Class 8. Oceans Figure: Ocean Depth (mean = 3.7 km)
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Transcript of Class 8. Oceans Figure: Ocean Depth (mean = 3.7 km)
![Page 1: Class 8. Oceans Figure: Ocean Depth (mean = 3.7 km)](https://reader036.fdocuments.in/reader036/viewer/2022062315/5697c0281a28abf838cd69e5/html5/thumbnails/1.jpg)
Class 8. Oceans
Figure: Ocean Depth (mean = 3.7 km)
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Ship-measurements
Only a limited area covered
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SST from buoys
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-2.0 34.2 0C16.1
Ocean Surface Temperature from Remote Sensing
(NOAA)
source NOAA
http://www.osdpd.noaa.gov/ml/ocean/sst/sst_anim_full.html
- maximum insolation- albedo of water ~ 7%
warm
cold water sinks
cold water sinks
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Ocean Surface Salinity
Evap>Prep
Prep>Evap
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ARGO: profiling the interior of the ocean (up to z=-
2000 m)
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ARGO: profiling the interior of the ocean (up to z=-
2000 m)
Data products:Temperature, salinity and density
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Zonal average temperature in deep ocean
abyss z>1000 mhomogeneous mass of very cold water
warm salty stratified lens of fluid
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Schematic of vertical structure
convection in the upper layer causes a vertically well mixed layer
strong vertical temperature gradient defines the thermocline
note: analogy to thermal inversion in the atmosphere
very cold water present below z<1000 m
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Thermal expansion: Sea-level transgression scenarios for Bangladesh
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Density (anomaly s), Temperature and Salinity
Fig. 9.2: Contours of seawater density anomalies ( = -s r rref in kg/m3)
rref = 1000 kg/m3
PSU = Practical Salinity Unit ≈ g/kg grams of salt per kg of solution
higher density
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Simplified equation of state (defined with respect to
s0(T0,S0))
€
σ =σ0 + ρ ref −α T T − T0[ ] + βS S −S0[ ]( )
€
αT = −1
ρ ref
∂ρ
∂T
€
βS =1
ρ ref
∂ρ
∂S
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Simplified equation of state (defined with respect to
s0(T0,S0))
€
σ =σ0 + ρ ref −α T T − T0[ ] + βS S −S0[ ]( )
a
s
s
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Schematic of vertical structure
€
∂T
∂t= −
1
ρwcw
∂F
∂z
tendency due to radiative heating
T = temperatureF = heat flux (Wm-2)rw = density of watercw = heat capacity of water
μ
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1000
dep
th (
m)
0
cold water -deep convection
cold waterdeep convection
upwelling
900S 900N 00 latitude
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P>E P<E P<E P>E
Low salinity if precipitation (P) exceeds evaporation (E)
1000
dep
th (
m)
0
900S 900N 00 latitude
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Thermohaline circulation
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Sea level height
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Which balances do apply in the ocean?
Hydrostatic balance -> yes
Geostrophic balance?
Thermal "wind"?
Ekman pumping/suction?
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Rossby and Reynolds number in the ocean
Far away from the equator, e.g. latitude = 400,
North-South length scale L = 2000 km
(east-west larger)
Velocity scale U = 0.1
m/s
€
f = 2×2π
24 × 3600sin 400
( ) =1×10−4 s−1
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Pressure in the ocean
€
p x,y,z( ) = ps + gρdzz
η
∫ = ps + g ρ η − z( )
high pressure low pressure
€
ρ =ρref =
ρdzz
η
∫η − z( )
mean densityin water column
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Which sea level tilt is needed to explain U=0.1 m/s?
€
p x,y,z0( ) = ps + gρdzz0
η
∫ = ps + g ρ η(x,y) − z0[ ]
Example 1: assume density is constant
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Geostrophic flow at depth
Example 2: assume density is NOT constant,
but varies in the x,y directions => r(x,y)=rref+s(x,y)
€
0 = −1
ρ
∂p
∂x+ fv
1000
de
pth
(m
)
0
900S 900N 00
latitude
2324
25
2626.5
27
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Estimating the geostrophic wind from the density field:
The dynamic method
€
∂ug
∂z=
g
fρ ref
∂σ
∂y
€
ug z( ) − ug z1( ) =g
f
1
ρ ref
∂σ
∂ydz
z1
z
∫
This method allows for assessing geostrophic velocities relative to some reference level
One can assume that at a "sufficiently" deep height ug=0
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Geostrophic flow at depth z
Example 3: I) assume density is NOT constant,
but varies in the x,y directions => r(x,y)=rref+s(x,y)
II) surface height is NOT constant
€
0 = −1
ρ
∂p
∂x+ fv
€
p x,y,z( ) = ps + gρdzz
η
∫ = ps + g ρ η(x,y) − z[ ]
€
v z( ) =g
fρ ref
η − z( )∂σ
∂x+
g
f
∂η
∂x
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Geostrophic flow
Example 1: In the ocean geostrophic flow applies (not too close to equator)
Pressure induced by surface height variations η
Example 2: Horizontal density gradients cause a vertical change in the geostrophic flow velocity ("thermal" wind)
Example 3: In principle both height and density variations may apply
€
0 = −g∂η
∂x+ fvg
€
∂vg
∂z= −
g
fρ ref
∂σ
∂x
€
0 = −g∂η
∂y− fug
€
∂ug
∂z=
g
fρ ref
∂σ
∂y
€
v z( ) =g
fρ ref
η − z( )∂σ
∂x+
g
f
∂η
∂x
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Determining the ocean flow from floating plastic ducks?
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1000
dep
th (
m)
0
cold water -deep convection
cold waterdeep convection
upwelling
900S 900N 00 latitude
![Page 31: Class 8. Oceans Figure: Ocean Depth (mean = 3.7 km)](https://reader036.fdocuments.in/reader036/viewer/2022062315/5697c0281a28abf838cd69e5/html5/thumbnails/31.jpg)
Ekman pumping/suction
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Wind-driven ocean flow
Equations with wind-stress
€
x - component 0 = −1
ρ
∂p
∂x+ fv +
1
ρ ref
∂τx
∂z
€
y - component 0 = −1ρ
∂p∂y
−fu +1
ρ ref
∂τ y
∂z
![Page 33: Class 8. Oceans Figure: Ocean Depth (mean = 3.7 km)](https://reader036.fdocuments.in/reader036/viewer/2022062315/5697c0281a28abf838cd69e5/html5/thumbnails/33.jpg)
Wind-driven ocean flow
Equations with wind-stress
€
x - component 0 = −1
ρ
∂p
∂x+ fv +
1
ρ ref
∂τx
∂z
Split velocity in geostrophic ('g') and ageostrophic parts ('ag')
€
v = vg + vag
€
vg =1
ρf
∂p
∂x
€
−fvag =1
ρ ref
∂τx
∂z
€
fuag =1
ρ ref
∂τy
∂z
e.g.
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Ekman transport
€
MEk = ρ ref−δ
0
∫ uagdz
€
MEk = ρ ref uag,vag( )−δ
0
∫ dz =1
fτy,−τx( )
![Page 35: Class 8. Oceans Figure: Ocean Depth (mean = 3.7 km)](https://reader036.fdocuments.in/reader036/viewer/2022062315/5697c0281a28abf838cd69e5/html5/thumbnails/35.jpg)
Ekman pumping (downwards)/suction
X wind into the screen
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Ekman pumping (downwards)/suction
tropics
midlatitudes
elevated sea level heightin convergence area
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Ekman pumping/suction due to wind stress
![Page 38: Class 8. Oceans Figure: Ocean Depth (mean = 3.7 km)](https://reader036.fdocuments.in/reader036/viewer/2022062315/5697c0281a28abf838cd69e5/html5/thumbnails/38.jpg)
Ekman pumping/suction
Explanation
€
∂w∂z
= −∂u ag
∂x+
∂vag
∂y
⎛
⎝ ⎜
⎞
⎠ ⎟ mass conservation
€
w zsfc( ) −w zEkman,bottom( ) = −∂u ag
∂x+
∂vag
∂y
⎛
⎝ ⎜
⎞
⎠ ⎟dz
zEkman ,bottom
zsfc
∫
0
![Page 39: Class 8. Oceans Figure: Ocean Depth (mean = 3.7 km)](https://reader036.fdocuments.in/reader036/viewer/2022062315/5697c0281a28abf838cd69e5/html5/thumbnails/39.jpg)
Ekman pumping/suction
Explanation
€
vag = −1
fρ ref
∂τ x
∂z
€
u ag =1
fρ ref
∂τ y
∂z€
w zEkman,bottom( ) =∂u ag
∂x+
∂vag
∂y
⎛
⎝ ⎜
⎞
⎠ ⎟dz
zEkman ,bottom
zsfc
∫
€
w zEkman,bottom( ) =1
ρ ref
1
f
∂τy,sfc
∂x−
∂
∂y
τx,sfc
f
⎛
⎝ ⎜
⎞
⎠ ⎟
1. we do not assume that f is constant, but f=f(y)2. variations in wind stress are much larger than in f
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Ekman pumping/suction
Example
€
w zEkman,bottom( ) =1
ρ ref
∂∂x
τ y,sfc
f−
∂∂y
τ x,sfc
f
⎛
⎝ ⎜
⎞
⎠ ⎟
€
= 11000
2×10−1
2×106( ) 1×10−4
( )
⎡
⎣ ⎢ ⎢
⎤
⎦ ⎥ ⎥=10−6 m /s
= 32 m/year
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Ekman pumping/suction from wind stress climatology
€
w zEkman,bottom( ) =1
ρ ref
∂∂x
τ y,sfc
f−
∂∂y
τ x,sfc
f
⎛
⎝ ⎜
⎞
⎠ ⎟
downward
upward
f=0