Course 2 Solving Multiplication Equations. Objectives Review vocabulary Review vocabulary Review...
-
Upload
julian-nelson -
Category
Documents
-
view
218 -
download
2
Transcript of Course 2 Solving Multiplication Equations. Objectives Review vocabulary Review vocabulary Review...
![Page 1: Course 2 Solving Multiplication Equations. Objectives Review vocabulary Review vocabulary Review solving equations by adding or subtracting Review solving.](https://reader036.fdocuments.in/reader036/viewer/2022082516/56649d755503460f94a5578a/html5/thumbnails/1.jpg)
Course 2
Solving Multiplication Equations
![Page 2: Course 2 Solving Multiplication Equations. Objectives Review vocabulary Review vocabulary Review solving equations by adding or subtracting Review solving.](https://reader036.fdocuments.in/reader036/viewer/2022082516/56649d755503460f94a5578a/html5/thumbnails/2.jpg)
Objectives
Review vocabulary Review solving equations by adding
or subtracting Solve multiplication equations using
Algebra tiles and paper and pencil Solve practical problems
![Page 3: Course 2 Solving Multiplication Equations. Objectives Review vocabulary Review vocabulary Review solving equations by adding or subtracting Review solving.](https://reader036.fdocuments.in/reader036/viewer/2022082516/56649d755503460f94a5578a/html5/thumbnails/3.jpg)
Review
Use the following to answer the questions:
6x + 5 – 3y = 12
Is it an equation, expression or an inequality? How do you know?
Identify the term(s). Identify the variable(s). Identify the constant(s). Identify the coefficient(s).
Equation, it has an equals sign
6x, 5, 3y and 12
x and y
5 and 12
6 and -3
![Page 4: Course 2 Solving Multiplication Equations. Objectives Review vocabulary Review vocabulary Review solving equations by adding or subtracting Review solving.](https://reader036.fdocuments.in/reader036/viewer/2022082516/56649d755503460f94a5578a/html5/thumbnails/4.jpg)
Review
Remember: Equations must be in balance, like a scale.
How would you solve this equation? x – 4 = 12
Use the opposite operation to undo the subtraction. x – 4 + 4 = 12 + 4 x = 16
![Page 5: Course 2 Solving Multiplication Equations. Objectives Review vocabulary Review vocabulary Review solving equations by adding or subtracting Review solving.](https://reader036.fdocuments.in/reader036/viewer/2022082516/56649d755503460f94a5578a/html5/thumbnails/5.jpg)
Let’s look at how to solve an a multiplication equation.
![Page 6: Course 2 Solving Multiplication Equations. Objectives Review vocabulary Review vocabulary Review solving equations by adding or subtracting Review solving.](https://reader036.fdocuments.in/reader036/viewer/2022082516/56649d755503460f94a5578a/html5/thumbnails/6.jpg)
Division Property of Equality
If you divide each side of an equation by the same nonzero number, the two sides remain equal.
![Page 7: Course 2 Solving Multiplication Equations. Objectives Review vocabulary Review vocabulary Review solving equations by adding or subtracting Review solving.](https://reader036.fdocuments.in/reader036/viewer/2022082516/56649d755503460f94a5578a/html5/thumbnails/7.jpg)
Let’s Try It!
1) 2x = -8
What is the coefficient in this equation?
What is the opposite (inverse) of multiplying by 2?
2
Dividing by 2
![Page 8: Course 2 Solving Multiplication Equations. Objectives Review vocabulary Review vocabulary Review solving equations by adding or subtracting Review solving.](https://reader036.fdocuments.in/reader036/viewer/2022082516/56649d755503460f94a5578a/html5/thumbnails/8.jpg)
2x = -8
Use the division property of equality: Divide both sides of the equation
by 22x = -82x = -8
2 2 x = -4
![Page 9: Course 2 Solving Multiplication Equations. Objectives Review vocabulary Review vocabulary Review solving equations by adding or subtracting Review solving.](https://reader036.fdocuments.in/reader036/viewer/2022082516/56649d755503460f94a5578a/html5/thumbnails/9.jpg)
2x = -8
Check: 2x = -8
Replace the variable with the solution:
2(-4) = -8 -8 = -8
![Page 10: Course 2 Solving Multiplication Equations. Objectives Review vocabulary Review vocabulary Review solving equations by adding or subtracting Review solving.](https://reader036.fdocuments.in/reader036/viewer/2022082516/56649d755503460f94a5578a/html5/thumbnails/10.jpg)
2) -5m = 40
What is the coefficient in this equation?
What is the opposite (inverse) of multiplying by -5?
Divide both sides of the equation by -5? -5m = 40 -5m = 40 -5 -5
m = -8
-5
Dividing by -5
![Page 11: Course 2 Solving Multiplication Equations. Objectives Review vocabulary Review vocabulary Review solving equations by adding or subtracting Review solving.](https://reader036.fdocuments.in/reader036/viewer/2022082516/56649d755503460f94a5578a/html5/thumbnails/11.jpg)
-5m = 40
Check -5m = 40
Replace the variable with the solution:
-5(-8) = 40 40 = 40
![Page 12: Course 2 Solving Multiplication Equations. Objectives Review vocabulary Review vocabulary Review solving equations by adding or subtracting Review solving.](https://reader036.fdocuments.in/reader036/viewer/2022082516/56649d755503460f94a5578a/html5/thumbnails/12.jpg)
3) 30 = 6n
What is the coefficient in this equation?
What is the opposite (inverse) of multiplying by 6?
Divide both sides of the equation by 6. 30 = 6n 30 = 6n
6 6 5 = n
6
Dividing by 6
![Page 13: Course 2 Solving Multiplication Equations. Objectives Review vocabulary Review vocabulary Review solving equations by adding or subtracting Review solving.](https://reader036.fdocuments.in/reader036/viewer/2022082516/56649d755503460f94a5578a/html5/thumbnails/13.jpg)
30 = 6n
Check 30 = 6n
Replace the variable with the solution:
30 = 6(5) 30 = 30
![Page 14: Course 2 Solving Multiplication Equations. Objectives Review vocabulary Review vocabulary Review solving equations by adding or subtracting Review solving.](https://reader036.fdocuments.in/reader036/viewer/2022082516/56649d755503460f94a5578a/html5/thumbnails/14.jpg)
4) 1.2x = -4.8
What is the coefficient in this equation?
What is the opposite (inverse) of multiplying by 1.2?
Divide both sides of the equation by 1.2. 1.2x = -4.8 1.2x = -4.8
1.2 1.2 x = -4
1.2
Dividing by 1.2
![Page 15: Course 2 Solving Multiplication Equations. Objectives Review vocabulary Review vocabulary Review solving equations by adding or subtracting Review solving.](https://reader036.fdocuments.in/reader036/viewer/2022082516/56649d755503460f94a5578a/html5/thumbnails/15.jpg)
1.2x = -4.8
Check 1.2x = -4.8
Replace the variable with the solution:
1.2(-4) = -4.8 -4.8 = -4.8
![Page 16: Course 2 Solving Multiplication Equations. Objectives Review vocabulary Review vocabulary Review solving equations by adding or subtracting Review solving.](https://reader036.fdocuments.in/reader036/viewer/2022082516/56649d755503460f94a5578a/html5/thumbnails/16.jpg)
5) -3y = 2
What is the coefficient in this equation? What is the opposite (inverse) of
multiplying by -3? Divide both sides of the equation by -3.
-3y = 2 -3y = 2
-3 -3 y =
3
2
Dividing by -3
-3
![Page 17: Course 2 Solving Multiplication Equations. Objectives Review vocabulary Review vocabulary Review solving equations by adding or subtracting Review solving.](https://reader036.fdocuments.in/reader036/viewer/2022082516/56649d755503460f94a5578a/html5/thumbnails/17.jpg)
-3y = 2
Check -3y = 2
Replace the variable with the solution:
-3( ) = 2 2 = 2
3
2
![Page 18: Course 2 Solving Multiplication Equations. Objectives Review vocabulary Review vocabulary Review solving equations by adding or subtracting Review solving.](https://reader036.fdocuments.in/reader036/viewer/2022082516/56649d755503460f94a5578a/html5/thumbnails/18.jpg)
Using an Equation to Solve a Problem
1) Sarah earns $5 per hour when she baby-sits. How many hours does she need to work to earn $75?
Write an equation: 5h = 75
Solve the equation: 5h = 75 5 5h = 15
Sarah must work 15 hours to earn $75.00.
![Page 19: Course 2 Solving Multiplication Equations. Objectives Review vocabulary Review vocabulary Review solving equations by adding or subtracting Review solving.](https://reader036.fdocuments.in/reader036/viewer/2022082516/56649d755503460f94a5578a/html5/thumbnails/19.jpg)
Using an Equation to Solve a Problem.
2) A 125 pound person uses 4.4 calories per minute when walking. How many minutes will it take this person to use 44 calories?
Write an equation: 4.4m = 44
Solve the equation: 4.4m = 44 4.4 4.4m = 10
A 125 pound person must walk for 10 minutes to use 44 calories.