Corrigendum to “A Fourier type transform on translation invariant valuations on convex sets”
Transcript of Corrigendum to “A Fourier type transform on translation invariant valuations on convex sets”
ISRAEL JOURNAL OF MATHEMATICS xxx (2014), 1–2
DOI: 10.1007/s11856-014-0018-2
CORRIGENDUM TO “A FOURIER TYPE TRANSFORMON TRANSLATION INVARIANT VALUATIONS
ON CONVEX SETS”
BY
Semyon Alesker
Department of Mathematics, Tel aviv University, Ramat Aviv, Tel Aviv 69978, Israel
e-mail: [email protected]
In Example 0.1.5 of the paper [1], there was given an incorrect explicit
description of the Fourier transform FV on 1-homogeneous valuations on a
two-dimensional vector space V (while the description of FV on 0- and 2-
homogeneous valuations was correct). This description was not used anywhere
in the paper and does not affect any of the other results and statements.
We present now a correct description. Any valuation φ ∈ V alsm1 (V ) can be
written uniquely in the form
φ(K) =
∫S1
h(ω)dS1(K,ω),
where h : S1 → C is a smooth function which is orthogonal on the unit circle
S1 to the two dimensional space of linear functionals. Let us decompose h to
the even and odd parts:
h = h+ + h−.
We decompose further the odd part h− to “holomorphic” and “anti-holomo-
rphic” parts,
h− = hhol− + hanti
− ,
as follows. Let us decompose h− to the usual Fourier series on the circle S1:
h−(ω) =∑k
h−(k)eikω .
Received January 30, 2013
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2 S. ALESKER Isr. J. Math.
Then by definition
hhol− (ω) :=
∑k>0
h−(k)eikω and hanti− (ω) :=
∑k<0
h−(k)eikω .
Hence the Fourier transform of the valuation φ is equal to
(FV φ)(K) =
∫S1
(h+(Jω) + hhol− (Jω))dS1(K,ω)−
∫S1
hanti− (Jω)dS1(K,ω),
where J is the rotation of R2 by π/2, counterclockwise.
References
[1] S. Alesker, A Fourier type transform on translation invariant valuations on convex sets,
Israel Journal of Mathematics 181 (2011), 189–294.