cov (X,Y) != 0 does not imply X independent of Y Example. X ~ N(0,1) Y = X 2

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cov(X,Y) != 0 does not imply X independent of Y Example. X ~ N(0,1) Y = X 2 Cov(X,Y) = E(XY) – E(X) E(Y0 There is a time series variant

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cov (X,Y) != 0 does not imply X independent of Y Example. X ~ N(0,1) Y = X 2 Cov (X,Y) = E(XY) – E(X) E(Y0 There is a time series variant. - PowerPoint PPT Presentation

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Page 1: cov (X,Y) != 0 does not imply X independent of Y Example. X ~ N(0,1) Y = X 2

cov(X,Y) != 0 does not imply X independent of Y

Example.

X ~ N(0,1) Y = X2

Cov(X,Y) = E(XY) – E(X) E(Y0

There is a time series variant

Page 2: cov (X,Y) != 0 does not imply X independent of Y Example. X ~ N(0,1) Y = X 2
Page 3: cov (X,Y) != 0 does not imply X independent of Y Example. X ~ N(0,1) Y = X 2
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Page 5: cov (X,Y) != 0 does not imply X independent of Y Example. X ~ N(0,1) Y = X 2

A ligação Setúbal-Paris · 2009. 11. 11. · 17 Carbochemicals products and tars 0,1 0,1 0,1 0,1 0,0 0,1 18 Chemical products, except carbochemicals products and tars 13,3 8,5

A ligação Setúbal-Paris · 2009. 11. 11. · 17 Carbochemicals products and tars 0,1 0,1 0,1 0,1 0,0 0,1 18 Chemical products, except carbochemicals products and tars 13,3 8,5

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Special Products a(x + y + z) = ax + ay + az (x + y)(x – y) = x 2 – y 2 (x + y) 2 = x 2 + 2xy +y 2 (x – y) 2 = x 2 – 2xy +y 2 (x + y + z) 2 = x 2 + y.

Special Products a(x + y + z) = ax + ay + az (x + y)(x – y) = x 2 – y 2 (x + y) 2 = x 2 + 2xy +y 2 (x – y) 2 = x 2 – 2xy +y 2 (x + y + z) 2 = x 2 + y.

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C = x,y, ¿ = 0,1.

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