
6. cin>>z;
7. one = 2 * two + static_cast<int>(z);
8. cin>>name;
9. two = two + 1;
10. cin>>ch;
11. one = one + static_cast<int>(ch);
12. z = one – z;103
Suppose the input is
8 16.3 Goofy D
Before the execution of statement 1 all variables are uninitialized.
104
Statement 1 stores 4 into one. So after the execution of statement 1, the values are
1. one = 4;
105
Statement 2 first evaluates the expression 2 * one + 6 (which evaluates to 14) and then stores the value of the expression, that is, 14 into two. After the execution of statement 2, the values are:
2. two = 2 * one + 6;
106
Statement 3 first evaluates the expression (one + 1)/2.0 (which evaluates to 2.5) and then stores the value of the expression into z. After the execution of statement 3, the values are:
3. z = (one + 1) / 2.0;
107
Statement 4 stores the character 'A' into ch. After the execution of statement 4, the values are:
4. ch = 'A';
108
Statement 5 reads a number from the keyboard (which is 8) and stores the number 8 into two. After the execution of statement 5, the values are:
5. cin>>two;
109
Statement 6 reads a number from the keyboard (which is 16.3) and stores the number 16.3 into z. After the execution of statement 6, the values are:
Note that the variable name is still undefined.
6. cin>>z;
110
Statement 7 first evaluates the expression 2 * two + static_cast<int>(z) (which evaluates to 32) and then stores the value of the expression, that is, 32 into one. After the execution of statement 7, the values are:
7. one = 2 * two + static_cast<int>(z);
111
Statement 8 gets the next input from the keyboard (which is Goofy) and stores it into name. After the execution of statement 8, the values are:
8. cin>>name;
112
Statement 9 first evaluates the expression two + 1 (which evaluates to 9) and stores the value of this expression, that is, 9 into two. After the execution of statement 9, the values are:
9. two = two + 1;
113
Statement 10 reads the next input from the keyboard (which is D) and stores it into ch. After the execution of statement 10, the values are:
10. cin>>ch;
114
Statement 11 first evaluates the expression one + static_cast<int>(ch). Here static_cast<int>( 'D') gives the collating sequence of the character D in the character data set, which is 68 (in ASCII)). After the execution of statement 11, the values are:
11. one = one + static_cast<int>(ch);
115
The statement 12 first evaluates the expression one – z (= 100.0 – 16.3 = 83.7) and then stores the value of this expression, that is 83.7 into z. The value of the variables after the execution of the last statement are:
12. z = one – z;
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INCREMENT AND DECREMENT OPERATORS
Increment operator - increment the value of a variable by 1Decrement operator- decrement the value of a variable by 1.
Pre Increment: ++variablePost Increment: variable++
Pre Decrement: --variablePost Decrement: variable--
117
++count;
or
count++;
increments the value of count by 1.
--count;
or
count--;
decrements the value of count by 1.
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1. x = 5;y = ++x;
• After the second statement both x and y are 6.
2. x = 5;y = x++;
• After the second statement y is 5 and x is 6.
Example 2-16Suppose a and b are int variables.
a = 5; b = 2 + (++a);
After the second statement a is 6 and b is 8.
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OUTPUT The syntax of cout together with << is
cout<<expression or manipulator<<expression or
manipulator...;
In C++, << is called the insertion operator. expression (that is, expression) is evaluated and its value is printed at the
current cursor position on the screen. manipulator manipulates the output. The simplest manipulator is endl (the last character is the letter el), which causes the cursor to move to the beginning of the next line.
This is called an output statement. Sometimes this is also called a cout statement.
In C++, << is called the stream insertion operator.
Strings and expressions involving only one variable or a single value are evaluated to itself.
120
Example 2-17Statement Output
1. cout<<29/4; 72. cout<<"Hello there. "; Hello there.3. cout<<12; 124. cout<<"4+7"; 4+75. cout<<4+7; 116. cout<<"A"; A7. cout<<"4 + 7 = "<<4 + 7; 4 + 7 = 11
8. cout<<2+3*5; 179. cout<<"Hello \nthere. "; Hello
there.•\n is called new line escape sequence. •\ (back slash) is called the escape character. 121
The output of the C++ statement
cout<<a;
is meaningful provided the variable a has been given a value. For example, the sequence of C++ statements,
a = 45;cout<<a;
will produce an output of 45.
122
Example 2-18
int a, b, c, d;
a = 65 ; //Line 1
b = 78 ; //Line 2
cout<<29/4<<endl;//Line 3
cout<<3.0/2<<endl; //Line 4
cout<<"Hello there.\n"; //Line 5
cout<<7<<endl; //Line 6
cout<<3+5<<endl; //Line 7
cout<<"3+5";//Line 8
cout<<endl; //Line 9
cout<<2+3*6<<endl; //Line 10
cout<<"a"<<endl; //Line 11
cout<<a<<endl; //Line 12
cout<<b<<endl; //Line 13
cout<<c<<'\n'; //Line 14
cout<<d; //Line 15
cout<<endl; //Line 16 123
Output of Statement at 7 Line 31.5 Line 4Hello there. Line 57 Line 68 Line 73+5 Line 8 20 Line 10a Line 1165 Line 1278 Line 136749684 Line 144203005 Line 15
124
The new line character, '\n'.
cout<<"Hello there.";cout<<"My name is Goofy.";
Output
Hello there.My name is Goofy.
Now consider the following C++ statements.
cout<<"Hello there.\n";cout<<"My name is Goofy.";
Output
Hello there.My name is Goofy.
125
When \n is encountered in the string, the cursor is positioned at the beginning of the next line.
\n may appear anywhere in the string.
The output of the statement
cout<<"\n";
is equivalent to the output of the statement
cout<<endl;
which is equivalent to the output of the statement
cout<<'\n'; 126
The output of the sequence of statements:
cout<<"Hello there.\n"; cout<<"My name is Goofy.";
is equivalent to the output of the sequence statements:
cout<<"Hello there."<<endl; cout<<"My name is Goofy.";
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Example
cout<<"Hello there.\nMy name is Goofy.";
Or
cout<<"Hello there.";
cout<<"\nMy name is Goofy.";
or
cout<<"Hello there.";
cout<<endl<<"My name is Goofy.";
In each case the output is
Hello there.
My name is Goofy.
128
Example 2-20
The output of the following C++ statement
cout<<"Count...\n....1\n.....2\n......3";
or
cout<<"Count..."<<endl<<"....1"<<endl
<<".....2"<<endl<<"......3";
Is
Count...
....1
.....2
......3
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Example
To output the following sentence in one line as part of a message:It is sunny, warm, and not a windy day. Let us go golfing.
We can use any of the following statements:
cout<<"It is sunny, warm, and not a windy day. ";
cout<<"Let us go golfing."<<endl;
or
cout<<"It is sunny, warm, and not a windy day. "
<<"Let us go golfing."<<endl;130
The following statement is illegal in C++.
cout<<"It is sunny, warm, and not a windy day. Let us go golfing."<<endl;
The return (or Enter) key on your keyboard cannot be part of the string.
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Example
The output of the statementcout<<"The newline escape sequence is \\n"<<endl;
IsThe new line escape sequence is \n
The output of the statementcout<<"The tab character is represented as \'\\t\'"<<endl;
isThe tab character is represented as '\t‘
The output of the statement cout<<"The string \"Sunny\" contains five characters\n";
isThe string "Sunny" contains five characters
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Prepr
ocessor Directives
Only a small number of operations are explicitly defined in C++.
Many of the functions and symbols that are necessary to run a C++ program are provided as a collection of libraries.
Every library has a name and is referred as a header file. For example, the descriptions of the functions needed to perform I/O are contained in the header file iostream.
The descriptions of some very useful mathematics functions such as power, absolute, sine, etc., are contained in the header file cmath.
Preprocessor directives are commands supplied to the preprocessor.
All preprocessor commands begin with #.
There is no semicolon at the end of these commands since these are preprocessor commands not C++ commands.
133
The general syntax to include a header file (provided by the SDK) in a C++ program is
#include <headerFileName>The preprocessor directive
#include <iostream>
causes the preprocessor to include the header file iostream in the program.
134
In Standard C++, header files have the file extension .h
In Standard C++, the descriptions of the functions needed to perform I/O are contained in the header file iostream.h
#include <iostream.h>#include <math.h>
135
136
Using cin and cout in a Program and namespace
One way to use cin and cout in a program is to refer them as std::cin and std::cout.
Another option is to include the following statement in your program:using namespace std;
The using statement appears after the statement
#include <iostream>.
137
Using the string Data Type in a Program
To use the string data type in a program, your must include the following preprocessor directive:
#include <string>
138
Program Style and Form
The Program Part
Every C++ program has a function main.
The basic parts of the function main are:
1. The heading
2. Body of the function
The heading part has the following form
typeOfFunction main(argument list)
139
The statement
int main(void)
means that the function main returns a value of the type int and it
has no arguments.
The previous statement is equivalent to statement
int main()
It is not necessary to put word the void in parentheses, but the parentheses are still needed.
140
The body of the function is enclosed between { and } and has two types of statements.
• Declaration statements.• Executable statements.
141
Declaration Statements
int a, b, c; double x, y;
Variables (or identifies) can be declared anywhere in the program, but they must be declared before they can be used.
Executable Statements
Example 2-24
Executable statements:a = 4; //assignment statement
cin>>b; //input statement
cout<<a<<endl<<b<<endl; //output statement142
SyntaxErrors in syntax are detected during compilation.
int x; //Line 1int y //Line 2; syntax errordouble z; //Line 3
y = w + x; //Line 4 ; syntax error
143
Use of Blanks In C++, one or more blanks are used to separate numbers when
data is input. Blanks are also used to separate reserved words and identifiers
from each other and other symbols. Commas are used to separate items in a list.
Use of Semicolons, Brackets, and Commas All C++ statements terminate with a semicolon. The semicolon is also called a statement terminator. { and } are not C++ statements.
144
SemanticsIt is quite possible for you to eradicate all syntax errors in a program and still not have it run. And if it runs it still may not do what you meant it to do. For example,
2 + 3 * 5
and
(2 + 3) * 5
are both syntactically correct expressions, but have different meanings.
145
Form and StyleConsider the following two ways of declaring variables.
int feet, inch;double x, y;or
int a,b;double x,y;
146
Blank spaces
int a,b,c; int a, b, c;
The blanks between the identifiers in the second statement are meaningless.
In the statement,
inta,b,c;
no blank between the t and a changes the reserved word int and the identifier a into a new identifier inta.
147
DocumentationComments
• Single line comments Single line comments begin with // anywhere in the line.
• Multiple line comments. Multiple line comments are enclosed between /* and */.
148
Naming Identifiers
const double a = 2.54; //conversion constantdouble x; //variable to hold centimetersdouble y; //variable to hold inches
x = y * a;
Consider the following
const double conversion = 2.54; double centimeters; double inches;
centimeters = inches * conversion;
Run-together-word
inchperfoot
Run-together-words can be handled either by using CAPS for the beginning of each new word or underscore just before the new word.
We could use
either inchPerFoot or inch_per_foot.149
Prompt Lines
cout<<"Please enter a number between 1 and 10 and" <<" press the return key"<<endl;cin>>num;
When these two statements execute in the order given, first the cout statement causes the following line of text to appear on the screen:
Please enter a number between 1 and 10 and press the return key
After seeing this line, users know that they must enter a number and press the return key.
150
MORE ON ASSIGNMENT STATEMENTSAssignment Statements
• Simple assignment statements. • Compound assignment statements.
151
Compound assignment operator
op=
where op is any of the arithmetic operators.
Using the compound assignment operator, the simple assignment statement
variable = variable op (expression);
can be rewritten as
variable op= expression;
and is called the compound assignment statement. 152
Example 2-25Simple Assignment Compound Assignment
Statement Statement
I = I + 5; I += 5;counter = counter + 1; counter += 1;sum = sum + number; sum += number;amount=amount*(interest+1); amount *= interest + 1;
x = x / ( y + 5); x /= y + 5;
153
PROGRAMMING EXAMPLE: CONVERT LENGTHWrite a program that takes as input a given length expressed in feet and inches. It then converts and outputs the length in centimeters.
Input: Length in feet and inches.
Output: Equivalent length in centimeters.
154
Problem Analysis and Algorithm DesignThe lengths are given in feet and inches, and you need to find the equivalent length in centimeters. One inch is equal to 2.54 centimeters. The first thing the program needs to do is convert the length given in feet and inches to all inches. Then you can use the conversion formula, 1 inch = 2.54 centimeters, to find the equivalent length in centimeters. To convert the length from feet and inches to inches, you multiply the number of feet by 12, as 1 foot is equal to 12 inches, and add the given inches.
For example, suppose input is 5 feet and 7 inches. Then total inches are given by
totalInches = 12 * feet + inches = 12 * 5 + 7 = 67
155
We now apply the conversion formula, that is, 1 inch = 2.54 centimeters to find the length in centimeters.
centimeters = totalInches * 2.54 = 67 * 2.54 = 170.18
The above discussion translates into the following algorithm:
1. Get the length in feet and inches.
2. Convert the length into total inches.
3. Convert total inches into centimeters.
4. Output centimeters.
156
Variables
int feet; //variable to hold given feetint inchs; //variable to hold given inchesint totalInches; //variable to hold total inchesdouble centimeters; // variable to hold length
//in centimeters.
Named Constant
const double conversion = 2.54;const int inchesPerFoot = 12;
157
Main Algorithm1. Prompt the user for the input. (Without a prompt line, the user
will be staring at a blank screen and will not know what to do.)
2. Get the data.
3. Echo the input—that is, output what the program read as input. (Without this step, after the program has executed, you will not know what the input was.)
4. Find the length in inches.
5. Output the length in inches.
6. Convert the length to centimeters.
7. Output the length in centimeters.
158
Putting it Together• The program will begin with comments that document its purpose and functionality. • There is both input to this program (the length in feet and inches) and output (the equivalent length
in centimeters), you will be using system resources for input/output. • The program will use input statements to get data into the program and output statements to print
the results. • The data will be entered from the keyboard and the output will be displayed on the screen, the
program must include the header file iostream. • The first statement of the program, after the comments as described above, will be the
preprocessor directive to include this header file.
159
This program requires two types of memory locations for data manipulation: named constants and variables.
Named constants are usually placed before the function main so that they can be used throughout the program.
This program has only one function, the function main, which will contain all of the programming instructions in its body.
The program needs variables to manipulate data, and these variables will be declared in the body of the function main.
The body of the function main has the following form:int main (){
declare variables statements return 0;}
160
In order to write the complete C++ program:
1. Begin the program with comments for documentation.
2. Include header files, if any are used in the program.
3. Declare named constants, if any.
4. Write the definition of the function main.
161
Complete Program Listing in ANSI/ISO Standard C++
//*************************************************// Program Convert: This program converts// measurements in feet and inches into centimeters// using the approximation that 1 inch is equal to // 2.54 centimeters.
//*************************************************
//header file#include <iostream>
using namespace std;
//named constantsconst double conversion = 2.54;const int inchesPerFoot = 12 ; 162
int main (){//declare variables int feet; int inches; int totalInches; double centimeter;
//Statements: Step 1 - Step 7 cout<<"Enter two integers, one for feet, " <<"one for inches: "; //Step 1 cin>>feet>>inches; //Step 2 cout<<endl; cout<<"The numbers you entered are "<<feet <<" for feet "<<"and "<<inches
<<" for inches. "<<endl; //Step 3163
totalInches = inchesPerFoot * feet + inches; //Step 4
cout<<endl; cout<<"The total number of inches = " <<totalInches<<endl; //Step 5 centimeter = conversion * totalInches;
//Step 6 cout<<"The number of centimeters = " <<centimeter<<endl; //Step 7 return 0;}
164
Sample Run: In this sample run, the user input is in red
Enter two integers, one for feet, one for inches: 15 7The numbers you entered are 15 for feet and 7 for inches.The total number of inches = 187The number of centimeters = 474.98
165
Complete Program Listing in Standard C++
//*************************************************
// Program Convert: This program converts
// measurements in feet and inches into centimeters
// using the approximation that 1 inch is equal to
// 2.54 centimeters.
//*************************************************
//header file
#include <iostream.h>
//named constants
const double conversion = 2.54;
const int inchesPerFoot = 12 ;166
int main (){//declare variables
int feet; int inches; int totalInches; double centimeter;
//Statements: Step 1 - Step 7 cout<<"Enter two integers, one for feet, " <<"one for inches: "; //Step 1 cin>>feet>>inches; //Step 2 cout<<endl; cout<<"The numbers you entered are "<<feet <<" for feet "<<"and "<<inches
<<" for inches. "<<endl; //Step 3167
totalInches = inchesPerFoot * feet + inches; //Step 4
cout<<endl; cout<<"The total number of inches = " <<totalInches<<endl; //Step 5 centimeter = conversion * totalInches;
//Step 6 cout<<"The number of centimeters = " <<centimeter<<endl; //Step 7 return 0;}
168
PROGRAMMING EXAMPLE: MAKE CHANGEWrite a program that takes as an input any change expressed in cents. It then computes the number of half-dollars, quarters, dimes, nickels and pennies to be returned, if you are to return as many half-dollars as possible, then quarters, dimes, nickels, and pennies in that order.
For example 483 cents should be returned as 9 half-dollars, 1 quarter, 1 nickel, and 3 pennies.
Input: Change in cents.
Output: Equivalent change in half-dollars, quarters, dimes, nickels and pennies.
169
Problem Analysis and Algorithm Design
Suppose the change is 646 cents.
1. Change = 6462. Number of Half-dollars = 646/50 = 123. Remaining Change = 646 % 50 = 464. Number of Quarters = 46 / 25 = 15. Remaining Change = 46 % 25 = 216. Number of Dimes = 21 / 10 = 27. Remaining Change = 21 % 10 = 18. Number of Nickels = 1 / 5 = 09. Remaining Change = 1 % 5 = 1
170
This discussion translates into the following algorithm.1. Get the change in cents.2. Find the number of half-dollars.3. Calculate the remaining change.4. Find the number of quarters.5. Calculate the remaining change.6. Find the number of dimes.7. Calculate the remaining change.8. Find the number of nickels.9. Calculate the remaining change.10. The remaining change is the number of pennies.
171
Variables• From the above steps it appears that we will need variables to hold half-dollars, quarters and so
on. • Since we are not going to use the values of half-dollars, quarters and so on in any calculation, we
can simply output them. The only thing that keeps changing is the change.
int change;
Named Constants
const int Halfdollar = 50;const int Quarter = 25;const int Dime = 10;const int Nickel = 5;
172
Main Algorithm1. Prompt the user for input.2. Get input.3. Echo the input by displaying the entered change on the screen.4. Compute and print the number of half-dollars.5. Calculate the remaining change.6. Compute and print the number of quarters.7. Calculate the remaining change.8. Compute and print the number of dimes.9. Calculate the remaining change.10. Compute and print the number of nickels.11. Calculate the remaining change.12. Print the remaining change. 173
Complete Program Listing// ****************************************************
// Program Make Change: Given any amount of change
// expressed in cents, this program computes the number
// of half-dollars, quarters, dimes, nickels, and
// pennies to be returned, returning as many
// half-dollars as possible, then quarters, dimes,
// nickels, and pennies in that order.
//*****************************************************
//header file
#include <iostream>
using namespace std;
//named constants
const int Halfdollar = 50;
const int Quarter = 25;
const int Dime = 10;
const int Nickel = 5;174
int main()
{
//declare variable
int change;
//Statements: Step 1 – Step 12
cout<<"Enter change in cents: "; //Step 1
cin>>change; //Step 2
cout<<endl;
cout<<"The change you entered is "<<change<<endl; //Step 3
cout<<"The number of half-dollars to be returned "
<<"are "<<change / Halfdollar<<endl; //Step 4
change = change % Halfdollar; //Step 5
cout<<"The number of quarters to be returned are "
<<change / Quarter<<endl; //Step 6175
change = change % Quarter; //Step 7
cout<<"The number of dimes to be returned are "
<<change / Dime<<endl; //Step 8
change = change % Dime; //Step 9
cout<<"The number of nickels to be returned are "
<<change / Nickel<<endl; //Step 10
change = change % Nickel; //Step 11
cout<<"The number of pennies to be returned are "
<<change<<endl; //Step 12
return 0;
}176
Sample Run: In this sample run, the user input is red:Enter change in cents: 583The change you entered is 583The number of half-dollars to be returned are 11The number of quarters to be returned are 1The number of dimes to be returned are 0The number of nickels to be returned are 1The number of pennies to be returned are 3
177
INTEGRAL DATA TYPEIl data types
178
Int Data Type
Integers are whole numbers (without any fractional Part)
Ex:-6728, -67, 0, 78, 36782, +763,...*Positive integers do not have to have a + sign in front of
them.
*No commas are used within an integer.
*In C++ commas are reserved for separating items in a list. So 36,782 would be interpreted as two integers 36 and 782.
179
180
/* PROGRAM THAT ILLUSTRATES INT DATA TYPE*/
#include<iostream.h>void main(){int n=45;cout<<“the integer value is “<<n;getch();}NOTE: n is an integer number which holds 2 bytes of memory.
the value ranges from -32768 to +32767.
181
182