Coz Martinez - Terry
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examen proecesos
Transcript of Coz Martinez - Terry
Hoja1TEMA:Curvas de calidadALUMNO: COZ MARTINEZ SANDRAFECHA: 5/21/121. Graficar e interpretarD 25 121.1 =31minD10 121.1 = 6min2. Determinar el punto comunD - Dref x 10^(Tref-T/z)DT = 31 x 10^(121.1-T/25)DT = 6 x 10^(121.1-T/10)T (C)DT (Vit B1)DT (Lys)90543.70295557097729.497310158895343.05337303312444.2816668247100216.4520452639772.9497310159105136.572007687244.428166682511086.171111300577.294973101611554.370295557124.442816668212034.30533730337.729497310212521.64520452642.444281666813013.65720076870.772949731T (C)DT (Vit B1)DT (Lys)902.73536169383.8881512504952.53536169383.38815125041002.33536169382.88815125041052.13536169382.38815125041101.93536169381.88815125041151.73536169381.38815125041201.53536169380.88815125041251.33536169380.38815125041301.1353616938-0.1118487496A6.33512.88B-0.04-0.1R11Perdida de NutrientesD10C 121.1C = 60 minC = Co 10^(-1/DT(t))logC = logCo - 1/DT (t)t = DT x (logCo-logC)Calcular perdida de nutrientes para T = 121.1C y T = 130CD10C 130C = T = 121.1 Ct = 60[log(100)-logC]C %Proteinat902.7454494336805.8146007805709.29411759916013.3109249775018.06179973984023.87640052033031.37272471682041.93820026021060A120B-26R1C = Co 10^(-k/ (t))C = Co 10^(-1/DT(t))logK = logko - Ea/238 (1/T)
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