Chem 1045 Lab hess-s_law

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Energy Relationships in Chemical Reactions

Transcript of Chem 1045 Lab hess-s_law

Page 1: Chem 1045 Lab hess-s_law

Energy Relationships in Chemical Reactions

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Energy is the capacity to do work

• Thermal energy is the energy associated with the random motion of atoms and molecules

• Chemical energy is the energy stored within the bonds of chemical substances

• Nuclear energy is the energy stored within the collection of neutrons and protons in the atom

• Electrical energy is the energy associated with the flow of electrons

• Potential energy is the energy available by virtue of an object’s position

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Thermochemical Definitions

System : That part of the Universe whose change we are going to measure.Surroundings : Every thing else that is relevant to the change is defined as the “surroundings”.Internal Energy : The sum of the kinetic and potential energy of all the particles in a system.Heat (q) : Is the energy transferred between a system and it’s surroundings as result in the differences in their temperatures only!Work (w) : The energy transferred when an object is moved by a force.

Therefore: E = q + w

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Heat is the transfer of thermal energy between two bodies that are at different temperatures.

Energy Changes in Chemical Reactions

Temperature is a measure of the thermal energy.

Temperature = Thermal Energy

900C400C

greater thermal energy6.2

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Change in Enthalpy = H

Enthalpy is defined as the system’s internal energyplus the product of its pressure and volume.

H = E + PVFor a change in enthalpy:

H = E + PV Exothermic and Endothermic Reactions:

H = H final - H initial = H products - H reactants

Exothermic : H final H initial H 0

Endothermic : H final H initial H 0

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For processes occurring at constant pressure the enthalpy change equals the heat gained or lost.

H = qp

enthalpy of reaction or heat of reaction. (Energy change + small correction factor.)

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Constant-Pressure Calorimetry

No heat enters or leaves!

qsys = qwater + qcal + qrxn

qsys = 0

qrxn = - (qwater + qcal)qwater = msDt

qcal = CcalDt

6.4

Reaction at Constant PDH = qrxn

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The specific heat (s) of a substance is the amount of heat (q) required to raise the temperature of one gram of the substance by one degree Celsius.

The heat capacity (C) of a substance is the amount of heat (q) required to raise the temperature of a given quantity (m) of the substance by one degree Celsius.

C = ms

Heat (q) absorbed or released:

q = msDt

q = CDtDt = tfinal - tinitial

6.4

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How much heat is given off when an 869 g iron bar cools from 940C to 50C?

s of Fe = 0.444 J/g • 0C

Dt = tfinal – tinitial = 50C – 940C = -890C

q = msDt = 869 g x 0.444 J/g • 0C x –890C = -34,000 J

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The standard enthalpy of reaction (DH0 ) is the enthalpy of a reaction carried out at 1 atm.

rxn

aA + bB cC + dD

DHorxn dDHo (D)fcDHo (C)f= [ + ] - bDHo (B)faDHo (A)f[ + ]

DHorxn nDHo (products)f= S mDHo (reactants)fS-

Hess’s Law: When reactants are converted to products, the change in enthalpy is the same whether the reaction takes place in one step or in a series of steps.

(Enthalpy is a state function. It doesn’t matter how you get there, only where you start and end.)

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Hess’s Law of Heat Summation

The enthalpy change of an overall process is the sum of the enthalpy changes of its individual steps.

Example: Problem: Calculate the energy involved in the oxidation of elemental sulfur to sulfur trioxide from reactions: 1) S (s) + O2 (g) SO2 (g) H1 = -296.0 kJ

2) 2 SO2 (g) + O2 (g) 2 SO3 (g) H2 = -198.2 kJ

3) S (s) + 3/2 O2 (g) SO3 (g) H3 = ?

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Hess’s Law of Heat Summation

The enthalpy change of an overall process is the sum of the enthalpy changes of its individual steps.

Example: Problem: Calculate the energy involved in the oxidation of elemental sulfur to sulfur trioxide from reactions:2 X 1) S (s) + O2 (g) SO2 (g) 2H1 = -296.0 kJ X2+ 2) 2 SO2 (g) + O2 (g) 2 SO3 (g) H2 = -198.2 kJ

3) S (s) + 3/2 O2 (g) SO3 (g) H3 = ?

H3 = 2H1 + H2