Copyright 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 1 Chapter 1 Linear Equations...
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Transcript of Copyright 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 1 Chapter 1 Linear Equations...
![Page 1: Copyright 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 1 Chapter 1 Linear Equations and Linear Functions.](https://reader035.fdocuments.in/reader035/viewer/2022081507/5a4d1b747f8b9ab0599b6a4f/html5/thumbnails/1.jpg)
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 1
Chapter 1Linear Equations and Linear Functions
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 2
1.4 Meaning of Slope for Equations, Graphs, and
Tables
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 3
Example: Finding the Slope of a Line
Find the slope of the line y = 2x + 1.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 4
SolutionWe use x = 0, 1, 2, 3 in the table to list the solutions, and sketch the graph of the equation.
If the run is 1, the rise is 2. So the slope is
runr 2e .
1is 2m
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 5
Finding the Slope from a Linear Equation of the Form y = mx + b
For a linear equation of the form y = mx + b, m is the slope of the line.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 6
Example: Identifying Parallel or Perpendicular Lines
Are the lines and 12y – 10x = 5 parallel, 5 36
y x
perpendicular, or neither?
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 7
Solution
For the line the slope is3,56
y x 56
.
For 12y – 10x = 5, the slope is not –10. To find the slope, we must solve the equation for y:
12 10 5y x
1012 10 105xy x x
12 10 5y x
12 1012 1 2
52 1
y x
5 56 12
y x
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 8
Solution
For the slope is the same as the 12
56
5 ,y x 56
,
slope of the line Therefore, the two 3.56
y x
lines are parallel. We use a graphing calculator to draw the lines on the same coordinate system.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 9
Vertical Change Property
For a line y = mx + b, if the run is 1, then the rise is the slope m.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 10
Finding the y-intercept from a Linear Equation of the Form y = mx + b
For a linear equation of the form y = mx + b, the y-intercept is (0, b).
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 11
Slope-intercept form
Definition
If an equation is of the form y = mx + b, we say it is in slope-intercept form.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 12
Example: Using Slope to Graph a Linear Equation
Sketch the graph of y = 3x – 1.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 13
Solution
Note that the y-intercept is (0, –1) and that theslope is To graph, 3 rise3 .
1 run
1. Plot the y-intercept, (0, –1).2. From (0, –1), look 1 unit to the right and 3
units up to plot a second point. (see the next slide)
3. Sketch the line that contains these two points. (see the next slide)
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 14
Solution
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 15
Using Slope to Graph a Linear Equation of the Form y = mx + b
To sketch the graph of a linear equation of the form y = mx + b.
1. Plot the y-intercept (0, b).
2. Use to plot a second point.
3. Sketch the line that passes through the two plotted points.
riserun
m
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 16
Using Slope to Graph a Linear Equation
Warning
Before we can use the y-intercept and the slope to graph a linear equation, we must solve for y to put the equation into the form y = mx + b.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 17
Example: Working with a General Linear Equation
1. Determine the slope and the y-intercept of the graph of ax + by = c, where a, b, and c are constants and b is nonzero.
2. Find the slope and the y-intercept of the graph of 3x + 7y = 5.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 18
Solution
1. ax by c axax axby c by ax c by a cb b
xb
a cy xb b
The slope is and the y-intercept is ,ab
0, .cb
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 19
Solution
2. We substitute 3 for a, 7 for b, and 5 for c in our results from Problem 1 to find that the slope is3
7 and the y-intercept is
50, .7
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 20
Slope Addition Property
For a linear equation of the form y = mx + b, if the value of the independent variable increases by 1, then the value of the dependent variable changes by the slope m.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 21
Example: Identifying Possible Linear Equations
Four sets of points are shown on the next slide. For each set, decide whether there is a line that passes through every point. If so, find the slope of that line. If not, decide whether there is a line that comes close to every point.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 22
Example: Identifying Possible Linear Equations
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 23
Solution
1. For set 1, when the value of x increases by 1, the value of y changes by –3. So, a line with slope –3 passes through every point.
2. For set 2, when the value of x increases by 1, the value of y changes by 5. Therefore, a line with slope 5 passes through every point.
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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 1.4, Slide 24
Solution
3. For set 3, when the value of x increases by 1, the y value does not change. Further, a line does not come close to every point, because the value of y changes by such different amounts each time the value of x increases by 1.
4. For set 4, when the value of x increases by 1, the value of y changes by 0. Therefore, a line with slope 0 (the horizontal line y = 8) passes through every point.