Copyright © 2009 Pearson Addison-Wesley 8.6-1 8 Applications of Trigonometry.
-
Upload
garett-roberts -
Category
Documents
-
view
218 -
download
0
Transcript of Copyright © 2009 Pearson Addison-Wesley 8.6-1 8 Applications of Trigonometry.
Copyright © 2009 Pearson Addison-Wesley 8.6-1
8Applications of Trigonometry
Copyright © 2009 Pearson Addison-Wesley 8.6-2
8.1 The Law of Sines8.2 The Law of Cosines8.3 Vectors, Operations, and the Dot Product8.4 Applications of Vectors8.5 Trigonometric (Polar) Form of Complex
Numbers; Products and Quotients8.6 De Moivre’s Theorem; Powers and Roots of
Complex Numbers8.7 Polar Equations and Graphs8.8 Parametric Equations, Graphs, and
Applications
8 Applications of Trigonometry
Copyright © 2009 Pearson Addison-Wesley
1.1-3
8.6-3
De Moivre’s Theorem; Powers and Roots of Complex Numbers
8.6
Powers of Complex Numbers (De Moivre’s Theorem) ▪ Roots of Complex Numbers
Copyright © 2009 Pearson Addison-Wesley
1.1-4
8.6-4
De Moivre’s Theorem
is a complex number, then
In compact form, this is written
Copyright © 2009 Pearson Addison-Wesley
1.1-5
8.6-5
r=√𝑎2+𝑏2 , tan θ=𝑏𝑎
Remember the following:
Copyright © 2009 Pearson Addison-Wesley
1.1-6
8.6-6
Example 1 FINDING A POWER OF A COMPLEX NUMBER
Find and express the result in rectangular form.
First write in trigonometric form.
Because x and y are both positive, θ is in quadrant I, so θ = 60°.
Copyright © 2009 Pearson Addison-Wesley
1.1-7
8.6-7
Example 1 FINDING A POWER OF A COMPLEX NUMBER (continued)
Now apply De Moivre’s theorem.
480° and 120° are coterminal.
Rectangular form
Copyright © 2009 Pearson Addison-Wesley
1.1-8
8.6-8
nth Root
For a positive integer n, the complex number a + bi is an nth root of the complex number x + yi if
Copyright © 2009 Pearson Addison-Wesley
1.1-9
8.6-9
nth Root Theorem
If n is any positive integer, r is a positive real number, and θ is in degrees, then the nonzero complex number r(cos θ + i sin θ) has exactly n distinct nth roots, given by
where
Copyright © 2009 Pearson Addison-Wesley
1.1-10
8.6-10
Note
In the statement of the nth root theorem, if θ is in radians, then
Copyright © 2009 Pearson Addison-Wesley
1.1-11
8.6-11
Example 2 FINDING COMPLEX ROOTS
Find the two square roots of 4i. Write the roots in rectangular form.
Write 4i in trigonometric form:
The square roots have absolute value and argument
Copyright © 2009 Pearson Addison-Wesley
1.1-12
8.6-12
Example 2 FINDING COMPLEX ROOTS (continued)
Since there are two square roots, let k = 0 and 1.
Using these values for , the square roots are
Copyright © 2009 Pearson Addison-Wesley
1.1-13
8.6-13
Example 2 FINDING COMPLEX ROOTS (continued)
Copyright © 2009 Pearson Addison-Wesley
1.1-14
8.6-14
Example 3 FINDING COMPLEX ROOTS
Find all fourth roots of Write the roots in rectangular form.
Write in trigonometric form:
The fourth roots have absolute value and argument
Copyright © 2009 Pearson Addison-Wesley
1.1-15
8.6-15
Example 3 FINDING COMPLEX ROOTS (continued)
Since there are four roots, let k = 0, 1, 2, and 3.
Using these values for α, the fourth roots are 2 cis 30°, 2 cis 120°, 2 cis 210°, and 2 cis 300°.
Copyright © 2009 Pearson Addison-Wesley
1.1-16
8.6-16
Example 3 FINDING COMPLEX ROOTS (continued)
Copyright © 2009 Pearson Addison-Wesley
1.1-17
8.6-17
Example 3 FINDING COMPLEX ROOTS (continued)
The graphs of the roots lie on a circle with center at the origin and radius 2. The roots are equally spaced about the circle, 90° apart.
Copyright © 2009 Pearson Addison-Wesley
1.1-18
8.6-18
Example 4 SOLVING AN EQUATION BY FINDING COMPLEX ROOTS
Find all complex number solutions of x5 – i = 0. Graph them as vectors in the complex plane.
There is one real solution, 1, while there are five complex solutions.
Write 1 in trigonometric form:
Copyright © 2009 Pearson Addison-Wesley
1.1-19
8.6-19
Example 4 SOLVING AN EQUATION BY FINDING COMPLEX ROOTS (continued)
The fifth roots have absolute value and argument
Since there are five roots, let k = 0, 1, 2, 3, and 4.
Solution set: {cis 0°, cis 72°, cis 144°, cis 216°, cis 288°}
Copyright © 2009 Pearson Addison-Wesley
1.1-20
8.6-20
Example 4 SOLVING AN EQUATION BY FINDING COMPLEX ROOTS (continued)
The graphs of the roots lie on a unit circle. The roots are equally spaced about the circle, 72° apart.
Copyright © 2009 Pearson Addison-Wesley
1.1-21
8.6-21