Connecting Algebra and Geometry through Coordinates...
Transcript of Connecting Algebra and Geometry through Coordinates...
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Unit 6 Lesson 1 – Part I
Connecting Algebra and Geometry
through Coordinates
Slope & Distance
By PresenterMedia.com
AKS 32: Prove simple geometric theorems algebraically using coordinates.
KEY CONCEPTS
Distance on a Number Line
• To find the distance between two points, a and b, on
a number line, find the absolute value of the
difference of a and b. This can be expressed
algebraically as |a – b| or |b – a|.
• For example, to find the distance between –4 and 5,
take the absolute value of the difference of –4 and 5.
• |–4 – 5| = |–9| = 9 or |5 – –4| = |5 + 4| = |9| = 9
• The distance between the numbers –4 and 5 is 9
units.
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KEY CONCEPTS
Pythagorean Theorem
• To find the distance between two points on a coordinate
system, we must use the Pythagorean Theorem.
• Right triangles are triangles with one right (90˚) angle.
• The side that is the longest and is always across from the
right angle is called the hypotenuse.
• The two shorter sides are referred to as the legs of the
right triangle.
KEY CONCEPTS - Pythagorean Theorem
• We can use the Pythagorean Theorem to calculate the length of any
one of the three sides.
• For example, to find the length of the hypotenuse of a triangle with
legs of 5 and 7 units, we use the Pythagorean Theorem.
• a2 + b2 = c2 Pythagorean Theorem
• 52+ 72 = c2 Substitute known values.
• 25 + 49 = c2 Simplify.
• 74 = c2 Simplify.
• √74 = √c2 Take the square root of both sides of the
equation.
• c =74 ≈8.6 The length of the hypotenuse of the right
triangle with side lengths 5 and 7 is 74 , or
approximately 8.6 units.
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KEY CONCEPTS
Pythagorean Theorem
EXAMPLE 1 Use the Pythagorean Theorem to calculate the distance
between the points (2,5) and (-4, -3).
STEP 1: Plot the points on a coordinate system.
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EXAMPLE 1 (cont.)Use the Pythagorean Theorem to calculate the distance between
the points (2,5) and (-4, -3).
STEP 2: Draw lines to form a right triangle, using each
point as the end of the hypotenuse.
EXAMPLE 1 (cont.)Use the Pythagorean Theorem to calculate the distance between
the points (2,5) and (-4, -3).
• STEP 3: Calculate the length of the vertical side, a,
of the right triangle.
• Let (x1, y1) = (2, 5) and (x2, y2) = (-4, -3)
• |y2-y1| = |-3-5| = |-8| = 8
• The length of side a is 8 units.
• STEP 4: Calculate the length of the horizontal side,
b, of the right triangle.
• |x2 – x1| = |–4 – 2| = |–6| = 6
• The length of side b is 6 units.
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EXAMPLE 1 (cont.)Use the Pythagorean Theorem to calculate the distance between
the points (2,5) and (-4, -3).
• STEP 5: Use the Pythagorean Theorem to calculate the
length of the hypotenuse, c.
• a2 + b2 = c2 Pythagorean Theorem
• 82 + 62 = c2 Substitute values for a and b.
• 64 + 36 = c2 Simplify each term.
• 100 = c2 Simplify.
• √100 = √c2 Take the square root of both sides
• 10 = c
• The distance between the points (2, 5) and (–4, –3) is 10
units.
EXAMPLE 2Tyler and Arsha have mapped out locations for a game of manhunt. Tyler’s position is
represented by the point (–2, 1). Arsha’s position is represented by the point (–7, 9).
Each unit is equivalent to 100 feet. What is the approximate distance between Tyler
and Arsha?
STEP 1: Plot the points on a coordinate system.
STEP 2: Draw lines to form a right triangle, using each point as the end
of the hypotenuse.
STEP 3: Calculate the length of the vertical side, a, of the right triangle.
STEP 4: Calculate the length of the horizontal side, b, of the right
triangle.
STEP 5: Use the Pythagorean Theorem to calculate the length of the
hypotenuse, c.
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EXAMPLE 2 (cont.)Tyler and Arsha have mapped out locations for a game of manhunt. Tyler’s position is
represented by the point (–2, 1). Arsha’s position is represented by the point (–7, 9). Each unit
is equivalent to 100 feet. What is the approximate distance between Tyler and Arsha?
EXAMPLE 3Kevin is standing 2 miles due north of the school. James is standing 4
miles due west of the school. What is the distance between Kevin and
James?