ConcepTest 6 Followup

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Which cannon ball hits the ground first? ConcepTest 6 Followup ConcepTest 6 Followup A. Cannon Ball A B. Cannon Ball B C. Both cannon balls hit the ground at the same time. A B Marker y 1 2 gt 2 v 0 y t y 0 0 = -0.5*9.8t 2 + V oy t, 4.9t 2 - V 0 sin()t = 0. t{4.9t - V 0 sin()}= 0. Thus, t = 0 or t = V 0 sin()/4.9

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ConcepTest 6 Followup. 0 = -0.5*9.8t 2 + V oy t, 4.9t 2 - V 0 sin( q )t = 0. t{4.9t - V 0 sin( q )}= 0. Thus, t = 0 or t = V 0 sin( q )/4.9. Which cannon ball hits the ground first?. Cannon Ball A Cannon Ball B Both cannon balls hit the ground at the same time. B. A. Marker. y. - PowerPoint PPT Presentation

Transcript of ConcepTest 6 Followup

Page 1: ConcepTest 6 Followup

Which cannon ball hits the ground first?

ConcepTest 6 FollowupConcepTest 6 Followup

A. Cannon Ball AB. Cannon Ball BC. Both cannon balls hit

the ground at the same time.

A

B

Marker

y 1

2gt 2 v0yt y0 0 = -0.5*9.8t2 + Voyt,

4.9t2 - V0sin()t = 0.t{4.9t - V0sin()}= 0.

Thus, t = 0 or t = V0sin()/4.9

Page 2: ConcepTest 6 Followup

Example Problem #3.21

(a) Basically means, “Find value of y when x = 2.1 m.”

Find time when x = 2.1 m: x = 2.1 m = x0 + v0xt = 0 + v0xt t = 2.1 m / 3.2 m/s t = 0.656 s

Now substitute this into equation for y: y = y0 + voyt – 0.5gt2

y = 0 + (5.54 m/s)(0.656 s) – 0.5(9.8 m/s2)(0.656 s)2 = 1.53 m

y

x

y = ?

x = 2.1 m

600

v0 = 6.4 m/sv0x = v0cos600 = 3.2 m/s

v0y = v0sin600 = 5.54 m/s

(b) vy = v0y – gt = 5.54 m/s – (9.8 m/s2)(0.656 s) = –0.89 m/s

Page 3: ConcepTest 6 Followup

Example Problem #4.10Free-body diagram:

x

y

N

W

F = 80 N

(a) Fx = max Fy = may = 0 (no motion in y – direction)

F = max N – W = 0 N = W

All acceleration is in the x – direction , so use

atotal = ax = 2(x – x0) / t2.