Coordination Compounds - Potassium Permanganate Hybridisation - Chemistry Stack Exchange

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sign up log in tour help Take the 2-minute tour × Chemistry Stack Exchange is a question and answer site for scientists, academics, teachers and students. It's 100% free, no registration required. Potassium permanganate hybridisation I'm clear with the concepts of crystal field theory. But I can't point out the exact reason why is the hybridisation of potassium permanganate ( ) is . Can anyone explain please? coordination-compounds edited Dec 23 '13 at 17:32 Ben Norris 12.9k 18 59 asked Dec 23 '13 at 11:58 Devgeet Patel 207 12 2 Answers This is a formally Mn(VII) compoud and hence there are no 3d electrons. The four ions are considered to be donating two electrons each to the Atomic Orbitals. Now most chemists didn't realize that tetrahedral "hybridization" can be achieved by using the 4s,3dxy,3dyz, and 3dxz AOs. Since in Mn(VII) the 3d AOs are lower in energy than the 4s and 4p AOs the "hybridization" is best considered as d^3s. I have put "hybridization" in quotes because it is not used in advanced chemistry (it is an artifact!) but it is correct in saying that the bonding MOs contain mostly 4s,3dxy,3dyz, 3dxz character but they'll also probably mix some 4p character in there for good measure! edited Jan 29 at 2:11 Satwik Pasani 2,327 1 5 27 answered Jan 28 at 16:05 Vatsal Patel 36 3 yes because there is d3s hybridisation in this complex and in d3s hybridisation only dxy, dyz and dzx atomic orbitals can only participates in this hybridisation so only three AO's out of five are utilised in this and according to CFT energy difference between t2g and next s orbital is less so hybridisation can be easily occurs answered Dec 31 '13 at 5:51 bhargav dave 21 1

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    Potassium permanganate hybridisation

    I'm clear with the concepts of crystal field theory. But I can't point out the exact reason why is the hybridisation of potassium permanganate () is . Can anyone explain please?,.O0

    /

    coordination-compounds

    edited Dec 23 '13 at 17:32Ben Norris12.9k 18 59

    asked Dec 23 '13 at 11:58Devgeet Patel207 12

    2 Answers

    This is a formally Mn(VII) compoud and hence there are no 3d electrons. The four ions areconsidered to be donating two electrons each to the Atomic Orbitals. Now most chemists didn'trealize that tetrahedral "hybridization" can be achieved by using the 4s,3dxy,3dyz, and 3dxz AOs.Since in Mn(VII) the 3d AOs are lower in energy than the 4s and 4p AOs the "hybridization" is bestconsidered as d^3s. I have put "hybridization" in quotes because it is not used in advancedchemistry (it is an artifact!) but it is correct in saying that the bonding MOs contain mostly4s,3dxy,3dyz, 3dxz character but they'll also probably mix some 4p character in there for goodmeasure!

    0

    .O

    edited Jan 29 at 2:11Satwik Pasani2,327 1 5 27

    answered Jan 28 at 16:05Vatsal Patel36 3

    yes because there is d3s hybridisation in this complex and in d3s hybridisation only dxy, dyz anddzx atomic orbitals can only participates in this hybridisation so only three AO's out of five areutilised in this and according to CFT energy difference between t2g and next s orbital is less sohybridisation can be easily occurs

    answered Dec 31 '13 at 5:51bhargav dave21 1