Cost and Benefit
-
Upload
theodora-xena -
Category
Documents
-
view
29 -
download
0
description
Transcript of Cost and Benefit
Cost and Benefit
Avinash Kishore([email protected])
Based on notes from Andrew Foss
Economics 1661 / API-135
February 11, 2011Review Section
Agenda
Basic Econometrics
– Bi-variate regression
– Multivariate linear regression
– Special cases
Elasticity
Social Welfare Cost
Benefits
– Aggregation of Demand Curves
– Travelling Cost Method
2
Note: A good general reference on costs and benefits is EPA, Guidelines for Preparing Economic Analyses, September 2000 (link), Chapters 7 and 8
Measures of Central Tendency and Dispersion
Measures of Central Tendency: Mean
– Mean = ∑Xi /n
– Mean takes all data points into account
– Mean is sensitive to outliers. Outliers have a lot of weight on
mean
Measures of Dispersion
– Variance = (Xi – mean)2/N
– Standard Deviation =[(Xi – mu)2/N]1/2 = (Variance)1/2
More dispersed data have higher variance
– Like mean, standard deviation is also sensitive to outliers
3
It is possible that two datasets have the same mean but different standard deviations
4From Wikipedia
OLS regression (2 Variables) http://www.ats.ucla.edu/stat/Stata/examples/rwg/rwgstata2/rwgstata2.htm
5Y (wateruse) = 1201.124 + 47.54*income
Bi-variate Regression Model
Yi = β0 + β1Xi + εi
– i = each observation; Y = Dependent Variable (water use); X =
Independent Variable (income); εi = Error term
– β0 = intercept. It tells us the predicted value of Y when X = 0.
– β1 = The coefficient that tells us how Y changes for unit change
in X.
water81 Coef. Std. Err. t P>t [95% Conf. Interval]
income 47.54869 4.652286 10.22 0.000 38.40798 56.6894
_cons 1201.124 123.3245 9.74 0.000 958.8191 1443.43
– N = 496; R-square = 0.1745
3 Sources of Error Term:
– Omitted variables, Measurement error and Chance or
Randomness 6
Multiple Regression
More than one independent variables
– Yi = β0 + β1Xi1 + β2Xi
2 + β3Xi3 + εi
Now, β1 is the change in value of Y for a unit change in
X1 while holding constant (or controlling for) X2 and X3
(the marginal interpretation)
Example:. reg water81 income educat peop81 water81 Coef. Std. Err. t P>t [95% Conf. Interval]
income 32.05796 4.285087 7.48 0.000 23.63864 40.47729
educat -42.61099 17.23512 -2.47 0.014 -76.4745 -8.747484
peop81 480.5194 31.73071 15.14 0.000 418.175 542.8639
_cons 678.8889 245.195 2.77 0.006 197.1305 1160.647
N = 496, R-squared = 0.38
7
The Coefficient and the Confidence Interval (precision)
8
Some Special Cases: binary independent variables
Normally, continuous dependent and independent variables in OLS.
But we can also have binary independents. Also Dummy Variables.
– Βeta coefficient of a dummy variable is not interpreted as its slope.
Let there be a dummy variable Female s.t. Female = 1 for female
employees; 0 for male employees.
Regression equation: Earnings = β0 + β1*Female + εi
– Earnings = 16.99 – 3.45*Female + εi
Interpretation: Constant, β0 = Mean earning of men = 16.99
β1 = Difference in mean earnings of men and women. Here, β1 = -3.45. So,
mean earning of women = 16.99 – 3.45 = 13.44.
Multivariate Example:
– Earnings = β0 + β1 Years of Education + β2Female + εi
– Earnings = 15.55 + 3.00* Years of Education –3.55*Female
Show graphically 9
Special Cases: Interaction Terms
It is possible that both intercepts and slopes (returns per year of
education in this case) are different for two groups.
e.g. Earnning = β0 + β1Years of Education + β2Female + β3
Female*Years of Education + εi
So, for females: Earnings = β0 + β1Years of Education + β2*1 +
β3*1*Years of Education+ εi
= (β0 + β2) + (β1+ β3)*Years of Education+ εi
for males: Earnings = β0 + β1Years of Education + β2*0 + β3*0*
Years of Education + εi
= β0 + β1Years of Education + εi
So, for females, Slope = (β1+ β3) and Intercept = β0 + β2
For males, Slope = β1 and intercept = β0 10
We can also capture non-linear relations through linear regression
Quadratic: If the dependent variable is a parabolic
function of the independent, we can still capture the
relationship by adding a squared term, e.g.
Environmental Kuznets Curve hypothesis:
– Pollution = β0 + β1GDPPC + β2 (GDPPC)2 + εi
Categorical Dependent Variable (as in RUM)
– We get estimates of probability
– OLS is not appropriate in such cases
– Logit or probit models
11
Cost and Benefits
12
Costs Estimation Methods and Elasticity
Direct Compliance Cost Method
Partial Equilibrium Analysis (behavioral response)
General Equilibrium Analysis
Want to know how consumers and firms will react to
changes in prices for the good/service being regulated
Depends on price elasticity of supply and demand
Elasticity = % ΔQ/% ΔP = (ΔQ/Q)/ (ΔP/P) =
(ΔQ/ΔP)*(P/Q) = (1/Slope)*(P/Q)
Higher the elasticity, greater the behavioral response
to regulation and greater the social welfare cost.
13
If demand is very responsive to change in price, good is price elastic. If demand does not respond much to price changes, demand is price inelastic
14
Elasticity = ∞ Elasticity = 0
Social Welfare Costs
Illustration of social welfare costs
– Losses in consumer and producer surplus from increased
marginal cost across regulated industry
15Quantity
Price
D
MC0 = S0CS0
PS0
Quantity
Price
MC0 = S0
CS1
PS1
MC1 = S1
P0
Q0
P0
Q0
P1
Q1
Welfare Effects of Industry-Wide Increase in Marginal Cost
D
Benefits: Aggregation of Demand Curves (Private Goods)
16
Let’s say Q is a private good. Person 1 demand for Q is: Q1 = 100 – PPerson 2 demand for Q is : Q2 = 100 – PSo, what is the aggregate market demand for Q?
Algebraically, it is
QT = 200 – 2P
Note: The algebra and the graph won’t be this simple if demand functions are different
Benefits: Aggregation of Demand Curves (Public Goods)
17
Now assume Q is a public good (non-rivalrous and non-excludable)
Does that change how we aggregate demand curves?
Algebraically, it is
P = 200 – 2Q
You work with inverse demand curve
One more example: public park provision
There are 500 people in a locality
Each has demand function: Q = 100 – P
– P = $ price per unit area of park people are willing to pay for
Q sq. yards of the park preserved
– MC = $ 10,000/sq. yard
How many sq yard of park area should be preserved?
– P = 100 – Q
– Aggregate demand: P =500[100 – Q]
– or P = 50,000 – 500Q
50,000 – 500Q = 10,000, Q* = 80 sq. yards
What is the total benefit @ Q*? Net benefit = ? 18
Travel Cost Method:Example Problem
Ruritania is a country with three cities and a beautiful
park at its center
Environmental economists in Ruritania have collected
the following data on park visitors from the three cities
The environmental economists want to estimate the
recreational value (i.e., non-market use value) of the
park to the people of Ruritania
19
Origin Population Visitors Travel Cost
1 100,000 15,000 $12.50
2 750,000 75,000 $25.00
3 1,000,000 50,000 $37.50
Travel Cost Method:Example Problem
First calculate the visitation rate for each origin
20
Origin Population Visitors Visit Rate Travel Cost
1 100,000 15,000 0.15 $12.50
2 750,000 75,000 0.10 $25.00
3 1,000,000 50,000 0.05 $37.50
Travel Cost Method:Example Problem
Next plot the relationship between visitation rate and
travel cost and express it in an equation
21
TC = - (50 / 0.20) * R + 50 = -250 * R + 50
or
R = - (0.20 / 50) * TC + 0.2
= -0.004 * TC + 0.2$0
$10
$20
$30
$40
$50
0.00 0.05 0.10 0.15 0.20
Tra
ve
l Co
st
(TC
)
Visitation Rate (R)
Origin 3
Origin 2
Origin 1
Travel Cost Method:Example Problem
Suppose a fee were charged to enter the park
Calculate the relationship between Origin 1’s visitation
rate and the hypothetical fee
22
R = -0.004 * (TC + Fee) + 0.2
TC1 = 12.5
R1 = -0.004 * (12.5 + Fee) + 0.2
= -0.004 * Fee + 0.15
or
Fee = -250 * R1 + 37.5
$0
$10
$20
$30
$40
0.00 0.05 0.10 0.15 0.20
Hy
po
the
tic
al F
ee
Visitation Rate (R)
Origin 1
Travel Cost Method:Example Problem
Calculate the relationship between Origin 2’s visitation
rate and the hypothetical fee
23
R = -0.004 * (TC + Fee) + 0.2
TC2 = 25
R2 = -0.004 * (25 + Fee) + 0.2
= -0.004 * Fee + 0.10
or
Fee = -250 * R2 + 25
$0
$10
$20
$30
$40
0.00 0.05 0.10 0.15 0.20
Hy
po
the
tic
al F
ee
Visitation Rate (R)
Origin 2
Travel Cost Method:Example Problem
Calculate the relationship between Origin 3’s visitation
rate and the hypothetical fee
24
R = -0.004 * (TC + Fee) + 0.2
TC3 = 37.5
R3 = -0.004 * (37.5 + Fee) + 0.2
= -0.004 * Fee + 0.05
or
Fee = -250 * R3 + 12.5
$0
$10
$20
$30
$40
0.00 0.05 0.10 0.15 0.20
Hy
po
the
tic
al F
ee
Visitation Rate (R)
Origin 3
Travel Cost Method:Example Problem
Calculate the relationship between all three origins’
visitation rate and the hypothetical fee
25
R = -0.004 * (TC + Fee) + 0.2
R1 = -0.004 * Fee + 0.15
R2 = -0.004 * Fee + 0.10
R3 = -0.004 * Fee + 0.05$0
$10
$20
$30
$40
0.00 0.05 0.10 0.15 0.20
Hy
po
the
tic
al F
ee
Visitation Rate (R)
Origin 1 Origin 2 Origin 3
Travel Cost Method:Example Problem
Calculate the relationship between the number of
visitors from Origin 1 and the hypothetical fee
26
Per capita demand function:
R1 = -0.004 * Fee + 0.15
Population = 100,000
So, demand function is: = 100,000*(-0.004 * Fee + 0.15)
= -400 * Fee + 15,000
$0
$10
$20
$30
$40
0 30,000 60,000 90,000 120,000 150,000
Hy
po
the
tic
al F
ee
Visitors (Q)
Origin 1
Travel Cost Method:Example Problem
Calculate the relationship between the number of visitors
from Origin 2 and the hypothetical fee
27
Per capita demand function:R1 = -0.004 * Fee + 0.10
Population = 75,000
So, total demand function is: = 75,000*(-0.004 * Fee + 0.10)
Q2 = -3,000 * Fee + 75,000$0
$10
$20
$30
$40
0 30,000 60,000 90,000 120,000 150,000
Hy
po
the
tic
al F
ee
Visitors (Q)
Origin 2
Travel Cost Method:Example Problem
Calculate the relationship between the number of
visitors from Origin 3 and the hypothetical fee
28
Per capita demand function:R1 = -0.004 * Fee + 0.05
Population = 50,000
So, total demand is: = 50,000*(-0.004 * Fee + 0.05)Q3 = -4,000 * Fee + 50,000
$0
$10
$20
$30
$40
0 30,000 60,000 90,000 120,000 150,000
Hy
po
the
tic
al F
ee
Visitors (Q)
Origin 3
Travel Cost Method:Example Problem
– Aggregate curve (from horizontal summation) represents total
recreational demand as a function of hypothetic park fee
– 1st kink @ Fee = $25, Qagg = 5000
– 2nd kink @ Fee = $ 12.50, Qagg = 10,000 + 37,500 = 47,500
– X-intercept = 15,000 + 75,000 + 50,000 = 140,000
–
29
Q1 = -400 * Fee + 15,000
Q2 = -3,000 * Fee + 75,000
Q3 = -4,000 * Fee + 50,000
$0
$10
$20
$30
$40
0 30,000 60,000 90,000 120,000 150,000
Hy
po
the
tic
al F
ee
Visitors (Q)
Origin 1 Origin 2 Origin 3 Aggregate
Travel Cost Method:Example Problem
Calculate recreational value as area under the
aggregate curve
– The recreational value of the park is $1,531,250
30
Area A = ½ * (37.5 - 25) * 5,000 = 31,250
Area B = ½ * (25 - 12.5) *(5,000 + 47,500)
= 328,125
Area C = ½ * (12.5 - 0) *(47,500 + 140,000)
= 1,171,875
Total Area = 1,531,250
$0
$10
$20
$30
$40
0 30,000 60,000 90,000 120,000 150,000
Hy
po
the
tic
al F
ee
Visitors (Q)
Aggregate
Area A
Area B
Area C
Travel Cost Method:Example Problem
Calculate recreational value as area under each of the
origin-specific demand curves (alternative method)
– The recreational value of the park is $1,531,250
31
Area 1 = ½ * 37.5 * 15,000 = 281,250
Area 2 = ½ * 25 * 75,000 = 937,500
Area 3 = ½ * 12.5 * 50,000 = 312,500
Total Area = 1,531,250
$0
$10
$20
$30
$40
0 30,000 60,000 90,000 120,000 150,000
Hy
po
the
tic
al F
ee
Visitors (Q)
Origin 1 Origin 2 Origin 3
Area 1
Area 2Area 3
Travel Cost Method:Example Problem
Calculate the number of visitors and consumer surplus
if no fee were charged to enter the park
– Total park visitation is 15,000 + 75,000 + 50,000 = 140,000
– CS is equal to recreational value: $1,531,250
32
Travel Cost Method:Example Problem
Calculate the number of visitors and consumer surplus
if a fee of $20 were charged to enter the park
– Total park visitation is 7,000 (Or. 1) + 15,000 (Or. 2) = 22,000
– CS is area below demand curve and above price: $98,750
33
Area A = ½ * (37.5 - 25) * 5,000 = 31,250
Area D = ½ * (25 - 20) * (5,000 + 22,000) = 67,500
Total Area = 98,750$0
$10
$20
$30
$40
0 30,000 60,000 90,000 120,000 150,000
Hy
po
the
tic
al F
ee
Visitors (Q)
Aggregate
Area A
Area DFee = $20
Benefits: Mid-term 2005
The City of Miami, Florida proposes to invest in a new water reservoir for its public water
system, and estimates its cost. To justify this substantial expenditure of public funds, the
Mayor explains that if the new reservoir is not constructed then the next most costly way to
increase Miami’s water supply will be to invest in a desalinization plant, which will be even
more expensive. Hence, the Mayor explains, the social benefits of building the new reservoir
clearly exceed its social costs. There are no environmental or other externalities involved with
either alternative. How would you assess this reasoning from an economic perspective?
34
– This is the “avoided cost” method of evaluating benefits.
It is incorrect because it ignores demand for the public good
(water), i.e., water’s real benefits to the society.
AvoidedCosts
Willingnessto Pay
Willingnessto Accept
To Be Continued…
Next time: More on benefit estimation methods
35