Comparison of 5 Stopping Rules and 2 LD50 Estimators: Appx L ...

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Comparison of 5 Stopping Rules and 2 LD50 Estimators Using Monte Carlo Simulation David Farrar, March 2000 Attached are graphs presented at an ICCVAM meeting in January 2000. Note the following: 1. For these graphs, the maximum number that could be tested was set at 25. Currently we propose to set the maximum at 15. 2. The test doses were not constrained to a range such as 1 to 5000 units, as in later simulations and as in our current guideline proposal. 3. The graphs include consideration of 2 stopping rules that were subsequently abandoned. The number of stopping rules has been retained, so that Rules number 1, 2, and 5 in later work correspond to the procedures here with the same numbers. 4. While here we do illustrate the use of an LR stopping rule, it is not precisely the rule proposed in the current guideline. The procedure in the current guideline is more simple, uses fewer animals, and results in better precision. D. Farrar - January 2000 H-1

Transcript of Comparison of 5 Stopping Rules and 2 LD50 Estimators: Appx L ...

Page 1: Comparison of 5 Stopping Rules and 2 LD50 Estimators: Appx L ...

Comparison of 5 Stopping Rules and 2 LD50 Estimators Using Monte Carlo Simulation

David Farrar, March 2000

Attached are graphs presented at an ICCVAM meeting in January 2000.

Note the following:

1. For these graphs, the maximum number that could be tested was set at 25. Currently we propose to set the maximum at 15.

2. The test doses were not constrained to a range such as 1 to 5000 units, as in later simulations and as in our current guideline proposal.

3. The graphs include consideration of 2 stopping rules that were subsequently abandoned. The number of stopping rules has been retained, so that Rules number 1, 2, and 5 in later work correspond to the procedures here with the same numbers.

4. While here we do illustrate the use of an LR stopping rule, it is not precisely the rule proposed in the current guideline. The procedure in the current guideline is more simple, uses fewer animals, and results in better precision.

D. Farrar - January 2000 H-1

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LD50 Estimators Evaluated:

• Maximum likelihood estimator, slope = 2 • • Geometric average dose (animals at/following reversal).

Stopping Rules Evaluated:

1. Fixed nominal sample size of 6

2. Stop after 5 reversals.

3a. Convergence of estimators:

0.5 < [estimate 1] / [estimate 2] < 2

estimate 1 = geometric average dose; estimate 2 = MLE with slope=0.5

3b. Like 3a but "factor" of #5 instead of #2.

4. For H:LD50=GM versus H:LD50=GM/2 (or H:LD50=GM*2),

profile likelihood ratio = 2

• Nominal sample size = 6; Number tested capped at 15 or 25

Performance Measurement based on Monte Carlo

• Bias index

median estimate / true value

?Acceptable . 0.8 - 1.2 X (or .20% bias)

• Spread Index

Ratio of high and low percentiles P95 / P5

?Acceptable . 3-4 X

• Numbers tested (mean, 95th percentile)

2

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Design of Monte Carlo Study

• True LD50 = 1500 units

• Inital dose 15, 100, 150, 1000, 1500

• Probit slope 0.5 - 8

• Max. number tested 15, 25

Graph Sets

• Comparision of 2 estimators based on stopping criterion 4 with max tested = 25

• Comparision of stopping criteria 1 and 4 based on geometric mean, max tested = 25

• Comparision of max. tested 15 versus 25 based on stopping criterion 4 and geometric mean.

D. Farrar - January 2000 H-3

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Initial Dose = LD50 / 100 sp

read

0

10

20

30

40

50

Geometric Average

MLE, slope = 2

0 2 4 6 8 10

slope

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Initial Dose = LD50 / 100 bi

as in

dex

0.2

0.4

0.6

0.8

1.0

1.2

MLE, slope = 2

Geometric Average

0 2 4 6 8 10

slope

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Initial Dose = LD50 / 10 sp

read

inde

x

0

5

10 15

20 25

30

35 40

MLE, slope = 2

Geometric Average

0 2 4 6 8 10

slope

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Initial Dose = LD50 / 10 bi

as in

dex

0.3

0.4

0.5 0.6

0.7 0.8

0.9

1.0 1.1

MLE, slope = 2

Geometric Average

0 2 4 6 8 10

slope

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Initial Dose = LD50 sp

read

inde

x

2 4 6 8

10 12 14 16 18 20 22 24

MLE, slope = 2

Geometric Average

0 2 4 6 8 10

slope

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Initial Dose = LD50 bi

as in

dex

0.6

0.7

0.8

0.9

1.0

1.1

1.2

1.3

MLE, slope = 2

Geometric Average

0 2 4 6 8 10

slope

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Initial Dose = LD50 / 100 sp

rea

d in

de

x

2.0

4.0

6.0

8.0

10.0

12.0

14.0

16.0

LR stopping

Fixed n stopping

1.0 2.0 3.0 4.0 5.0 6.0 7.0

probit slope

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Bia

s in

dex

0.50

0.55

0.60

0.65

0.70

0.75

0.80

0.85

0.90

LR stopping

Fixed n stopping

Initial Dose = LD50 / 100

1.0 2.0 3.0 4.0 5.0 6.0 7.0

probit slope

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Initial Dose = LD50 / 100m

ean

num

ber

test

ed

8

9

10

11

12

13

14

15

16

LR stopping

Fixed n stopping

1.0 2.0 3.0 4.0 5.0 6.0 7.0

probit slope

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Initial Dose = LD50 / 10 sp

read

inde

x

2

4

6

8

10

12

LR stopping

Fixed n stopping

1.0 2.0 3.0 4.0 5.0 6.0 7.0

probit slope

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Initial Dose = LD50 / 10 bi

as in

dex

0.5

0.6

0.7

0.8

0.9

1.0

LR stopping

Fixed n stopping

1.0 2.0 3.0 4.0 5.0 6.0 7.0

probit slope

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Initial Dose = LD50 / 10 m

ean

num

ber

test

ed

6

8

10

12

14

16

LR stopping

Fixed n stopping

1.0 2.0 3.0 4.0 5.0 6.0 7.0

probit slope

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Initial Dose = LD50sp

read

inde

x

2

3

4

5

6

7

8

9

LR stopping

Fixed n stopping

0.0 1.0 2.0 3.0 4.0 5.0 6.0 7.0

probit slope

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Initial Dose = LD50 bi

as in

dex

0.8

0.9

1.0

1.1

1.2

1.3

LR stopping

Fixed n stopping

0.0 1.0 2.0 3.0 4.0 5.0 6.0 7.0

probit slope

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Initial Dose = LD50 m

ean

num

ber

test

ed

5

6

7

8

9

10

11

12

LR stopping

Fixed n stopping

1.0 2.0 3.0 4.0 5.0 6.0 7.0

probit slope

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spre

ad in

dex

0

10

20

30

40

50

max. tested = 15

max. tested = 25

Initial Dose = LD50 / 100

0 2 4 6 8 10

slope

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Initial Dose = LD50 / 100 bi

as in

dex

0.0

0.2

0.4

0.6

0.8

1.0

1.2 max. tested = 15

max. tested = 25

0 2 4 6 8 10

slope

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num

ber

test

ed

8

10

12

14

16

18

20

max. tested = 15

max. tested = 25

Initial Dose = LD50 / 100

0 2 4 6 8 10

slope

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Initial Dose = LD50 / 10 sp

read

inde

x

0

5

10

15

20

25

30

35

max. tested = 15 max. tested = 25

0 2 4 6 8 10

slope

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bias

inde

x

0.3

0.4

0.5 0.6

0.7

0.8 0.9

1.0 1.1

max. tested = 15

max. tested = 25

Initial Dose = LD50 / 10

0 2 4 6 8 10

slope

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Initial Dose = LD50 / 10 m

ean

num

ber

test

ed

6

8

10

12

14

16

18

max. tested = 15

max. tested = 25

0 2 4 6 8 10

slope

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Initial Dose = LD50 sp

read

inde

x

2

4

6

8

10

12

14

16

max. tested = 15 max. tested = 25

0 2 4 6 8 10

slope

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Initial Dose = LD50 bi

as in

dex

0.6

0.7

0.8

0.9

1.0

1.1

1.2

1.3

0 2 4 6 8 10

slope

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mea

n nu

mbe

r te

sted

4

6

8

10

12

14

16

18

max. tested = 25

max. tested = 15

Initial Dose = LD50

0 2 4 6 8 10

slope

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