Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 1 Chapter 6 Polynomial...
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Transcript of Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 1 Chapter 6 Polynomial...
![Page 1: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 1 Chapter 6 Polynomial Functions.](https://reader035.fdocuments.in/reader035/viewer/2022070415/5697c02a1a28abf838cd8382/html5/thumbnails/1.jpg)
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 1
Chapter 6Polynomial Functions
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 2
6.4 Factoring Trinomials of the Form x2 + bx + c; Factoring Out the GCF
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 3
Comparing Multiplying with Factoring
Multiplying and factoring are reverse processes. For example,
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 4
Factoring a Trinomial of the Form x2 + bx + c
To see how to factor x2 + 5x + 6, let’s take another look at how we find the product (x + 2)(x + 3):
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 5
Example: Factoring a Trinomial of the Form x2 + bx + c
Factor x2 + 11x + 24.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 6
Solution
We need two integers whose product is 24 and whose sum is 11.
Since 3(8) = 24 and 3 + 8 = 11, we conclude that the last terms of the factors are 3 and 8.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 7
Solution
x2 + 11x + 24 = (x + 3)(x + 8)
Check by finding the product of the result:
(x + 3)(x + 8) = x2 + 8x + 3x + 24 = x2 + 11x + 24
By the commutative law, (x + 3)(x + 8) = (x + 8)(x + 3),
so we can write the factors in either order.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 8
Factoring x2 + bx + c
To factor x2 + bx + c, look for two integers p and q whose product is c and whose sum is b. That is pq = c and p + q = b. If such integers exist, the factored polynomial is
(x + p)(x + q)
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 9
Factoring x2 + bx + c with c Positive
To factor a trinomial of the form x2 + bx + c with a positive constant term c,
• If b is positive, look for two positive integers whose product is c and whose sum is b. For example,
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 10
Factoring x2 + bx + c with c Positive
• If b is negative, look for two negative integers whose product is c and whose sum is b. For example,
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 11
Example: Factring a Trinomial of the Form x2 + bx + c
Factor w2 – 3w – 18.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 12
Solution
We need two integers whose product is –18 and whose sum is –3. Since the product is negative, the two integers must have difference signs. Here are the possibilities:
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 13
Solution
Since 3(–6) = –18 and 3 + (–6) = –3, we conclude that the last terms of the factors are 3 and –6.
(w + 3)(w – 6)
Check by finding the product:
(w + 3)(w – 6) = w2 – 6w + 3w – 18 = w2 – 3w – 18
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 14
Factoring x2 + bx + c with c Negative
To factor a trinomial of the form x2 + bx + c with a negative constant term c, look for two integers with different signs whose product is c and whose sum is b. For example,
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 15
Example: Factoring a Trinomial with Two Variables
Factor a2 + 6ab + 8b2.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 16
Solution
Write the trinomial in the form a2 + (6b)a + 8b2. We need two monomials whose product is 8b2 and whose sum is 6b. So, the last two terms are 2b and 4b.
a2 + 6ab + 8b2 = (a + 2b)(a + 4b)
Check by finding the product.
(a + 2b)(a + 4b) = a2 + 6ab + 8b2
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 17
Prime Polynomials
Just as a prime number has no positive factors other than itself and 1, a polynomial that cannot be factored is called prime.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 18
Example: Identifying a Prime Polynomial
Factor –14 + 6x + x2.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 19
Solution
Write the polynomial in descending order:
x2 + 6x – 14
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 20
SolutionWe need two integers whose product is –14 and whose sum is 6. Since the product is negative, the integers must have different signs. Here are the possibilities:
Because none of the sums equal 6, we conclude that the trinomial is prime.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 21
Factoring Out the GCF
Definition
The greatest common factor (GCF) of two or more terms is the monomial with the largest coefficient and the highest degree that is a factor of all the terms.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 22
Example: Factoring Out the GCF
Factor 18x4 – 30x2.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 23
Solution
Begin by factoring 18x4 and 30x2:
18x4 = 2 ∙ 3 ∙ 3 ∙ x ∙ x ∙ x ∙ x30x2 = 2 ∙ 3 ∙ 5 ∙ x ∙ x
There are four common factors, shown in blue. So, the GCF is 6x2:
2 224 218 30 6 63 5xx x xx 2 236 5x x
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 24
Solution
Use a graphing calculator table to verify our work.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 25
Example: Completely Factoring a Polynomial
Factor 3x3 + 21x2 + 36x.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 26
Solution
The GCF is 3x:
3x3 + 21x2 + 36x = 3x(x2 + 7x + 12)
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 27
SolutionTemporarily put aside the GCF, 3x.
To factor x2 + 7x + 12, we need two integers whose product is 12 and whose sum is 7:
Because 3(4) = 12 and 3 + 4 = 7, we conclude that the last terms of the factors are 3 and 4.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 28
Solution
2 7 12 ( 3 4)( )x x x x
So,
3 2 23 21 36 3 7 12 3 ( 3)( 4)x x x x x x x x x
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 29
Factor Out the GCF First
In general, when the leading coefficient of a polynomial is positive and the GCF is not 1, first factor out the GCF.
But, don’t forget to include the GCF as part of your answer!
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 30
Factoring Completely
Warning
When factoring a polynomial, always completely factor it.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 31
Factoring when the Leading Coefficient is Negative
When the leading coefficient of a polynomial is negative, first factor out the opposite of the GCF.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 32
Example: Factoring Out the Opposite of the GCF
Factor –2r4 + 18r3 – 40r2.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 33
Solution
For this polynomial, the GCF is 2r2. The leading coefficient of –2r4 + 18r3 – 40r2 is –2, which is negative. So, first factor out the opposite of the GCF:
4 3 2 2 22 18 40 2 9 20r r r r r r 22 ( 5)( 4)r r r
![Page 34: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 1 Chapter 6 Polynomial Functions.](https://reader035.fdocuments.in/reader035/viewer/2022070415/5697c02a1a28abf838cd8382/html5/thumbnails/34.jpg)
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 34
Solution
Use a graphing calculator table to verify our work.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.4, Slide 35
Summary
1. If the leading coefficient of a polynomial is positive and the GCF is not 1, first factor out the GCF. If the leading coefficient is negative, first factor out the opposite of the GCF.
2. Always completely factor a polynomial.