Chemistry Chapter 19 Practice with acids and bases.
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Transcript of Chemistry Chapter 19 Practice with acids and bases.
![Page 1: Chemistry Chapter 19 Practice with acids and bases.](https://reader036.fdocuments.in/reader036/viewer/2022082417/56649f295503460f94c42120/html5/thumbnails/1.jpg)
Chemistry Chapter 19
Practice with acids and bases
![Page 2: Chemistry Chapter 19 Practice with acids and bases.](https://reader036.fdocuments.in/reader036/viewer/2022082417/56649f295503460f94c42120/html5/thumbnails/2.jpg)
Calculate the pH
• A solution is found to contain 3.65 x 10-3 mol/liter HCl, a strong acid.– What is the pH of the solution?
– What is the hydroxide ion concentration in the solution?
![Page 3: Chemistry Chapter 19 Practice with acids and bases.](https://reader036.fdocuments.in/reader036/viewer/2022082417/56649f295503460f94c42120/html5/thumbnails/3.jpg)
Calculate the pH
• A solution is found to contain 3.65 x 10-3 mol/liter HCl, a strong acid.– What is the pH of the solution?
» pH = -log[H+]
» - log(3.65 x 10-3) = 2.44
» Because the solution has an ion concentration of greater than 1 x 10-7, it is an acidic solution.
» Also because the pH is less than 7, we know it is acidic.
![Page 4: Chemistry Chapter 19 Practice with acids and bases.](https://reader036.fdocuments.in/reader036/viewer/2022082417/56649f295503460f94c42120/html5/thumbnails/4.jpg)
Calculate the pH
• A solution is found to contain 3.65 x 10-3 mol/liter HCl, a strong acid.– What is the hydroxide ion concentration in the
solution?» OH- ion concentration can be found by using Kw.
» Kw = [H+][OH-]
» 1 x 10-14 = (3.65 x 10-3)(x)
» 2.74 x 10-12
![Page 5: Chemistry Chapter 19 Practice with acids and bases.](https://reader036.fdocuments.in/reader036/viewer/2022082417/56649f295503460f94c42120/html5/thumbnails/5.jpg)
Working backwards
• A solution has a pH of 9.3. Using a mathematical approach, show that the solution is acidic or basic.
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Solution
• Acids have an H+ concentration of 1 x 10-7 or greater. We will therefore calculate the concentration using pH = -log[H+].9.3 = -log(x) or antilog -9.3 = x
x = 3.17 x 10-10
The solution is basic because the H+ ion concentration is less than 1 x 10-7
![Page 7: Chemistry Chapter 19 Practice with acids and bases.](https://reader036.fdocuments.in/reader036/viewer/2022082417/56649f295503460f94c42120/html5/thumbnails/7.jpg)
More practice
• What is the pH of a solution that contains 5.44 x 10 –5 M NaOH?
![Page 8: Chemistry Chapter 19 Practice with acids and bases.](https://reader036.fdocuments.in/reader036/viewer/2022082417/56649f295503460f94c42120/html5/thumbnails/8.jpg)
Solution
• What is the pH of a solution that contains 5.44 x 10 –5 M NaOH?
Two ways to do this:
solve for the H+, or calculate pOH and then use pKw to get pH
![Page 9: Chemistry Chapter 19 Practice with acids and bases.](https://reader036.fdocuments.in/reader036/viewer/2022082417/56649f295503460f94c42120/html5/thumbnails/9.jpg)
Solution
• What is the pH of a solution that contains 5.44 x 10 –5 M NaOH?
• 1 x 10-14 = [H+][OH-]
• 1 x 10-14/5.44 x 10-5 = [H+] = 1.84 x 10-10
• pH = -log(1.84 x 10-10) = 9.7 - basic
![Page 10: Chemistry Chapter 19 Practice with acids and bases.](https://reader036.fdocuments.in/reader036/viewer/2022082417/56649f295503460f94c42120/html5/thumbnails/10.jpg)
Other solution
• What is the pH of a solution that contains 5.44 x 10 –5 M NaOH?
• pOH = -log[OH-]
• -log(5.44 x 10-5) = 4.26
• pKw = pH + pOH or 14 – 4.26 = pH
• pH = 9.74 (answers are the same)
![Page 11: Chemistry Chapter 19 Practice with acids and bases.](https://reader036.fdocuments.in/reader036/viewer/2022082417/56649f295503460f94c42120/html5/thumbnails/11.jpg)
Polyprotic acids
• Many acids release more than one proton.Examples: H2SO4, H3PO4, H2C2O4
When these dissociate, they change the pH differently. Strong acids will donate all protons from H+, weak will not donate even all the first ions.
![Page 12: Chemistry Chapter 19 Practice with acids and bases.](https://reader036.fdocuments.in/reader036/viewer/2022082417/56649f295503460f94c42120/html5/thumbnails/12.jpg)
Example
• Calculate the pH of a 0.002 M H2SO4 solution.
![Page 13: Chemistry Chapter 19 Practice with acids and bases.](https://reader036.fdocuments.in/reader036/viewer/2022082417/56649f295503460f94c42120/html5/thumbnails/13.jpg)
Solution
• Calculate the pH of a 0.002 M H2SO4 solution.
• [H+] = 2(0.002) 0r 0.004 M H+ ions
• pH = -log(0.004) = 2.40
![Page 14: Chemistry Chapter 19 Practice with acids and bases.](https://reader036.fdocuments.in/reader036/viewer/2022082417/56649f295503460f94c42120/html5/thumbnails/14.jpg)
Problem
• What is the H+ ion concentration if the OH- ion concentration is 1 x 10-4 M? Kw for water is 1.0 x 10-14
• Is this solution an acid or a base?
![Page 15: Chemistry Chapter 19 Practice with acids and bases.](https://reader036.fdocuments.in/reader036/viewer/2022082417/56649f295503460f94c42120/html5/thumbnails/15.jpg)
Problem
• Show the neutralization reaction of acetic acid, a weak acid, and sodium hydroxide, a strong base.
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Problem
• If I were to put sodium acetate salt into water, would the solution be acidic, basic, or neutral? Why?
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Problem
• What acids and bases will produce ammonium chloride?
• When placed in water, would the solution be acidic, basic, or neutral? Why?
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Problem
• When placed in water would the solution of sodium bromide be acidic, basic or neutral?
• What color would it turn a strip of litmus paper?
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Questions
• What consitutes a strong acid?
• What constitutes a weak acid?
• What is a conjugate acid? How does it differ from a conjugate base?
• What is the difference between Bronsted –lowry acids and Arrhenius acids?