CT wire sizing

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    Selection of Current Transformers

    and Wire Sizing in Substations

    Presented to:59th Conference for Protective Relay Engineers

    Texas A&M UniversityCollege Station, Texas

    April 4-6, 2006

    Sethuraman Ganesan

    ABB Inc.Allentown, PA

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    Characteristics of CT

    Metering and Protection Class

    Specifications of CTs

    CT Wiring and other issues

    IEEE Std C57.13, Guide C37.110 IEC Std 60044-6

    Discussion Paper

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    CT Simplified Circuit and Phasor

    IP IS1:n

    a c

    b d

    IP/n

    IE

    RCT

    Xm

    e

    f

    RB

    Vef

    ISRCT

    Vcd=n. VabIS

    IE

    IPn

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    Metering

    Metering class Typical Spec 0.3 B-0.1

    Meters can be off Protection CTs

    Thermal stress

    Auxiliary CTs

    Burdens of auxiliary CTs, accuracy Summation CTs

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    Protection Class CTs

    Ratings, Ratio

    Polarity Class, Knee point voltage, Excitation

    characteristics

    Secondary Current

    Magnetizing

    Voltage

    Vx

    Vk

    10A(10%)

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    AC Saturation

    Severe Saturation

    Too large CT secondary burden,currents

    Ideal Actual

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    CT ratings to avoid AC saturation

    Vx > If (RCT+RL+RB)

    Vx = Saturation VoltageIf = CT secondary current during fault

    RCT= CT Secondary Resistance- OhmsRL = CT lead Resistance- Ohms

    RB

    = CT Connected burden Resistance-

    Ohms

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    CT Transient Saturation

    Caused by DC Transients in the power

    system

    Current

    0

    1

    2

    -2

    -1

    DCAC

    Cycles

    1 2

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    CT Transient Saturation (Minimum Math!)

    i = current , v = voltage = Flux in the magnetic core,all instantaneous;

    i v (d /d t)where d /d t represents the rate of change of flux.

    i (d /d t)Integrating,

    i Rewriting,

    i (Flux is decided by area under the

    time function i)

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    Flux during AC currents

    v i d/dt

    i

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    Flux during DC Transients

    v i d/dt

    i

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    CT ratings to avoid Transient saturation

    Vx > If (1+X/R) (RCT+RL+RB)

    Where,

    X, R= Primary system reactance andresistances

    Avoiding CT saturation may not always bepossible.

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    Waveforms during AC+DC Transients

    DC

    (Ideal CT)

    AC+DC Actual in CT

    Saturation

    I

    Time

    Ideal CT secondary current

    Actual CT secondary current

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    Specifications for ANSI CTs

    Classification Letter C, K or T

    C Performance can be Calculated, low leakagereactance

    K- Same as C but with Knee point 70% of secondaryterminal voltage

    T- Performance to be Tested

    Recommended maximum secondary current100A

    Error max: 10% at 100A, so 10A error

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    Class C CTs

    To avoid AC Saturation, in C800,

    100(RCT+ 8) > If (RCT+RL+RB)

    Typically

    If < 100A

    Connected burden RL+RB < 8 Ohms

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    Class C CTs

    To avoid DC Saturation, in C800,

    100(RCT+ 8) > If (1+X/R)(RCT+RL+RB)

    Normally If < 100A, Connected burden is lessthan design burden;

    Define Ni = 100/ If ( Ideally >1)

    Define Nr = (RCT+ 8) / (RCT+RL+RB ) (Ideally >1)

    The equation above becomes

    Ni. Nr > (1+X/R)

    In other words CT saturation is avoided if

    (1+X/R) < Ni. Nr

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    Remanence

    Remanence, Residual flux

    Similar to permanent magnetism

    Reduces available excursion of flux totranslate currents

    If is the per unit of maximum flux remaining

    as residual flux, CTs have to be oversized by afactor

    1/(1-)

    If = 0.9, the above factor is 10, that biggerCT is required!!!

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    Remanence

    Reduce

    Gap in the steel core

    Different core materials

    Biased core

    Account for remanence-

    Increase the CT size- Not an option alwaysReduce the burdens, leads etc.

    Make the relay faster- to operate before CT

    saturation starts Increased slope

    Special relays with algorithms

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    CT- Time to saturate

    t/T

    Vx / (IRT)

    0 1 2 3 4 5 60

    2

    1

    Vx = Saturation VoltsI = Symm. Secy Current, A

    R = Secy. Circuit Resist, Ie = Exciting Current, A

    T = Primary Circuit Time Constant, Cycles

    t = Time to saturate in Cycles

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    Calculating Lead Resistance - Example

    Data

    CT C400, 1000/5A, RCT = 0.25 Ohms

    Fault Primary = 10kA at X/R = 15

    Relay burden = Negligible

    Calculations:

    If = 10000/CTR = 10000/200 = 50A

    Ni= 100/ 50 = 2

    Nr = 4.25/(0.25+RL)

    Checking for adequacy,

    (1+X/R) > Ni.Nr

    (1+15) > 2 x 4.25 /(0.25 + RL)

    RL < 0.28 Ohms

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    Case Study Fig 1

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    Case Study Fig 2

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    Case Study Fig 3

    I

    t

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    Case Study Fig 4

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    Conclusion

    A thorough understanding of the application ofCT is required

    Previous experience of CT wire sizing may not

    always be correct in a newer application

    More than adequate CT sizes and cable sizeswaste resources

    Application check is recommended, always forcritical applications